printing integer and char using the same argument in c - c

Question

I have an assignment to implement a board game. I come up with an idea to print integer and char using the same statement for example,
int main() {
char c[2];
c[0]=1;
c[1]='X';
for (int i = 0;i<=1;++i) {
printf("%d", c[i]);
}
return 0;
}
this is not working as I have integer and char in the array. how could i modify this to just use one for loop?
EDIT:
I am trying to implement a noughts and crosses game. So I display my board as
1 2 3
4 5 6
7 8 9
and whenever a player put down a X or O at a position, I want to display my board for example,
1 X 3
4 5 6
7 8 9

Answer 1

You can just print chars. Since your digits are always 1 to 9 you can use chars '1' to '9' (49 to 57) instead.
It's not exactly a code you'd be writing in production, but it's a nice case of a little puzzle and what you can do with C.
int main() {
char c[2];
c[0]='1';
c[1]='X';
for (int i = 0;i<=1;++i) {
printf("%c", c[i]);
}
return 0;
}
I've slightly modified your code to make it clear how that might work.

Answer 2

Your code won't work as intended as you're mixing up two distinct data types. int and char are not the same type of element. They don't even have the same size; the size of char is defined as 1, and the size of int varies by implementation, but is usually 4 or 8. So your array will not even be able to hold ints. When you say:
c[0] = 1;
what is actually happening is that the array stores the char with the ASCII value of 1, which is the "Start of Heading" character.
To do what you want, do not use the int type at all. Use char throughout. That is, write something like this:
c[0] = '1';
Putting the '1' in single quotes makes it a char, not an int. You can use this to fill your 2D array and then make replacements with 'X' and '0' when needed.

Answer 3

You're doing to mistakes here.
You're using c[0]=1; instead of c[0]='1';. You want the character 1 and not the number 1.
You're using printf("%d instead of printf("%c. You want to print a character and not a number.
Here is some example code to achieve what you want:
void print_board(char *board) {
for(int i=0; i<9; i++) {
printf("%c ", board[i]);
if(i % 3 == 2)
printf("\n");
}
printf("\n");
}
void init_board(char *board) {
for(int i=0; i<9; i++)
board[i] = '1' + i;
}
int main(void) {
char board[9];
init_board(board);
print_board(board);
board[2] = 'X';
print_board(board);
board[5] = 'O';
print_board(board);
init_board(board);
print_board(board);
}
The above is not really production code. But it's enough to get you going.
Output:
$ ./a.out
1 2 3
4 5 6
7 8 9
1 2 X
4 5 6
7 8 9
1 2 X
4 5 O
7 8 9
1 2 3
4 5 6
7 8 9