How to chunk a file into 4 equal files - file

Question

I have a file of huge size for example 100MB, I need to chunk it into 4 25MB files using golang.
The thing here is, if i use go routine and read the file, the order of the data inside the files are not preserved. the code i used is
package main
import (
"bufio"
"fmt"
"log"
"os"
"sync"
"github.com/google/uuid"
)
func main() {
file, err := os.Open("sampletest.txt")
if err != nil {
log.Fatal(err)
}
defer file.Close()
lines := make(chan string)
// start four workers to do the heavy lifting
wc1 := startWorker(lines)
wc2 := startWorker(lines)
wc3 := startWorker(lines)
wc4 := startWorker(lines)
scanner := bufio.NewScanner(file)
go func() {
defer close(lines)
for scanner.Scan() {
lines <- scanner.Text()
}
if err := scanner.Err(); err != nil {
log.Fatal(err)
}
}()
writefiles(wc1, wc2, wc3, wc4)
}
func writefile(data string) {
file, err := os.Create("chunks/" + uuid.New().String() + ".txt")
if err != nil {
fmt.Println(err)
}
defer file.Close()
file.WriteString(data)
}
func startWorker(lines <-chan string) <-chan string {
finished := make(chan string)
go func() {
defer close(finished)
for line := range lines {
finished <- line
}
}()
return finished
}
func writefiles(cs ...<-chan string) {
var wg sync.WaitGroup
output := func(c <-chan string) {
var d string
for n := range c {
d += n
d += "\n"
}
writefile(d)
wg.Done()
}
wg.Add(len(cs))
for _, c := range cs {
go output(c)
}
go func() {
wg.Wait()
}()
}
Here using this code my file got split into 4 equal files, but the order in it is not preserved.
I am very new to golang, any suggestions are highly appreciated.
I took this code from some site and tweaked here and there to meet my requirements.

Answer 1

I took this code from some site and tweaked here and there to meet my requirements.
Based on your statement, you should be able to modify the code from running concurrently to sequentially, it's faaar easier than applying concurrent aspect to existing code.
The work is basically just: remove the concurrent part.
Anyway, below is a simple example of how to achieve what you want. I use your code as the base, and then I remove everything related to concurrent process.
package main
import (
"bufio"
"fmt"
"log"
"os"
"strings"
"github.com/google/uuid"
)
func main() {
split := 4
file, err := os.Open("file.txt")
if err != nil {
log.Fatal(err)
}
defer file.Close()
scanner := bufio.NewScanner(file)
texts := make([]string, 0)
for scanner.Scan() {
text := scanner.Text()
texts = append(texts, text)
}
if err := scanner.Err(); err != nil {
log.Fatal(err)
}
lengthPerSplit := len(texts) / split
for i := 0; i < split; i++ {
if i+1 == split {
chunkTexts := texts[i*lengthPerSplit:]
writefile(strings.Join(chunkTexts, "\n"))
} else {
chunkTexts := texts[i*lengthPerSplit : (i+1)*lengthPerSplit]
writefile(strings.Join(chunkTexts, "\n"))
}
}
}
func writefile(data string) {
file, err := os.Create("chunks-" + uuid.New().String() + ".txt")
if err != nil {
fmt.Println(err)
}
defer file.Close()
file.WriteString(data)
}

Answer 2

Here is a simple file splitter. You can handle the leftovers yourself, I added the leftover bytes to 5th file.
package main
import (
"bufio"
"fmt"
"os"
)
func main() {
file, err := os.Open("sample-text-file.txt")
if err != nil {
panic(err)
}
defer file.Close()
// to divide file in four chunks
info, _ := file.Stat()
chunkSize := int(info.Size() / 4)
// reader of chunk size
bufR := bufio.NewReaderSize(file, chunkSize)
// Notice the range over slice of len 5, after 4 leftover will be written to 5th file
for i := range [5]int{} {
reader := make([]byte, chunkSize)
rlen, err := bufR.Read(reader)
fmt.Println("Read: ", rlen)
if err != nil {
panic(err)
}
writeFile(i, rlen, &reader)
}
}
// Notice bufW as a pointer to avoid exchange of big byte slices
func writeFile(i int, rlen int, bufW *[]byte) {
fname := fmt.Sprintf("file_%v", i)
f, err := os.Create(fname)
defer f.Close()
w := bufio.NewWriterSize(f, rlen)
wbytes := *(bufW)
wLen, err := w.Write(wbytes[:rlen])
if err != nil {
panic(err)
}
fmt.Println("Wrote ", wLen, "to", fname)
w.Flush()
}