I have a SQL Server 2016 temp table that looks like this:
SECTION_NAME SORT_ORDER COL1 COL2 COL3 COL4 COL5 COL6 COL7 COL8 COL9 COL10
ONE 1 A B C D E F G H I J
ONE 2 C D E F G H I X Y Z
I am only selecting the COL columns and want each records COL columns to be on a separate row, like this:
SELECT * FROM #TEMPTABLE
A
B
C
D
E
etc
How can I do that? I don't know PIVOT very well so not sure if I can use that. Thanks!
You need to "unpivot" which I prefer to do using cross apply and values, like this
SELECT
row_number() over (order by SECTION_NAME, SORT_ORDER, ca.value) as ID
, section_name
, sort_order
, ca.value
FROM pivoted
CROSS APPLY (
VALUES
(col1)
, (col2)
, (col3)
, (col4)
, (col5)
, (col6)
, (col7)
, (col8)
, (col9)
, (col10)
) AS ca(value)
which produces:
+----+--------------+------------+-------+
| ID | section_name | sort_order | value |
+----+--------------+------------+-------+
| 1 | ONE | 1 | A |
| 2 | ONE | 1 | B |
| 3 | ONE | 1 | C |
| 4 | ONE | 1 | D |
| 5 | ONE | 1 | E |
| 6 | ONE | 1 | F |
| 7 | ONE | 1 | G |
| 8 | ONE | 1 | H |
| 9 | ONE | 1 | I |
| 10 | ONE | 1 | J |
| 11 | ONE | 2 | C |
| 12 | ONE | 2 | D |
| 13 | ONE | 2 | E |
| 14 | ONE | 2 | F |
| 15 | ONE | 2 | G |
| 16 | ONE | 2 | H |
| 17 | ONE | 2 | I |
| 18 | ONE | 2 | X |
| 19 | ONE | 2 | Y |
| 20 | ONE | 2 | Z |
+----+--------------+------------+-------+
see this demo
Related
I need a hierarchy for my database and decided to use the closure table model. The hierarchy tables have the usual structure, like this:
locations table
+----+---------+
| id | name |
+----+---------+
| 1 | Europe |
| 2 | France |
| 3 | Germany |
| 4 | Spain |
| 5 | Paris |
| 6 | Nizza |
| 7 | Berlin |
| 8 | Munich |
| 9 | Madrid |
+----+---------+
CREATE TABLE locations (
id int IDENTITY(1,1) PRIMARY KEY,
name varchar(30)
)
lacations_relation table
+----+--------+--------+-------+
| id | src_id | dst_id | depth |
+----+--------+--------+-------+
| 1 | 1 | 1 | 0 |
| 2 | 2 | 2 | 0 |
| 3 | 1 | 2 | 1 |
| 4 | 3 | 3 | 0 |
| 5 | 1 | 3 | 1 |
| 6 | 4 | 4 | 0 |
| 7 | 1 | 4 | 1 |
| 8 | 5 | 5 | 0 |
| 9 | 2 | 5 | 1 |
| 10 | 1 | 5 | 2 |
| 11 | 6 | 6 | 0 |
| 12 | 2 | 6 | 1 |
| 13 | 1 | 6 | 2 |
| 14 | 7 | 7 | 0 |
| 15 | 3 | 7 | 1 |
| 16 | 1 | 7 | 2 |
| 17 | 8 | 8 | 0 |
| 18 | 3 | 8 | 1 |
| 19 | 1 | 8 | 2 |
| 20 | 9 | 9 | 0 |
| 21 | 4 | 9 | 1 |
| 22 | 1 | 9 | 2 |
+----+--------+--------+-------+
CREATE TABLE locations_relation (
id int IDENTITY(1,1) PRIMARY KEY,
src_id int,
dst_id int,
depth int,
CONSTRAINT FK_src FOREIGN KEY (src_id)
REFERENCES locations (id),
CONSTRAINT FK_dst FOREIGN KEY (dst_id)
REFERENCES locations (id)
)
Now there is a third table, which holds information about documents and is referencing the locations table, which looks like this:
closure_junction
+----+------------+-------------+
| id | country_id | document_id |
+----+------------+-------------+
| 1 | 2 | 1 |
| 2 | 2 | 2 |
| 3 | 6 | 2 |
| 4 | 6 | 3 |
| 5 | 5 | 2 |
| 6 | 5 | 4 |
+----+------------+-------------+
CREATE TABLE closure_junction (
id int IDENTITY(1,1) PRIMARY KEY,
country_id int NOT NULL,
document_id int,
CONSTRAINT FK_countries FOREIGN KEY (id)
REFERENCES countries(id)
)
What I'd like to have is single SQL-Query which counts the document per location and if there are documents in a child it should be counted up in the parent. For example if paris holds 2 documents than france should automatically also hold 2 documents. The query should also output the path of each node to the root aswell as the depth of the node. I know there is way to do this recursively, but I'd like to avoid that.
I have a query which gives me the correct result, but I'm not satisfied with how it works. Is there a way to circumentvent storing the children in a column?
This is my query with the correct output:
;WITH cte (name, path, depth, children) AS
(
SELECT
node.name,
STRING_AGG(locations.name, ' / ' ) WITHIN GROUP (ORDER BY relation.depth DESC) as path,
MAX(relation.depth) as depth,
STRING_AGG(locations.id, ' ') as children
FROM locations node
INNER JOIN locations_relation relation
ON node.id = relation.dst_id
INNER JOIN locations
ON relation.src_id = locations.id
GROUP BY node.name
)
SELECT
name,
path,
depth,
COUNT(DISTINCT document_id) as count_docs
FROM cte
CROSS APPLY string_split(children, ' ')
LEFT JOIN closure_junction ON
closure_junction.country_id = value
GROUP BY name, path, depth
ORDER BY depth ASC
+---------+---------------------------+-------+------------+
| name | path | depth | count_docs |
+---------+---------------------------+-------+------------+
| Europe | Europe | 0 | 0 |
| France | Europe / France | 1 | 2 |
| Germany | Europe / Germany | 1 | 0 |
| Spain | Europe / Spain | 1 | 0 |
| Berlin | Europe / Germany / Berlin | 2 | 0 |
| Madrid | Europe / Spain / Madrid | 2 | 0 |
| Munich | Europe / Germany / Munich | 2 | 0 |
| Nizza | Europe / France / Nizza | 2 | 3 |
| Paris | Europe / France / Paris | 2 | 3 |
+---------+---------------------------+-------+------------+
Would be great if someone could give me a clue on how to accomplish this.
The count you can easily replace with a simple LEFT JOIN, but for this path you will still need to concatenate it somehow.
Something like this:
WITH CTE_path
AS
( SELECT node.id,
STRING_AGG(locations.name, ' / ' ) WITHIN GROUP (ORDER BY relation.depth DESC) as path
FROM locations node
INNER JOIN locations_relation relation
ON node.id = relation.dst_id
INNER JOIN locations
ON relation.src_id = locations.id
GROUP BY node.id)
SELECT l.name,count(DISTINCT cj.document_id),pa.path
FROM locations l
JOIN CTE_path pa
ON pa.id = l.id
LEFT JOIN locations_relation lr
ON l.id = lr.dst_id
LEFT JOIN closure_junction cj
ON cj.country_id = lr.src_id
GROUP BY l.name,pa.path
I want to hide duplicate rows based on 2 columns (row,type)
In the status column I have 4 types of text
Enable,Disable,Run,End
Also 4 extra columns for these 4 texts
The number of each text based on that 2 columns is displayed in the corresponding column
I want to convert from :
|--------------------------------|
| id | row |value | type |status |
|--------------------------------|
| 1 | a | a | a |Enable |
| 2 | a | a | a |Disable|
| 3 | a | a | a |Run |
| 4 | a | a | a |End |
| 5 | a | a | a |End |
| |
| 6 | a | a | b |Enable |
| 7 | a | a | b |Run |
| |
| 8 | b | a | b |Enable |
| 9 | b | a | b |Disable|
| |
| 10 | b | a | c |Run |
| 11 | b | a | c |End |
| 12 | b | a | c |End |
| |
| 13 | c | a | a |Enable |
| 14 | c | a | a |Run |
|--------------------------------|
to :
|---------------------------------------------------------------|
| id | row |value | type |status |number |Enable|Disable|Run|End|
|---------------------------------------------------------------|
| 1 | a | a | a |Enable | 5 | 1 | 1 | 1 | 2 |
| 2 | a | a | b |Enable | 2 | 1 | 0 | 1 | 0 |
| 3 | b | a | b |Enable | 2 | 1 | 1 | 0 | 0 |
| 4 | b | a | c |Run | 3 | 0 | 0 | 1 | 2 |
| 5 | c | a | a |Enable | 2 | 1 | 0 | 1 | 0 |
|---------------------------------------------------------------|
my query :
SELECT
ROW_NUMBER() OVER(order by min(id)) AS 'id'
, row
, MIN(value) AS 'value'
, type
, MIN(status) AS 'status'
, COUNT(*) AS'number'
, (SELECT COUNT(1) FROM Work WHERE status LIKE 'Enable' ) AS 'Enable'
, (SELECT COUNT(1) FROM Work WHERE status LIKE 'Disable' ) AS 'Disable'
, (SELECT COUNT(1) FROM Work WHERE status LIKE'Run') AS 'Run'
, (SELECT COUNT(1) FROM Work WHERE status LIKE 'End') AS 'End'
FROM Work AS w
WHERE type ='a'
GROUP BY row,type
ORDER BY MIN(id)
But with this query the output is :
|---------------------------------------------------------------|
| id | row |value | type |status |number |Enable|Disable|Run|End|
|---------------------------------------------------------------|
| 1 | a | a | a |Enable | 5 | 1 | 1 | 1 | 2 |
| 2 | a | a | b |Enable | 2 | 1 | 1 | 1 | 2 |
| 3 | b | a | b |Enable | 2 | 1 | 1 | 1 | 2 |
| 4 | b | a | c |Run | 3 | 1 | 1 | 1 | 2 |
| 5 | c | a | a |Enable | 2 | 1 | 1 | 1 | 2 |
|---------------------------------------------------------------|
There is missing where part in every select count(*)... .
...
,(select count(*) from Work w2 where status like 'Enable' and w.row = w2.row and w.type = w2.type ) as 'Enable'
...
I need to take data from a table that looks like this:
name | server | instance | version | user
----------|----------|------------|----------|--------- -
package_a | x | 1 | 1 | AB
package_b | x | 1 | 1 | TL
package_a | x | 2 | 4 | SK
package_a | y | 1 | 2 | MD
package_c | y | 1 | 4 | SK
package_b | y | 2 | 1 | SK
package_a | y | 2 | 1 | TL
package_b | x | 2 | 3 | TL
package_c | x | 2 | 1 | TL
and I need to put it in a table like that:
name | v_x_1 | u_x_1 | v_x_2 | u_x_2 | v_y_1 | u_y_1 | v_y_2 | u_y_2
----------|-------|-------|-------|-------|-------|-------|-------|-------
package_a | 1 | AB | 4 | SK | 2 | MD | 1 | TL
package_b | 1 | TL | 3 | TL | NULL | NULL | 1 | SK
package_c | NULL | NULL | 1 | TL | 4 | SK | NULL | NULL
I already tried INSERT with (SUB)SELECT, tried to INSERT package names first using DISTINCT and UPDATE afterwards, played around with PIVOT and stuff like that.
But I'm rather new to SQL and programming in general, so I couldn't come up with a solution. Since I not only have a version number in the source table but also nvarchar columns, It seems like PIVOT won't be the way to go, right?
You can use PIVOT on a sub query that uses UNION to separate the user and version values.
insert into YourNewTable (name, [v_x_1],[u_x_1],[v_x_2],[u_x_2],[v_y_1],[u_y_1],[v_y_2],[u_y_2])
select *
from (
select name, cast([version] as varchar(30)) as value, concat('v_',[server],'_',instance) as title from YourTable
union all
select name, [user] as value, concat('u_',[server],'_',instance) as title from YourTable
) q
pivot (max(value) FOR title IN (
[v_x_1],[u_x_1],[v_x_2],[u_x_2],[v_y_1],[u_y_1],[v_y_2],[u_y_2]
)
) pvt;
I'm trying to have 2 tables (In this case it's actually 1 table in a self join) joined by their matching children.
Let me preface the purpose of this which might give a better understanding what I need:
I'm trying to look up a new order that I just got, to see if we ever had the same order, in order to find out in which box type this would be packaged.
So i'd need the matching order to contain the same item and the same qty for the item.
Look at the tables below and note that order 1300981 has the same items as order 1303097, how do I write this join?
Remember: I don't want the results to include any matches that do not match %100.
SQL Fiddle
OrderMain:
| OrderID | BoxId |
|---------|--------|
| 1300981 | 34 |
| 1303096 | (null) |
| 1303097 | (null) |
| 1303098 | (null) |
| 1303099 | (null) |
| 1303100 | (null) |
| 1303101 | (null) |
| 1303102 | (null) |
| 1303103 | (null) |
| 1303104 | B1 |
| 1303105 | (null) |
| 1303106 | (null) |
| 1303107 | 48 |
| 1303108 | (null) |
| 1303109 | (null) |
| 1303110 | (null) |
| 1303111 | (null) |
| 1303112 | (null) |
| 1303113 | (null) |
| 1303114 | (null) |
| 1303115 | (null) |
| 1303116 | (null) |
| 1303117 | (null) |
Order Detail:
| id | OrderID | Item | Qty |
|----|---------|--------|-----|
| 1 | 1300981 | 172263 | 3 |
| 2 | 1300981 | 171345 | 3 |
| 3 | 1300981 | 138757 | 3 |
| 4 | 1303117 | 231711 | 1 |
| 5 | 1303116 | 227835 | 1 |
| 6 | 1303115 | 244798 | 1 |
| 7 | 1303114 | 121755 | 1 |
| 8 | 1303113 | 145275 | 2 |
| 9 | 1303112 | 219554 | 1 |
| 10 | 1303111 | 179385 | 1 |
| 11 | 1303110 | 6229 | 1 |
| 12 | 1303109 | 217330 | 1 |
| 13 | 1303108 | 243596 | 1 |
| 14 | 1303107 | 246758 | 1 |
| 15 | 1303106 | 193931 | 1 |
| 16 | 1303105 | 244659 | 1 |
| 17 | 1303104 | 192548 | 1 |
| 18 | 1303103 | 228410 | 1 |
| 19 | 1303102 | 147474 | 1 |
| 20 | 1303101 | 239191 | 1 |
| 21 | 1303100 | 243594 | 1 |
| 22 | 1303099 | 232301 | 1 |
| 23 | 1303098 | 201212 | 1 |
| 24 | 1303097 | 172263 | 3 |
| 25 | 1303097 | 171345 | 3 |
| 26 | 1303097 | 138757 | 3 |
| 27 | 1303096 | 172263 | 3 |
| 28 | 1303096 | 171345 | 1 |
| 29 | 1303096 | 138757 | 3 |
| 30 | 1303095 | 172263 | 3 |
Expected Results
| OrderID | BoxId |
|---------|--------|
| 1303097 | 34 |
May be a weird way to do this, but if you convert the order details to xml and compare it to other orders, you can look for matches.
WITH BoxOrders AS
(
SELECT om.[OrderId],
om.[BoxId],
(SELECT Item, Qty
FROM orderDetails od
WHERE od.[OrderId] = om.[OrderId]
ORDER BY Item
FOR XML PATH('')) Details
FROM orderMain om
WHERE BoxID IS NOT NULL
)
SELECT mo.OrderId, bo.BoxId
FROM BoxOrders bo
JOIN (
SELECT om.[OrderId],
om.[BoxId],
(SELECT Item, Qty
FROM orderDetails od
WHERE od.[OrderId] = om.[OrderId]
ORDER BY Item
FOR XML PATH('')) Details
FROM orderMain om
WHERE BoxID IS NULL
) mo ON bo.Details = mo.Details
SQL Fiddle
Here's a different approach using SQL and a few analytics.
This joins order detail to itself based on item and qty and order number < other order number and ensures the count of items in each order matches. Thus if items match, count matches and qty matches then the order has the same items.
This returns both orders but easily enough to adjust. Using the CTE so the count materializes. Pretty sure you can't use a having with an analytic like this.
The one major assumption I'm making is that order numbers are sequential and when you say see if an older order exists, I should only need to look at earlier order numbers when evaluating if a prior order had the same items and quantities.
I'm also assuming a 100% match means: Exact same items. Same Quantity of items. and SAME Item Count so count of items for order 1 is 3 and order 2 is 3 and items and quantities match that is 100% but if order 2 had 4 items and order 1 only had 3, no match.
with cte as (
SELECT distinct OD1.OrderID PriorOrder, od2.orderID newOrder, OM.BoxId,
count(OD1.Item) over (partition by OD1.OrderID) OD1Cnt,
count(OD2.Item) over (partition by OD2.OrderID) OD2cnt
FROM OrderDetails OD1
INNER JOIN orderDetails OD2
on OD1.item=OD2.item
and od1.qty = od2.qty
and OD1.OrderID < OD2.OrderID
LEFT JOIN ORderMain OM
on OM.OrderID = OD1.orderID)
Select PriorOrder, NewOrder, boxID from cte where od1cnt = od2cnt
I have a problem on sql server.
How to get running number from foreign key in one time select data from table?
example :
I have one table such as
-----------------
| id | pid | desc |
-----------------
| 1 | 1 | a |
| 2 | 1 | b |
| 3 | 1 | c |
| 4 | 2 | d |
| 5 | 2 | e |
| 6 | 2 | f |
| 7 | 2 | g |
| 8 | 3 | h |
| 9 | 3 | i |
| 10 | 1 | j |
| 11 | 1 | k |
-----------------
I want to get result as below
------------------------
| id | pid | desc | rec |
------------------------
| 1 | 1 | a | 1 |
| 2 | 1 | b | 2 |
| 3 | 1 | c | 3 |
| 4 | 2 | d | 1 |
| 5 | 2 | e | 2 |
| 6 | 2 | f | 3 |
| 7 | 2 | g | 4 |
| 8 | 3 | h | 1 |
| 9 | 3 | i | 2 |
| 10 | 1 | j | 4 |
| 11 | 1 | K | 5 |
------------------------
In above tables foreign key ('pid') Column has values 1 to 3 in different row numbers.
I tried to get the running number from each 'pid' field name.
I havn't found any way to do this,
Can I do that? Can some one help me? am still newbie at sql server
Try this
SELECT
id,
pid,
[desc],
Row_Number() OVER (PARTITION BY pid ORDER BY id) AS rec
FROM <yourtable>
ORDER BY id
You can use Ranking function in SQL Server 2005+ to accomplish that,
So here is your query
Select Row_Number() over (partition by pid order by id) as rec , * from Table