list to bytes conversion on python - arrays

Question

I have a list with the following values:
l = [205, 1, 239, 215, 48]
when I convert it with bytes by doing
byte_l = bytes(l)
print(byte_l)
gives:
b'\xcd\x01\xef\xd70'
but I want it to return
b'\xcd\x01\xef\xd7\x30'
when i do
byte_l == b'\xCD\x01\xEF\xD7\x30'
it returns True
What is going on here?
And how do I get it to return what I want it to?

Answer 1

You are seeing the ASCII representation of the bytes the print can interpret. Your last number is 48, whose utf representation is 0. Try this:
x = bytearray(b'\x30')
print(x)
You get:
bytearray(b'0')
If you look at the last character of your print, just after \xd7 (i.e., 215) there is 0, that is the representation of 48 (30 in hexadecimal) in ASCII code.
If you try with this code:
l = [47, 48, 49, 50, 51, 52]
byte_l = bytes(l)
print(byte_l)
this is what you get:
b'/01234'
All bytes were interpreted as ASCII codes.
If you want to print the content of the bytes bypassing the ASCII interpretation, you can use something like this:
print(''.join(['\\x{:02x}'.format(x) for x in byte_l]))
If byte_l = bytes([47, 48, 49, 50, 51, 52]) it gives:
\x2f\x30\x31\x32\x33\x34
while in your case (byte_l = bytes([205, 1, 239, 215, 48])), it prints:
\xcd\x01\xef\xd7\x30