Check if an array is mirrored in C - arrays

Question

I'm trying to check if the inputted array of the user is mirrored or not
Users input:
//for the rows and column
3 3
//elements inside array
1 0 1
2 0 3
4 0 4
the output should tell if the first index and the last index of the array is the same, but the only thing that i have done is mirror it and print mirror even if its not the same
int main()
{
int arr[10][10];
int col,row;
scanf("%d %d", &col, &row);
for (int i = 0; i < col; i++) {
for (int j = 0; j < row; j++) {
scanf("%d", &arr[i][j]);
}
}
for (int i = 0; i < col; i++) {
for(int j = row - 1; j >= 0; j--) {
printf("Mirror");
}
}
}
the size of the array and the elements depends on the user, thank youuu

Answer 1

This is my solution for your problem, this code can have some isuess but in general do what you ask for. Adapt for your particular needs.
OUTPUT:
This program will check if an array is mirrored. Press enter to proceed!
Insert row*col -> 3*3
Insert row 1 elements, one by one!
Element 1 -> 1
Element 2 -> 0
Element 3 -> 1
Insert row 2 elements, one by one!
Element 1 -> 2
Element 2 -> 0
Element 3 -> 3
Insert row 3 elements, one by one!
Element 1 -> 4
Element 2 -> 0
Element 3 -> 4
Mirror found at row 1!
1 0 1
Mirror found at row 3!
4 0 4
CODE:
#include <stdio.h>
#define MAXCOLUMN 10
#define MAXROW 10
void clean(){
int temp;
while ((temp = getchar()) != '\n' && temp != EOF);
}
void print(int dim,int r, int row[][MAXCOLUMN]){
for(int index = 0; index < dim; index++)
printf("%d ",row[r][index]);
putchar('\n');
}
int main(void){
int arr[MAXROW][MAXCOLUMN];
int col,row,mirror;
puts("This program will check if an array is mirrored. Press enter to proceed!");
do{
clean();
printf("Insert row*col -> ");
}
while(scanf("%d*%d", &row, &col)!=2);
for(int r = 0; r < row; r++){
printf("Insert row %d elements, one by one!\n",r+1);
for(int c = 0; c < col; c++){
do{
clean();
printf("Element %d -> ", c+1);
}while(!scanf("%d",&arr[r][c]));
}
}
for(int r = 0; r < row; r++){
mirror = 1;
for(int cFH = 0, cSH = col-1; cFH < col/2; cFH++, cSH--)//cFH -> column index first half | cSH -> column index second half
if(arr[r][cFH] != arr[r][cSH]){
mirror = 0;
break;
}
if(mirror){
printf("Mirror found at row %d!\n",r+1);
print(col,r,arr);
}
}
return 0;
}

Answer 2

Usually you iterate through the columns of each row, that means that usually i (the outer loop) represents the rows and j the columns.
This piece of code shows a way to check if a 2D array is mirrored horizontally:
int mirror = 1;
for(int i = 0; i < row; i++) {
for(int j = 0; j < col/2; j++) {
// comparing first element with last element of row `i`
// than comparing the second element with the second last
// and so on, till you reach the center of the row, `j==col/2`
// if the comparison is true just one time, the array is not mirrored
if( array[i][j] != array[i][col-j-1] ) {
mirror = 0;
i = row; // to break the outer loop
break;
}
}
}
mirror ? puts("Mirror!") : puts("No mirror.");
At the end of the program if the variable mirror still have a value of 1, you got a mirror array.