Semicolons at beginning of the line, delims and FOR cycle - batch-file

I cannot figure out how to correctly identify an empty/undefined variable having two semicolon one after one other or the line that starts with it.
This is the cycle:
for /F "delims=; tokens=1-7" %%m IN (testlist.txt) DO echo FUNCGROUP=%%r a=%%m b=%%n c=%%o d=%%p e=%%q f=%%s
I also tried adding "eol=;" and "......eol=" without success.
This is content of the first line of the file testlist.txt:
;xxxxxx;Active;;FALSE;con ter - dong;HWID000001;Item;sites/coll-
The result I need is, for the first cycle:
a=
b=xxxxxx
c=Active
d=
e=FALSE
f=con ter - dong
g=HWID000001
Thanks for any help.

To achieve that, you need to put a "NULL value" for empty fields in the lines of the file.
As there is no direct string substitution utilities with batch, you have to make substitutions beforehand to create "empty" fields. I suggest you to use a "NULL" character for empty fields like unbreakable space (Alt+0160).
In your case, this gives :
#echo off
SETLOCAL ENABLEDELAYEDEXPANSION
for /F "eol= tokens=*" %%l in (file.txt) DO (
SET "LINE=%%l"
SET "LINE=###!LINE:;;=; ;!###"
SET "LINE=!LINE:###;= ;!"
SET "LINE=!LINE:;###=; !"
SET "LINE=!LINE:###=!"
for /F "delims=; tokens=1-7" %%m in ("!LINE!") DO (
SET "RES=FUNCGROUP=%%r a=%%m b=%%n c=%%o d=%%p e=%%q f=%%s"
echo !RES: =!
)
)
Note that the SET "LINE=###!LINE:;;=; ;!###", SET "LINE=!LINE:###;= ;!" and the SET "LINE=!LINE:;###=; !" sections use the unbreakable space (Alt+0160) and replace beginning ";" with "Alt+0160;", the ending ";" with ";Alt+0160" and any following ";;" with ";Alt+0160;". The for loop parses then correctly the line, and next you just have to remove the unbreakable space to get "empty" variables.
EDIT: As brightly suggested by #jeb in the comments, you can also use quotes to handle empty fields. Each for loop variables can be then directly and simply unquoted.
#echo off
SETLOCAL ENABLEDELAYEDEXPANSION
for /F "eol= tokens=*" %%l in (file.txt) DO (
SET "LINE=%%l"
SET "LINE=###^"!LINE:;=^";^"!^"###"
SET "LINE=!LINE:###^";=^"^";!"
SET "LINE=!LINE:;^"###=;^"^"!"
SET "LINE=!LINE:###=!"
for /F "delims=; tokens=1-7" %%m in ("!LINE!") DO (
echo FUNCGROUP=%%~r a=%%~m b=%%~n c=%%~o d=%%~p e=%%~q f=%%~s
)
)

Unfortunately, you have not provided sufficient information for what you intend to do with your empty field, so this is only a demonstration to provide you with output similar to that which you've indicated in your question:
#Echo Off
SetLocal EnableExtensions DisableDelayedExpansion
For /F "Delims==" %%G In ("(Set Field[) 2>NUL") Do Set "%%G="
Set "i=0"
For /F UseBackQ^ Delims^=^ EOL^= %%G In ("testlist.txt") Do Call :GetFields "%%G"
Pause
GoTo :EOF
:GetFields
Set "Record=%~1"
Set /A i += 1
SetLocal EnableDelayedExpansion
Set "Index=1"
Set "Field[!Index!]=%Record:;=" & Set /A Index +=1 & Set "Field[!Index!]=%"
Echo(&Echo Record !i!
For /L %%G In (1,1,!Index!) Do If Not Defined Field[%%G] (Echo Field[%%G]=) Else Set Field[%%G]
Exit /B

Related

Limit amount of lines concatenated from list BATCH

I am trying to make a batch file that will concatenate a list but I want it to make a new line after 13 items. Below is the code that I am using to pull the data into one line but I am having issues limiting it. I have tried putting a counter on it but I am not implementing it correctly. Any help would be appreciated.
#echo off
setlocal enableextensions enabledelayedexpansion
set "var="
for /f "usebackq delims=" %%a in (%~1) do set "var=!var!%%a "
echo(%var%
)
Your supplied code did not really attempt the task, and you did not make clear what you meant by concatenating. What the following example does therefore, is write a new file, defined on line 4 with the content from your input file argument, %1, but with the content of each block of thirteen lines of input per line of output. I have separated each original line with a single whitespace character, based upon %%a in your own code.
#Echo Off
SetLocal EnableExtensions DisableDelayedExpansion
Set "InputFile=%~1"
Set "OutputFile=concatenated.txt"
If Not Exist "%InputFile%" Exit /B
For /F %%G In ('Copy /Z "%~f0" NUL') Do Set "CR=%%G" & (Set LF=^
% 0x0A %
)
SetLocal EnableDelayedExpansion
Set "i=0"
1>"%OutputFile%" (For /F UseBackQ^ Delims^=^ EOL^= %%G In ("%InputFile%"
) Do (Set /A "i += 1, # = i %% 13"
If !#! Equ 0 (Set /P "=%%G!CR!!LF!" 0<NUL) Else Set /P "=%%G " 0<NUL))
EndLocal

windows batch escape whole string

Ok. this is a self updating batch file. I just simplified the problem from a bigger file.
this is a windows batch file(.bat) that upon execution should open itself and update first line
SET variableName=D:\Data
setlocal enableextensions enabledelayedexpansion
set /A i=0
for /f "tokens=*" %%f in ('type "%0"^&cd.^>"%0"') do (
set /A i=!i!+1
if !i! EQU 1 (
echo SET variableName=D:\Data2>>%0
) else (
echo %%f>>%0
)
)
endlocal
so let explain the situation.
i have !i! variable in lines 5 and 6. after executing this file, the variable in each line will replace by line number. it obviously because of echo %%f>>%0 that could not ignore and escape variable.
and my question is how to solve this problem?
another less problem is that the above code ignores spaces at beginning of line (indents) and generates a flat file.
the result of executing this file is:
SET variableName=D:\Data2
setlocal enableextensions enabledelayedexpansion
set /A i=0
for /f "tokens=*" %%f in ('type "%0"^&cd.^>"%0"') do (
set /A i=5+1
if 6 EQU 1 (
echo SET variableName=D:\Data2>>%0
) else (
echo %%f>>%0
)
)
endlocal
Stopping expansion of the variable when executing the file is as simple as turning delayed expansion off prior to the line that updates the file, and pairing it with an endlocal.
Retaining the space / tab formatting is achieved by including delims= in the For loop options.
Set variableName=D:\Data
Setlocal enableextensions enabledelayedexpansion
Set /A i=0
For /f "tokens=* delims=" %%f in ('type "%0"^&cd.^>"%0"') do (
Set /A i+=1
If !i! EQU 1 (
Echo SET variableName=D:\Data2>>%0
) Else (
Setlocal DisableDelayedExpansion
Echo(%%f>>%0
Endlocal
)
)
Endlocal
set "variableName=D:\Data"
setlocal enableextensions enabledelayedexpansion
rem !test! exclaimations, %test% percentages
for /f "skip=1 delims=" %%A in ('
type "%~f0" ^&
^> "%~f0" echo set "variableName=D:\Data2"
') do (
setlocal disabledelayedexpansion
>> "%~f0" echo %%A
endlocal
)
endlocal
You can avoid counting as skip=1 can be used to skip the first line. Use delims= to avoid delimiting the line. tokens=* ignores delimiters at start of the line and get the remainder of the line so that can be omitted for this task.
The new first line is now in the for loop command instead of erasing the file to empty. If you echo more lines, then increase the skip number.
Also may need to use setlocal disabledelayedexpansion so exclamation marks are retained.
Modifying the same file that is being read can a risk, though I assume you understand the risk.

Extract a specific portion from a string(filename) using batch file

I am trying to extract a portion of all the filenames(pdf files) in the current directory.
The length of filenames vary except for the last portion(datetime and extension) which will always be 16 characters. The remaining part will always have different lengths. Even the portion I require may have varying lengths.
I tried using lastIndexOf function obtained here.
filename eg : academyo-nonpo-2582365-082416051750.pdf
I want to extract the section in Bold.
I tried trimming the last 17 characters(this portion will always have a fixed length.) first and then tried to obtain the last Index Of '-'(since the fist portion can have variable character length.) and trim the characters until that position, which should return the required portion of the filename.
#echo off
Setlocal enabledelayedexpansion
For %%# in ("%~dp0\*.pdf") Do (
Set "File=%%~nx#"
Set "File=!File:~0,-17!"
Set "lio2="
#echo on
echo !File!
#echo off
call :lastindexof !File! - lio2
Set "File=!File:~%lio%!"
)
Pause&Exit
:lastindexof [%1 - string ; %2 - find last index of ; %3 - if defined will store the result in variable with same name]
#echo off
setlocal enableDelayedExpansion
set "str=%~1"
set "p=!str:%~2=&echo.!"
set "splitter=%~2"
set LF=^
rem ** Two empty lines are required
echo off
for %%L in ("!LF!") DO (
for /f "delims=" %%R in ("!splitter!") do (
set "var=!str:%%R=%%L!"
)
)
for /f delims^=^" %%P in ("!var!") DO (
set "last_part=%%~P"
)
if "!last_part!" equ "" if "%~3" NEQ "" (
echo "not contained" >2
endlocal
set %~3=-1
exit
) else (
echo "not contained" >2
endlocal
set argv=original
set $strLen=for /L %%n in (1 1 2) do if %%n==2 (%\n%
for /F "tokens=1,2 delims=, " %%1 in ("!argv!") do (%\n%
set "str=A!%%~2!"%\n%
echo -1
)
setlocal DisableDelayedExpansion
set ^"\n=^^^%LF%%LF%^%LF%%LF%^^"
set "len=0"%\n%
for /l %%A in (12,-1,0) do (%\n%
set /a "len|=1<<%%A"%\n%
for %%B in (!len!) do if "!str:~%%B,1!"=="" set /a "len&=~1<<%%A"%\n%
)%\n%
for %%v in (!len!) do endlocal^&if "%%~b" neq "" (set "%%~1=%%v") else echo %%v%\n%
) %\n%
) ELSE setlocal enableDelayedExpansion ^& set argv=,
%$strlen% strlen,str
%$strlen% plen,last_part
%$strlen% slen,splitter
set /a lio=strlen-plen-slen
endlocal & if "%~3" NEQ "" (set %~3=%lio%) else echo %lio%
exit /b
The reference of the variable passed to the function as the 3rd parameter doesn't seem to be returning the required value.
I dunno what is wrong here.
To get the section in bold then:
Example#
#Echo Off
SetLocal EnableDelayedExpansion
For %%# in ("%~dp0*.pdf") Do (
Set "File=%%~n#"
Set "File=!File:~-20,7!"
Echo=!File!%%~x#)
Pause
Okay what about?
#Echo Off
SetLocal EnableDelayedExpansion
For %%# in ("%~dp0*.pdf") Do (
Set "File=%%~n#"
Set "File=!File:~,-13!"
Call :Sub "!File:-=\!%%~x#")
Pause
:Sub
Echo=%~nx1
To extract the portion in between the last hyphen and the next-to-last one, you could use the following script (provide the strings/files as command line arguments):
#echo off
setlocal EnableExtensions EnableDelayedExpansion
set "SEP=-"
for %%A in (%*) do (
set "ITEM=%%~A"
set "PREV="
if defined ITEM (
for %%B in ("!ITEM:%SEP%=" "!") do (
set "PREV=!PART!"
set "PART=%%~B"
)
if defined PREV (
echo(!PREV!
)
)
)
endlocal
exit /B
This approach basically replaces every - by the standard cmd tokenisation character SPACE and iterates through the resulting string using a standard for loop (no /F option). The currently iterated part is stored in variable PART, whose content is first copied into PREV to gain a delay of one loop iteration. So the next-to-last portion is finally stored in PREV.
Note that this script might return unexpected results in case the strings/files contain exclamation marks because of delayed expansion.
Have a look on this answer. Thought is to first count the number of tokens (you still do have to trim the string before this) and then get the last token.
In the first loop where it says "tokens=1*" , you have to edit it to the following: "tokens=1* delims=-" and in the second loop add delims=- as well after %i%. It should be looking like this in total with your script:
#echo off
SetLocal EnableDelayedExpansion
For %%# in ("%~dp0\*.pdf") Do (
Set "File=%%~nx#"
Set "File=!File:~0,-17!"
Set "lio2="
#echo on
echo !File!
#echo off
call:subfunction !File! - lio2
Set "File=!File:~%lio%!"
)
:subfunction
set var1=%1
set var2=%var1%
set i=0
:loopprocess
for /F "tokens=1* delims=-" %%A in ( "%var1%" ) do (
set /A i+=1
set var1=%%B
goto loopprocess )
for /F "tokens=%i% delims=-" %%G in ( "%var2%" ) do set last=%%G
echo %last%
REM do what you want with last here!
I tested it and it seems to be working correctly even with something like ac-ade-myo-n-on-po-15482729242321654-082416051750.pdf, however after finishing correctly, it give an error message one time with a syntax error I could not find...
If you can ignore that error (everything else works), this might help.

how to read second to second last word from a string in a batch file

Suppose my string is "Hello;world!How;are;you;doing?". How do I read 2nd word to second last word in a loop.
I have tried the following, but ended with errors
set argC=0
FOR /f %%x IN ("Hello;world!How;are;you;doing?") DO (
SET /A argC+=1
)
set /a last2last=!argC!-1
for /f "usebackq tokens=2-!argC! delims=;" %%y in ("Hello;world!How;are;you;doing?") do (
set "somestr=!somestr! %%y "
)
echo !somestr!
I am getting the error "!last2last! delims=;" was unexpected at this time."
Note: Number of words in the string may vary
Can anyone help me?
Based on the actual data in the comments - this works.
#echo off
setlocal enabledelayedexpansion
FOR %%x IN ("&&";"XMLWrirter";"class";"free";"&&") DO (
if defined read SET a=!a! !b!& set b=%%x
set read=1
)
echo !a:~2!
pause
Try this:
#echo off
setlocal EnableDelayedExpansion
set "all="
set "this="
for %%a in ("&&";"XMLWrirter";"class";"free";"&&") do (
set "all=!all!;!this!"
if "!all!" neq ";" set "this=%%a"
)
echo !all:~3!
The output is "XMLWrirter";"class";"free", but the semicolons may be changed by spaces, if you wish, and the quotes may be deleted.

Loop through CSV file with batch - Space issue

I have a csv file like this
name,sex,age
venu,m,16
test,,22
[EDIT]
name could have comma also
"venu,gopal",m,16
I want to handle if sex is nothing and save it to another file.
I have a script like this
#Echo Off
For /F "usebackq tokens=1-3 delims=," %%a in (test.csv) Do (
echo %%a, %%b, %%c >> test-new.csv
)
But for the third record, I am getting %%b as 22 which should be space. How to fix this?
[EDIT2]
I have tried as per that link. I am not sure what I am doing wrong. I am getting same issue. Please check it once.
#echo off
setlocal DisableDelayedExpansion
For /F "usebackq tokens=1-3 delims=" %%x in (C:\somefile.csv) Do (
setlocal EnableDelayedExpansion
set "var=%%x"
set "var=!var:"=""!"
set "var=!var:^=^^!"
set "var=!var:&=^&!"
set "var=!var:|=^|!"
set "var=!var:<=^<!"
set "var=!var:>=^>!"
set "var=!var:,=^,^,!"
set var=!var:""="!
set "var=!var:"=""Q!"
set "var=!var:,,="S"S!"
set "var=!var:^,^,=,!"
set "var=!var:""="!"
set "var=!var:"Q=!"
For /F "tokens=1-3 delims=," %%a in ("!var:"S"S=","!") Do (
endlocal
echo %%~a, %%~b, %%~c
setlocal EnableDelayedExpansion
pause
)
endlocal
)
This is a bit tricky, as multiple delims will be condensed to a single delim.
So you need to replace them before to a unique delim sequence.
#Echo Off
setlocal DisableDelayedExpansion
For /F "usebackq tokens=1-3 delims=" %%a in (test.csv) Do (
set "line=%%a"
setlocal EnableDelayedExpansion
set "line="!line:,=","!""
For /F "tokens=1-3 delims=," %%a in ("!line!") Do (
echo %%~a, %%~b, %%~c
)
)
This enclose each column into quotes, and with the %%~a the quotes will be removed later
EDIT: The solution for embedded commas
In this case it's only a bit different than the solution for how to split on ';' in CMD shell
#echo off
setlocal DisableDelayedExpansion
For /F "usebackq tokens=1-3 delims=" %%x in (test.csv) Do (
set "var=%%x"
setlocal EnableDelayedExpansion
set "var=!var:^=^^!"
set "var=!var:&=^&!"
set "var=!var:|=^|!"
set "var=!var:<=^<!"
set "var=!var:>=^>!"
set "var=!var:,=^,^,!"
rem ** This is the key line, the missing quote is intention
call set var=%%var:""="%%
set "var=!var:"="Q!"
set "var=!var:^,^,="C!"
set "var=!var:,,=,!"
set "var=!var:""="!"
set "var="!var:,=","!""
for /F "tokens=1-3 delims=," %%a in ("!var!") do (
endlocal
set "col1=%%~a"
set "col2=%%~b"
set "col3=%%~c"
setlocal EnableDelayedExpansion
if defined col1 (
set "col1=!col1:"C=,!"
set "col1=!col1:"Q="!"
)
if defined col2 (
set "col2=!col2:"C=,!"
set "col2=!col2:"Q="!"
)
if defined col3 (
set "col3=!col3:"C=,!"
set "col3=!col3:"Q="!"
)
echo a=!col1!, b=!col2!, c=!col3!
endlocal
)
)
using a string editor like SSED, I have overcome this issue by creating a temp file where I have replaced ",," with ",-," twice, then regarding a "-" as having been an empty field in the original file...
ssed "s/,,/,-,/ig;s/,,/,-,/ig" file1.csv > file1.tmp
Then the tokens are allocated correctly. If you need to edit the temp file and then return to a CSV, then use...
ssed "s/,-,/,,/ig;s/,-,/,,/ig" file1.tmp > file1.csv
This seems much simpler than doing in flight string replacements by token and having subroutines/etc.

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