Printing array of strings produces bad output - c

Question

I'm trying to solve a challenge, but I have no idea of what's wrong with my code!
The challenge is:
Create a function that splits a string of characters into words.
Separators are spaces, tabs and line breaks.
This function returns an array where each box contains a character-string’s address represented by a word. The last element of this array should be equal to 0 to emphasise the end of the array.
There can’t be any empty strings in your array. Draw the necessary conclusions.
The given string can’t be modified.
Note: The only allowed function is malloc()
The bug/problem:
I faced this problem and I tried to solve it but I wasn't able to identify what's wrong.
I created a function named split_whitespaces() to do the job.
When I print the array of strings inside of the split_whitespaces function, I get the following output:
Inside the function:
arr_str[0] = This
arr_str[1] = is
arr_str[2] = just
arr_str[3] = a
arr_str[4] = test!
And when I print the array of string inside the main function, I get the following output:
Inside the main function:
arr_str[0] = #X#?~
arr_str[1] = `X#?~
arr_str[2] = just
arr_str[3] = a
arr_str[4] = test!
I created a function word_count to count how many words in the input string so I can allocate memory using malloc and with word_count + 1 (null pointer).
int word_count(char *str) {
int i;
int w_count;
int state;
i = 0;
w_count = 0;
state = 0;
while (str[i]) {
if (!iswhitespace(str[i])) {
if (!state)
w_count++;
state = 1;
i++;
} else {
state = 0;
i++;
}
}
return (w_count);
}
And another function called strdup_w to mimic the behavior of strdup but just for single words:
char *strdup_w(char *str, int *index) {
char *word;
int len;
int i;
i = *index;
len = 0;
while (str[i] && !iswhitespace(str[i]))
len++, i++;;
word = (char *) malloc(len + 1);
if (!word)
return (NULL);
i = 0;
while (str[*index]) {
if (!iswhitespace(str[*index])) {
word[i++] = str[*index];
(*index)++;
} else
break;
}
word[len] = '\0';
return (word);
}
Here's my full code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char **split_whitespaces(char *str);
char *strdup_w(char *str, int *index);
int word_count(char *str);
int iswhitespace(char c);
int main(void) {
char *str = "This is just a test!";
char **arr_str;
int i;
i = 0;
arr_str = split_whitespaces(str);
printf("\nOutside the function:\n");
while (arr_str[i]) {
printf("arr_str[%d] = %s\n", i, arr_str[i]);
i++;
}
return (0);
}
char **split_whitespaces(char *str) {
char **arr_str;
int i;
int words;
int w_i;
i = 0;
w_i = 0;
words = word_count(str);
arr_str = (char **)malloc(words + 1);
if (!arr_str)
return (NULL);
printf("Inside the function:\n");
while (w_i < words) {
while (iswhitespace(str[i]) && str[i])
if (!str[i++])
break;
arr_str[w_i] = strdup_w(str, &i);
printf("arr_str[%d] = %s\n", w_i, arr_str[w_i]);
w_i++;
}
arr_str[words] = 0;
return (arr_str);
}
char *strdup_w(char *str, int *index) {
char *word;
int len;
int i;
i = *index;
len = 0;
while (str[i] && !iswhitespace(str[i]))
len++, i++;;
word = (char *)malloc(len + 1);
if (!word)
return (NULL);
i = 0;
while (str[*index]) {
if (!iswhitespace(str[*index])) {
word[i++] = str[*index];
(*index)++;
} else
break;
}
word[len] = '\0';
return (word);
}
int word_count(char *str) {
int i;
int w_count;
int state;
i = 0;
w_count = 0;
state = 0;
while (str[i]) {
if (!iswhitespace(str[i])) {
if (!state)
w_count++;
state = 1;
i++;
} else {
state = 0;
i++;
}
}
return (w_count);
}
int iswhitespace(char c) {
if (c == ' ' || c == '\t' || c == '\n' || c == '\r')
return (1);
return (0);
}
I'm sorry, if anything this is my first time trying to seek help.

Answer 1

There are multiple problems in the code:
the size is incorrect in arr_str = (char **)malloc(words + 1); You must multiply the number of elements by the size of the element:
arr_str = malloc(sizeof(*arr_str) * (words + 1));
it is good style to free the array in the main() function after use.
the test while (iswhitespace(str[i]) && str[i]) is redundant: if w_count is computed correctly, testing str[i] should not be necessary. You should use strspn() to skip the white space and strcspn() to skip the word characters.
if (!str[i++]) break; is completely redundant inside the loop: str[i] has already been tested and is not null.
while (str[i] && !iswhitespace(str[i])) len++, i++;; is bad style. Use braces if there is more than a single simple statement in the loop body.
the last loop in strdup_w is complicated, you could simply use memcpy(word, str + *index, len); *index += len;
Here is a modified version:
#include <stdio.h>
#include <stdlib.h>
char **split_whitespaces(const char *str);
char *strdup_w(const char *str, int *index);
int word_count(const char *str);
int iswhitespace(char c);
int main(void) {
const char *str = "This is just a test!";
char **arr_str;
int i;
arr_str = split_whitespaces(str);
if (arr_str) {
printf("\nOutside the function:\n");
i = 0;
while (arr_str[i]) {
printf("arr_str[%d] = %s\n", i, arr_str[i]);
i++;
}
while (i --> 0) {
free(arr_str[i]);
}
free(arr_str);
}
return 0;
}
char **split_whitespaces(const char *str) {
char **arr_str;
int i;
int words;
int w_i;
i = 0;
w_i = 0;
words = word_count(str);
arr_str = malloc(sizeof(*arr_str) * (words + 1));
if (!arr_str)
return NULL;
printf("Inside the function:\n");
while (w_i < words) {
while (iswhitespace(str[i]))
i++;
arr_str[w_i] = strdup_w(str, &i);
if (!arr_str[w_i])
break;
printf("arr_str[%d] = %s\n", w_i, arr_str[w_i]);
w_i++;
}
arr_str[words] = NULL;
return arr_str;
}
char *strdup_w(const char *str, int *index) {
char *word;
int len;
int start;
int i;
i = *index;
start = i;
while (str[i] && !iswhitespace(str[i])) {
i++;
}
*index = i;
len = i - start;
word = malloc(len + 1);
if (!word)
return NULL;
i = 0;
while (i < len) {
word[i] = str[start + i];
i++;
}
word[i] = '\0';
return word;
}
int word_count(const char *str) {
int i;
int w_count;
int state;
i = 0;
w_count = 0;
state = 0;
while (str[i]) {
if (!iswhitespace(str[i])) {
if (!state)
w_count++;
state = 1;
} else {
state = 0;
}
i++;
}
return w_count;
}
int iswhitespace(char c) {
return (c == ' ' || c == '\t' || c == '\n' || c == '\r');
}

Answer 2

From my top comment ...
In split_whitespaces, try changing:
arr_str = (char **) malloc(words + 1);
into:
arr_str = malloc(sizeof(*arr_str) * (words + 1));
As you have it, words is a count and not a byte length, so you're not allocating enough space, so you have UB.
UPDATE:
But watched some tutorials and they said that malloc takes one argument which is the size of the memory to be allocated (in bytes), that's why I allocated memory for 5 bytes! can you please tell my an alternative of using malloc without sizeof() function. I'll appreciate it. – Achraf EL Khnissi
There's really no clean way to specify this without sizeof.
sizeof is not a function [despite the syntax]. It is a compiler directive. It "returns" the number of bytes occupied by its argument as a compile time constant.
If we have char buf[5];, there are 5 bytes, so sizeof(buf) [or sizeof buf] is 5.
If we have: int buf[5];, there are 5 elements, each of size int which is [typically] 4 bytes, so the total space, in bytes, is sizeof(int) * 5 or 4 * 5 which is 20.
But, int can vary depending on the architecture. On Intel 8086's [circa the 1980's], an int was 2 bytes (i.e. 16 bits). So, the above 4 * 5 would be wrong. It should be 2 * 5.
If we use sizeof(int), then sizeof(int) * 5 works regardless of the architecture.
Similarly, on 32 bit machines, a pointer is [usually] 32 bits. So, sizeof(char *) is 4 [bytes]. On a 64 bit machine, a pointer is 64 bits, which is 8 bytes. So, sizeof(char *) is 8.
Because arr_str is: char **arr_str, we could have done:
arr_str = malloc(sizeof(char *) * (words + 1));
But, if the definition of arr_str ever changed (to (e.g.) struct string *arr_str;), then what we just did would break/fail if we forgot to change the assignment to:
arr_str = malloc(sizeof(struct string) * (words + 1));
So, doing:
arr_str = malloc(sizeof(*arr_str) * (words + 1));
is a preferred idiomatic way to write cleaner code. More statements will adjust automatically without having to find all affected lines of code manually.
UPDATE #2:
You might just add why you removed the (char **) cast :) -- chqrlie
Note that I removed the (char **) cast. See: Do I cast the result of malloc?
This just adds extra/unnecessary "stuff" as the void * return value of malloc can be assigned to any type of pointer.
If we forgot to do: #include <stdlib.h>, there would be no function prototype for malloc, so the compiler would default the return type to int.
Without the cast, the compiler would issue an an error on the statement [which is what we want].
With the cast, this action is masked at compile time [more or less]. On a 64 bit machine, the compiler will use a value that is truncated to 32 bits [because it thinks malloc returns a 32 bit value] instead of the full 64 bit return value of malloc.
This truncation is a "silent killer". What should have been flagged as a compile time error produces a runtime fault (probably segfault or other UB) that is much harder to debug.