I have written a program to calculate compound interest.
Here is the code:
#include <stdio.h>
#include <math.h>
int main(void) {
float value, rate, years,r;
int column = 0, tmp;
printf("Enter money values: ");
scanf("%f",&value);
printf("Enter a interest rate: ");
scanf("%f",&rate);
printf("Enter number of years: ");
scanf("%f",&years);
printf("\nYears ");
tmp = rate + 4;
r = rate;
for (int a = rate; a <= tmp; a++) {
printf(" %d ", a);
column++;
}
for (int b = 1; b <= column; b++) {
printf("\n %d",b);
for (int i = 1; i<= column; i++) {
printf(" %.2f ", (float) pow ( (value)*(1.0+((r/100.0)/(1.0))) , (1.0*b))
r++;
}
r = rate;
printf("\n");
}
// I = P*R*T
// P= AMOUNT (value)
// R=RATE (r)
// T=YEARS (b)
return 0;
}
It asks the user for a value (money), interest rate, number of years and displays the interest rate like so:
Enter money values: 100
Enter a interest rate: 6
Enter number of years: 5
Years 6 7 8 9 10
1 106.00 107.00 108.00 109.00 110.00
2 11236.00 11449.00 11664.00 11881.00 12100.00
3 1191016.00 1225043.00 1259712.00 1295029.00 1331000.00
4 126247696.00 131079600.00 136048896.00 141158160.00 146410000.00
5 13382255616.00 14025517056.00 14693280768.00 15386240000.00 16105100288.00
But my problem is the floating point calculation.
As you may be able to tell the numbers in the output above and very long and have many trailing digits
which i am very confused about.
For example in the 2nd row the first output is 11236.00,
this is wrong since it should be outputting 112.36 but for some reason the decimal has moved
forward two spaces. Why is this? and how could i fix this problem and print the correct solution
with the decimal in the correct place.
You have the value inside the pow. So when you square for two years, you are squaring the amount. Move the (value)* to output the pow call.
Related
Working with Repl.it and trying to use a function in C to average the elements in a variable length array. My program works fine in every other i/o area other than the average which returns:
The average for that day is: -nan. Any insight on what the issue may be?
The goal is to receive user input as a double(for example, how many pints of blood were taken per hour over a 7 hr period and then use a function call to calculate the average amount for that seven hour period.
New code is as follows:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
double average(int size, float ary[*]);
int main(void)
{
char dayOne[8], dayTwo[8];
int size;
float ave;
printf("Over how many hours do you want to view donation amounts?: ");
scanf("%d", &size);
if (size < 7 || size > 7)
size = 7;
printf("Enter day that you want to see average donation amount for: ");
scanf("%s", dayOne);
{
float ary[size];
for (int i = 0; i < size; i++)
{
printf("\nEnter amount taken in hour %d:", i + 1);
scanf("%f", &ary[i]);
}
ave = average(size, ary);
printf("\nThe average donated for %s is: %2.1f", dayOne, ave);
}
printf("\n\nEnter day that you want to see average donation amount for: ");
scanf("%s", dayTwo);
if(strcmp(dayOne, dayTwo)== 0)
printf("\nEnter a different day please: ");
scanf("%s", dayTwo);
{
float ary[size];
for (int i = 0; i < size; i++)
{
printf("\nEnter amount taken in hour %d:", i + 1);
scanf("%f", &ary[i]);
}
ave = average(size, ary);
printf("\nThe average donated for %s is: %2.1f", dayTwo, ave);
}
return 0;
}
double average(int size, float ary[])
{
double sum = 0;
double ave;
for (int i = 0; i < size; i++)
sum += ary[i];
ave = (double)sum / size;
return ave;
}
This is wrong:
int ary[7];
…
scanf("%f", &ary[i]);
%f is for scanning a float, but ary[i] is an int. The resulting behavior is not defined.
This is wrong:
double size;
…
ave = average(size, ary);
Nothing in the “…” assigns a value to size, so it has no defined value when average is called.
Quite a few syntactical and logical changes to be made buddy. As Eric Postpischil has mentioned in his answer, your size variable isn't initialized to anything before use. And using %f for accepting integers is incorrect too. Along with these, there are a few other glitches which I will list below, with the corresponding fixes. I have also attached the full working code along with the output.
Error: size variable not initialized.
Fix:: Since you have a fixed number of hours, you can either use the 7 directly or through size. Hence initialize the variable while declaring it. And just a suggestion buddy, use int for size. ==> int size = 7;
Error: Accepting input for array values. The array ary is of type int, but you have used %f which is a format specifier for float.
Fix: Use %d which is the format specifier for int data type. ==> scanf("%d", &ary[i]);
Error: Format specifier used for printing the average value. You have used %f again which is for float while the variable ave for average if of type double.
Fix: Use %lf which is the format specifier for double. ==> printf("\nThe average for the 2nd day is: %.3lf", ave); The .3 before lf is just to limit the number of decimal points to 3. It is optional.
Error: You accept the second day and display a message if it is the same as the first day, but the scanf for this is out of the if loop. hence it prompts the user to input another name of the day regardless of whether the second input day is same as the first or not.
Fix: just move that scanf into the if loop where you check if that day is same as the previous one.
I wouldn't really call this one an error, because it's just an improvement which I find that needs to be done. You accept the second day which should be different from the first with the message that average would be found. But you are not calculating the average for this day. Hence I have included that part in the code.
CODE:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
double average(int, int [7]);
int main(void)
{
char dayOne[8], dayTwo[8];
int size = 7;
double ave;
printf("Enter day that you want to see average donation amount for: ");
scanf("%s", dayOne);
int ary[7];
for (int i = 0; i < 7; i++)
{
printf("Enter amount taken in hour %d:", i + 1);
scanf("%d", &ary[i]);
}
ave = average(size, ary);
printf("\nThe average for the 1st day is: %.3lf", ave);
printf("\n\nEnter day that you want to see average donation amount for:");
scanf("%s", dayTwo);
if(strcmp(dayOne, dayTwo)== 0) {
printf("\nEnter a different day please: ");
scanf("%s", dayTwo);
}
for (int i = 0; i < 7; i++)
{
printf("Enter amount taken in hour %d:", i + 1);
scanf("%d", &ary[i]);
}
ave = average(size, ary);
printf("\nThe average for the 2nd day is: %.3lf", ave);
return 0;
}
double average(int size, int ary[7])
{
int sum = 0;
double ave;
for (int i = 0; i < size; i++) {
sum = sum + ary[i];
}
ave = sum / size;
return ave;
}
OUTPUT:
Enter day that you want to see average donation amount for: Day1
Enter amount taken in hour 1: 1
Enter amount taken in hour 2: 2
Enter amount taken in hour 3: 3
Enter amount taken in hour 4: 4
Enter amount taken in hour 5: 5
Enter amount taken in hour 6: 6
Enter amount taken in hour 7: 7
The average for the 1st day is: 4.000
Enter day that you want to see average donation amount for: Day2
Enter amount taken in hour 1: 8
Enter amount taken in hour 2: 8
Enter amount taken in hour 3: 8
Enter amount taken in hour 4: 8
Enter amount taken in hour 5: 8
Enter amount taken in hour 6: 8
Enter amount taken in hour 7: 8
The average for the 2nd day is: 8.000
Hope this helps.
double size;
The size variable has not been set before calling the average function.
ave = average(size, ary);
May be size can be initialized to 0 and incremented in the for loop as given below
double size = 0;
double ave;
printf("Enter day that you want to see average donation amount for: ");
scanf("%s", dayOne);
{
int ary[7];
for (int i = 0; i < 7; i++)
{
printf("Enter amount taken in hour %d:", i + 1);
scanf("%f", &ary[i]);
size++;
}
ave = average(size, ary);
printf("\nThe average for the day is: %f", ave);
}
If the goal is to receive user input as a double, the array used to hold those values should be double.
double ary[7];
instead of
int ary[7];
I've been trying to figure this out the last few days, but no luck. The objective is to find the sum, average, minimum, and maximum grades and display them.
Here is my code, everything except minimum, maximum and grade input seem to work
// Includes printf and scanf functions
#include <stdio.h>
int main(void) {
unsigned int counter; // number of grade to be entered next
int grade; // grade value
int total; // sum of grades entered by user
float average; // average of grades
int maxi; // Max grade
int mini; // min grade
int i;
int max;
int min;
maxi = 1;
mini = 1;
printf("Enter number of grades: "); // User enters number of grades
scanf("%d", &counter); // Countss number of grades
//scanf("%d%d", &min, &max);
for (i = 1; i <= counter; i++) {
printf("Enter grade %d: ", i); // User enters grade
scanf("%d", &grade); // Counts grades
//scanf("%d",&counter);
if (grade < 0 || grade > 100) {
printf("Please enter a number between 0 and 100!\n"); // Lets user know if input is invalid
i--;
break;
}
else {
total = total + grade;
average = (float)total / counter; // NOTE: integer division, not decimal
}
}
max = (grade < maxi) ? maxi : grade;
min = (grade > mini) ? mini : grade;
printf("Class average is: %.3f\n", average); // Displays average
printf("Your maximum grade is %d\n", max); // Displays Max
printf("Your minimum grade is %d\n", min); // Displays minimum
printf("Sum: %d\n", total); // Displays total
}
Output:
Enter number of grades: 2
5
7
Enter grade 1: 4
Enter grade 2: 3
Class average is: 3.500
Your maximum grade is 3
Your minimum grade is 1
Sum: 7
For some reason when I start the program, I have to enter a few numbers, in this case 5 & 7 before it prompts me to "Enter grade" then from there it calculates everything. Also, it seems that the Maximum is always the last grade that I enter and shows 1 as the minimum when no where in the input is 1. I am supposed to use a conditional operator for the max/min, I tried looking it up and reading the book, but they just use letters like a,b,c, etc. Which just confused me so I'm not sure if I did it wrong.
Could that be what is messing everything up? If it isn't what am I doing wrong?
Another thing is I'm thinking I need a While loop if I want to make the counter have an input from 1-100, is that right?
Edit: just realized I had to remove the scanf for max and min. Taht's why I had to inptu 2 nubmers first
There are two major problems, as I see it
The variable total is not initialized, so the first occurrence of total = total + grade; would invoke undefined behaviour.
You have to initialize it explicitly to 0.
The same variable grade is used for holding the repeated input. After the loop, grade will only hold the last input value.
You need to either use an array for storing inputs and comparison, or, compare and update the min and max as you go, inside the loop.
For future references, please seperate your code in different functions or add comments, since analyzing an unfamiliar code always takes much time.
min: Your problem here lies, that you're initializing your min value with 1. That value is most of the time below your input grades. If you want to initialize it, you should use a high number.
For example:
#include <limits.h>
int min = INT_MAX;
max: Your "grade" will be always the last typed grade, which you scanned. That's not what you want. It would be good, to save all values, which you get as input in an array or a list.
Also your codesnippet at the end
max = (grade<maxi) ? maxi : grade;
min = (grade>mini) ? mini : grade;
will just compare one grade. You need to compare all values, which you entered.
You could just put them in the for-loop.
gradeinput: You need to temporarily save your inputs in a datastructure like an array/list to use them in your program.
int x[counter];
for (i = 1; i <= counter; i++) {
printf("Enter grade %d: ", i);
x[i]=scanf("%d", &grade);
}
.. have to enter a few numbers, in this case 5 & 7 before it prompts me to "Enter grade"
This happens because OP's stdout is buffered and not one character at a time.
To insure output is seen before the scanf(), use fflush().
See What are the rules of automatic flushing stdout buffer in C?
printf("Enter number of grades: ");
fflush(stdout); // add
scanf("%d", &counter);
Rather than set the min = 1, set to a great value
maxi = 1;
mini = 1;
maxi = 0;
mini = 100;
// or
maxi = INT_MIN;
mini = INT_MAX;
Move the test for min/max in the loop to test each value and fold maxi, max into the same variable.
if (max > grade) max = grade;
if (min < grade) min = grade;
The first total + grade is a problem as total is uninitialized.
// int total; // sum of grades entered by user
int total = 0; // sum of grades entered by user
Unnecessary to calculate average each time though the loop. Sufficient to do so afterward.
Style: After the break; the else is not needed.
Good that code tests user input range. Yet the i-- is incorrect. If code is to break, just break. If code it to try again, the i-- makes sense, but then code should continue.
The comment // NOTE: integer division, not decimal is incorrect as (float) total / counter is FP division.
if (grade < 0 || grade > 100) {
printf("Please enter a number between 0 and 100!\n");
i--;
continue;
}
total = total + grade;
} // end for
average = (float) total / counter;
In general, casting should be avoided.
Advanced issue: Consider the situation if later on code was improved to handle a wider range of integers and used higher precision FP math.
The 1st form causes total to become a float (this could lose precision) and perhaps use float to calculate the quotient, even if average was a double. Of course the (float) cast could be edited to (double) as part of the upgrade, but that is a common failure about updates. Types may be changed, but their affected object uses are not fully vetted.
The 2nd form below causes total to become the same type as average and use the matching math for the type. Reduced changed needed as the types change. This form is also easier to review as one does not need to go back and check the FP type of average to see if a cast to float, double or even long double was needed.
average = (float) total / counter;
// or
average = total;
average /= counter;
For some reason when I start the program, I have to enter a few numbers, in this case 5 & 7 before it prompts me to "Enter grade"
You have two scanf before "Enter grade"
scanf("%d", &counter);
scanf("%d%d", &min, &max);
#include <stdio.h>
int main(void) {
int counter; // number of grade to be entered next
int grade; // grade value
int total=0; // sum of grades entered by user
float average; // average of grades
int i;
int max;
int min;
printf("Enter number of grades: "); // User enters number of grades
scanf("%d", &counter); // Countss number of grades
for (i = 1; i <= counter; i++) {
printf("Enter grade %d: ", i); // User enters grade
scanf("%d", &grade); // Counts grades
if (grade < 0 || grade > 100) {
printf("Please enter a number between 0 and 100!\n"); // Lets user know if input is invalid
i--;
} else {
if(i==1){
max = grade;
min = grade;
}
else{
max = (grade < max) ? max : grade;
min = (grade > min) ? min : grade;
}
total = total + grade;
average = (float) total / counter; // NOTE: integer division, not decimal
}
}
printf("Class average is: %.3f\n", average); // Displays average
printf("Your maximum grade is %d\n", max); // Displays Max
printf("Your minimum grade is %d\n", min); // Displays minimum
printf("Sum: %d\n", total); // Displays total
}
I've edited your Code as there were some mistakes. First, you were not initialising the total, which may make it take some garbage value. The second one is no need of using break as you are reducing the value of i.The third one is that you are updating the min and max outside the for loop, where the value of grade will be the last entered grade. And maxi and mini are not at all needed. The code was running perfectly without waiting for dummy values. Cheers!
disclaimer: I'm new to programming
I'm working on this problem
so far ive written this which takes user inputs and calculates an average based on them
#include <stdio.h>
int main()
{
int n, i;
float num[100], sum = 0.0, average;
for(i = 0; i < n; ++i)
{
printf("%d. Enter number: ", i+1);
scanf("%f", &num[i]);
sum += num[i];
}
average = sum / n;
printf("Average = %.2f", average);
return 0;
}
I'd like the user to enter -1 to indicate that they are done entering data; I can't figure out how to do that. so if possible can someone explain or give me an idea as to how to do it
Thank you!
#include <stdio.h>
int main()
{
int i = 0;
float num[100], sum = 0.0, average;
float x = 0.0;
while(1) {
printf("%d. Enter number: ", i+1);
scanf("%f", &x);
if(x == -1)
break;
num[i] = x;
sum += num[i];
i++;
}
average = sum / i;
printf("\n Average = %.2f", average);
return 0;
}
There is no need for the array num[] if you don't want the data to be used later.
Hope this will help.!!
You just need the average. No need to store all the entered numbers for that.
You just need the number inputs before the -1 stored in a variable, say count which is incremented upon each iteration of the loop and a variable like sum to hold the sum of all numbers entered so far.
In your program, you have not initialised n before using it. n has only garbage whose value in indeterminate.
You don't even need the average variable for that. You can just print out sum/count while printing the average.
Do
int count=0;
float num, sum = 0;
while(scanf("%f", &num)==1 && num!=-1)
{
count++;
sum += num;
}
to stop reading at -1.
There is no need to declare an array to store entered numbers. All you need is to check whether next entered number is equal to -1 and if not then to add it to the sum.
Pay attention to that according to the assignment the user has to enter integer numbers. The average can be calculated as an integer number or as a float number.
The program can look the following way
#include <stdio.h>
int main( void )
{
unsigned int n = 0;
unsigned long long int sum = 0;
printf("Enter a sequence of positive numbers (-1 - exit): ");
for (unsigned int num; scanf("%u", &num) == 1 && num != -1; )
{
++n;
sum += num;
}
if (n)
{
printf("\nAverage = %llu\n", sum / n);
}
else
{
puts("You did not eneter a number. Try next time.");
}
return 0;
}
The program output might look like
Enter a sequence of positive numbers (-1 - exit): 1 2 3 4 5 6 7 8 9 10 -1
Average = 5
If you need to calculate the average as a float number then just declare the variable sum as having the type double and use the corresponding format specifier in the printf statement to output the average.
I'm a newbie!
I'm supposed to get 2 integers from the user, and print the result(sum of all numbers between those two integers).
I also need to make sure that the user typed the right number.
The second number should be bigger than the first one.
And if the condition isn't fulfilled, I have to print "The second number should be bigger than the first one." and get the numbers from the user again until the user types right numbers that meet the condition.
So if I programmed it right, an example of the program would be like this.
Type the first number(integer) : 10
Type the second number(integer) : 1
The second number should be bigger than the first one.
Type the first number(integer) : 1
Type the second number(integer) : 10
Result : 55
End
I think that I have to make two loops, but I can't seem to figure out how.
My English is limited, to help your understanding of this quiz, I'll add my flowchart below.
I tried many different ways I can think of, but nothing seems to work.
This is the code that I ended up with now.
But this doesn't work either.
#include <stdio.h>
void main(void)
{
int a = 0;
int b = 0;
int total_sum = 0;
printf("Type the first number : \n");
scanf("%d", &a);
printf("Type the second number : \n");
scanf("%d", &b);
while (a > b) {
printf("The second number should be bigger than the first one.\n");
printf("Type the first number : \n");
scanf("%d", &a);
printf("Type the second number : \n");
scanf("%d", &b);
}
while (a <= b) {
total_sum += a;
a++;
}
printf("Result : \n", total_sum);
}
Instead of using loop to sum the numbers, we can use mathematical formula.
Sum of first N integers= N*(N+1)/2
#include <stdio.h>
int main(void)
{
int a = 0;
int b = 0;
int sum;
//Run infinite loop untill a>b
while(1)
{
printf("Type the first number : ");
scanf("%d", &a);
printf("Type the second number : ");
scanf("%d", &b);
if(a>b)
{
printf("The second number should be bigger than the first one.\n");
}
else
{
break;
}
}
//Reduce comlexity of looping
sum=((b*(b+1))-(a*(a-1)))/2;
printf("Result : %d " , sum);
return 0;
}
After corrections your code should run. The community has pointed out many mistakes in your code. Here's an amalgamated solution:
#include <stdio.h>
int main(void)
{
int a = 0;
int b = 0;
int correctInput=0;
int total_sum = 0;
do
{
printf("Type the first number : \n");
scanf("%d", &a);
printf("Type the second number : \n");
scanf("%d", &b);
if(a<b)
correctInput=1;
else
printf("The second number should be bigger than the first one.\n");
}
while (correctInput ==0) ;
while (a <= b) {
total_sum += a;
a++;
}
printf("Result : %d \n" , total_sum);
return 0;
}
Factorials are used frequently in probability problems. The factorial of a positive integer n (written n! and pronounced "n factorial") is equal to the product of the positive integers from 1 to n: n! = 1 x 2 x 3 x x n Write a program that takes as input an integer n and computes n!.
My friend and I are trying to build a program together, but it just doesn't seem to be working. Neither of us have much experience with C, so we just can't spot the issue... Any advice or help would be much appreciated!
Apologies for the slightly awkward lyrics?
[Edit] The problem is that when we input values, we get ridiculous figures like 4586368.
#include "stdafx.h"
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <math.h>
void main()
{
int room[20] = {};
int i;
int rooms = 0;
char option = 0;
int lights = 0;
int hrsUsed = 0;
int Telly = 0;
int TVWatt =0;
int sumTV;
int TVuse = 0;
int Computer = 0;
int compWatt = 0;
int compUsed = 0;
int compTotal;
int kwH_lights;
int fridge = 0;
int washLoad = 0;
int dryerLoad = 0, dishLoad = 0, cookLoad = 0;
int showeruse = 0;
int total_kWh;
printf("Enter number of rooms");
scanf_s("%d", &rooms);
for(i=0;i<rooms;i++)
{
printf("input average wattage of lights");
scanf_s("%d", &lights);
lights=lights/1000;
printf("input number of hours use/day (average)");
scanf_s("%d", &hrsUsed);
kwH_lights=((lights*hrsUsed)*365);
printf("input number of TVs");
scanf_s("%d", &Telly);
printf("input average wattage");
scanf_s("%d", &TVWatt);
printf("input average use a day");
scanf_s("%d", &TVuse);
sumTV=((Telly*(TVWatt/1000))*TVuse)*365;
}
printf("Input number of fridge/freezer");
scanf_s("%d",&fridge);
fridge=(fridge*2)*365;
printf("input number of Computers and/or video game consoles in the house");
scanf_s("%d", &Computer);
for(i=0;i<Computer;i++) {
printf("input wattage");
scanf_s("%d", &compWatt);
printf("input average hrs used/day");
scanf_s("%d", &compUsed);
compTotal=((compWatt/1000)*compUsed)*365;
}
printf("Input average number of washing machine loads /day");
scanf_s("%d",&washLoad);
washLoad=washLoad*365;
printf("Input average number of clothes dryer loads/day");
scanf_s("%d",&dryerLoad);
dryerLoad=(dryerLoad*3)*365;
printf("Input average number of dishwasher loads/day");
scanf_s("%d",&dishLoad);
dishLoad=(dishLoad*1.5)*365;
printf("Input average cooking load/day");
scanf_s("%d",&cookLoad);
cookLoad=(cookLoad*7)*365;
printf("Input average hrs/day of shower usage");
scanf_s("%d",&showeruse);
showeruse=(showeruse*7)*365;
total_kWh=((kwH_lights)+(sumTV)+(fridge)+(compTotal)+(dryerLoad)+(dishLoad)+(cookLoad)+(showeruse));
printf("Total= %d", &total_kWh);
}
You should change this:
printf("Total= %d", &total_kWh);
to that:
printf("Total= %d", total_kWh);
Same is true for all your other integer variables.
There were quite a few mistakes in your code:
you printed the memory-address instead of result value (don't use & with printf if your variable is a plain int)
the computer for-loop had no curly brackets (so only the printf statement was looped)
results were not summed up (in all loops you've just overwritten your inputs from the last loop)
the rooms[] Array was never used - a few other variables also (possible error source, if you wanted to use them and just forgot it)
the result from a multiplication with 1.5 will hold a double value - you should cast that back to int (dishLoad)
The bold mistake is probably that one, why your values were wrong...
Also notice: The 'average number of washing machine loads/clothes dryer loads/ dishwasher loads' should better be asked by week or month... Or should hold Floating Point values: Because everyone I know don't use the washing machine and clothes dryer every day multiple times. So now you can't enter something like once a week (which would be an factor of 0.14, but is not enterable cause all values are stored as int).
Here Comes the code with everything fixed, I could found:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <math.h>
int main(int argc, char** argv){
int i = 0;
int rooms = 0;
int lights = 0;
int hrsUsed = 0;
int Telly = 0;
int TVWatt =0;
int sumTV = 0;
int TVuse = 0;
int Computer = 0;
int compWatt = 0;
int compUsed = 0;
int compTotal= 0;
int kwH_lights = 0;
int fridge = 0;
int washLoad = 0;
int dryerLoad = 0, dishLoad = 0, cookLoad = 0;
int showeruse = 0;
int total_kWh = 0;
printf("Enter number of rooms: ");
scanf_s("%d", &rooms);
for(i=0;i<rooms;i++){
printf("A few questions about room %d\n", i+1);
printf("input average wattage of lights: ");
scanf_s("%d", &lights);
lights+=lights/1000;
printf("input number of hours use/day (average): ");
scanf_s("%d", &hrsUsed);
kwH_lights+=((lights*hrsUsed)*365);
printf("input number of TVs: ");
scanf_s("%d", &Telly);
printf("input average wattage: ");
scanf_s("%d", &TVWatt);
printf("input average use a day: ");
scanf_s("%d", &TVuse);
sumTV+=((Telly*(TVWatt/1000))*TVuse)*365;
}
printf("Input number of fridge/freezer: ");
scanf_s("%d",&fridge);
fridge=(fridge*2)*365;
printf("input number of Computers and/or video game consoles in the house: ");
scanf_s("%d", &Computer);
for(i=0;i<Computer;i++){
printf("A few questions about computer %d\n", i+1);
printf("input wattage: ");
scanf_s("%d", &compWatt);
printf("input average hrs used/day: ");
scanf_s("%d", &compUsed);
compTotal += ((compWatt/1000)*compUsed)*365;
}
printf("Input average number of washing machine loads/day: ");
scanf_s("%d",&washLoad);
washLoad=washLoad*365;
printf("Input average number of clothes dryer loads/day: ");
scanf_s("%d",&dryerLoad);
dryerLoad=(dryerLoad*3)*365;
printf("Input average number of dishwasher loads/day: ");
scanf_s("%d",&dishLoad);
dishLoad=(int)((dishLoad*1.5)*365);
printf("Input average cooking load/day: ");
scanf_s("%d",&cookLoad);
cookLoad=(cookLoad*7)*365;
printf("Input average hrs/day of shower usage: ");
scanf_s("%d",&showeruse);
showeruse=(showeruse*7)*365;
total_kWh=((kwH_lights)+(sumTV)+(fridge)+(compTotal)+(dryerLoad)+(dishLoad)+(cookLoad)+(showeruse));
printf("Total= %d\n", total_kWh);
system("Pause");
return 0;
}
I hope it helps you out - if you got any questions left, feel free to ask.
My first step would be to correct the second for loop { } ... fix this and ask again.
[EDIT]
your calculations with usages of int values divided by other ints (compwatt / 1000) ... are you sure your idea of using int is correct?
or:
cookLoad=(cookLoad*7)*365;
why multiplying with 7 AND 365? should not the average / day be multiplied by 365 only?
For more readability of your code, you can employ compound assignment operators as below,
Operator Name Syntax Meaning
-------------------------------------------------
Addition assignment a += b a = a + b
Subtraction assignment a -= b a = a - b
Multiplication assignment a *= b a = a * b
Division assignment a /= b a = a / b