How do i create multiple distinguishable members in a struct - arrays

Question

I need to store multiple distinguishable members in a struct for a personal diary to show different records for each day. I want multiple members like e1 without writing it 365 times. I want a solution that works e1 on a loop or on an array.
struct add
{
char day[365];
char date[365];
char time[365];
char place[365];
char data[365];
};
int main()
{
int i=1;
struct add e1;
while(i!=0)
{
printf("Enter Day:");
gets(e1.day);
printf("Enter Date:");
gets(e1.date);
printf("Enter Time:");
gets(e1.time);
printf("Enter Place:");
gets(e1.place);
printf("Tell me about your day:");
gets(e1.data);
printf("\n\n\n");
printf("Day: %s\n",e1.day);
printf("Day: %s\n",e1.date);
printf("Day: %s\n",e1.time);
printf("Day: %s\n",e1.place);
printf("Day: %s\n\n\n",e1.data);
}
return 0;
}

Answer 1

I don't think its possible to create different variable with each loop, you can refer to this question for info. Instead of making different instances, make your struct in a way so that it stores data for all (365) days. Something like array of strings so that it stores for all days, currently even if you write something like char day[365] it creates separate day for each instance. make something like:
struct add
{
char day[NUMBER_OF_STRING][MAX_STRING_SIZE]; // syntax
// MAX_STRING_SIZE does not need to be 365, i just used it because you used that
// otherwise it does not make sense, date , time etc won't take more than 10 char
char date[365][365];
char time[365][365];
char place[365][365];
char data[365][365];
};
Now keep on adding to a single instance of struct add using for loop, this should be easy.
Also Better approach can be to create a array of struct add itself with your original struct code.

Answer 2

This example does what you want, and you can create as many instance of add as you want.
I limit your loop to run once and have tested that the code works with visual studio 2019:
#include <stdio.h>
#include <string.h>
#include <malloc.h>
#define DAY_SIZ 20
#define DATE_SIZ 40
#define TIME_SIZ 20
#define PLACE_SIZ 120
#define DATA_SIZ (BUFSIZ - 1)
struct add
{
char day[DAY_SIZ];
char date[DATE_SIZ];
char time[TIME_SIZ];
char place[PLACE_SIZ];
char data[DATA_SIZ];
};
struct add* create_add_struct() {
struct add* rec;
rec = (struct add*)malloc(sizeof(struct add));
return rec;
}
void destroy_add_struct(struct add* rec) {
free(rec);
}
void clear_add_struct(struct add* rec) {
memset(rec->day, 0, sizeof(rec->day));
memset(rec->date, 0, sizeof(rec->date));
memset(rec->time, 0, sizeof(rec->time));
memset(rec->place, 0, sizeof(rec->place));
memset(rec->data, 0, sizeof(rec->data));
}
void get_text_from_user(const char prompt[], char *txt, int siz) {
char buf[BUFSIZ];
printf("%s", prompt);
fgets(buf, BUFSIZ, stdin);
memcpy(txt, buf, siz);
}
void fill_add_struct(struct add* rec) {
printf("Do not enter any lines longer than %d\n\n", BUFSIZ);
get_text_from_user("Enter Day:", rec->day, sizeof(rec->day) - 1);
get_text_from_user("Enter Date:", rec->date, sizeof(rec->date) - 1);
get_text_from_user("Enter Time:", rec->time, sizeof(rec->time) - 1);
get_text_from_user("Enter Place:", rec->place, sizeof(rec->place) - 1);
get_text_from_user("Tell me about your day:", rec->data, sizeof(rec->data) - 1);
}
void print_add_struct(struct add* rec) {
printf("\n\n\n");
printf("Day : %s\n", rec->day);
printf("Date : %s\n", rec->date);
printf("Time : %s\n", rec->time);
printf("Place: %s\n", rec->place);
printf("Data : %s\n\n\n", rec->data);
}
int main()
{
// The number of times we want the loop to run
int i = 1;
// Collect data from the user and print it
while (i-- != 0)
{
// Allocate memory and initialize it
struct add* rec = create_add_struct();
clear_add_struct(rec);
// Get data from the user and print it
fill_add_struct(rec);
print_add_struct(rec);
// Release memory
destroy_add_struct(rec);
}
// Return success
return 0;
}
The reason I allocate your structure, is to make sure a stack-overflow does not occur, no pun intended.
If you want to create 365 add structs, you can create them like so:
struct add **records;
records = (struct add **) malloc(sizeof(struct add *) * 365);
for(int idx = 0; idx < 365; ++idx) {
records[idx] = create_add_struct();
clear_add_struct(records[idx]);
/* ... insert code ... */
}
/* ... insert code ... */
// Free memory
for(int idx = 0; idx < 365; ++idx) {
destroy_add_struct(records[idx]);
}
free(records);
I have not tested if the last piece of code compiles and works. Again I use malloc() and free() to avoid a stack-overflow.

Answer 3

typedef struct
{
time_t tm;
char *description;
}entry;
typedef struct day
{
time_t date;
size_t nentries;
struct day *next;
entry entries[];
}day;
and create linked list od days. Every day has array of diary entries.