Our data provider supplies the data in a weird format. The arrays date and value are corresponding and guaranteed to have the same length. For whatever reason, they even decide to mix up int and string values in date.
[
{
"_id": "A000005933",
"date": [905270400000, 918748800000, 937843200000, 965923200000, 983289600000, 984931200000, 1152806400000, "1171987200000", "1225382400000", "1229616000000", "1286208000000", "1455552000000"],
"value": ["0.25", "0.15", "0", "0.25", "0.15", "0", "0.25", "0.5", "0.3", "0.1", "0.1", "-0.1"],
"version": 1614837436798
},
{
"_id": "A000005934",
"date": [915120000000, 923587200000, 941731200000, 949593600000, 953222400000, 956851200000, 962121600000, 967737600000, 970761600000, 989510400000, 999187200000, 1000742400000, 1005235200000, 1039104000000, 1046966400000, 1054828800000, 1133798400000, 1141747200000, 1150300800000, 1155052800000, 1160496000000, 1165939200000, 1173801600000, 1181664000000, 1215532800000, 1224000000000, 1226419200000, 1228838400000, 1232467200000, 1236700800000, 1239120000000, 1242144000000, 1302624000000, 1310486400000, 1320768000000, 1323792000000, 1341936000000, 1367942400000, 1384272000000, 1402416000000, 1410278400000, 1458057600000],
"value": ["3", "2.5", "3", "3.25", "3.5", "3.78", "4.25", "4.5", "4.78", "4.5", "4.25", "3.75", "3.25", "2.78", "2.5", "2", "2.25", "2.5", "2.75", "3", "3.25", "3.5", "3.75", "4", "4.25", "3.75", "3.25", "2.5", "2", "1.5", "1.25", "1", "1.25", "1.5", "1.25", "1", "0.75", "0.5", "0.25", "0.15", "0.05", "0"],
"version": 1614837436548
},
......
]
Our typical use case is to look up value based on _id and date, so I had to do something like this.
def get_value_from_mongo(id_: str, date: datetime.date) -> float:
result = db.indicators.find_one({"_id": _id}, {"value": 1, "date": 1})
date_list = list(map(str, result["date"]))
price_list = list(map(str, result["value"]))
dt = date.strftime("%s000")
price = float(price_list[date_list.index(dt)])
return price
This is hopelessly inefficient because the whole array is scanned each time I want to retrieve a single value. Maybe I could do a binary search, but date is not guaranteed to be sorted and I don't want to rely on that behavior.
Are there any MongoDB operators I can use to speed up the query?
A first possibility is to focus on the lookup: create an index on dates array
Which comes at the sake of a slower write.
In below execution plan you can see the index is used (you should benchmark if it brings that of an improvement)
> db.indicators.explain().find({dates: '1.1'})
{
"queryPlanner" : {
"plannerVersion" : 1,
"namespace" : "dummy.indicators",
"indexFilterSet" : false,
"parsedQuery" : {
"dates" : {
"$eq" : "1.1"
}
},
"queryHash" : "4204704C",
"planCacheKey" : "1DBFE945",
"winningPlan" : {
"stage" : "FETCH",
"inputStage" : {
"stage" : "IXSCAN",// <------
"keyPattern" : {
"dates" : 1
},
"indexName" : "dates_1",
"isMultiKey" : true,
"multiKeyPaths" : {
"dates" : [
"dates"
]
},
"isUnique" : false,
"isSparse" : false,
"isPartial" : false,
"indexVersion" : 2,
"direction" : "forward",
"indexBounds" : {
"dates" : [
"[\"1.1\", \"1.1\"]"
A second possibility is to focus on retrieving the minimal data possible
With hint that bottleneck is not the date lookup but the data transfer
Thus this does not improve the lookup (given you "iterate" your array on db side instead of application code side).
You can make it with the use of
the positional operator
the projection as second argument in find with mongo >= 4.4
db.indicators.remove({})
db.indicators.insert([{_id: '0', dates: [1, '1.1', 2], prices: [1,2,3]}])
fetch = date => {
print(date)
res = db.indicators.find(
{
dates: {
$elemMatch: {
$in: [Number(date), String(date)]
}
}
},
{
'prices.$': 1 // <<--------
}
).toArray()
printjson(res)
}
fetch(2) // [ { "_id" : "0", "prices" : [ 3 ] } ]
fetch('1.1') // [ { "_id" : "0", "prices" : [ 2 ] } ]
Obviously you can compose 1 and 2, but I would have a try with just 2 to avoid creating an index
Related
What I'm asking for should be very simple but the Druid docs have little to no info about this.
I am making a groupBy query, and the data is very large so I'm "paging" it by increasing limitSpec.limit on each subsequent query.
By default, the returned array starts from the beginning timestamp and moves forward in time. I want the results to start from the end timestamp and move backwards in time from there.
Does anyone know how to do that?
So in other words, by default a groupBy query would look like this:
[
{
"version" : "v1",
"timestamp" : "2012-01-01T00:00:00.000Z",
"event" : {
"total_usage" : <some_value_one>
}
},
{
"version" : "v1",
"timestamp" : "2012-01-02T00:00:00.000Z",
"event" : {
"total_usage" : <some_value_two>
}
}
]
Whereas I want it to look like this:
[
{
"version" : "v1",
"timestamp" : "2012-01-02T00:00:00.000Z",
"event" : {
"total_usage" : <some_value_two>
}
},
{
"version" : "v1",
"timestamp" : "2012-01-01T00:00:00.000Z",
"event" : {
"total_usage" : <some_value_one>
}
}
]
You can achieve the ordering by using the "columns" attribute in the limit spec. see the below example.
{
"type" : "default",
"limit" : <integer_value>,
"columns" : [list of OrderByColumnSpec],
}
For more details you can refer the below druid doc -
http://druid.io/docs/latest/querying/limitspec.html
You can add timestamp as a dimension but truncated to date (assuming you use day granularity in your query) and force Druid to sort the result first by dimension values and then by timestamp.
Example Query:
{
"dataSource": "your_datasource",
"queryType": "groupBy",
"dimensions": [
{
"type": "default",
"dimension": "some_dimension_in",
"outputName": "some_dimension_out",
"outputType": "STRING"
},
{
"type": "extraction",
"dimension": "__time",
"outputName": "__timestamp",
"extractionFn": {
"type": "timeFormat",
"format" : "yyyy-MM-dd"
}
}
],
"aggregations": [
{
"type": "doubleSum",
"name": "some_metric",
"fieldName": "some_metric_field"
}
],
"limitSpec": {
"type": "default",
"limit": 1000,
"columns": [
{
"dimension": "__timestamp",
"direction": "descending",
"dimensionOrder": "numeric"
},
{
"dimension": "some_metric",
"direction": "descending",
"dimensionOrder": "numeric"
}
]
},
"intervals": [
"2019-09-01/2019-10-01"
],
"granularity": "day",
"context": {
"sortByDimsFirst": "true"
}
}
I have this kind of structure into a Mongo collection :
{
"_id": "12345678",
"Invoices": [
{
"_id": "123456789",
"Currency": "EUR",
"DueTotalAmountInvoice": 768.3699999999999,
"InvoiceDate": "2016-01-01 00:00:00.000",
"Items": [
{
"Item": 10,
"ProductCode": "ABC567",
"Quantity": 1
},
{
"Item": 20,
"ProductCode": "CDE987",
"Quantity": 1
}
]
},
{
"_id": "87654321",
"Currency": "EUR",
"DueTotalAmountInvoice": 768.3699999999999,
"InvoiceDate": "2016-01-01 00:00:00.000",
"Items": [
{
"Item": 30,
"ProductCode": "PLO987",
"Quantity": 1,
"Units": "KM3"
},
{
"Item": 40,
"ProductCode": "PLS567",
"Quantity": 1,
"DueTotalAmountInvoice": 768.3699999999999
}
]
}
]
}
So I have a first object storing several Invoices and each Invoice is storing several Items. An item is an embedded document.
So in relational modelisation :
A customer has 1 or several Invoice
An Invoice has 1 or several Item
I am facing an issue since I am trying to update a specific Item into a specific a specific Invoice. For example I want to change the quantity of the item 10 in Invoice 123456789.
How is it possible to do that in Mongodb ?
I tried :
Push statement but it doesn't seem to work for nested arrays
arrayFilters but it doesn't seem to work for embedded document in nested arrays (only simple value arrays).
Can you give me some advice about it ?
Thank you !
As per your problem description here:
For example I want to change the quantity of the item 10 in Invoice 123456789. I just changed the Quantity to 3. You can perform any operations here as you want. You just need to take note of how I used arrayFilters here.
Try this query:
db.collection.update(
{"_id" : "12345678"},
{$set:{"Invoices.$[element1].Items.$[element2].Quantity":3}},
{multi:true, arrayFilters:[ {"element1._id": "123456789"},{
"element2.Item": { $eq: 10 }} ]}
)
The above query successfully executed from mongo shell (Mongo 3.6.3). And I see this result:
/* 1 */
{
"_id" : "12345678",
"Invoices" : [
{
"_id" : "123456789",
"Currency" : "EUR",
"DueTotalAmountInvoice" : 768.37,
"InvoiceDate" : "2016-01-01 00:00:00.000",
"Items" : [
{
"Item" : 10,
"ProductCode" : "ABC567",
"Quantity" : 3.0
},
{
"Item" : 20,
"ProductCode" : "CDE987",
"Quantity" : 1
}
]
},
{
"_id" : "87654321",
"Currency" : "EUR",
"DueTotalAmountInvoice" : 768.37,
"InvoiceDate" : "2016-01-01 00:00:00.000",
"Items" : [
{
"Item" : 30,
"ProductCode" : "PLO987",
"Quantity" : 1,
"Units" : "KM3"
},
{
"Item" : 40,
"ProductCode" : "PLS567",
"Quantity" : 1,
"DueTotalAmountInvoice" : 768.37
}
]
}
]
}
Is that what you wanted?
Mongo Db has a way to get the specific array element by using its index. For example, you have an array and you need to get [your] index, then in mongo we use dot . but not braces [ ] !! And one thing is important either! - If you are getting the embedded value (in object or array) you must use " " for your way so if you are changing your value inside this must be like that:
yourModel.findOneAndUpdate(
{ _id: "12345678" },
{
$set: {
"Invoices.0.Items.0.Quantity": 10,
},
}
);
0 - is your element indexes in the array!
$set is the operator to set new value
10 - new value
Else you can go further, you can construct your way to the value with the variable indexes. Use string template
yourModel.findOneAndUpdate(
{ _id: "12345678" },
{
$set: {
[`Invoices.${invoiceIndex}.Items.${itemIndex}.Quantity`]:newValue ,
},
}
);
it is the same but you can paste variable indexes
Suppose you have the following documents in my collection:
{
"_id":ObjectId("562e7c594c12942f08fe4192"),
"shapes":[
{
"shape":"square",
"color":"blue"
},
{
"shape":"circle",
"color":"red"
}
]
},
{
"_id":ObjectId("562e7c594c12942f08fe4193"),
"shapes":[
{
"shape":"square",
"color":"black"
},
{
"shape":"circle",
"color":"green"
}
]
}
Do query:
db.test.find({"shapes.color": "red"}, {"shapes.color": 1})
Or
db.test.find({shapes: {"$elemMatch": {color: "red"}}}, {"shapes.color": 1})
Returns matched document (Document 1), but always with ALL array items in shapes:
{ "shapes":
[
{"shape": "square", "color": "blue"},
{"shape": "circle", "color": "red"}
]
}
However, I'd like to get the document (Document 1) only with the array that contains color=red:
{ "shapes":
[
{"shape": "circle", "color": "red"}
]
}
How can I do this?
MongoDB 2.2's new $elemMatch projection operator provides another way to alter the returned document to contain only the first matched shapes element:
db.test.find(
{"shapes.color": "red"},
{_id: 0, shapes: {$elemMatch: {color: "red"}}});
Returns:
{"shapes" : [{"shape": "circle", "color": "red"}]}
In 2.2 you can also do this using the $ projection operator, where the $ in a projection object field name represents the index of the field's first matching array element from the query. The following returns the same results as above:
db.test.find({"shapes.color": "red"}, {_id: 0, 'shapes.$': 1});
MongoDB 3.2 Update
Starting with the 3.2 release, you can use the new $filter aggregation operator to filter an array during projection, which has the benefit of including all matches, instead of just the first one.
db.test.aggregate([
// Get just the docs that contain a shapes element where color is 'red'
{$match: {'shapes.color': 'red'}},
{$project: {
shapes: {$filter: {
input: '$shapes',
as: 'shape',
cond: {$eq: ['$$shape.color', 'red']}
}},
_id: 0
}}
])
Results:
[
{
"shapes" : [
{
"shape" : "circle",
"color" : "red"
}
]
}
]
The new Aggregation Framework in MongoDB 2.2+ provides an alternative to Map/Reduce. The $unwind operator can be used to separate your shapes array into a stream of documents that can be matched:
db.test.aggregate(
// Start with a $match pipeline which can take advantage of an index and limit documents processed
{ $match : {
"shapes.color": "red"
}},
{ $unwind : "$shapes" },
{ $match : {
"shapes.color": "red"
}}
)
Results in:
{
"result" : [
{
"_id" : ObjectId("504425059b7c9fa7ec92beec"),
"shapes" : {
"shape" : "circle",
"color" : "red"
}
}
],
"ok" : 1
}
Caution: This answer provides a solution that was relevant at that time, before the new features of MongoDB 2.2 and up were introduced. See the other answers if you are using a more recent version of MongoDB.
The field selector parameter is limited to complete properties. It cannot be used to select part of an array, only the entire array. I tried using the $ positional operator, but that didn't work.
The easiest way is to just filter the shapes in the client.
If you really need the correct output directly from MongoDB, you can use a map-reduce to filter the shapes.
function map() {
filteredShapes = [];
this.shapes.forEach(function (s) {
if (s.color === "red") {
filteredShapes.push(s);
}
});
emit(this._id, { shapes: filteredShapes });
}
function reduce(key, values) {
return values[0];
}
res = db.test.mapReduce(map, reduce, { query: { "shapes.color": "red" } })
db[res.result].find()
Another interesing way is to use $redact, which is one of the new aggregation features of MongoDB 2.6. If you are using 2.6, you don't need an $unwind which might cause you performance problems if you have large arrays.
db.test.aggregate([
{ $match: {
shapes: { $elemMatch: {color: "red"} }
}},
{ $redact : {
$cond: {
if: { $or : [{ $eq: ["$color","red"] }, { $not : "$color" }]},
then: "$$DESCEND",
else: "$$PRUNE"
}
}}]);
$redact "restricts the contents of the documents based on information stored in the documents themselves". So it will run only inside of the document. It basically scans your document top to the bottom, and checks if it matches with your if condition which is in $cond, if there is match it will either keep the content($$DESCEND) or remove($$PRUNE).
In the example above, first $match returns the whole shapes array, and $redact strips it down to the expected result.
Note that {$not:"$color"} is necessary, because it will scan the top document as well, and if $redact does not find a color field on the top level this will return false that might strip the whole document which we don't want.
Better you can query in matching array element using $slice is it helpful to returning the significant object in an array.
db.test.find({"shapes.color" : "blue"}, {"shapes.$" : 1})
$slice is helpful when you know the index of the element, but sometimes you want
whichever array element matched your criteria. You can return the matching element
with the $ operator.
db.getCollection('aj').find({"shapes.color":"red"},{"shapes.$":1})
OUTPUTS
{
"shapes" : [
{
"shape" : "circle",
"color" : "red"
}
]
}
The syntax for find in mongodb is
db.<collection name>.find(query, projection);
and the second query that you have written, that is
db.test.find(
{shapes: {"$elemMatch": {color: "red"}}},
{"shapes.color":1})
in this you have used the $elemMatch operator in query part, whereas if you use this operator in the projection part then you will get the desired result. You can write down your query as
db.users.find(
{"shapes.color":"red"},
{_id:0, shapes: {$elemMatch : {color: "red"}}})
This will give you the desired result.
Thanks to JohnnyHK.
Here I just want to add some more complex usage.
// Document
{
"_id" : 1
"shapes" : [
{"shape" : "square", "color" : "red"},
{"shape" : "circle", "color" : "green"}
]
}
{
"_id" : 2
"shapes" : [
{"shape" : "square", "color" : "red"},
{"shape" : "circle", "color" : "green"}
]
}
// The Query
db.contents.find({
"_id" : ObjectId(1),
"shapes.color":"red"
},{
"_id": 0,
"shapes" :{
"$elemMatch":{
"color" : "red"
}
}
})
//And the Result
{"shapes":[
{
"shape" : "square",
"color" : "red"
}
]}
You just need to run query
db.test.find(
{"shapes.color": "red"},
{shapes: {$elemMatch: {color: "red"}}});
output of this query is
{
"_id" : ObjectId("562e7c594c12942f08fe4192"),
"shapes" : [
{"shape" : "circle", "color" : "red"}
]
}
as you expected it'll gives the exact field from array that matches color:'red'.
Along with $project it will be more appropriate other wise matching elements will be clubbed together with other elements in document.
db.test.aggregate(
{ "$unwind" : "$shapes" },
{ "$match" : { "shapes.color": "red" } },
{
"$project": {
"_id":1,
"item":1
}
}
)
Likewise you can find for the multiple
db.getCollection('localData').aggregate([
// Get just the docs that contain a shapes element where color is 'red'
{$match: {'shapes.color': {$in : ['red','yellow'] } }},
{$project: {
shapes: {$filter: {
input: '$shapes',
as: 'shape',
cond: {$in: ['$$shape.color', ['red', 'yellow']]}
}}
}}
])
db.test.find( {"shapes.color": "red"}, {_id: 0})
Use aggregation function and $project to get specific object field in document
db.getCollection('geolocations').aggregate([ { $project : { geolocation : 1} } ])
result:
{
"_id" : ObjectId("5e3ee15968879c0d5942464b"),
"geolocation" : [
{
"_id" : ObjectId("5e3ee3ee68879c0d5942465e"),
"latitude" : 12.9718313,
"longitude" : 77.593551,
"country" : "India",
"city" : "Chennai",
"zipcode" : "560001",
"streetName" : "Sidney Road",
"countryCode" : "in",
"ip" : "116.75.115.248",
"date" : ISODate("2020-02-08T16:38:06.584Z")
}
]
}
Although the question was asked 9.6 years ago, this has been of immense help to numerous people, me being one of them. Thank you everyone for all your queries, hints and answers. Picking up from one of the answers here.. I found that the following method can also be used to project other fields in the parent document.This may be helpful to someone.
For the following document, the need was to find out if an employee (emp #7839) has his leave history set for the year 2020. Leave history is implemented as an embedded document within the parent Employee document.
db.employees.find( {"leave_history.calendar_year": 2020},
{leave_history: {$elemMatch: {calendar_year: 2020}},empno:true,ename:true}).pretty()
{
"_id" : ObjectId("5e907ad23997181dde06e8fc"),
"empno" : 7839,
"ename" : "KING",
"mgrno" : 0,
"hiredate" : "1990-05-09",
"sal" : 100000,
"deptno" : {
"_id" : ObjectId("5e9065f53997181dde06e8f8")
},
"username" : "none",
"password" : "none",
"is_admin" : "N",
"is_approver" : "Y",
"is_manager" : "Y",
"user_role" : "AP",
"admin_approval_received" : "Y",
"active" : "Y",
"created_date" : "2020-04-10",
"updated_date" : "2020-04-10",
"application_usage_log" : [
{
"logged_in_as" : "AP",
"log_in_date" : "2020-04-10"
},
{
"logged_in_as" : "EM",
"log_in_date" : ISODate("2020-04-16T07:28:11.959Z")
}
],
"leave_history" : [
{
"calendar_year" : 2020,
"pl_used" : 0,
"cl_used" : 0,
"sl_used" : 0
},
{
"calendar_year" : 2021,
"pl_used" : 0,
"cl_used" : 0,
"sl_used" : 0
}
]
}
if you want to do filter, set and find at the same time.
let post = await Post.findOneAndUpdate(
{
_id: req.params.id,
tasks: {
$elemMatch: {
id: req.params.jobId,
date,
},
},
},
{
$set: {
'jobs.$[i].performer': performer,
'jobs.$[i].status': status,
'jobs.$[i].type': type,
},
},
{
arrayFilters: [
{
'i.id': req.params.jobId,
},
],
new: true,
}
);
This answer does not fully answer the question but it's related and I'm writing it down because someone decided to close another question marking this one as duplicate (which is not).
In my case I only wanted to filter the array elements but still return the full elements of the array. All previous answers (including the solution given in the question) gave me headaches when applying them to my particular case because:
I needed my solution to be able to return multiple results of the subarray elements.
Using $unwind + $match + $group resulted in losing root documents without matching array elements, which I didn't want to in my case because in fact I was only looking to filter out unwanted elements.
Using $project > $filter resulted in loosing the rest of the fields or the root documents or forced me to specify all of them in the projection as well which was not desirable.
So at the end I fixed all of this problems with an $addFields > $filter like this:
db.test.aggregate([
{ $match: { 'shapes.color': 'red' } },
{ $addFields: { 'shapes': { $filter: {
input: '$shapes',
as: 'shape',
cond: { $eq: ['$$shape.color', 'red'] }
} } } },
])
Explanation:
First match documents with a red coloured shape.
For those documents, add a field called shapes, which in this case will replace the original field called the same way.
To calculate the new value of shapes, $filter the elements of the original $shapes array, temporarily naming each of the array elements as shape so that later we can check if the $$shape.color is red.
Now the new shapes array only contains the desired elements.
for more details refer =
mongo db official referance
suppose you have document like this (you can have multiple document too) -
{
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44b"
},
"results": [
{
"yearOfRelease": "2022",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/d/d4/The_Kashmir_Files_poster.jpg",
"title": "The Kashmir Files",
"overview": "Krishna endeavours to uncover the reason behind his parents' brutal killings in Kashmir. He is shocked to uncover a web of lies and conspiracies in connection with the massive genocide.",
"originalLanguage": "hi",
"imdbRating": "8.3",
"isbookMark": null,
"originCountry": "india",
"productionHouse": [
"Zee Studios"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44c"
}
},
{
"yearOfRelease": "2022",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/a/a9/Black_Adam_%28film%29_poster.jpg",
"title": "Black Adam",
"overview": "In ancient Kahndaq, Teth Adam was bestowed the almighty powers of the gods. After using these powers for vengeance, he was imprisoned, becoming Black Adam. Nearly 5,000 years have passed, and Black Adam has gone from man to myth to legend. Now free, his unique form of justice, born out of rage, is challenged by modern-day heroes who form the Justice Society: Hawkman, Dr. Fate, Atom Smasher and Cyclone",
"originalLanguage": "en",
"imdbRating": "8.3",
"isbookMark": null,
"originCountry": "United States of America",
"productionHouse": [
"DC Comics"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44d"
}
},
{
"yearOfRelease": "2022",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/0/09/The_Sea_Beast_film_poster.png",
"title": "The Sea Beast",
"overview": "A young girl stows away on the ship of a legendary sea monster hunter, turning his life upside down as they venture into uncharted waters.",
"originalLanguage": "en",
"imdbRating": "7.1",
"isbookMark": null,
"originCountry": "United States Canada",
"productionHouse": [
"Netflix Animation"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44e"
}
},
{
"yearOfRelease": "2021",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/7/7d/Hum_Do_Hamare_Do_poster.jpg",
"title": "Hum Do Hamare Do",
"overview": "Dhruv, who grew up an orphan, is in love with a woman who wishes to marry someone with a family. In order to fulfil his lover's wish, he hires two older individuals to pose as his parents.",
"originalLanguage": "hi",
"imdbRating": "6.0",
"isbookMark": null,
"originCountry": "india",
"productionHouse": [
"Maddock Films"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44f"
}
},
{
"yearOfRelease": "2021",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/7/74/Shang-Chi_and_the_Legend_of_the_Ten_Rings_poster.jpeg",
"title": "Shang-Chi and the Legend of the Ten Rings",
"overview": "Shang-Chi, a martial artist, lives a quiet life after he leaves his father and the shadowy Ten Rings organisation behind. Years later, he is forced to confront his past when the Ten Rings attack him.",
"originalLanguage": "en",
"imdbRating": "7.4",
"isbookMark": null,
"originCountry": "United States of America",
"productionHouse": [
"Marvel Entertainment"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c450"
}
}
],
"__v": 0
}
=======
mongo db query by aggregate command -
mongomodels.movieMainPageSchema.aggregate(
[
{
$project: {
_id:0, // to supress id
results: {
$filter: {
input: "$results",
as: "result",
cond: { $eq: [ "$$result.yearOfRelease", "2022" ] }
}
}
}
}
]
)
For the new version of MongoDB, it's slightly different.
For db.collection.find you can use the second parameter of find with the key being projection
db.collection.find({}, {projection: {name: 1, email: 0}});
You can also use the .project() method.
However, it is not a native MongoDB method, it's a method provided by most MongoDB driver like Mongoose, MongoDB Node.js driver etc.
db.collection.find({}).project({name: 1, email: 0});
And if you want to use findOne, it's the same that with find
db.collection.findOne({}, {projection: {name: 1, email: 0}});
But findOne doesn't have a .project() method.
Suppose you have the following documents in my collection:
{
"_id":ObjectId("562e7c594c12942f08fe4192"),
"shapes":[
{
"shape":"square",
"color":"blue"
},
{
"shape":"circle",
"color":"red"
}
]
},
{
"_id":ObjectId("562e7c594c12942f08fe4193"),
"shapes":[
{
"shape":"square",
"color":"black"
},
{
"shape":"circle",
"color":"green"
}
]
}
Do query:
db.test.find({"shapes.color": "red"}, {"shapes.color": 1})
Or
db.test.find({shapes: {"$elemMatch": {color: "red"}}}, {"shapes.color": 1})
Returns matched document (Document 1), but always with ALL array items in shapes:
{ "shapes":
[
{"shape": "square", "color": "blue"},
{"shape": "circle", "color": "red"}
]
}
However, I'd like to get the document (Document 1) only with the array that contains color=red:
{ "shapes":
[
{"shape": "circle", "color": "red"}
]
}
How can I do this?
MongoDB 2.2's new $elemMatch projection operator provides another way to alter the returned document to contain only the first matched shapes element:
db.test.find(
{"shapes.color": "red"},
{_id: 0, shapes: {$elemMatch: {color: "red"}}});
Returns:
{"shapes" : [{"shape": "circle", "color": "red"}]}
In 2.2 you can also do this using the $ projection operator, where the $ in a projection object field name represents the index of the field's first matching array element from the query. The following returns the same results as above:
db.test.find({"shapes.color": "red"}, {_id: 0, 'shapes.$': 1});
MongoDB 3.2 Update
Starting with the 3.2 release, you can use the new $filter aggregation operator to filter an array during projection, which has the benefit of including all matches, instead of just the first one.
db.test.aggregate([
// Get just the docs that contain a shapes element where color is 'red'
{$match: {'shapes.color': 'red'}},
{$project: {
shapes: {$filter: {
input: '$shapes',
as: 'shape',
cond: {$eq: ['$$shape.color', 'red']}
}},
_id: 0
}}
])
Results:
[
{
"shapes" : [
{
"shape" : "circle",
"color" : "red"
}
]
}
]
The new Aggregation Framework in MongoDB 2.2+ provides an alternative to Map/Reduce. The $unwind operator can be used to separate your shapes array into a stream of documents that can be matched:
db.test.aggregate(
// Start with a $match pipeline which can take advantage of an index and limit documents processed
{ $match : {
"shapes.color": "red"
}},
{ $unwind : "$shapes" },
{ $match : {
"shapes.color": "red"
}}
)
Results in:
{
"result" : [
{
"_id" : ObjectId("504425059b7c9fa7ec92beec"),
"shapes" : {
"shape" : "circle",
"color" : "red"
}
}
],
"ok" : 1
}
Caution: This answer provides a solution that was relevant at that time, before the new features of MongoDB 2.2 and up were introduced. See the other answers if you are using a more recent version of MongoDB.
The field selector parameter is limited to complete properties. It cannot be used to select part of an array, only the entire array. I tried using the $ positional operator, but that didn't work.
The easiest way is to just filter the shapes in the client.
If you really need the correct output directly from MongoDB, you can use a map-reduce to filter the shapes.
function map() {
filteredShapes = [];
this.shapes.forEach(function (s) {
if (s.color === "red") {
filteredShapes.push(s);
}
});
emit(this._id, { shapes: filteredShapes });
}
function reduce(key, values) {
return values[0];
}
res = db.test.mapReduce(map, reduce, { query: { "shapes.color": "red" } })
db[res.result].find()
Another interesing way is to use $redact, which is one of the new aggregation features of MongoDB 2.6. If you are using 2.6, you don't need an $unwind which might cause you performance problems if you have large arrays.
db.test.aggregate([
{ $match: {
shapes: { $elemMatch: {color: "red"} }
}},
{ $redact : {
$cond: {
if: { $or : [{ $eq: ["$color","red"] }, { $not : "$color" }]},
then: "$$DESCEND",
else: "$$PRUNE"
}
}}]);
$redact "restricts the contents of the documents based on information stored in the documents themselves". So it will run only inside of the document. It basically scans your document top to the bottom, and checks if it matches with your if condition which is in $cond, if there is match it will either keep the content($$DESCEND) or remove($$PRUNE).
In the example above, first $match returns the whole shapes array, and $redact strips it down to the expected result.
Note that {$not:"$color"} is necessary, because it will scan the top document as well, and if $redact does not find a color field on the top level this will return false that might strip the whole document which we don't want.
Better you can query in matching array element using $slice is it helpful to returning the significant object in an array.
db.test.find({"shapes.color" : "blue"}, {"shapes.$" : 1})
$slice is helpful when you know the index of the element, but sometimes you want
whichever array element matched your criteria. You can return the matching element
with the $ operator.
db.getCollection('aj').find({"shapes.color":"red"},{"shapes.$":1})
OUTPUTS
{
"shapes" : [
{
"shape" : "circle",
"color" : "red"
}
]
}
The syntax for find in mongodb is
db.<collection name>.find(query, projection);
and the second query that you have written, that is
db.test.find(
{shapes: {"$elemMatch": {color: "red"}}},
{"shapes.color":1})
in this you have used the $elemMatch operator in query part, whereas if you use this operator in the projection part then you will get the desired result. You can write down your query as
db.users.find(
{"shapes.color":"red"},
{_id:0, shapes: {$elemMatch : {color: "red"}}})
This will give you the desired result.
Thanks to JohnnyHK.
Here I just want to add some more complex usage.
// Document
{
"_id" : 1
"shapes" : [
{"shape" : "square", "color" : "red"},
{"shape" : "circle", "color" : "green"}
]
}
{
"_id" : 2
"shapes" : [
{"shape" : "square", "color" : "red"},
{"shape" : "circle", "color" : "green"}
]
}
// The Query
db.contents.find({
"_id" : ObjectId(1),
"shapes.color":"red"
},{
"_id": 0,
"shapes" :{
"$elemMatch":{
"color" : "red"
}
}
})
//And the Result
{"shapes":[
{
"shape" : "square",
"color" : "red"
}
]}
You just need to run query
db.test.find(
{"shapes.color": "red"},
{shapes: {$elemMatch: {color: "red"}}});
output of this query is
{
"_id" : ObjectId("562e7c594c12942f08fe4192"),
"shapes" : [
{"shape" : "circle", "color" : "red"}
]
}
as you expected it'll gives the exact field from array that matches color:'red'.
Along with $project it will be more appropriate other wise matching elements will be clubbed together with other elements in document.
db.test.aggregate(
{ "$unwind" : "$shapes" },
{ "$match" : { "shapes.color": "red" } },
{
"$project": {
"_id":1,
"item":1
}
}
)
Likewise you can find for the multiple
db.getCollection('localData').aggregate([
// Get just the docs that contain a shapes element where color is 'red'
{$match: {'shapes.color': {$in : ['red','yellow'] } }},
{$project: {
shapes: {$filter: {
input: '$shapes',
as: 'shape',
cond: {$in: ['$$shape.color', ['red', 'yellow']]}
}}
}}
])
db.test.find( {"shapes.color": "red"}, {_id: 0})
Use aggregation function and $project to get specific object field in document
db.getCollection('geolocations').aggregate([ { $project : { geolocation : 1} } ])
result:
{
"_id" : ObjectId("5e3ee15968879c0d5942464b"),
"geolocation" : [
{
"_id" : ObjectId("5e3ee3ee68879c0d5942465e"),
"latitude" : 12.9718313,
"longitude" : 77.593551,
"country" : "India",
"city" : "Chennai",
"zipcode" : "560001",
"streetName" : "Sidney Road",
"countryCode" : "in",
"ip" : "116.75.115.248",
"date" : ISODate("2020-02-08T16:38:06.584Z")
}
]
}
Although the question was asked 9.6 years ago, this has been of immense help to numerous people, me being one of them. Thank you everyone for all your queries, hints and answers. Picking up from one of the answers here.. I found that the following method can also be used to project other fields in the parent document.This may be helpful to someone.
For the following document, the need was to find out if an employee (emp #7839) has his leave history set for the year 2020. Leave history is implemented as an embedded document within the parent Employee document.
db.employees.find( {"leave_history.calendar_year": 2020},
{leave_history: {$elemMatch: {calendar_year: 2020}},empno:true,ename:true}).pretty()
{
"_id" : ObjectId("5e907ad23997181dde06e8fc"),
"empno" : 7839,
"ename" : "KING",
"mgrno" : 0,
"hiredate" : "1990-05-09",
"sal" : 100000,
"deptno" : {
"_id" : ObjectId("5e9065f53997181dde06e8f8")
},
"username" : "none",
"password" : "none",
"is_admin" : "N",
"is_approver" : "Y",
"is_manager" : "Y",
"user_role" : "AP",
"admin_approval_received" : "Y",
"active" : "Y",
"created_date" : "2020-04-10",
"updated_date" : "2020-04-10",
"application_usage_log" : [
{
"logged_in_as" : "AP",
"log_in_date" : "2020-04-10"
},
{
"logged_in_as" : "EM",
"log_in_date" : ISODate("2020-04-16T07:28:11.959Z")
}
],
"leave_history" : [
{
"calendar_year" : 2020,
"pl_used" : 0,
"cl_used" : 0,
"sl_used" : 0
},
{
"calendar_year" : 2021,
"pl_used" : 0,
"cl_used" : 0,
"sl_used" : 0
}
]
}
if you want to do filter, set and find at the same time.
let post = await Post.findOneAndUpdate(
{
_id: req.params.id,
tasks: {
$elemMatch: {
id: req.params.jobId,
date,
},
},
},
{
$set: {
'jobs.$[i].performer': performer,
'jobs.$[i].status': status,
'jobs.$[i].type': type,
},
},
{
arrayFilters: [
{
'i.id': req.params.jobId,
},
],
new: true,
}
);
This answer does not fully answer the question but it's related and I'm writing it down because someone decided to close another question marking this one as duplicate (which is not).
In my case I only wanted to filter the array elements but still return the full elements of the array. All previous answers (including the solution given in the question) gave me headaches when applying them to my particular case because:
I needed my solution to be able to return multiple results of the subarray elements.
Using $unwind + $match + $group resulted in losing root documents without matching array elements, which I didn't want to in my case because in fact I was only looking to filter out unwanted elements.
Using $project > $filter resulted in loosing the rest of the fields or the root documents or forced me to specify all of them in the projection as well which was not desirable.
So at the end I fixed all of this problems with an $addFields > $filter like this:
db.test.aggregate([
{ $match: { 'shapes.color': 'red' } },
{ $addFields: { 'shapes': { $filter: {
input: '$shapes',
as: 'shape',
cond: { $eq: ['$$shape.color', 'red'] }
} } } },
])
Explanation:
First match documents with a red coloured shape.
For those documents, add a field called shapes, which in this case will replace the original field called the same way.
To calculate the new value of shapes, $filter the elements of the original $shapes array, temporarily naming each of the array elements as shape so that later we can check if the $$shape.color is red.
Now the new shapes array only contains the desired elements.
for more details refer =
mongo db official referance
suppose you have document like this (you can have multiple document too) -
{
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44b"
},
"results": [
{
"yearOfRelease": "2022",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/d/d4/The_Kashmir_Files_poster.jpg",
"title": "The Kashmir Files",
"overview": "Krishna endeavours to uncover the reason behind his parents' brutal killings in Kashmir. He is shocked to uncover a web of lies and conspiracies in connection with the massive genocide.",
"originalLanguage": "hi",
"imdbRating": "8.3",
"isbookMark": null,
"originCountry": "india",
"productionHouse": [
"Zee Studios"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44c"
}
},
{
"yearOfRelease": "2022",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/a/a9/Black_Adam_%28film%29_poster.jpg",
"title": "Black Adam",
"overview": "In ancient Kahndaq, Teth Adam was bestowed the almighty powers of the gods. After using these powers for vengeance, he was imprisoned, becoming Black Adam. Nearly 5,000 years have passed, and Black Adam has gone from man to myth to legend. Now free, his unique form of justice, born out of rage, is challenged by modern-day heroes who form the Justice Society: Hawkman, Dr. Fate, Atom Smasher and Cyclone",
"originalLanguage": "en",
"imdbRating": "8.3",
"isbookMark": null,
"originCountry": "United States of America",
"productionHouse": [
"DC Comics"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44d"
}
},
{
"yearOfRelease": "2022",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/0/09/The_Sea_Beast_film_poster.png",
"title": "The Sea Beast",
"overview": "A young girl stows away on the ship of a legendary sea monster hunter, turning his life upside down as they venture into uncharted waters.",
"originalLanguage": "en",
"imdbRating": "7.1",
"isbookMark": null,
"originCountry": "United States Canada",
"productionHouse": [
"Netflix Animation"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44e"
}
},
{
"yearOfRelease": "2021",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/7/7d/Hum_Do_Hamare_Do_poster.jpg",
"title": "Hum Do Hamare Do",
"overview": "Dhruv, who grew up an orphan, is in love with a woman who wishes to marry someone with a family. In order to fulfil his lover's wish, he hires two older individuals to pose as his parents.",
"originalLanguage": "hi",
"imdbRating": "6.0",
"isbookMark": null,
"originCountry": "india",
"productionHouse": [
"Maddock Films"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c44f"
}
},
{
"yearOfRelease": "2021",
"imagePath": "https://upload.wikimedia.org/wikipedia/en/7/74/Shang-Chi_and_the_Legend_of_the_Ten_Rings_poster.jpeg",
"title": "Shang-Chi and the Legend of the Ten Rings",
"overview": "Shang-Chi, a martial artist, lives a quiet life after he leaves his father and the shadowy Ten Rings organisation behind. Years later, he is forced to confront his past when the Ten Rings attack him.",
"originalLanguage": "en",
"imdbRating": "7.4",
"isbookMark": null,
"originCountry": "United States of America",
"productionHouse": [
"Marvel Entertainment"
],
"_id": {
"$oid": "63b5cfbfbcc3196a2a23c450"
}
}
],
"__v": 0
}
=======
mongo db query by aggregate command -
mongomodels.movieMainPageSchema.aggregate(
[
{
$project: {
_id:0, // to supress id
results: {
$filter: {
input: "$results",
as: "result",
cond: { $eq: [ "$$result.yearOfRelease", "2022" ] }
}
}
}
}
]
)
For the new version of MongoDB, it's slightly different.
For db.collection.find you can use the second parameter of find with the key being projection
db.collection.find({}, {projection: {name: 1, email: 0}});
You can also use the .project() method.
However, it is not a native MongoDB method, it's a method provided by most MongoDB driver like Mongoose, MongoDB Node.js driver etc.
db.collection.find({}).project({name: 1, email: 0});
And if you want to use findOne, it's the same that with find
db.collection.findOne({}, {projection: {name: 1, email: 0}});
But findOne doesn't have a .project() method.
So I have some query to database (mongodb) which will order results by value field.
all := EValues{}
err := con.Find(bson.M{"name": "somename}).Sort("-value").All(&all)
Json output for this looks like:
"values": [
{
"user_name": "guest7485",
"value": 8911,
"value_date": "2016-03-09T14:40:34.512Z"
},
{
"user_name": "guest7485",
"value": 539,
"value_date": "2016-03-07T14:11:05.217Z"
},
{
"user_name": "guest7485",
"value": 221,
"value_date": "2016-03-07T14:11:08.853Z"
},
{
"user_name": "guest7485",
"value": 77,
"value_date": "2016-03-07T14:11:12.377Z"
}
]
In my json response I need to add parameter "position" which should be basically equal to 1 - first result, 2 - second result and so on, for all results. So my final output should be:
"values": [
{
"position": 1,
"user_name": "guest7485",
"value": 8911,
"value_date": "2016-03-09T14:40:34.512Z"
},
{
"position": 2,
"user_name": "guest7485",
"value": 539,
"value_date": "2016-03-07T14:11:05.217Z"
},
{
"position": 3,
"user_name": "guest7485",
"value": 221,
"value_date": "2016-03-07T14:11:08.853Z"
},
{
"position": 4,
"user_name": "guest7485",
"value": 77,
"value_date": "2016-03-07T14:11:12.377Z"
}
]
I'm wondering how to solve this with mgo and go in general, and I would be really greatfull if someone can give me the most efficient way to solve this.
Update:
Definition of Evalues is bellow:
type EValue struct {
ID bson.ObjectId `json:"-" bson:"_id,omitempty"`
Name string `json:"-" bson:"name"`
UserId bson.ObjectId `json:"-" bson:"userId"`
UserName string `json:"user_name" bson:"userName"`
Value int64 `json:"value" bson:"value"`
AddedTime time.Time `json:"value_date" bson:"addedTime"`
}
type EValues []EValue
Add a position field to EValue:
type EValue struct {
... other fields here
Position int `json:"position" bson:"-"`
}
Loop through db results and set the field:
for i := range all {
all[i].Position = i + 1
}
Marshal the result as JSON.
With MongDB 3.2 this can be done using the $unwind operator where you can pass an object with the field path and the field includeArrayIndex which will hold the array index:
pipeline = [
{ "$match": {"name": "somename"} },
{ "$unwind": { "path": "$values", "includeArrayIndex": "position" } },
{
"$project": {
"name": 1,
"newarray.position": "$position",
"newarray.user_name": "$values.user_name",
"newarray.value_date": "$values.value_date",
"newarray.value": "$values.value",
}
},
{
"$group": {
"_id": "$name",
"values": { "$push": "$newarray" }
}
}
]
db.test.aggregate(pipeline);
Output
> db.test.aggregate(pipeline).pretty();
{
"_id" : "somename",
"values" : [
{
"position" : NumberLong(0),
"user_name" : "guest8911",
"value_date" : "2016-03-09T14:40:34.512Z",
"value" : 8911
},
{
"position" : NumberLong(1),
"user_name" : "guest7485",
"value_date" : "2016-03-07T14:11:05.217Z",
"value" : 539
},
{
"position" : NumberLong(2),
"user_name" : "guest7485",
"value_date" : "2016-03-07T14:11:08.853Z",
"value" : 221
},
{
"position" : NumberLong(3),
"user_name" : "guest7485",
"value_date" : "2016-03-07T14:11:12.377Z",
"value" : 77
}
]
}
>
If this is not supported with the mgo driver, then a not so efficient approach would be to use Map-Reduce for this. The following mongo shell example demonstrates how you can run the operation:
Populate test collection:
db.test.insert({
"name": "somename",
"values": [
{
"user_name": "guest8911",
"value": 8911,
"value_date": "2016-03-09T14:40:34.512Z"
},
{
"user_name": "guest7485",
"value": 539,
"value_date": "2016-03-07T14:11:05.217Z"
},
{
"user_name": "guest7485",
"value": 221,
"value_date": "2016-03-07T14:11:08.853Z"
},
{
"user_name": "guest7485",
"value": 77,
"value_date": "2016-03-07T14:11:12.377Z"
}
]
})
Run the following map-reduce operation:
> mr = db.runCommand({
"mapreduce": "test",
"map": function() {
var arr = []
for(var i=0; i < this.values.length; i++){
var val = this.values[i];
val["position"] = i+1;
arr.push(val);
}
emit(this._id, arr);
},
"reduce" : function() {},
"out": "test_keys"
})
Query resulting collection:
> db[mr.result].find().pretty()
{
"_id" : ObjectId("56e18ab84b9018ec86d2a6bd"),
"value" : [
{
"user_name" : "guest8911",
"value" : 8911,
"value_date" : "2016-03-09T14:40:34.512Z",
"position" : 1
},
{
"user_name" : "guest7485",
"value" : 539,
"value_date" : "2016-03-07T14:11:05.217Z",
"position" : 2
},
{
"user_name" : "guest7485",
"value" : 221,
"value_date" : "2016-03-07T14:11:08.853Z",
"position" : 3
},
{
"user_name" : "guest7485",
"value" : 77,
"value_date" : "2016-03-07T14:11:12.377Z",
"position" : 4
}
]
}
>
Now given the listing above, you can assemble your query in mgo using MapReduce
job := mgo.MapReduce{
Map: "function(){var arr=[];for(var i=0;i<this.values.length; i++){var val=this.values[i];val['position']=i+1;arr.push(val);};emit(this._id,arr);}",
Reduce: "function() { }",
}
var result []struct { Id int "_id"; Value []EValue }
_, err := collection.Find(nil).MapReduce(job, &result)
if err != nil {
panic(err)
}
for _, item := range result {
fmt.Println(item.Value)
}
For more details, check the documentation: https://godoc.org/labix.org/v1/mgo#MapReduce: