Split string and output into rows - snowflake-cloud-data-platform

Question

I want to split a string based on delimiter ',' and put the results into rows. Hence, I'm trying to use SPLIT_TO_TABLE function in Snowflake, but not working successfully.
I used the regexp_replace to clean the string. How can I output this into rows for each id?
SELECT value,
TRIM(regexp_replace(value, '[{}_]', ' ')) AS extracted
Here is the sample data:
+--------+------------------------------------+
| id | value |
+--------+------------------------------------+
| fsaf12 | {Other Questions,Missing Document} |
| sfas11 | {Other} |
+--------+------------------------------------+
Expected result:
+--------+------------------+
| id | extracted |
+--------+------------------+
| fsaf12 | Other Questions |
| fsaf12 | Missing Document |
| sfas11 | Others |
+--------+------------------+

Answer 1

Adding another way to split the data and output it as rows :
SELECT b,TRIM(regexp_replace(splitvalue, '[{}_]', '')) AS extracted from
(SELECT b, C.value::string AS splitvalue
FROM split,
LATERAL FLATTEN(input=>split(a, ',')) C);
where a and b are the columns in table "split" and data is as follows :
A
B
{First,Second}
row1
{Third,Fourth}
row2

Answer 2

HEre is answer , used replace function instead of regexp_replace
WITH DATATABLE(ID ,VALUEA ) AS
(
SELECT * FROM VALUES ('fsaf12','{Other Questions,Missing Document}'),('sfas11',' {Other} ')
)
SELECT ID, REPLACE(REPLACE(VALUE,'{',''),'}','') SPLITTED_VALUE FROM DATATABLE , LATERAL SPLIT_TO_TABLE (VALUEA,',') ;