I'll get right into my problem. So basically what I want to do is to generate an array of random numbers of different amounts. So one with 10,000, 50,000, 100,000, 500,000, 600,000, etc. Then I would sort them using quicksort and print the sorted array to the screen. Additionally, the time taken for it to run would be recorded and printed as well. The only part I'm having problems with however is generating the array. For some reason generating past 500,000 random numbers does not work and returns this:
Process exited after 2.112 seconds with return value 3221225725
Press any key to continue . . .
([1]: https://i.stack.imgur.com/m83el.png)
This is my code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void randNums(int array[], int range) {
int i, num;
for (i = 0; i < range; i++) {
num = rand() % range;
array[i] = num;
}
}
//prints elements of given array
void display(int array[], int size) {
int i;
for (i = 0; i < size; i++) {
printf("#%d. %d\n", i, array[i]);
}
}
//displays time taken for sorting algorithm to run
void timeTaken(char sortingAlgo[], int size, clock_t start, clock_t end) {
double seconds = end - start;
double milliseconds = seconds / 1000;
printf("Time taken for %s Sort to sort %d numbers was %f milliseconds or %f seconds",
sortingAlgo, size, milliseconds, seconds);
}
//quick sort
void quickSort(int array[], int first, int last) {
int i, j, pivot, temp;
if (first < last) {
pivot = first;
i = first;
j = last;
while (i < j) {
while (array[i] <= array[pivot] && i < last)
i++;
while (array[j] > array[pivot])
j--;
if (i < j) {
temp = array[i];
array[i] = array[j];
array[j] = temp;
}
}
temp = array[pivot];
array[pivot] = array[j];
array[j] = temp;
quickSort(array, first, j - 1);
quickSort(array, j + 1, last);
}
}
int main() {
int size = 600000;
int myArray[size];
time_t end, start;
int first, last;
randNums(myArray, size);
first = myArray[0];
last = sizeof(myArray) / sizeof(myArray[0]);
time(&start);
quickSort(myArray, first, last);
time(&end);
display(myArray, size);
timeTaken("Quick", size, start, end);
return 0;
}
Any help would be greatly appreciated, Thank you!
There's a lot of little bugs in this code that aren't too difficult to resolve. I'll try and break it down here in this refactoring and cleanup:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void randNums(int* array, int range) {
// Declare iterator variables like `i` within the scope of the iterator.
for (int i = 0; i < range; i++) {
// No need for a single-use variable here, just assign directly.
array[i] = rand () % range;
}
}
void display(int* array, int size) {
// for is not a function, it's a control flow mechanism, so
// it is expressed as `for (...)` with a space. `for()` implies
// it is a function, which it isn't.
for (int i = 0; i < size; i++) {
printf("#%d. %d\n", i, array[i]);
}
}
void timeTaken(char* sortingAlgo, int size, clock_t start, clock_t end) {
// Time calculation here needs to account for the fact that clock_t
// does not use seconds as units, it must be converted
// https://en.cppreference.com/w/c/chrono/clock_t
printf(
"Time taken for %s Sort to sort %d numbers was %.6f seconds",
sortingAlgo,
size,
((double) (end - start)) / CLOCKS_PER_SEC
);
}
void quickSort(int* array, int first, int last) {
// Establish a guard condition. Rest of the function is no longer
// nested in a control flow structure, so it simplifies the code.
if (first >= last) {
return;
}
int pivot = first;
int i = first;
int j = last;
// Use `while (...)` as it's also a control flow structure.
while (i < j) {
// Adding space around operators improves clarity considerably. Unspaced
// elements like `a->b()` are supposed to stand out and not be confused
// with visually similar `a>>b()` which does something very different.
while (array[i] <= array[pivot] && i < last) {
i++;
}
// Use surrounding braces on all blocks, even single-line ones, as this
// can avoid a whole class of errors caused by flawed assumptions.
// while (...) { ... }
while (array[j] > array[pivot]) {
j--;
}
if (i < j) {
int temp = array[i];
array[i] = array[j];
array[j] = temp;
}
}
int temp = array[pivot];
array[pivot] = array[j];
array[j] = temp;
quickSort(array, first, j - 1);
quickSort(array, j + 1, last);
}
int main(int argc, char** argv) {
int size = 600000;
// If an argument was given...
if (argc > 1) {
// ...use that as the size parameter instead.
size = atol(argv[1]);
}
// Allocate an array of sufficient size
int* numbers = calloc(size, sizeof(int));
randNums(numbers, size);
// time_t has at best second-level precision, it's very inaccurate.
// Use clock_t which gives far more fidelity.
clock_t start = clock();
// This function takes *offsets*, not values.
quickSort(numbers, 0, size - 1);
clock_t end = clock();
display(numbers, size);
timeTaken("Quick", size, start, end);
free(numbers);
return 0;
}
The number one bug here was calling quickSort() incorrectly:
// Represents first *value* in the array
first = myArray[0]; // Should be: 0
// Rough calculation of the size of the array, but this is off by one
last = sizeof(myArray)/sizeof(myArray[0]); // Should be: size - 1
quickSort(myArray, first, last);
Related
I'm trying this exercice but I don't know how to printf my function in main.
Exercice:
1) Write a function who returning an int tab with all values between min and max
#include <stdlib.h>
#include <stdio.h>
int *ft_range(int min, int max)
{
int len;
int *tab;
len = min;
while (len < max)
len++;
tab = (int *)malloc(sizeof(*tab) * len + 1);
while (min < max)
{
*tab = min;
min++;
}
return(tab);
}
int main()
{
ft_range(0, 10);
return(0);
}
returning an int tab with all values between min and max
Depending on the idea of "between", it is an open question if the end values should be included. Given OP's mis-coded +1 in sizeof(*tab) * len + 1, I'll go with the idea both ends should be included.
Miscalculation of len
Rather than loop, simply subtract
//len = min;
//while (len < max)
// len++;
len = max - min + 1;
Allocation miscalculated
Good to use sizeof *pointer, yet the + 1 makes little sense. If anything the ... * len + 1 should have been ... * (len + 1). Yet the +1 is handled with the above fix. Also cast not needed in C.
// tab = (int *)malloc(sizeof(*tab) * len + 1);
tab = malloc(sizeof *tab * len);
Wrong assignment
Code repeatedly assigned the same *tab location.
//while (min < max)
//{
// *tab = min;
// min++;
//}
for (int i = min; i <= max; i++) {
tab[i - min] = i;
}
No allocation error checking nor min, max validation
Potential for int overflow with mix - min
Be sure to free allocations
Alternative
#include <stdlib.h>
#include <stdio.h>
int *ft_range(int min, int max) {
if (min > max) {
return NULL;
}
size_t len = (size_t)max - min + 1;
int *tab = malloc(sizeof *tab * len);
if (tab == NULL) {
return NULL;
}
for (size_t i = 0; i < len; i++) {
tab[i] = int(min + i);
}
return tab;
}
int main() {
int mn = 0;
int mx = 10;
int *ft = ft_range(mn, mx);
if (ft) {
int *p = ft;
for (int i = mn; i <= mx; i++) {
printf("%d ", *p++);
}
free(ft);
}
return 0;
}
inside "ft_range", when you are trying to calculate the length the array needs to do, all you have to do is subtract the minimum from the maximum. what you did is much slower and unnecessary.
when allocating memory, you did not need to add a "+1" at the end. you may have seen it done in other examples, but it does not apply here.
the "while" loop inside "ft_range" needs to have a "<=" sign, otherwise it will stop before it reaches the "max" value.
when adding a value to the "tab" int array, you are always doing so by dereferencing it (putting a "*" before it), so every one of your values will come on the first position of the array and overwrite themselves. you need to have another "int i" to keep track of the current index of the array.
make sure to free the memory you allocated with "malloc" after you finish your enumeration. it does not matter right now, but if you ever get to writing more complex programs you will need to do so to keep the performance up, which can be critical.
here's a working code, with a few comments (i'm shit at comments, if you don't understand them, just ask me bro)
#include <stdlib.h>
#include <stdio.h>
int *ft_range(int min, int max)
{
int len;
int * tab;
len = max-min;
tab = (int *)malloc(sizeof(*tab) * len);
// create an index to track the position inside "tab"
int i = 0;
// sign needs to be "<=" so it does not stop before it reaches the max value
while (min <= max)
{
tab[i] = min;
// ++ needs to come before so the variable's value is updated right here
++min;
// increase the i index to the next position in "tab"
++i;
}
return(tab);
}
int main()
{
int min = 5;
int max = 10;
int len = max-min;
int * range = ft_range(min, max);
for(int i = 0; i <= len; ++i)
{
// %d = integer
// \n = move to next line
printf("%d\n", range[i]);
}
getchar();
return(0);
}
You correctly allocate memory to the table, you just need to printf the value in your main by using a loop trough your tab, i write this code who work perfectly.
#include <stdlib.h>
int *ft_range(int min, int max)
{
int *ptr;
int mi;
int i;
int range;
range = (max - min);
mi = min;
ptr = NULL;
if (min > max)
return (NULL);
else
ptr = malloc(sizeof(int) * range);
i = 0;
while (i < range)
{
ptr[i] = mi + i;
i++;
}
return (ptr);
}
// #include <stdio.h>
// int main()
// {
// //int i = 0;
// int min = 1;
// int max = 30;
// while(min < max)
// {
// printf("%d\n", *ft_range(min, max));
// min++;
// }
// }
I'm doing quick sorting with different methods of selecting pivots, I don't see any problems in my code, the functions work while testing separated, but when I put them together, they don't work most of the time.
I've tried moving the files to another path, and changing the way I access the array.
void quick_sort(uint32_t arr[], int first, int last, int pivot_opt)
{
int i, j;
uint32_t pivot = pivot_select(arr, last, pivot_opt);
i = first;
j = last;
do
{
comparations_count++;
while (arr[i] < pivot) i++; // Counting elements smaller than pivot
comparations_count++;
while (arr[j] > pivot) j--; // Counting elements greater than pivot
comparations_count++;
if (i <= j)
{
exchanges_count++;
swap(&arr[i++], &arr[j--]); // Placing smaller elements in the left, and greater elements in the right without touching the pivot
}
comparations_count++;
} while (i <= j);
comparations_count++;
if (first < j)
quick_sort(arr, first, j, pivot_opt); // Sorting smaller elements of array
comparations_count++;
if (i < last)
quick_sort(arr, i, last, pivot_opt); // Sorting greater elements of array
}
uint32_t pivot_select(uint32_t arr[], int last, int pivot_opt)
{
uint32_t pivot = 0;
int random_index = 0;
switch (pivot_opt)
{
case 0:
pivot = arr[last]; // Choosing the pivot as the last element in the array
break;
case 1:
random_index = rand()%(last); // Choosing the pivot as a random element of array
pivot = arr[random_index];
break;
case 2:
pivot = median(arr, last); // Choosing the pivot as avg of three random indexes of the array
break;
default:
break;
}
return pivot;
}
uint32_t median(uint32_t arr[], int n)
{
if (n <= 3)
{
return arr[0]; // If the array have 3 or less elements, choose as pivot first element
}
else
{
int index[3] = {0}; // Index of 3 elements of original array
int last_index = 0; // Last chosen index, to verify if index was selected
int i = 0;
while(i < 3) // Selecting 3 random index
{
int current_index = (rand()%(n));
if (current_index == last_index)
i--;
else
{
index[i++] = current_index;
last_index = current_index;
}
}
uint32_t array[3] = {arr[index[0]], arr[index[1]], arr[index[2]]}; // Creating array with the elements on random indexes
insertion_sort(array, 3); // Sorting the array
return array[1]; // Returning the pivot as the middle element of array
}
}
I'm getting this error on median function
Program received signal SIGSEGV, Segmentation fault.
0x0000555555555546 in median (arr=<error reading variable: Cannot access memory at address 0x7fffff7fefd8>, n=<error reading variable: Cannot access memory at address 0x7fffff7fefd4>) at /media/storage/Codes/Data Structure/Recursive_Sorting/main.c:107
107 {
I put all the libraries I'm using so I don't miss one.
Code for testing:
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <sys/time.h>
#include <time.h>
#define size 1000
uint32_t comparations_count;
uint32_t exchanges_count;
int main(int argc, char** argv)
{
uint32_t array[size];
fill(array, size);
permute_array(array, size);
comparations_count = 0;
exchanges_count = 0;
quick_sort(array, 0, size-1, 2);
return 0;
}
void fill(uint32_t arr[], uint32_t n)
{
for (size_t i = 0; i < n; i++) // Filling the array in ascending order
arr[i] = i;
}
void swap(uint32_t *a, uint32_t *b)
{
// Swapping two elements
uint32_t t = *a;
*a = *b;
*b = t;
}
void permute_array(int a[], size_t n)
{
// Adapted from:
// https://www.geeksforgeeks.org/shuffle-a-given-array-using-fisher-yates-shuffle-algorithm/
srand(time(NULL)); // Init random seed
for (size_t i = n - 1; i > 0; i--) // Permute array
{
size_t j = rand() % (i+1); // Pick a random index from 0 to i
swap(&a[i], &a[j]); // Swap arr[i] with the element at random index
}
}
void insertion_sort(uint32_t arr[], size_t n)
{
uint32_t current_index = 0;
uint32_t current_value = 0;
for (size_t i = 1; i < n; i++) {
current_index = i;
current_value = arr[i];
while (current_index > 0) {
if (current_value < arr[current_index - 1]) {
swap(&arr[current_index], &arr[current_index-1]);
current_index--;
}else { break; }
}
}
}
Let's start with this one:
while (arr[i] < pivot) i++;
What if all the elements are less than pivot, your i will be out of bounds, change the condition to while(arr[i] < pivot && i <= j) i++;
Consider this one:
while (arr[j] > pivot) j--;
What if all the elements are greater than pivot, your j will be out of bounds (a negative number), change the condition here too.
According to my opinion, the above-mentioned areas are causing problems.
Happy debugging!
I'm a French student and trying to calculate the execution time of the Merge Sort algorithm for different size of array.
I also want to write the different execution time in a .csv file. But when my program tries to sort an array with 1 million elements the process returns -1073741571 (0xC00000FD) in Code::Blocks. So if you could point me to a way to find a solution I would be very grateful!
Here is my code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
void genTab(int *tab, int n) {
int i;
for (i = 0; i < n; i++) {
tab[i] = rand() % 100;
}
}
void fusion(int *tab, int deb, int mid, int fin) {
int i = deb;
int j = mid + 1;
int k = deb;
int temp[fin + 1];
while ((i <= mid) && (j <= fin)) {
if (tab[i] <= tab[j]) {
temp[k] = tab[i];
i++;
} else {
temp[k] = tab[j];
j++;
}
k++;
}
while (i <= mid) {
temp[k] = tab[i];
i++;
k++;
}
while (j <= fin) {
temp[k] = tab[j];
k++;
j++;
}
for (i = deb; i <= fin; i++) {
tab[i] = temp[i];
}
}
void triFusion(int *tab, int i, int j) {
if (i < j) {
triFusion(tab, i, (int)((i + j) / 2));
triFusion(tab, (int)((i + j) / 2 + 1), j);
fusion(tab, i, (int)((i + j) / 2), j);
}
}
void reset(int *tab1, int *tab2, int n) {
for (int i = 0; i < n; i++) {
tab2[i] = tab1[i];
}
}
int main() {
srand(time(NULL));
clock_t start, end;
int nbrTest[15] = {
1000, 5000, 10000, 50000, 80000, 100000, 120000, 140000,
150000, 180000, 200000, 250000, 300000, 450000, 1000000
};
FILE *fp;
char *tpsExecution = "exeTime.csv";
fp = fopen(tpsExecution, "w");
fprintf(fp, "Array Size; Merge Time");
for (int i = 0; i < 15; i++) {
int n = nbrTest[i];
printf("Calculating time for an array of %d \n", n);
int *tab = malloc(sizeof(int) * n);
genTab(tab, n);
int *copie = malloc(sizeof(int) * n);
reset(tab, copie, n);
start = clock();
triFusion(tab, 0, n - 1);
end = clock();
float tpsFusion = (float)(end - start) / CLOCKS_PER_SEC;
reset(tab, copie, n);
printf("writing in the file\n");
fprintf(fp, "\n%d;%f", n, tpsFusion);
free(tab);
free(copie);
}
fclose(fp);
return 0;
}
int temp[fin+1]; may exceed the space limit for the stack. You should allocate it with malloc instead, and free it with free.
If you want to exclude malloc and free from the timed code, the allocation could be performed outside the timed code and passed in as work space.
(Note: posted after the answer from #Eric Postpischil).
The function
void fusion(int * tab, int deb, int mid, int fin)
Has the line
int temp[fin+1];
and the value of fin comes through another function from the number of elements n to be sorted
triFusion(tab, 0, n-1);
and as an automatic variable, breaks the stack when n is large.
I suggest replacing the line with
int *temp = malloc((fin+1) * sizeof *temp);
if(temp == NULL) {
puts("malloc");
exit(1);
}
// ...
free(temp);
fusion() is always allocating the full size of the array for temp, even when only a small fraction of temp is being used. You could change this to:
int k = 0;
...
int temp[fin+1-deb];
...
tab[i]=temp[i-deb];
still this will exceed stack space if n is large. So as suggested in the other answers:
int k = 0;
...
int *temp = malloc((fin+1-deb)*sizeof(int));
...
tab[i]=temp[i-deb];
...
free(temp)
or better still, do a one time allocation of a second array in main or in a "helper" function, the include a pointer to the second array in the merge sort functions.
I am writing this C/C++ program that is suppose to find the mean, median, and mode of a varied size array. Although, I keep getting a Segmentation Fault regardless of the input. What is wrong with my code? Any suggestions always appreciated! :)
Here is the code:
#include <stdio.h>
//#include <string.h>
//#include <math.h>
#include <stdlib.h>
Prototypes:
void sort(double*[],int);
static int min(double,double[],int);
double mean(double[],int);
double median(double[],int);
double mode(double[],int);
int numberOf(double,double[],int);
Main Function:
int main() {
int i;
scanf(" %d ",&i); //10
double arr[i]; //array that contains all the values and will be sortted
for (int j=0; j<i; j++) { //64630 11735 14216 99233 14470 4978 73429 38120 51135 67060
scanf(" %lf ",&arr[j]);
}
printf("%.1lf\n%.1lf\n%.0lf",mean(arr,i),median(arr,i),mode(arr,i));
return 0;
}
Sort Function:
The end result should update the array arr from the call in the Median Function. Changes the used values in the original array to -1 until that is the entire array.
void sort(double* arr[],int l) {
double arr2[l];
for (int i=0; i<l; i++) {
int j;
if (i)
j = min(arr2[i-1], *arr, l);
else
j = min(0, *arr, l);
arr2[i] = *arr[j];
*arr[j] = -1;
}
for (int i=0; i<l; i++) {
*arr[i] = arr2[i];
}
}
Min Function (helper function for the Sort Function):
Finds the minimum value amongst the array elements that is greater than or equal to minLookingTo
Returns the position the value is in.
static int min(double minLookingTo,double arr[],int l) {
int minP;
double minA = minLookingTo;
for (int i=0; i<l; i++) {
if (arr[i] == -1)
continue;
if (minLookingTo<=arr[i] && arr[i]<=minA) {
minP = i;
minA = arr[i];
}
}
return minP;
}
Mean Function:
Returns the mean of the inputted array with the length l
double mean(double arr[],int l){
double total = 0;
for (int i=0; i<l; i++) {
total += arr[i];
}
return total/l;
}
Median Function:
Uses the Sort Function. Assuming that works, returns the median.
double median(double arr[],int l){
sort(&arr,l);
double d = arr[(l/2)+1];
double dd = arr[(l/2)];
if (l%2!=0)
return d;
return (d+dd)/2;
}
Mode Function:
Uses the NumberOf Function to determine the array element with the maximum amount of repeats. Returns the lowest value of the highest (equal) repeats.
double mode(double arr[],int l){
int maxA;
int maxP;
for (int i=0;i<l;i++) {
int j = numberOf(arr[i],arr,l);
if (j>maxA) {
maxA = j;
maxP = i;
}
else if (j==maxA && arr[maxP]>arr[i])
maxP = i;
}
double d = arr[maxP];
return d;
}
NumberOf Function:
Helper function for the Mode Function. Returns the amount of elements with the looking value.
int numberOf(double looking,double arr[],int l) {
int amount = 0;
for (int i=0; i<l; i++)
if (looking == arr[i])
amount++;
return amount;
}
I tracked your segmentation fault to your sort() routine called by median(). Rather than fix sort(), I substituted qsort() from the library to convince myself that's the problem:
// Median Function:
// Uses the Sort Function. Assuming that works, returns the median.
int comparator(const void *p, const void *q) {
double a = *((double *) p);
double b = *((double *) q);
return (a > b) - (a < b); // compare idiom
}
double median(double array[], int length) {
// sort(array, length);
qsort(array, length, sizeof(double), &comparator);
double d = array[length / 2];
if (length % 2 != 0) {
return d;
}
double dd = array[(length / 2) - 1];
return (d + dd) / 2;
}
For the example list of numbers provided, after correcting the rest of the code, this returns a median of 44627.5
Other fixes:
You're missing a final newline here:
printf("%.1lf\n%.1lf\n%.0lf",mean(arr,i),median(arr,i),mode(arr,i));
You should probably initialize the variables in mode():
double mode(double array[], int length) {
int maxA = INT_MIN;
int maxP = -1;
for (int i = 0; i < length; i++) {
int j = numberOf(array[i], array, length);
if (j > maxA) {
maxA = j;
maxP = i;
} else if (j == maxA && array[maxP] > array[i]) {
maxP = i;
}
}
return array[maxP];
}
Your code has a series of errors. Some of them:
You donĀ“t need (in this case) to use spaces in scanf. This is causing a reading error.
You don't need to pass an array address to a function in order to alter its values. Arrays are always passed by reference. So change your function from void sort(double*[],int); to void sort(double[],int);, make the necessary corrections inside the function and call it using sort(arr,l); instead of sort(&arr,l);
Your min() function declares an uninitialized variable minP, so this variable contains garbage from your memory. The for() loop isn't entering none of the both if() conditions, so your function ends and returns the still uninitialized variable minP. This random value is then used to access an index in your array: j = min(0, arr, l); min returns an random number and then arr2[i] = arr[j]; accessing forbidden memory region, which is causing your segmentation fault error. The same problem is occurring with the variables maxP and maxA in the mode() function.
You must always be careful when accessing your arrays to not go beyond its bounds and always be sure that variables will be initialized when using them. And as others have commented, I also highly recommend you to learn how to debug your programs, since this will help you to analyze its execution and trace bugs.
I'm working on a C implementation as an exercise (I'm a student). I have the logic fine (I've used the implementation itself before), but I get a segfault when actually running it. I've looked for a long time, and I can't understand what's causing it. Here is my complete code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define ARRAY_CAPACITY 50
void do_sort(int* list);
void merge_sort(int* list_of, int* buffer_of, int start, int end);
void do_sort(int* list)
{
int capacity = ((ARRAY_CAPACITY) / 2);
int buffer[capacity];
merge_sort(list, buffer, 0, ARRAY_CAPACITY);
}
void merge_sort(int* list_of, int* buffer_of, int start, int end)
{
printf("%s", "hi!");
int i, t;
if((end - start) < 2) return;
int mid = (start + end) / 2;
merge_sort(list_of, buffer_of, start, mid);
merge_sort(list_of, buffer_of, mid, end);
int left = 0;
int right = mid;
for(i = 0; i < ARRAY_CAPACITY; i++)
{
buffer_of[i] = list_of[i];
}
for(t = start; t < end; t++)
{
if((left < (mid - start)) && (right == end || buffer_of[left] < list_of[right]))
{
list_of[t] = buffer_of[left];
left++;
}
else
{
list_of[t] = list_of[right];
right++;
}
}
}
int main()
{
srand(time(NULL));
int number_array[ARRAY_CAPACITY];
int i;
for(i = 0; i < ARRAY_CAPACITY; i++)
{
number_array[i] = (rand() % 100);
}
printf("%d\n", number_array[3]);
int j, m;
printf("%s\n", "Pre-Sorted Array: ");
for(j = 0; j < ARRAY_CAPACITY; j++)
{
printf("%d ", number_array[j]);
}
do_sort(number_array);
for(m = 0; m < ARRAY_CAPACITY; m++)
{
printf("%d ", number_array[m]);
}
printf("\n");
}
The output is as follows:
50 (this is a random number, but it always prints successfully)
Pre-Sorted Array:
Segmentation fault
So the segfault triggers when I try to loop to print the pre sorted array, but I've just proven that the array values were properly set, so I can't fathom this error. Help?
You have the following code:
void merge_sort(int* list_of, int* buffer_of, int start, int end)
{
...
for(i = 0; i < ARRAY_CAPACITY; i++)
{
buffer_of[i] = list_of[i];
}
...
That code will get called, at one point, with the following arguments:
list_of is an array of 50 integers.
buffer_of is an array of 25 integers.
start is 0.
end is 50.
You will copy 50 elements of list_of into buffer_of, but buffer_of has only room for 25 elements.