Printf Statement Runs After Function Goes From 'Void' to 'Int' - arrays

Question

I'm new to C.
I've made some code which creates an array, allows for user input to initialise the indexes of the array, and finally the inputs are checked against some parameters.
When I was originally testing the code, the function which contained the verification process was a 'void' function, but since I want this verification function to be the gatekeeper as to whether other functions run in my program, I changed it to an 'int' function so it could return a value which determined whether or not the rest of the program would run.
However, now it returns the printf statement in about invalid inputs twice. When it was a void function it would only display it once. How do I only get the printf statement in 'int verify' to display once?
Expected Input & Output:
1 2 1 3 4 5 } Input
Invalid input: 6 integers 1..9 in sorted order must be supplied. } Output
Current Output:
1 2 1 3 4 5 } Input
Invalid input: 6 integers 1..9 in sorted order must be supplied.}
Invalid input: 6 integers 1..9 in sorted order must be supplied.} Output
#define SIZE 6 //Size of array
void input(int selection[SIZE]);
int verify(int selection[SIZE]);
int main (void){
int selection[SIZE] = {0};
input(selection);
verify(selection);
if (verify(selection) == 1) {
printf("Correct!\n");
}
return 0;
}
//Function which assigns user input into array
void input(int selection[SIZE]){
int i = 0;
while (i < SIZE) {
scanf("%d", &selection[i]);
i++;
}
}
//Function to verify that user's input stays within the bounds
int verify(int selection[SIZE]){
int ver1 = 0;
int ver2 = 0;
int para = 1;
//Checks if inputted numbers are in desired range.
while (ver1 < SIZE) {
if (selection[ver1] > 9 || selection[ver1] < 1) {
printf("Invalid input: 6 integers 1..9 ");
printf("in sorted order must be supplied.\n");
ver2 = SIZE; //Prevents other checks from running as to have duplicate text
ver1 = SIZE; //Prevents other checks from running as to have duplicate text
para = 0;
}
ver1++;
}
//Loops through each value inputed into the function and verifies that
//they are in sorted order
while (ver2 < (SIZE-1)) {
if (selection[ver2] > selection[ver2+1]){
printf("Invalid input: 6 integers 1..9");
printf(" in sorted order must be supplied.\n");
ver2 = SIZE;
para = 0;
}
ver2++;
}
return para;
}

Answer 1

Change this code:
verify(selection);
if (verify(selection) == 1) {
printf("Correct!\n");
}
to this:
if (verify(selection) == 1) {
printf("Correct!\n");
}
Basically, verify was producing output twice because you were calling it twice.

Answer 2

Your code was calling verify twice, causing 'invalid input' to be printed twice.
You called it once before the if, and once inside the if.
If you want to check what the verify function returned, without calling it again, you can write something like this:
int checkResult = verify(selection);
if ( checkResult == 1) {
printf("Correct!\n");