How to use a radiobutton with IF statement? - wpf

Question

I´m trying use RadioButton with statement IF
in short: I created a WPF application in which I want to select one of the four options and then click the button to open another window.I'd like to make sure the user clicked one off.
private void Button_Click(object sender, RoutedEventArgs e)
{
if (here I don't know how to create a condition)
{
MessageBox.Show("Musíš zvolit, jednu z početních operací!");
}
else
{
uroven lvl = new uroven();
lvl.Show();
this.Close();
}
}
RadioButton == unchecked I thought of this condition but it does not go as well as the possibility of or(||)
as seen from the code I use error message in if and else opens another window
I'll be happy for any advice
Thank you
edit:
solution though not very nice
private void Button_Click(object sender, RoutedEventArgs e)
{
if (scitani.IsChecked.HasValue && scitani.IsChecked.Value)
{
uroven lvl = new uroven();
lvl.Show();
this.Close();
}
else if (odcitani.IsChecked.HasValue && odcitani.IsChecked.Value)
{
uroven lvl = new uroven();
lvl.Show();
this.Close();
}
else if (nasobeni.IsChecked.HasValue && nasobeni.IsChecked.Value)
{
uroven lvl = new uroven();
lvl.Show();
this.Close();
}
else if (deleni.IsChecked.HasValue && deleni.IsChecked.Value)
{
uroven lvl = new uroven();
lvl.Show();
this.Close();
}
else
{
MessageBox.Show("Musíš zvolit, jednu z početních operací!");
}
}

Answer 1

I made a sample source for you by using MVVM pattern.
👉Github
Structure
First,
you better use ListBox, that contains RadioButton as ListBoxItem.
MainMenuViewModel.cs
public class MainMenuViewModel : ObservableObject
{
private List<RadioItem> _radios;
public List<RadioItem> Radios
{
get { return _radios; }
set { _radios = value; OnPropertyChanged(); }
}
private RadioItem _currentRadio;
public RadioItem CurrentRadio
{
get { return _currentRadio; }
set { _currentRadio = value; OnPropertyChanged(); }
}
...
}
MainMenuResource.xaml
<Style TargetType="{x:Type ListBox}" x:Key="LBX">
<Setter Property="ItemContainerStyle" Value="{StaticResource LBXI}"/>
<Setter Property="ItemsSource" Value="{Binding Radios}"/>
<Setter Property="SelectedItem" Value="{Binding CurrentRadio}"/>
<Setter Property="VerticalAlignment" Value="Center"/>
<Setter Property="BorderBrush" Value="Transparent"/>
</Style>
Radios binds to ItemsSource in ListBox, and CurrnetRadio binds to SelectedItem.
Second,
by using Command, you can close the MainWindow and show the SubWindow.
MainMenuViewModel.cs
public class MainMenuViewModel : ObservableObject
{
...
public ICommand ClickCommand { get; set; }
public MainMenuViewModel()
{
ClickCommand = new RelayCommand<Window>(Click);
...
}
private void Click(Window obj)
{
if (CurrentRadio.DisplayName == "Radio 1")
{
obj.DialogResult = true;
}
else
{
MessageBox.Show("Select another one!");
}
}
}
MainMenuResource.xaml
<Style TargetType="{x:Type Button}" x:Key="BTN.MAIN">
<Setter Property="Command" Value="{Binding ClickCommand}"/>
<Setter Property="CommandParameter" Value="{Binding RelativeSource={RelativeSource AncestorType=Window}}"/>
...
</Style>
Finally,
Because you need to control multiple windows in the application, it is common to treat them with the OnStartup method.
App.xaml.cs
public partial class App : Application
{
protected override void OnStartup(StartupEventArgs e)
{
base.OnStartup(e);
MainWindow main;
SubWindow sub;
this.ShutdownMode = ShutdownMode.OnExplicitShutdown;
main = new MainWindow();
main.ShowDialog();
if (main.DialogResult == true)
{
sub = new SubWindow();
sub.ShowDialog();
}
Environment.Exit(0);
}
}

Answer 2

you should reach your control
XAML:
<RadioButton x:Name="myRadioButton" />
CS:
private void Button_Click(object sender, RoutedEventArgs e)
{
if (myRadioButton.IsChecked.HasValue && myRadioButton.IsChecked.Value)
{
MessageBox.Show("Musíš zvolit, jednu z početních operací!");
}
else
{
uroven lvl = new uroven();
lvl.Show();
this.Close();
}
}