How to select all children from XML in Sql Server? - sql-server

Question

I have the below XML when I run the select query it considers only the first value, what I am missing here?
<?xml version="1.0" encoding="utf-16"?>
<ArrayOfString xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<string>1</string>
<string>2</string>
<string>3</string>
.............
</ArrayOfString>
Below query only returns 1, I am expecting it to return all values like 1,2,3...
SELECT xmlu.v1.value('string[1]', 'BIGINT')
FROM
#xml.nodes('/ArrayOfString')
AS xmlU(v1)

Answer 1

If you want one row per string node, you need to include the string node in your nodes clause:
SELECT AOS.s.value('(./text())[1]','bigint') AS string --If it's string, why are you asking for a bigint?
FROM (VALUES(#XML))V(X)
CROSS APPLY V.X.nodes('/ArrayOfString/string')AOS(s);

Answer 2

It seems that you are looking for something like the following.
It is better not to use the IN clause because it usually gets converted to inefficient OR expressiions.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, city VARCHAR(20));
INSERT INTO #tbl (city) VALUES
('Miami'),
('Orlando'),
('Dallas'),
('New York'),
('Hollywood');
DECLARE #parameter XML =
N'<ArrayOfString xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<string>1</string>
<string>2</string>
<string>3</string>
</ArrayOfString>'
-- DDL and sample data population, end
;WITH rs AS
(
SELECT c.value('.', 'INT') AS ID
FROM #parameter.nodes('/ArrayOfString/string/text()') AS t(c)
)
SELECT *
FROM #tbl AS t INNER JOIN
rs ON t.ID = rs.ID;