Sort Numbers after Letters in Angular - angularjs

Question

I want to sort Letters first and followed by numbers like below:
[Austria , France , Germany , 101110 , 124563]
This is what i have tried:
obj.sort((a,b) => a.text > b.text ? 1 : -1)
But it is sorting numbers first and then letters.
Any help?

Answer 1

If you are looking for a solution like you want to sort string at the first portion of array and numbers at the last of array, just make sure that you are following this procedure.
Never compare a string with a number.
If both a and b are string or both are numbers just compare both with a > b and return 1 or -1 depending on the result of comparision.
The last else block corresponds to the comparision between a number and a string. The return value determines the location of the numbers in the array. If either one of them is not a number, return -1 or 1 depending on the requirement. Since you want the numbers at the end of your array, return -1 if the value is not a number. If you send 1 instead, the numbers will take the first posion in he output array.
const data = [101110 , 124563 , 'France' , 'Austria', 'Germany'];
const output = data.sort((a,b) => {
if (
(isNaN(a) && isNaN(b)) || (!isNaN(a) && !isNaN(b))
) {
// Both are strings
// OR
// Both are numbers
return a > b ? 1 : -1;
}
else {
// One of them is a number
return isNaN(a) ? -1 : 1;
}
});
console.log(output);
Much Simplified version
const data = [101110, 'France', 'Austria', 124563, 'Germany'];
const checkOfSamePattern = (a, b) => (isNaN(a) && isNaN(b)) || (!isNaN(a) && !isNaN(b));
const output = data.sort((a, b) => checkOfSamePattern(a, b) ? a > b ? 1 : -1 : isNaN(a) ? -1 : 1);
console.log(output);