How to properly fill an NxN matrix - arrays

Question

I have been trying to create an NxN square matrix (the size of the square matrix is determined by the user) but seem to have run into an issue. The displayed matrix is actually a symmetric matrix which is not what I am trying to as I want to be able to have each value hold a unique integer. Any help is greatly appreciated. Here's my code:
#include <stdio.h>
int main()
{
int i;
int j;
int size = 1;
int array [size][size];
printf ("Enter the size you would like for the nxn matrix: ");
scanf ("%d", &size);
printf ("Now enter elements into the matrix. \n");
for (i = 0; i < size; i++)
{
for (j = 0; j < size; j++)
{
printf ("[%d][%d] = ", i, j);
scanf ("%d", &array [i][j]);
}
}
printf ("------------------------\n\n");
printf ("the matrix is: \n\n");
for (i = 0; i < size; i++)
{
for (j = 0; j < size; j++)
{
printf (" %d ", array [i][j]);
}
printf ("\n");
}
return (0);
}

Answer 1

#include <stdio.h>
#include <stdlib.h>
int main()
{
// Create variables
int i, j, size;
// Create 2D array
printf ("Enter the size you would like for the nxn matrix: ");
scanf ("%d", &size);
int *array = (int *)malloc(size * size * sizeof(int));
// Fill 2D array with values
printf ("Now enter elements into the matrix. \n");
for (i = 0; i < size; i++)
{
for (j = 0; j < size; j++)
{
printf ("[%d][%d] = ", i, j);
scanf ("%d", &array[i * size + j]);
}
}
printf ("------------------------\n\n");
// Display values of 2D array
printf ("the matrix is: \n\n");
for (i = 0; i < size; i++)
{
for (j = 0; j < size; j++)
{
printf ("%d", array[i * size + j]);
}
printf ("\n");
}
free(array);
return (0);
}