How to read specific words from a file? - c

I have a file that contains words and their synonyms each on a separate line.
I am writing this code that should read the file line by line then display it starting from the second word which is the synonym.
I used the variable count in the first loop in order to be able to count the number of synonyms of each word because the number of synonyms differs from one to another. Moreover I used the condition synonyms[i]==',' because each synonym is separate by a comma.
The purpose of me writing such code is to put them in a binary search tree in order to have a full dictionary.
The code doesn't contain any error yet it is not working.
I have tried to each the loop but that didn't work too.
Sample input from the file:
abruptly - dead, short, suddenly
acquittance - release
adder - common, vipera
Sample expected output:
dead short suddenly
acquittance realse
common vipera
Here is the code:
void LoadFile(FILE *fp){
int count;
int i;
char synonyms[50];
char word[50];
while(fgets(synonyms,50,fp)!=NULL){
for (i=0;i<strlen(synonyms);i++)
if (synonyms[i]==',' || synonyms[i]=='\n')
count++;
}
while(fscanf(fp,"%s",word)==1){
for(i=1;i<strlen(synonyms);i++){
( fscanf(fp,"%s",synonyms)==1);
printf("%s",synonyms);
}
}
}
int main(){
char fn[]="C:/Users/CLICK ONCE/Desktop/Semester 4/i2206/Project/Synonyms.txt";
FILE *fp;
fp=fopen(fn,"rt");
if (fp==NULL){
printf("Cannot open this file");
}
else{
LoadFile(fp);
}
return 0;
}

Here is my solution. I have split the work into functions for readability. The actual parsing is done in parsefunction. That function thakes into account hyphenated compound words such as seventy-two. The word and his synonyms must be separated by an hyphen preceded by at least one space.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
// Trim leading and trailing space characters.
// Warning: string is modified
char* trim(char* s) {
char* p = s;
int l = strlen(p);
while (isspace(p[l - 1])) p[--l] = 0;
while (*p && isspace(*p)) ++p, --l;
memmove(s, p, l + 1);
return s;
}
// Warning: string is modified
int parse(char* line)
{
char* token;
char* p;
char* word;
if (line == NULL) {
printf("Missing input line\n");
return 0;
}
// first find the word delimiter: an hyphen preceded by a space
p = line;
while (1) {
p = strchr(p, '-');
if (p == NULL) {
printf("Missing hypen\n");
return 0;
}
if ((p > line) && (p[-1] == ' ')) {
// We found an hyphen preceded by a space
*p = 0; // Replace by nul character (end of string)
break;
}
p++; // Skip hyphen inside hypheneted word
}
word = trim(line);
printf("%s ", word);
// Next find synonyms delimited by a coma
char delim[] = ", ";
token = strtok(p + 1, delim);
while (token != NULL) {
printf("%s ", token);
token = strtok(NULL, delim);
}
printf("\n");
return 1;
}
int LoadFile(FILE* fp)
{
if (fp == NULL) {
printf("File not open\n");
return 0;
}
int ret = 1;
char str[1024]; // Longest allowed line
while (fgets(str, sizeof(str), fp) != NULL) {
str[strcspn(str, "\r\n")] = 0; // Remove ending \n
ret &= parse(str);
}
return ret;
}
int main(int argc, char *argv[])
{
FILE* fp;
char* fn = "Synonyms.txt";
fp = fopen(fn, "rt");
if (fp == NULL) {
perror(fn);
return 1;
}
int ret = LoadFile(fp);
fclose(fp);
return ret;
}

I think the biggest conceptual misunderstanding demonstrated in the code is a failure to understand how fgets and fscanf work.
Consider the following lines of code:
while(fgets(synonyms,50,fp)!=NULL){
...
while(fscanf(fp,"%49s",word)==1){
for(i=1;i<strlen(synonyms);i++){
fscanf(fp,"%49s",synonyms);
printf("%s",synonyms);
}
}
}
The fgets reads one line of the input. (Unless there is an input line that is greater than 49 characters long (48 + a newline), in which case fgets will only read the first 49 characters. The code should check for that condition and handle it.) The next fscanf then reads a word from the next line of input. The first line is effectively being discarded! If the input is formatted as expected, the 2nd scanf will read a single - into synonyms. This makes strlen(synonyms) evaluate to 1, so the for loop terminates. The while scanf loop then reads another word, and since synonyms still contains a string of length 1, the for loop is never entered. while scanf then proceeds to read the rest of the file. The next call to fgets returns NULL (since the fscanf loop has read to the end of the file) so the while/fgets loop terminates after 1 iteration.
I believe the intention was for the scanfs inside the while/fgets to operate on the line read by fgets. To do that, all the fscanf calls should be replaced by sscanf.

Related

C - Program not detecting blank spaces

I want my program to read a file containing words separated by blank spaces and then prints words one by one. This is what I did:
char *phrase = (char *)malloc(LONGMAX * sizeof(char));
char *mot = (char *)malloc(TAILLE * sizeof(char));
FILE *fp = NULL;
fp = fopen("mots.txt", "r");
if (fp == NULL) {
printf("err ");
} else {
fgets(phrase, LONGMAX, fp);
while (phrase[i] != '\0') {
if (phrase[i] != " ") {
mot[m] = phrase[i];
i++;
m++;
} else {
printf("%s\n", phrase[i]);
mot = "";
}
}
}
but it isn't printing anything! Am I doing something wrong? Thanks!
The i in the following:
while (phrase[i]!='\0'){
Should be initialized to 0 before being used, then incremented as you iterate through the string.
You have not shown where/how it is created.
Also in this line,
if(phrase[i]!=" "){
the code is comparing a char: (phrase[i]) with a string: ( " " )
// char string
if(phrase[i] != " " ){
change it to:
// char char
if(phrase[i] != ' '){
//or better yet, include all whitespace:
if(isspace(phrase[i]) {
There is no error checking in the following, but it is basically your code with modifications. Read comments for explanation on edits to fgets() usage, casting return of malloc(), how and when to terminate the output buffer mot, etc.:
This performs the following: read a file containing words separated by blank spaces and then prints words one by one.
int main(void)
{
int i = 0;
int m = 0;
char* phrase=malloc(LONGMAX);//sizeof(char) always == 0
if(phrase)//test to make sure memory created
{
char* mot=malloc(TAILLE);//no need to cast the return of malloc in C
if(mot)//test to make sure memory created
{
FILE* fp=NULL;
fp=fopen("_in.txt","r");
if(fp)//test to make sure fopen worked
{//shortcut of what you had :) (left off the print err)
i = 0;
m = 0;
while (fgets(phrase,LONGMAX,fp))//fgets return NULL when no more to read.
{
while(phrase[i] != NULL)//test for end of last line read
{
// if(phrase[i] == ' ')//see a space, terminate word and write to stdout
if(isspace(phrase[i])//see ANY white space, terminate and write to stdout
{
mot[m]=0;//null terminate
if(strlen(mot) > 0) printf("%s\n",mot);
i++;//move to next char in phrase.
m=0;//reset to capture next word
}
else
{
mot[m] = phrase[i];//copy next char into mot
m++;//increment both buffers
i++;// "
}
}
mot[m]=0;//null terminate after while loop
}
//per comment about last word. Print it out here.
mot[m]=0;
printf("%s\n",mot);
fclose(fp);
}
free(mot);
}
free(phrase);
}
return 0;
}
phrase[i]!=" "
You compare character (phrase[i]) and string (" "). If you want to compare phrase[i] with space character, use ' ' instead.
If you want to compare string, use strcmp.
printf("%s\n",phrase[i]);
Here, you use %s for printing the string, but phrase[i] is a character.
Do not use mot=""; to copy string in c. You should use strcpy:
strcpy(mot, " ");
If you want to print word by word from one line of string. You can use strtok to split string by space character.
fgets(phrase,LONGMAX,fp);
char * token = strtok(phrase, " ");
while(token != NULL) {
printf("%s \n", token);
token = strtok(NULL, " ");
}
OT, your program will get only one line in the file because you call only one time fgets. If your file content of many line, you should use a loop for fgets function.
while(fgets(phrase,LONGMAX,fp)) {
// do something with pharse string.
// strtok for example.
char * token = strtok(phrase, " ");
while(token != NULL) {
printf("%s \n", token);
token = strtok(NULL, " ");
}
}
Your program has multiple problems:
the test for end of file is incorrect: you should just compare the return value of fgets() with NULL.
the test for spaces is incorrect: phrase[i] != " " is a type mismatch as you are comparing a character with a pointer. You should use isspace() from <ctype.h>
Here is a much simpler alternative that reads one byte at a time, without a line buffer nor a word buffer:
#include <ctype.h>
#include <stdio.h>
int main() {
int inword = 0;
int c;
while ((c = getchar()) != EOF) {
if (isspace(c)) {
if (inword) {
putchar('\n');
inword = 0;
}
} else {
putchar(c);
inword = 1;
}
}
if (inword) {
putchar('\n');
}
return 0;
}

C Reading a file of digits separated by commas

I am trying to read in a file that contains digits operated by commas and store them in an array without the commas present.
For example: processes.txt contains
0,1,3
1,0,5
2,9,8
3,10,6
And an array called numbers should look like:
0 1 3 1 0 5 2 9 8 3 10 6
The code I had so far is:
FILE *fp1;
char c; //declaration of characters
fp1=fopen(argv[1],"r"); //opening the file
int list[300];
c=fgetc(fp1); //taking character from fp1 pointer or file
int i=0,number,num=0;
while(c!=EOF){ //iterate until end of file
if (isdigit(c)){ //if it is digit
sscanf(&c,"%d",&number); //changing character to number (c)
num=(num*10)+number;
}
else if (c==',' || c=='\n') { //if it is new line or ,then it will store the number in list
list[i]=num;
num=0;
i++;
}
c=fgetc(fp1);
}
But this is having problems if it is a double digit. Does anyone have a better solution? Thank you!
For the data shown with no space before the commas, you could simply use:
while (fscanf(fp1, "%d,", &num) == 1 && i < 300)
list[i++] = num;
This will read the comma after the number if there is one, silently ignoring when there isn't one. If there might be white space before the commas in the data, add a blank before the comma in the format string. The test on i prevents you writing outside the bounds of the list array. The ++ operator comes into its own here.
First, fgetc returns an int, so c needs to be an int.
Other than that, I would use a slightly different approach. I admit that it is slightly overcomplicated. However, this approach may be usable if you have several different types of fields that requires different actions, like a parser. For your specific problem, I recommend Johathan Leffler's answer.
int c=fgetc(f);
while(c!=EOF && i<300) {
if(isdigit(c)) {
fseek(f, -1, SEEK_CUR);
if(fscanf(f, "%d", &list[i++]) != 1) {
// Handle error
}
}
c=fgetc(f);
}
Here I don't care about commas and newlines. I take ANYTHING other than a digit as a separator. What I do is basically this:
read next byte
if byte is digit:
back one byte in the file
read number, irregardless of length
else continue
The added condition i<300 is for security reasons. If you really want to check that nothing else than commas and newlines (I did not get the impression that you found that important) you could easily just add an else if (c == ... to handle the error.
Note that you should always check the return value for functions like sscanf, fscanf, scanf etc. Actually, you should also do that for fseek. In this situation it's not as important since this code is very unlikely to fail for that reason, so I left it out for readability. But in production code you SHOULD check it.
My solution is to read the whole line first and then parse it with strtok_r with comma as a delimiter. If you want portable code you should use strtok instead.
A naive implementation of readline would be something like this:
static char *readline(FILE *file)
{
char *line = malloc(sizeof(char));
int index = 0;
int c = fgetc(file);
if (c == EOF) {
free(line);
return NULL;
}
while (c != EOF && c != '\n') {
line[index++] = c;
char *l = realloc(line, (index + 1) * sizeof(char));
if (l == NULL) {
free(line);
return NULL;
}
line = l;
c = fgetc(file);
}
line[index] = '\0';
return line;
}
Then you just need to parse the whole line with strtok_r, so you would end with something like this:
int main(int argc, char **argv)
{
FILE *file = fopen(argv[1], "re");
int list[300];
if (file == NULL) {
return 1;
}
char *line;
int numc = 0;
while((line = readline(file)) != NULL) {
char *saveptr;
// Get the first token
char *tok = strtok_r(line, ",", &saveptr);
// Now start parsing the whole line
while (tok != NULL) {
// Convert the token to a long if possible
long num = strtol(tok, NULL, 0);
if (errno != 0) {
// Handle no value conversion
// ...
// ...
}
list[numc++] = (int) num;
// Get next token
tok = strtok_r(NULL, ",", &saveptr);
}
free(line);
}
fclose(file);
return 0;
}
And for printing the whole list just use a for loop:
for (int i = 0; i < numc; i++) {
printf("%d ", list[i]);
}
printf("\n");

Jumping to next line with fscanf()

I have two files .csv and I need to read the whole file but it have to be filed by field. I mean, csv files are files with data separated by comma, so I cant use fgets.
I need to read all the data but I don't know how to jump to the next line.
Here is what I've done so far:
int main()
{
FILE *arq_file;
arq_file = fopen("file.csv", "r");
if(arq_file == NULL){
printf("Not possible to read the file.");
exit(0);
}
while( !feof(arq_file) ){
fscanf(arq_file, "%i %lf", &myStruct[i+1].Field1, &myStruct[i+1].Field2);
}
fclose(arq_file);
return 0;
}
It will get in a infinity loop because it never gets the next line.
How could I reach the line below the one I just read?
Update: File 01 Example
1,Alan,123,
2,Alan Harper,321
3,Jose Rendeks,32132
4,Maria da graça,822282
5,Charlie Harper,9999999999
File 02 Example
1,320,123
2,444,321
3,250,123,321
3,3,250,373,451
2,126,621
1,120,320
2,453,1230
3,12345,0432,1830
I think an example is better than giving you hints, this is a combination of fgets() + strtok(), there are other functions that could work for example strchr(), though it's easier this way and since I just wanted to point you in the right direction, well I did it like this
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int
main(void)
{
FILE *file;
char buffer[256];
char *pointer;
size_t line;
file = fopen("data.dat", "r");
if (file == NULL)
{
perror("fopen()");
return -1;
}
line = 0;
while ((pointer = fgets(buffer, sizeof(buffer), file)) != NULL)
{
size_t field;
char *token;
field = 0;
while ((token = strtok(pointer, ",")) != NULL)
{
printf("line %zu, field %zu -> %s\n", line, field, token);
field += 1;
pointer = NULL;
}
line += 1;
}
return 0;
}
I think it's very clear how the code works and I hope you can understand.
If the same code has to handle both data files, then you're stuck with reading the fields into a string, and subsequently converting the string into a number.
It is not clear from your description whether you need to do something special at the end of line or not — but because only one of the data lines ends with a comma, you do have to allow for fields to be separated by a comma or a newline.
Frankly, you'd probably do OK with using getchar() or equivalent; it is simple.
char buffer[4096];
char *bufend = buffer + sizeof(buffer) - 1;
char *curfld = buffer;
int c;
while ((c = getc(arq_file)) != EOF)
{
if (curfld == bufend)
…process overlong field…
else if (c == ',' || c == '\n')
{
*curfld = '\0';
process(buffer);
curfld = buffer;
}
else
*curfld++ = c;
}
if (c == EOF && curfld != buffer)
{
*curfld = '\0';
process(buffer);
}
However, if you want to go with higher level functions, then you do want to use fgets() to read lines (unless you need to worry about deviant line endings, such as DOS vs Unix vs old-style Mac (CR-only) line endings). Or use POSIX
getline() to read arbitrarily long lines. Then split the lines using strtok_r() or equivalent.
char *buffer = 0;
size_t buflen = 0;
while (getline(&buffer, &buflen, arq_file) != -1)
{
char *posn = buffer;
char *epos;
char *token;
while ((token = strtok_r(posn, ",\n", &epos)) != 0)
{
process(token);
posn = 0;
}
/* Do anything special for end of line */
}
free(buffer);
If you think you must use scanf(), then you need to use something like:
char buffer[4096];
char c;
while (fscanf(arq_file, "%4095[^,\n]%c", buffer, &c) == 2)
process(buffer);
The %4095[^,\n] scan set reads up to 4095 characters that are neither comma nor newline into buffer, and then reads the next character (which must, therefore, either be comma or newline — or conceivably EOF, but that causes problems) into c. If the last character in the file is neither comma nor newline, then you will skip the last field.

Reading a file in C

I have an input file I need to extract words from. The words can only contain letters and numbers so anything else will be treated as a delimiter. I tried fscanf,fgets+sscanf and strtok but nothing seems to work.
while(!feof(file))
{
fscanf(file,"%s",string);
printf("%s\n",string);
}
Above one clearly doesn't work because it doesn't use any delimiters so I replaced the line with this:
fscanf(file,"%[A-z]",string);
It reads the first word fine but the file pointer keeps rewinding so it reads the first word over and over.
So I used fgets to read the first line and use sscanf:
sscanf(line,"%[A-z]%n,word,len);
line+=len;
This one doesn't work either because whatever I try I can't move the pointer to the right place. I tried strtok but I can't find how to set delimitters
while(p != NULL) {
printf("%s\n", p);
p = strtok(NULL, " ");
This one obviously take blank character as a delimitter but I have literally 100s of delimitters.
Am I missing something here becasue extracting words from a file seemed a simple concept at first but nothing I try really works?
Consider building a minimal lexer. When in state word it would remain in it as long as it sees letters and numbers. It would switch to state delimiter when encountering something else. Then it could do an exact opposite in the state delimiter.
Here's an example of a simple state machine which might be helpful. For the sake of brevity it works only with digits. echo "2341,452(42 555" | ./main will print each number in a separate line. It's not a lexer but the idea of switching between states is quite similar.
#include <stdio.h>
#include <string.h>
int main() {
static const int WORD = 1, DELIM = 2, BUFLEN = 1024;
int state = WORD, ptr = 0;
char buffer[BUFLEN], *digits = "1234567890";
while ((c = getchar()) != EOF) {
if (strchr(digits, c)) {
if (WORD == state) {
buffer[ptr++] = c;
} else {
buffer[0] = c;
ptr = 1;
}
state = WORD;
} else {
if (WORD == state) {
buffer[ptr] = '\0';
printf("%s\n", buffer);
}
state = DELIM;
}
}
return 0;
}
If the number of states increases you can consider replacing if statements checking the current state with switch blocks. The performance can be increased by replacing getchar with reading a whole block of the input to a temporary buffer and iterating through it.
In case of having to deal with a more complex input file format you can use lexical analysers generators such as flex. They can do the job of defining state transitions and other parts of lexer generation for you.
Several points:
First of all, do not use feof(file) as your loop condition; feof won't return true until after you attempt to read past the end of the file, so your loop will execute once too often.
Second, you mentioned this:
fscanf(file,"%[A-z]",string);
It reads the first word fine but the file pointer keeps rewinding so it reads the first word over and over.
That's not quite what's happening; if the next character in the stream doesn't match the format specifier, scanf returns without having read anything, and string is unmodified.
Here's a simple, if inelegant, method: it reads one character at a time from the input file, checks to see if it's either an alpha or a digit, and if it is, adds it to a string.
#include <stdio.h>
#include <ctype.h>
int get_next_word(FILE *file, char *word, size_t wordSize)
{
size_t i = 0;
int c;
/**
* Skip over any non-alphanumeric characters
*/
while ((c = fgetc(file)) != EOF && !isalnum(c))
; // empty loop
if (c != EOF)
word[i++] = c;
/**
* Read up to the next non-alphanumeric character and
* store it to word
*/
while ((c = fgetc(file)) != EOF && i < (wordSize - 1) && isalnum(c))
{
word[i++] = c;
}
word[i] = 0;
return c != EOF;
}
int main(void)
{
char word[SIZE]; // where SIZE is large enough to handle expected inputs
FILE *file;
...
while (get_next_word(file, word, sizeof word))
// do something with word
...
}
I would use:
FILE *file;
char string[200];
while(fscanf(file, "%*[^A-Za-z]"), fscanf(file, "%199[a-zA-Z]", string) > 0) {
/* do something with string... */
}
This skips over non-letters and then reads a string of up to 199 letters. The only oddness is that if you have any 'words' that are longer than 199 letters they'll be split up into multiple words, but you need the limit to avoid a buffer overflow...
What are your delimiters? The second argument to strtok should be a string containing your delimiters, and the first should be a pointer to your string the first time round then NULL afterwards:
char * p = strtok(line, ","); // assuming a , delimiter
printf("%s\n", p);
while(p)
{
p = strtok(NULL, ",");
printf("%S\n", p);
}

Parsing text in C

I have a file like this:
...
words 13
more words 21
even more words 4
...
(General format is a string of non-digits, then a space, then any number of digits and a newline)
and I'd like to parse every line, putting the words into one field of the structure, and the number into the other. Right now I am using an ugly hack of reading the line while the chars are not numbers, then reading the rest. I believe there's a clearer way.
Edit: You can use pNum-buf to get the length of the alphabetical part of the string, and use strncpy() to copy that into another buffer. Be sure to add a '\0' to the end of the destination buffer. I would insert this code before the pNum++.
int len = pNum-buf;
strncpy(newBuf, buf, len-1);
newBuf[len] = '\0';
You could read the entire line into a buffer and then use:
char *pNum;
if (pNum = strrchr(buf, ' ')) {
pNum++;
}
to get a pointer to the number field.
fscanf(file, "%s %d", word, &value);
This gets the values directly into a string and an integer, and copes with variations in whitespace and numerical formats, etc.
Edit
Ooops, I forgot that you had spaces between the words.
In that case, I'd do the following. (Note that it truncates the original text in 'line')
// Scan to find the last space in the line
char *p = line;
char *lastSpace = null;
while(*p != '\0')
{
if (*p == ' ')
lastSpace = p;
p++;
}
if (lastSpace == null)
return("parse error");
// Replace the last space in the line with a NUL
*lastSpace = '\0';
// Advance past the NUL to the first character of the number field
lastSpace++;
char *word = text;
int number = atoi(lastSpace);
You can solve this using stdlib functions, but the above is likely to be more efficient as you're only searching for the characters you are interested in.
Given the description, I think I'd use a variant of this (now tested) C99 code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
struct word_number
{
char word[128];
long number;
};
int read_word_number(FILE *fp, struct word_number *wnp)
{
char buffer[140];
if (fgets(buffer, sizeof(buffer), fp) == 0)
return EOF;
size_t len = strlen(buffer);
if (buffer[len-1] != '\n') // Error if line too long to fit
return EOF;
buffer[--len] = '\0';
char *num = &buffer[len-1];
while (num > buffer && !isspace((unsigned char)*num))
num--;
if (num == buffer) // No space in input data
return EOF;
char *end;
wnp->number = strtol(num+1, &end, 0);
if (*end != '\0') // Invalid number as last word on line
return EOF;
*num = '\0';
if (num - buffer >= sizeof(wnp->word)) // Non-number part too long
return EOF;
memcpy(wnp->word, buffer, num - buffer);
return(0);
}
int main(void)
{
struct word_number wn;
while (read_word_number(stdin, &wn) != EOF)
printf("Word <<%s>> Number %ld\n", wn.word, wn.number);
return(0);
}
You could improve the error reporting by returning different values for different problems.
You could make it work with dynamically allocated memory for the word portion of the lines.
You could make it work with longer lines than I allow.
You could scan backwards over digits instead of non-spaces - but this allows the user to write "abc 0x123" and the hex value is handled correctly.
You might prefer to ensure there are no digits in the word part; this code does not care.
You could try using strtok() to tokenize each line, and then check whether each token is a number or a word (a fairly trivial check once you have the token string - just look at the first character of the token).
Assuming that the number is immediately followed by '\n'.
you can read each line to chars buffer, use sscanf("%d") on the entire line to get the number, and then calculate the number of chars that this number takes at the end of the text string.
Depending on how complex your strings become you may want to use the PCRE library. At least that way you can compile a perl'ish regular expression to split your lines. It may be overkill though.
Given the description, here's what I'd do: read each line as a single string using fgets() (making sure the target buffer is large enough), then split the line using strtok(). To determine if each token is a word or a number, I'd use strtol() to attempt the conversion and check the error condition. Example:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
/**
* Read the next line from the file, splitting the tokens into
* multiple strings and a single integer. Assumes input lines
* never exceed MAX_LINE_LENGTH and each individual string never
* exceeds MAX_STR_SIZE. Otherwise things get a little more
* interesting. Also assumes that the integer is the last
* thing on each line.
*/
int getNextLine(FILE *in, char (*strs)[MAX_STR_SIZE], int *numStrings, int *value)
{
char buffer[MAX_LINE_LENGTH];
int rval = 1;
if (fgets(buffer, buffer, sizeof buffer))
{
char *token = strtok(buffer, " ");
*numStrings = 0;
while (token)
{
char *chk;
*value = (int) strtol(token, &chk, 10);
if (*chk != 0 && *chk != '\n')
{
strcpy(strs[(*numStrings)++], token);
}
token = strtok(NULL, " ");
}
}
else
{
/**
* fgets() hit either EOF or error; either way return 0
*/
rval = 0;
}
return rval;
}
/**
* sample main
*/
int main(void)
{
FILE *input;
char strings[MAX_NUM_STRINGS][MAX_STRING_LENGTH];
int numStrings;
int value;
input = fopen("datafile.txt", "r");
if (input)
{
while (getNextLine(input, &strings, &numStrings, &value))
{
/**
* Do something with strings and value here
*/
}
fclose(input);
}
return 0;
}

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