How To Skip The 2nd Input Of n - c

Question

I've been messing with functions recently and i wanted to transform the following code:
#include<stdio.h>
int main()
{
int i,n,tab[100];
printf("Insert The Number Of Elements :\n");
scanf("%d",&n);
for(i=0;i<n;i++)
{
printf("Give The Element N~%d:",i+1);
scanf("%d",&tab[i]);
}
printf("The Elements Are:\n");
for(i=0;i<n;i++)
{
printf("Index[%d]=%d\n",i,tab[i]);
}
return 0;
}
... into a code where i can use functions to:
Ask for the number of elements that the array is going to hold
Show the output of the array with the elements the user entered
Here's what i got to so far but it seems like it keeps asking me for the number of elements the array will hold even though it has been already entered.
Thanks in advance to those who will help <3
#include<stdio.h>
int Number_Of(int a)
{
printf("Insert The Number Of Elements :\n");
scanf("%d",&a);
return a;
}
int Array(int tab[])
{
int i,n;
n=Number_Of(n);
for(i=0;i<n;i++)
{
printf("Index[%d]=%d\n",i,tab[i]);
}
}
int main()
{
int i,n,tab[100];
n=Number_Of(n);
for(i=0;i<n;i++)
{
printf("Give The Element N~%d:",i+1);
scanf("%d",&tab[i]);
}
printf("The Elements Are:\n");
Array(tab);
return 0;
}

Answer 1

You are calling "Number_Of" function two times that's why you prompted to enter again.
First time you called in main function.
Second time you called in Array function.
You can do like this.
#include<stdio.h>
int Number_Of(int a)
{
printf("Insert The Number Of Elements :\n");
scanf("%d",&a);
return a;
}
void Array(int tab[], int n)
{
int i;
for(i=0;i<n;i++)
{
printf("Index[%d]=%d\n",i,tab[i]);
}
}
int main()
{
int i,n,tab[100];
n=Number_Of(n);
for(i=0;i<n;i++)
{
printf("Give The Element N~%d:",i+1);
scanf("%d",&tab[i]);
}
printf("The Elements Are:\n");
Array(tab, n);
return 0;
}