How to create matrix in matlab that adds cells horizontally - arrays

Question

I want to create a matrix, for example, a 1xn, where n is determined by another input.
For example, I have the following:
Example = [3 5 7 9];
New_matrix = [int_col(Example (1)) int_col(Example (2)) int_col(Example (3)) int_col(Example (4))];
This New_matrix is how I want my outputs.
However, for my actual data input, my Example matrix is 1x47. How can I put this in a for loop so it gives the outputs of 1 to a specified number for all of the length Example? (keeping it horizontal as well)
Help function I used is added here:
% Helper function added as well
function v = int_col(n)
v = zeros(1,n);
for index=1:n
val = randi(n);
while (val == index || any(val == v))
val = randi(n);
if (index == n && (any(v == n) ~= 1))
val = n;
break
end
end
v(index) = val;
if (index == n && val == n)
% v(n) = v(n-1);
% v(n-1) = n;
end
if n == 1
v = 1;
end
end
v = v';
v = (sortrows(v))';
end

Answer 1

Are you trying to reimplement randperm() in int_col()? I'm not sure what the purpose of running sortrows() on each column separately is, but I guess this may be what you wanted:
% Make up vector of column lengths
Example=randi(60,[1 47]);
% Create matrix
New_matrix=nan([max(Example) numel(Example)]);
for i=1:numel(Example)
New_matrix(1:Example(i),i)=randperm(Example(i));
end
% Sort matrix rows from left to right
New_matrix=sortrows(New_matrix);
Please note that all columns in a matrix must have the same number of entries, so you will need to pad shorter columns with some value; a typical choice is NaN, which is treated as a special value by sortrows() and some other functions.
~
If my guess is incorrect and you do mean your code as it currently is, you just need:
New_matrix=[];
for i=1:numel(Example)
New_matrix=[New_matrix 1:Example(i)];
end
Changing the size of New_matrix on every iteration is generally not good practice, but for 47 iterations only this should be fine.