How do I test if _Static_assert is defined? - c

_Static_assert is built-in to some C compilers such as gcc and clang, but it may not be included in all C compilers. I would like to use the _Static_assert functionality while keeping my code as cross-platform as possible. I figured the best way to do this was to test
#ifdef _Static_assert
_Static_assert(0, "Test");
#endif
but that doesn't seem to work out. It compiles, but it does not detect that _Static_assert is defined. Then I figured I could test if the compiler was GCC or not, but I read that having __GNUC__ defined doesn't necessarily prove that the compiler used is GCC. This also doesn't detect other compilers where _Static_assert is defined that I may not know about. So my question is, what is the best way to detect if the compiler supports _Static_assert in the preprocessor?
EDIT:
This is the solution I came up with that suits my purposes. Thanks to #KamilCuk below for the link that helped me out.
// Check that we can use built-in _Static_assert
#if defined( __STDC_VERSION__ ) && __STDC_VERSION__ >= 201112L
#define WE_HAVE_STATIC_ASSERT 1
#endif
#if WE_HAVE_STATIC_ASSERT
_Static_assert(0, "Test");
#endif
This code works for me on both gcc and clang: https://godbolt.org/z/svaYjWj4j
FINAL EDIT (I think): This provides an answer to my original question about how to detect if _Static_assert is available. It also provides a fallback option that results in relatively helpful errors in most compilers I tested.
Here is the link to the test code: https://godbolt.org/z/TYEj7Tezd
// Check if we can use built-in _Static_assert
#if defined( __STDC_VERSION__ ) && __STDC_VERSION__ >= 201112L
#define MY_STATIC_ASSERT(cond, msg) _Static_assert(cond, msg)
#else // We make our own
// MY_JOIN macro trick generates a unique token
#define MY_JOIN2(pre, post) MY_JOIN3(pre, post)
#define MY_JOIN3(pre, post) pre ## post
#if defined( __COUNTER__ ) // try to do it the smart way...
#define MY_JOIN(pre) MY_JOIN2(pre, __COUNTER__)
#define MY_STATIC_ASSERT(cond, msg) \
static const char *MY_JOIN(static_assert)[(cond) * 2 - 1] = { msg }
#else // we did our best...
//will break if static assert on same line in different file
#define MY_JOIN(pre) MY_JOIN2(pre, __LINE__)
#define MY_STATIC_ASSERT(cond, msg) \
static const char *MY_JOIN(static_assert)[(cond) * 2 - 1] = { msg }
#endif
#endif
/* - CHANGE CODE HERE TO TEST THE ASSERTIONS - */
enum {
A = 3,
B = 3,
C = B - A
};
/* - --------------------------------------- - */
// Test to see if the enum values match our assertions
MY_STATIC_ASSERT(B > A, "B must be greater than A");
MY_STATIC_ASSERT(C > 0, "C must be greater than zero");
Helpful information I used to make this came from these links:
http://jonjagger.blogspot.com/2017/07/compile-time-assertions-in-c.html
https://www.tutorialspoint.com/cprogramming/c_preprocessors.htm
https://stackoverflow.com/a/43990067/16292858

How do I test if _Static_assert is defined?
_Static_assert is part of C11. So check for C11.
#if __STDC_VERSION__ > 201112L
You could also #include <assert.h> and check for #ifdef static_assert.
My first google hit for static_assert.h github has a nice example how to handle different tools and compilers: https://github.com/wc-duck/dbgtools/blob/master/include/dbgtools/static_assert.h#L68 .
If you want to write a C11 compatibility layer and use static assertion in your code, for example use this answer and fallback to your own wrapper:
// static_assert.h
#define CTASTR2(pre,post) pre ## post
#define CTASTR(pre,post) CTASTR2(pre,post)
#define STATIC_ASSERT(cond) \
typedef struct { int static_assertion_failed : !!(cond); } \
CTASTR(static_assertion_failed_,__COUNTER__)
#include <assert.h>
#ifndef static_assert
#define static_assert(expr, str) STATIC_ASSERT(expr)
#endif
// somefile.c
#include <static_assert.h>
static_assert(something == something, "Uwu");

Related

Function name macros which work accross compilers

There are preprocessor macros which define the name of a function inside it, __func__ for g++ and __FUNCTION__ for cl. (func is the c++ standard way of doing this (from dcl.fct.def.general) but it is not implmented everywhere)
For source which will be compiled by both of these compilers what should I do?
I have tried
#ifdef __func__
#define FUNCTION_NAME __func__
#else
#ifdef __FUNCTION__
#define FUNCTION_NAME __FUNCTION__
#else
#error "Function name macro not found"
#endif
#endif
but as it is not in a function the macros are not defined.
I have also tried
void implementation_detail() {
#ifdef __func__
#define FUNCTION_NAME __func__
#else
#ifdef __FUNCTION__
#define FUNCTION_NAME __FUNCTION__
#else
#error "Function name macro not found"
#endif
#endif
}
but that also gives an error.
How can I do this so it will work in multiple compliers?
I have found that there is a boost macro for this, BOOST_CURRENT_FUNCTION.
From looking at the source code here how this is implemented is they use an inline function like so.
inline void current_function_helper()
{
#if defined(__GNUC__) || (defined(__MWERKS__) && (__MWERKS__ >= 0x3000)) || (defined(__ICC) && (__ICC >= 600)) || defined(__ghs__) || defined(__DMC__)`
...
(also it is declared in a namespace called detail which is very wise)
I will use this.
EDIT: implementing __func__ will be in the Visual Studio customer technology preview out now, see here.

#define IDENTIFIER without a token

What does the following statement mean:
#define FAHAD
I am familiar with the statements like:
#define FAHAD 1
But what does the #define statement without a token signify?
Is it that it is similar to a constant definition?
Defining a constant without a value acts as a flag to the preprocessor, and can be used like so:
#define MY_FLAG
#ifdef MY_FLAG
/* If we defined MY_FLAG, we want this to be compiled */
#else
/* We did not define MY_FLAG, we want this to be compiled instead */
#endif
it means that FAHAD is defined, you can later check if it's defined or not with:
#ifdef FAHAD
//do something
#else
//something else
#endif
Or:
#ifndef FAHAD //if not defined
//do something
#endif
A real life example use is to check if a function or a header is available for your platform, usually a build system will define macros to indicate that some functions or headers exist before actually compiling, for example this checks if signal.h is available:
#ifdef HAVE_SIGNAL_H
# include <signal.h>
#endif/*HAVE_SIGNAL_H*/
This checks if some function is available
#ifdef HAVE_SOME_FUNCTION
//use this function
#else
//else use another one
#endif
Any #define results in replacing the original identifier with the replacement tokens. If there are no replacement tokens, the replacement is empty:
#define DEF_A "some stuff"
#define DEF_B 42
#define DEF_C
printf("%s is %d\n", DEF_A, DEF_B DEF_C);
expands to:
printf("%s is %d\n", "some stuff", 42 );
I put a space between 42 and ) to indicate the "nothing" that DEF_C expanded-to, but in terms of the language at least, the output of the preprocessor is merely a stream of tokens. (Actual compilers generally let you see the preprocessor output. Whether there will be any white-space here depends on the actual preprocessor. For GNU cpp, there is one.)
As in the other answers so far, you can use #ifdef to test whether an identifier has been #defined. You can also write:
#if defined(DEF_C)
for instance. These tests are positive (i.e., the identifier is defined) even if the expansion is empty.
#define FAHAD
this will act like a compiler flag, under which some code can be done.
this will instruct the compiler to compile the code present under this compiler option
#ifdef FAHAD
printf();
#else
/* NA */
#endif

Is there a way to both check a macro is defined and it equals a certain value at the same time

I regularly use object-like preprocessor macros as boolean flags in C code to turn on and off sections of code.
For example
#define DEBUG_PRINT 1
And then use it like
#if(DEBUG_PRINT == 1)
printf("%s", "Testing");
#endif
However, it comes a problem if the header file that contains the #define is forgotten to be included in the source code. Since the macro is not declared, the preprocessor treats it as if it equals 0, and the #if statement never runs.
When the header file is forgotten to be included, non-expected, unruly behaviour can occur.
Ideally, I would like to be able to both check that a macro is defined, and check that it equals a certain value, in one line. If it is not defined, the preprocessor throws an error (or warning).
I'm looking for something along the lines of:
#if-def-and-true-else-throw-error(DEBUG_PRINT)
...
#endif
It's like a combination of #ifdef and #if, and if it doesn't exist, uses #error.
I have explored a few avenues, however, preprocessor directives can't be used inside a #define block, and as far as I can tell, there is no preprocessor option to throw errors/warnings if a macro is not defined when used inside a #if statement.
This may not work for the general case (I don't think there's a general solution to what you're asking for), but for your specific example you might consider changing this sequence of code:
#if(DEBUG_PRINT == 1)
printf("%s", "Testing");
#endif
to:
if (DEBUG_PRINT == 1) {
printf("%s", "Testing");
}
It's no more verbose and will fail to compile if DEBUG_PRINT is not defined or if it's defined to be something that cannot be compared with 1.
as far as I can tell, there is no preprocessor option to throw errors/warnings if a macro is not defined when used inside a #if statement.
It can't be an error because the C standard specifies that behavior is legal. From section 6.10.1/3 of ISO C99 standard:
After all replacements due to macro expansion and the defined unary
operator have been performed, all remaining identifiers are replaced with the pp-number
0....
As Jim Balter notes in the comment below, though, some compilers (such as gcc) can issue warnings about it. However, since the behavior of substituting 0 for unrecognized preprocessor tokens is legal (and in many cases desirable), I'd expect that enabling such warnings in practice would generate a significant amount of noise.
There's no way to do exactly what you want. If you want to generate a compilation failure if the macro is not defined, you'll have to do it explicitly
#if !defined DEBUG_PRINT
#error DEBUG_PRINT is not defined.
#endif
for each source file that cares. Alternatively, you could convert your macro to a function-like macro and avoid using #if. For example, you could define a DEBUG_PRINT macro that expands to a printf call for debug builds but expands to nothing for non-debug builds. Any file that neglects to include the header defining the macro then would fail to compile.
Edit:
Regarding desirability, I have seen numerous times where code uses:
#if ENABLE_SOME_CODE
...
#endif
instead of:
#ifdef ENABLE_SOME_CODE
...
#endif
so that #define ENABLE_SOME_CODE 0 disables the code rather than enables it.
Rather than using DEBUG_PRINT directly in your source files, put this in the header file:
#if !defined(DEBUG_PRINT)
#error DEBUG_PRINT is not defined
#endif
#if DEBUG_PRINT
#define PrintDebug([args]) [definition]
#else
#define PrintDebug
#endif
Any source file that uses PrintDebug but doesn't include the header file will fail to compile.
If you need other code than calls to PrintDebug to be compiled based on DEBUG_PRINT, consider using Michael Burr's suggestion of using plain if rather than #if (yes, the optimizer will not generate code within a false constant test).
Edit:
And you can generalize PrintDebug above to include or exclude arbitrary code as long as you don't have commas that look like macro arguments:
#if !defined(IF_DEBUG)
#error IF_DEBUG is not defined
#endif
#if IF_DEBUG
#define IfDebug(code) code
#else
#define IfDebug(code)
#endif
Then you can write stuff like
IfDebug(int count1;) // IfDebug(int count1, count2;) won't work
IfDebug(int count2;)
...
IfDebug(count1++; count2++;)
Yes you can check both:
#if defined DEBUG && DEBUG == 1
# define D(...) printf(__VA_ARGS__)
#else
# define D(...)
#endif
In this example even when #define DEBUG 0 but it is not equal to 1 thus nothing will be printed.
You can do even this:
#if defined DEBUG && DEBUG
# define D(...) printf(__VA_ARGS__)
#else
# define D(...)
#endif
Here if you #define DEBUG 0 and then D(1,2,3) also nothing will be printed
DOC
Simply create a macro DEBUG_PRINT that does the actual printing:
#define DEBUG_PRINT(n, str) \
\
if(n == 1) \
{ \
printf("%s", str); \
} \
else if(n == 2) \
{ \
do_something_else(); \
} \
\
#endif
#include <stdio.h>
int main()
{
DEBUG_PRINT(1, "testing");
}
If the macro isn't defined, then you will get a compiler error because the symbol is not recognized.
#if 0 // 0/1
#define DEBUG_PRINT printf("%s", "Testing")
#else
#define DEBUG_PRINT printf("%s")
#endif
So when "if 0" it'll do nothing and when "if 1" it'll execute the defined macro.

Checking types of macro parameters at compile time

To check that two variables have the same structure type I use a macro
#define assert_same_struct_types(a, b) ((void) (sizeof((a)=(b))))
If some function-like macro
#define m(a,b) blablabla
assumes a and b should be of the same structure type, I add a compile time check:
#define m(a,b) (assert_same_struct_types(a, b), blablabla)
which provokes compiler error if caller of m(a,b) accidentally passes to m different types of structs.
However, this approach doesn't always work for builtin and pointer types due to implicit conversions between them.
So, is it possible to solve this problem for arbitrary types, not necessarily structs?
I need a solution for C89, however, it would be interesting to hear about C99 or C11 possibilities.
#define ASSERT_SAME_TYPE(a, b) ((void) (&(a) == &(b)))
will get you a compile diagnostic and an error with -Werror (for gcc or a similar option for other compilers).
Note that a lot of compilers have a non standard extension typeof operator to get the type of an object and this can be used to check two types are the same.
This questions asks about a C89 solution, so far I didn't find a good way to do this, so instead of relying on C89, you can check if the compiler supports typeof and use it when available. Its not ideal but means as long as some developers use GCC/Clang/IntelC, the error gets caught. of course, if you tell your compiler only to support C89 this isn't going to help.
It gives better type checking but obviously fails to be of any use at all when not supported.
#ifdef __GNUC__
#define CHECK_TYPE(var, type) { \
typeof(var) *__tmp; \
__tmp = (type *)NULL; \
(void)__tmp; \
} (void)0
#define CHECK_TYPE_PAIR(var_a, var_b) { \
typeof(var_a) *__tmp; \
__tmp = (typeof(var_b) *)NULL; \
(void)__tmp; \
} (void)0
#define CHECK_TYPE_PAIR_INLINE(var_a, var_b) ((void)({ \
typeof(var_a) *__tmp; \
__tmp = (typeof(var_b) *)NULL; \
(void)__tmp; \
}))
#else
# define CHECK_TYPE(var, type)
# define CHECK_TYPE_PAIR(var_a, var_b)
# define CHECK_TYPE_PAIR_INLINE(var_a, var_b) (void)0
#endif
/* inline type checking - can mix in with other macros more easily using the comma operator,
* C11 gives best results here */
#if defined(__STDC_VERSION__) && (__STDC_VERSION__ >= 201112L)
# define CHECK_TYPE_INLINE(val, type) \
(void)((void)(((type)0) != (0 ? (val) : ((type)0))), \
_Generic((val), type: 0, const type: 0))
#else
# define CHECK_TYPE_INLINE(val, type) \
((void)(((type)0) != (0 ? (val) : ((type)0))))
#endif

Ways to ASSERT expressions at build time in C

I'm tidying up some older code that uses 'magic numbers' all over the place to set hardware registers, and I would like to use constants instead of these numbers to make the code somewhat more expressive (in fact they will map to the names/values used to document the registers).
However, I'm concerned that with the volume of changes I might break the magic numbers. Here is a simplified example (the register set is more complex):
const short mode0 = 0;
const short mode1 = 1;
const short mode2 = 2;
const short state0 = 0;
const short state1 = 4;
const short state2 = 8;
so instead of :
set_register(5);
we have:
set_register(state1|mode1);
What I'm looking for is a build time version of:
ASSERT(5==(state1|mode1));
Update
#Christian, thanks for the quick response, I'm interested on a C / non-boost environment answer too because this is driver/kernel code.
NEW ANSWER :
In my original answer (below), I had to have two different macros to support assertions in a function scope and at the global scope. I wondered if it was possible to come up with a single solution that would work in both scopes.
I was able to find a solution that worked for Visual Studio and Comeau compilers using extern character arrays. But I was able to find a more complex solution that works for GCC. But GCC's solution doesn't work for Visual Studio. :( But adding a '#ifdef __ GNUC __', it's easy to choose the right set of macros for a given compiler.
Solution:
#ifdef __GNUC__
#define STATIC_ASSERT_HELPER(expr, msg) \
(!!sizeof \ (struct { unsigned int STATIC_ASSERTION__##msg: (expr) ? 1 : -1; }))
#define STATIC_ASSERT(expr, msg) \
extern int (*assert_function__(void)) [STATIC_ASSERT_HELPER(expr, msg)]
#else
#define STATIC_ASSERT(expr, msg) \
extern char STATIC_ASSERTION__##msg[1]; \
extern char STATIC_ASSERTION__##msg[(expr)?1:2]
#endif /* #ifdef __GNUC__ */
Here are the error messages reported for STATIC_ASSERT(1==1, test_message); at line 22 of test.c:
GCC:
line 22: error: negative width in bit-field `STATIC_ASSERTION__test_message'
Visual Studio:
test.c(22) : error C2369: 'STATIC_ASSERTION__test_message' : redefinition; different subscripts
test.c(22) : see declaration of 'STATIC_ASSERTION__test_message'
Comeau:
line 22: error: declaration is incompatible with
"char STATIC_ASSERTION__test_message[1]" (declared at line 22)
ORIGINAL ANSWER :
I do something very similar to what Checkers does. But I include a message that'll show up in many compilers:
#define STATIC_ASSERT(expr, msg) \
{ \
char STATIC_ASSERTION__##msg[(expr)?1:-1]; \
(void)STATIC_ASSERTION__##msg[0]; \
}
And for doing something at the global scope (outside a function) use this:
#define GLOBAL_STATIC_ASSERT(expr, msg) \
extern char STATIC_ASSERTION__##msg[1]; \
extern char STATIC_ASSERTION__##msg[(expr)?1:2]
There is an article by
Ralf Holly that examines different options for static asserts in C.
He presents three different approaches:
switch case values must be unique
arrays must not have negative dimensions
division by zero for constant expressions
His conclusion for the best implementation is this:
#define assert_static(e) \
do { \
enum { assert_static__ = 1/(e) }; \
} while (0)
Checkout boost's static assert
You can roll your own static assert if you don't have access to a third-party library static assert function (like boost):
#define STATIC_ASSERT(x) \
do { \
const static char dummy[(x)?1:-1] = {0};\
} while(0)
The downside is, of course, that error message is not going to be very helpful, but at least, it will give you the line number.
#define static_assert(expr) \
int __static_assert(int static_assert_failed[(expr)?1:-1])
It can be used anywhere, any times.
I think it is the easiest solution.
Before usage, test it with your compiler carefully.
Any of the techniques listed here should work and when C++0x becomes available you will be able to use the built-in static_assert keyword.
If you have Boost then using BOOST_STATIC_ASSERT is the way to go. If you're using C or don't want to get Boost
here's my c_assert.h file that defines (and explains the workings of) a few macros to handle static assertions.
It's a bit more convoluted that it should be because in ANSI C code you need 2 different macros - one that can work in the area where you have declarations and one that can work in the area where normal statements go. There is a also a bit of work that goes into making the macro work at global scope or in block scope and a bunch of gunk to ensure that there are no name collisions.
STATIC_ASSERT() can be used in the variable declaration block or global scope.
STATIC_ASSERT_EX() can be among regular statements.
For C++ code (or C99 code that allow declarations mixed with statements) STATIC_ASSERT() will work anywhere.
/*
Define macros to allow compile-time assertions.
If the expression is false, an error something like
test.c(9) : error XXXXX: negative subscript
will be issued (the exact error and its format is dependent
on the compiler).
The techique used for C is to declare an extern (which can be used in
file or block scope) array with a size of 1 if the expr is TRUE and
a size of -1 if the expr is false (which will result in a compiler error).
A counter or line number is appended to the name to help make it unique.
Note that this is not a foolproof technique, but compilers are
supposed to accept multiple identical extern declarations anyway.
This technique doesn't work in all cases for C++ because extern declarations
are not permitted inside classes. To get a CPP_ASSERT(), there is an
implementation of something similar to Boost's BOOST_STATIC_ASSERT(). Boost's
approach uses template specialization; when expr evaluates to 1, a typedef
for the type
::interslice::StaticAssert_test< sizeof( ::interslice::StaticAssert_failed<true>) >
which boils down to
::interslice::StaticAssert_test< 1>
which boils down to
struct StaticAssert_test
is declared. If expr is 0, the compiler will be unable to find a specialization for
::interslice::StaticAssert_failed<false>.
STATIC_ASSERT() or C_ASSERT should work in either C or C++ code (and they do the same thing)
CPP_ASSERT is defined only for C++ code.
Since declarations can only occur at file scope or at the start of a block in
standard C, the C_ASSERT() or STATIC_ASSERT() macros will only work there. For situations
where you want to perform compile-time asserts elsewhere, use C_ASSERT_EX() or
STATIC_ASSERT_X() which wrap an enum declaration inside it's own block.
*/
#ifndef C_ASSERT_H_3803b949_b422_4377_8713_ce606f29d546
#define C_ASSERT_H_3803b949_b422_4377_8713_ce606f29d546
/* first some utility macros to paste a line number or counter to the end of an identifier
* this will let us have some chance of generating names that are unique
* there may be problems if a static assert ends up on the same line number in different headers
* to avoid that problem in C++ use namespaces
*/
#if !defined( PASTE)
#define PASTE2( x, y) x##y
#define PASTE( x, y) PASTE2( x, y)
#endif /* PASTE */
#if !defined( PASTE_LINE)
#define PASTE_LINE( x) PASTE( x, __LINE__)
#endif /* PASTE_LINE */
#if!defined( PASTE_COUNTER)
#if (_MSC_VER >= 1300) /* __COUNTER__ introduced in VS 7 (VS.NET 2002) */
#define PASTE_COUNTER( x) PASTE( x, __COUNTER__) /* __COUNTER__ is a an _MSC_VER >= 1300 non-Ansi extension */
#else
#define PASTE_COUNTER( x) PASTE( x, __LINE__) /* since there's no __COUNTER__ use __LINE__ as a more or less reasonable substitute */
#endif
#endif /* PASTE_COUNTER */
#if __cplusplus
extern "C++" { // required in case we're included inside an extern "C" block
namespace interslice {
template<bool b> struct StaticAssert_failed;
template<> struct StaticAssert_failed<true> { enum {val = 1 }; };
template<int x> struct StaticAssert_test { };
}
}
#define CPP_ASSERT( expr) typedef ::interslice::StaticAssert_test< sizeof( ::interslice::StaticAssert_failed< (bool) (expr) >) > PASTE_COUNTER( IntersliceStaticAssertType_)
#define STATIC_ASSERT( expr) CPP_ASSERT( expr)
#define STATIC_ASSERT_EX( expr) CPP_ASSERT( expr)
#else
#define C_ASSERT_STORAGE_CLASS extern /* change to typedef might be needed for some compilers? */
#define C_ASSERT_GUID 4964f7ac50fa4661a1377e4c17509495 /* used to make sure our extern name doesn't collide with something else */
#define STATIC_ASSERT( expr) C_ASSERT_STORAGE_CLASS char PASTE( PASTE( c_assert_, C_ASSERT_GUID), [(expr) ? 1 : -1])
#define STATIC_ASSERT_EX(expr) do { enum { c_assert__ = 1/((expr) ? 1 : 0) }; } while (0)
#endif /* __cplusplus */
#if !defined( C_ASSERT) /* C_ASSERT() might be defined by winnt.h */
#define C_ASSERT( expr) STATIC_ASSERT( expr)
#endif /* !defined( C_ASSERT) */
#define C_ASSERT_EX( expr) STATIC_ASSERT_EX( expr)
#ifdef TEST_IMPLEMENTATION
C_ASSERT( 1 < 2);
C_ASSERT( 1 < 2);
int main( )
{
C_ASSERT( 1 < 2);
C_ASSERT( 1 < 2);
int x;
x = 1 + 4;
C_ASSERT_EX( 1 < 2);
C_ASSERT_EX( 1 < 2);
return( 0);
}
#endif /* TEST_IMPLEMENTATION */
#endif /* C_ASSERT_H_3803b949_b422_4377_8713_ce606f29d546 */
Try:
#define STATIC_ASSERT(x, error) \
do { \
static const char error[(x)?1:-1];\
} while(0)
Then you can write:
STATIC_ASSERT(a == b, a_not_equal_to_b);
Which may give you a better error message (depending on your compiler).
The common, portable option is
#if 5 != (state1|mode1)
# error "aaugh!"
#endif
but it doesn't work in this case, because they're C constants and not #defines.
You can see the Linux kernel's BUILD_BUG_ON macro for something that handles your case:
#define BUILD_BUG_ON(condition) ((void)sizeof(char[1 - 2*!!(condition)]))
When condition is true, this becomes ((void)sizeof(char[-1])), which is illegal and should fail at compile time, and otherwise it becomes ((void)sizeof(char[1])), which is just fine.
Ensure you compile with a sufficiently recent compiler (e.g. gcc -std=c11).
Then your statement is simply:
_Static_assert(state1|mode1 == 5, "Unexpected change of bitflags");
#define MODE0 0
#define MODE1 1
#define MODE2 2
#define STATE0 0
#define STATE1 4
#define STATE2 8
set_register(STATE1|STATE1); //set_register(5);
#if (!(5==(STATE1|STATE1))) //MY_ASSERT(5==(state1|mode1)); note the !
#error "error blah blah"
#endif
This is not as elegant as a one line MY_ASSERT(expr) solution. You could use sed, awk, or m4 macro processor before compiling your C code to generate the DEBUG code expansion of MY_ASSERT(expr) to multiple lines or NODEBUG code which removes them for production.

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