Snowflake Timestamp conversion - snowflake-cloud-data-platform

Question

The following code gives me the value of Fri Aug 06 2021 12:16:27 GMT-0700 (Pacific Daylight Time) instead of mm/dd/yyyy hh:mm:ss. What am I missing here? Please advise
create or replace procedure Load_Employee()
returns varchar not null
language javascript
EXECUTE AS CALLER
as
$$
//Variable Initialization
var IntegrationTable ='EMPLOYEE';
var TypeID=0;
var MaxDate=' ';
var cmd = "Select max(COMPLETED_DATE) from SCHEMA.TABLE where TARGET_TABLE_NAME= " + "'" + IntegrationTable + "'" ;
var sql = snowflake.createStatement({sqlText: cmd});
var result = sql.execute();
result.next();
MaxDate=result.getColumnValue(1);
return MaxDate;
$$
;

Answer 1

That's how JavaScript will render a date when presented as a string. You can change to YYYY-MM-DD like this:
create or replace procedure Load_Employee()
returns varchar not null
language javascript
EXECUTE AS CALLER
as
$$
//Variable Initialization
var IntegrationTable ='EMPLOYEE';
var TypeID=0;
var MaxDate=' ';
var cmd = "Select max(COMPLETED_DATE) from SCHEMA.TABLE where TARGET_TABLE_NAME= " + "'" + IntegrationTable + "'" ;
var sql = snowflake.createStatement({sqlText: cmd});
var result = sql.execute();
result.next();
MaxDate=formatDate(result.getColumnValue(1));
return MaxDate;
// Helper functions
function formatDate(date) {
var d = new Date(date),
month = '' + (d.getMonth() + 1),
day = '' + d.getDate(),
hour = '' + d.getHours(),
minute = '' + d.getMinutes(),
second = '' + d.getSeconds(),
year = d.getFullYear();
if (month.length < 2) month = '0' + month;
if (day.length < 2) day = '0' + day;
if (hour.length < 2) hour = "0" + hour;
if (minute.length < 2) minute = "0" + minute;
if (second.length < 2) second = "0" + second;
return [month, day, year].join('/') + " " + [hour,minute,second].join(':');
}
$$
;