I have to create an email and attach an XLSX file. I looked at the BCS_EXAMPLE_7 program.
I have transformed the content with the following method:
TRY.
cl_bcs_convert=>string_to_solix(
EXPORTING
iv_string = lv_content
iv_codepage = '4103'
iv_add_bom = 'X'
IMPORTING
et_solix = pt_binary_content
ev_size = pv_size ).
CATCH cx_bcs.
ls_return-type = text-023.
ls_return-message = text-024.
APPEND ls_return TO pt_return.
ENDTRY.
CONCATENATE lv_save_file_name '_' sy-datum '.xlsx' INTO lv_save_file_name.
lv_attachment_subject = lv_save_file_name.
CONCATENATE '&SO_FILENAME=' lv_attachment_subject INTO ls_attachment_header.
APPEND ls_attachment_header TO lt_attachment_header.
lo_document->add_attachment( i_attachment_type = 'XLS'
i_attachment_subject = lv_attachment_subject
i_attachment_size = pv_size
i_att_content_hex = pt_binary_content
i_attachment_header = lt_attachment_header ).
The email is sent correctly but when I open the attachment I see the error
Cannot open the file because the file extension is incorrect
Could you help me? thanks
That's a normal behavior of Excel, unrelated to ABAP, when the file name has extension .xlsx but doesn't contain data in format corresponding to XLSX. Excel does the same kind of checks for other extensions. If you need more information about these checks, please search the Web.
As I see that your program creates the attachment based on text converted into UTF-16LE code page (SAP code page 4103), I guess that you created the Excel data in format CSV, tab-separated values or even the old Excel XMLSS/XML 2003 format.
In that case, the extension .xlsx is not valid, to avoid the message, use the adequate extension, respectively .csv, .txt or .xml.
If you really need the extension .xlsx for some reason, then you must create the data in XLSX format. You may use the free API abap2xlsx. If you need further assistance about how to use abap2xlsx, please ask a new question (unrelated to email).
NB: maybe you were told to use the extension .xlsx although there is no real need to use it (each format has its own features, but simple unformatted values can be achieved with all formats), in that case you may propose to use a simple format like CSV or tab-separated values.
NB: you may also have the opposite case that Excel sniffs that the file contains data in format corresponding to XLSX, but the file name doesn't have the extension .xlsx, and the same for all other formats, but I can't say what is the exact Excel reaction to each case.
It appears that whatever you have in lv_content isn't actually a valid excel file. You can not just take arbitrary data, give it the extension .xlsx and expect MS Excel to know what to do with it.
Unfortunately, creating valid MS Office files is anything but trivial. It's a format which is theoretically open and based on XML (actually a zip archive containing multiple XML files), but in practice the specification is over a 5000(!) pages long.
Fortunately, there is a library for that. abap2xlsx is an open source (Apache License) library which provides an easy API to create (and read) valid XLSX files in ABAP.
You could also try to open the file with a text editor (eg. NotePad++), maybe this gives a hint of the actual content.
But I guess that something went wrong generating the binary table. Maybe you are using the wrong file size or code page.
Possible problems:
First problem: as correctly said by Sandra you may have invalid content of your lv_content variable, which doesn't correspond to correct XLSX structure.
Second problem: which you already solved, as seen from your coding, BCS classes do not support 4-character extensions.
Here is the sample how to build and send correct XLSX file via mail:
SELECT * UP TO 100 ROWS
FROM spfli
INTO TABLE #DATA(lt_spfli).
cl_salv_table=>factory( IMPORTING r_salv_table = DATA(lr_table)
CHANGING t_table = lt_spfli ).
DATA: lr_xldimension TYPE REF TO if_ixml_node,
lr_xlworksheet TYPE REF TO if_ixml_element.
DATA(lv_xlsx) = lr_table->to_xml( if_salv_bs_xml=>c_type_xlsx ).
DATA(lr_zip) = NEW cl_abap_zip( ).
lr_zip->load( lv_xlsx ).
lr_zip->get( EXPORTING name = 'xl/worksheets/sheet1.xml' IMPORTING content = DATA(lv_file) ).
DATA(lr_file) = NEW cl_xml_document( ).
lr_file->parse_xstring( lv_file ).
* Row elements are under SheetData
DATA(lr_xlnode) = lr_file->find_node( 'sheetData' ).
DATA(lr_xlrows) = lr_xlnode->get_children( ).
* Create new element in the XML file
lr_xlworksheet ?= lr_file->find_node( 'worksheet' ).
DATA(lr_xlsheetpr) = cl_ixml=>create( )->create_document( )->create_element( name = 'sheetPr' ).
DATA(lr_xloutlinepr) = cl_ixml=>create( )->create_document( )->create_element( name = 'outlinePr' ).
lr_xlsheetpr->if_ixml_node~append_child( lr_xloutlinepr ).
lr_xloutlinepr->set_attribute( name = 'summaryBelow' value = 'false' ).
lr_xldimension ?= lr_file->find_node( 'dimension' ).
lr_xlworksheet->if_ixml_node~insert_child( new_child = lr_xlsheetpr ref_child = lr_xldimension ).
* Create xstring and move it to XLSX
lr_file->render_2_xstring( IMPORTING stream = lv_file ).
lr_zip->delete( EXPORTING name = 'xl/worksheets/sheet1.xml' ).
lr_zip->add( EXPORTING name = 'xl/worksheets/sheet1.xml' content = lv_file ).
lv_xlsx = lr_zip->save( ).
DATA lv_size TYPE i.
DATA lt_bintab TYPE solix_tab.
* Convert to binary
CALL FUNCTION 'SCMS_XSTRING_TO_BINARY'
EXPORTING
buffer = lv_xlsx
IMPORTING
output_length = lv_size
TABLES
binary_tab = lt_bintab.
DATA main_text TYPE bcsy_text.
* create persistent send request
DATA(send_request) = cl_bcs=>create_persistent( ).
* create document object from internal table with text
APPEND 'Valid Excel file' TO main_text.
DATA(document) = cl_document_bcs=>create_document( i_type = 'RAW' i_text = main_text i_subject = 'Test Created for stella' ).
DATA lt_att_head TYPE soli_tab.
APPEND '<(>&< )>SO_FILENAME=MySheet.xlsx' TO lt_att_head.
* add the spread sheet as attachment to document object
document->add_attachment(
i_attachment_type = 'xls'
i_attachment_subject = 'MySheet'
i_attachment_size = CONV so_obj_len( lv_size )
i_attachment_header = lt_att_head
i_att_content_hex = lt_bintab ).
send_request->set_document( document ).
DATA(recipient) = cl_cam_address_bcs=>create_internet_address( 'some_recipient#mail.com' ).
send_request->add_recipient( recipient ).
DATA(sent_to_all) = send_request->send( i_with_error_screen = 'X' ).
COMMIT WORK.
Related
Classic Snowflake Web UI and the new Snowsight are great at importing sql from a file but neither allows you to export sql to a file. Is there a workaround?
You can use an IDE to connect to snowflake and write queries. Then the scripts can be downloaded using IDE features and can sync with git repo as well.
dbeaver is one such IDE which supports snowflake :
https://hevodata.com/learn/dbeaver-snowflake/
The query pane is interactive so the obvious workaround will be:
CTRL + A (select all)
CTRL + C (copy)
<open_favourite_text_editor>
CTRL + P (paste)
CTRL + S (save)
This tool can help you while the team develops a native feature to export worksheets:
"Snowflake Snowsight Extensions wrap Snowsight features that do not have API or SQL alternatives, such as manipulating Dashboards and Worksheets, and retrieving Query Profile and step timings."
https://github.com/Snowflake-Labs/sfsnowsightextensions
Further explained on this post:
https://medium.com/snowflake/importing-and-exporting-snowsight-dashboards-and-worksheets-3cd8e34d29c8
For example, to save to a file within PowerShell:
PS > $dashboards | foreach {$_.SaveToFolder(“path/to/folder”)}
PS > $dashboards[0].SaveToFile(“path/to/folder/mydashboard.json”)
ETA: I'm adding this edit to the front because this is what actually worked.
Again, BSON was a dead end & punycode is irrelevant. I don't know why punycode is referenced in the metadata file; but my best guess is that they might use punycode to encode the worksheet name itself (though I'm not sure why that would be needed since it shouldn't need to be part of a URL).
After doing terrible things and trying a number of complex ways of dealing with escape character hell, I found that the actual encoding is very simple. It just works as an 8 bit encoding with anything that might cause problems escaped away (null, control codes, double quotes, etc.). To load, treat the file as a text file using an 8-bit encoding; extract the data as a JSON field, then re-encode that extracted data as that same encoding. I just used latin_1 to read; but it may not even matter which encoding you use as long as you are consistent and use the same one to re-encode. The encoded field will then be valid zlib compressed data.
I decided that I wanted to start from scratch so I needed to back the worksheets first and I made a Python script based on my findings above. Be warned that this may return even worksheets that you previously closed for good. After running this and verifying that backups were created, I just ran rm #~/worksheet_data/;, closed the tab & reopened it.
Here's the code (fill in the appropriate base directory location):
import os
from collections import OrderedDict
import configparser
from sqlalchemy import create_engine, exc
from snowflake.sqlalchemy import URL
import pathlib
import json
import zlib
import string
def format_filename(s: str) -> str: # From https://gist.github.com/seanh/93666
"""Take a string and return a valid filename constructed from the string.
Uses a whitelist approach: any characters not present in valid_chars are
removed. Also spaces are replaced with underscores.
Note: this method may produce invalid filenames such as ``, `.` or `..`
When I use this method I prepend a date string like '2009_01_15_19_46_32_'
and append a file extension like '.txt', so I avoid the potential of using
an invalid filename.
"""
valid_chars = "-_.() %s%s" % (string.ascii_letters, string.digits)
filename = ''.join(c for c in s if c in valid_chars)
# filename = filename.replace(' ','_') # I don't like spaces in filenames.
return filename
def trlng_dash(s: str) -> str:
"""Removes trailing character if present."""
return s[:-1] if s[-1] == '-' else s
sso_authenticate = True
# Assumes CLI config file exists.
config = configparser.ConfigParser()
home = pathlib.Path.home()
config_loc = home/'.snowsql/config' # Assumes it's set up from Snowflake CLI.
base_dir = home/r'{your Desired base directory goes here.}'
json_dir = base_dir/'json' # Location for your worksheet stage JSON files.
sql_dir = base_dir/'sql' # Location for your worksheets.
# Assumes CLI config file exists.
config.read(config_loc)
# Add connection parameters here (assumes CLI config exists).
# Using sso so only 2 are needed.
# If there's no config file, etc. enter by hand here (or however you want to do it).
connection_params = {
'account': config['connections']['accountname'],
'user': config['connections']['username'],
}
if sso_authenticate:
connection_params['authenticator'] = 'externalbrowser'
if config['connections'].get('password', None) is not None:
connection_params['password'] = config['connections']['password']
if config['connections'].get('rolename', None) is not None:
connection_params['role'] = config['connections']['rolename']
if locals().get('database', None) is not None:
connection_params['database'] = database
if locals().get('schema', None) is not None:
connection_params['schema'] = schema
sf_engine = create_engine(URL(**connection_params))
if not base_dir.exists():
base_dir.mkdir()
if not json_dir.exists():
json_dir.mkdir()
if not (sql_dir).exists():
sql_dir.mkdir()
with sf_engine.connect() as connection:
connection.execute(f'get #~/worksheet_data/ \'file://{str(json_dir.as_posix())}\';')
for file in [path for path in json_dir.glob('*') if path.is_file()]:
if file.suffix != '.json':
file.replace(file.with_suffix(file.suffix + '.json'))
with open(json_dir/'metadata.json', 'r') as metadata_file:
files_meta = json.load(metadata_file)
# List of files from metadata file will contain some empty worksheets.
files_description_orig = OrderedDict((file_key_value['name'], file_key_value) for file_key_value in sorted(files_meta['activeWorksheets'] + list(files_meta['inactiveWorksheets'].values()), key=lambda x: x['name']) if file_key_value['name'])
# files_description will only track non empty worksheets
files_description = files_description_orig.copy()
# Create updated files description filtering out empty worksheets.
for item in files_description_orig:
json_file = json_dir/f"{files_description_orig[item]['name']}.json"
# If a file didn't make it or was deleted by hand, we should
# remove from the filtered description & continue to the next item.
if not (json_file.exists() and json_file.is_file()):
del files_description[item]
continue
with open(json_file, 'r', encoding='latin_1') as f:
json_dat = json.load(f)
# If the file represents a worksheet with a body field, we want it.
if not json_dat['wsContents'].get('body'):
del files_description[item]
## Delete JSON files corresponsing to empty worksheets.
# f.close()
# try:
# (json_dir/f"{files_description_orig[item]['name']}.json").unlink()
# except:
# pass
# Produce a list of normalized filenames (no illegal or awkward characters).
file_names = set(
format_filename(trlng_dash(files_description[item]['encodedDetails']['scriptName']).strip())
for item in files_description)
# Add useful information to our files_description OrderedDict
for file_name in file_names:
repeats_cnt = 0
file_name_repeats = (
item
for item
in files_description
if file_name == format_filename(trlng_dash(files_description[item]['encodedDetails']['scriptName']).strip())
)
for file_uuid in file_name_repeats:
files_description[file_uuid]['normalizedName'] = file_name
files_description[file_uuid]['stemSuffix'] = '' if repeats_cnt == 0 else f'({repeats_cnt:0>2})'
repeats_cnt += 1
# Now we iterate on non-empty worksheets only.
for item in files_description:
json_file = json_dir/f"{files_description[item]['name']}.json"
with open(json_file, 'r', encoding='latin_1') as f:
json_dat = json.load(f)
body = json_dat['wsContents']['body']
body_bin = body.encode('latin_1')
body_txt = zlib.decompress(body_bin).decode('utf8')
sql_file = sql_dir/f"{files_description[item]['normalizedName']}{files_description[item]['stemSuffix']}.sql"
with open(sql_file, 'w') as sql_f:
sql_f.write(body_txt)
creation_stamp = files_description[item]['created']/1000
os.utime(sql_file, (creation_stamp,creation_stamp))
print('Done!')
As mentioned at Is there any option in snowflake to save or load worksheets? (and in Snowflake's own documentation), in the Classic UI, the worksheets are saved at the user stage under #~/worksheet_data/.
You can download it with a get command like:
get #~/worksheet_data/<name> file:///<your local location>; (though you might need quoting if running from Windows).
The problem is that I do not know how to access it programmatically. The downloaded files look like JSON but it is not valid JSON. The main key is "wsContents" and contains most of the worksheet information. Its value includes two subkeys, "encoding" and "body".
The "encoding" key denotes that gzip is being used. The "body" key seems to be the actual worksheet data which looks a lot like a straight binary representation of the compressed text data. As such, any JSON reader will choke on it.
If it is anything like that, I do not currently know how to access it programmatically using Python.
I do see that a JSON like format exists, BSON, that is bundled into PyMongo. Trying to use this on these files fails. I even tried bson.is_valid and it returns False so I am assuming that it means that these files in Snowflake are not actually BSON.
Edited to add: Again, BSON is a dead end.
Examining the "body" value as just binary data, the first two bytes of sample files do seem to correspond to default zlib compression (0x789c). However, attempting to run straight zlib.decompress on the slice created from that first byte to the last corresponding to the first & last characters of the "body" value results in the error:
Error - 3 while decompressing data: invalid code lengths set
This makes me think that the bytes there, as is, are at least partly garbage and still need some processing before they can be decompressed.
One clue that I failed to mention earlier is that the metadata file (called "metadata" and which serves as an inventory of the remaining files at the #~/worksheet_data/ location) declares that the files use the punycode encoding. However, I have not known how to use that information. The data in these files doesn't particularly look like what I feel punycode should look like nor does it particularly make sense to me that you would use punycode on binary data that is not meant to ever be used to directly generate text such as zlib compressed data.
I wonder how to convert a dm3 file into .jpg/jpeg images? there is test annotation and scale bar on the image. I setup a script but it always show that "the format cannot contain the data to be saved". This can be done via file/batch convert function. So how to realize the same function in script？ Thanks
image test:=IntegerImage("test",2,1,100,100)
test.ShowImage()
image frontimage:=GetFrontImage()
string filename=getname(frontimage)
imagedisplay disp = frontImage.ImageGetImageDisplay(0)
disp.applydatabar()
ImageDocument frontDoc = GetFrontImageDocument()
string directoryname, pathname
number length
if(!SaveAsDialog("","Do Not Change Me",directoryname)) exit(0)
length=len(directoryname)-16
directoryname=mid(directoryname,0,length)
pathname=directoryname+filename
frontDoc.ImageDocumentSaveToFile( "JPG Format", pathname )
To convert to jpg you have to use "JPEG/JFIF Format" as the handler (=format).
It has to be exactly this string in the ImageDocument.ImageDocumentSaveToFile() function. Other formats are mentioned in the help (F1 > Scripting > Objects > Document Object Model > ImageDocument Object > ImageDocumentSaveToFile() function). Those are (for example):
'Gatan Format'
'Gatan 3 Format'
'GIF Format'
'BMP Format'
'JPEG/JFIF Format'
'Enhanced Metafile Format'
In your code you are using the SaveAsDialog() to get a directory. This is not necessary. You can use GetDirectoryDialog() to get a directory. This saves you the name operation for the directoryname and avoids problems when users do change your filename.
Also for concatinating paths I prefer using PathConcatenate(). On the first hand this makes your code a lot more readable since its name tells what you are doing. On the other hand this also takes care of the directory ending with \ or not and other path related things.
The following code is what I think you need:
Image test := IntegerImage("test", 2, 1, 100, 100);
test.ShowImage();
Image frontimage := GetFrontImage();
ImageDisplay disp = frontImage.ImageGetImageDisplay(0);
disp.applydatabar();
ImageDocument frontDoc = GetFrontImageDocument();
string directoryname;
if(!GetDirectoryDialog("Select directory", "C:\\\\", directoryname)){
// ↑
// You can of course use something else as the start point for selection here
exit(0);
}
string filename = GetName(frontimage);
string pathname = directoryname.PathConcatenate(filename);
frontDoc.ImageDocumentSaveToFile("JPEG/JFIF Format", pathname);
This answer is correct and should be accepted. Your problem is the wrong file-type string. You want to use "JPEG/JFIF Format"
A bit more general information on image file saving in DigitalMicrograph.
One doesn't save images but always imageDocuments that can contain one, more, or even zero image objects in them. Script-commands that save an image like SaveAsGatan() really just call things like: ImageGetOrCreateImageDocument().ImageDocumentSaveToFile()
The difference doesn't really matter for simple one-image-in-document type images, but it can make a difference when there are multiple images in a document, or when a single image is displayed multiple times simultaneously (which can be done.) So it is always good to know what "really" goes on.
ImageDocuments contain some properties relating to saving:
A save format (“Gatan Format”, “TIFF Format”, …)
Default value: What it was opened with, or last used save-format in case of creation
Script commands: ImageDocumentGetCurrentFileSaveFormat() ImageDocumentSetCurrentFileSaveFormat()
A current file path:
Default value: What it was opened from, or empty
Script commands: ImageDocumentGetCurrentFile() ImageDocumentSetCurrentFile()
A dirty-state:
Default value: clean when opened, dirty when created
Script commands: ImageDocumentIsDirty() ImageDocumentClean()
A linked-to-file state:
Default value: true when opened, false when created
Script commands: ImageDocumentIsLinkedToFile()
There are two ways of saving an imageDocument:
Saving the current document itself to disc:
void ImageDocumentSave( ImageDocument imgDoc, Number save_style ) This utilizes the current properties of the imageDocument to save it to current path in current format, marking it clean in the process. The save_style parameter determines how the program deals with missing info:
0 = never ask for path
1 = ask if not linked (or empty path)
2 = always ask
Saving a copy of the current document to disc:
void ImageDocumentSaveToFile( ImageDocument imgDoc, String handler, String fileName ) This makes a copy and save the file under provided path in the provided format. The imageDocument in memory does not change its properties. Most noticeable: It does not become clean, and it is not linked to the provided file on disc. The filename parameter specifies the saving location including the filename. If a file extension is provided, it has to match the file-format, but it can be left out. The handler parameter specified the file-format and can be anything GMS currently supports, such as:
Gatan Format
Gatan 3 Format
GIF Format
BMP Format
JPEG/JFIF Format
Enhanced Metafile Format
In short:
To save the currently opened imageDocument with a different format, you would want to do:
imageDocument doc = GetFrontImageDocument()
doc.ImageDocumentSetCurrentFileSaveFormat("TIFF Format")
doc.ImageDocumentSave(0)
While to just save a copy of the current state you would use:
imageDocument doc = GetFrontImageDocument()
string path = doc.ImageDocumentGetCurrentFile() // full path including extension!
path = PathExtractDirectory(path,0) + PathExtractBaseName(path,0) // path without file extension
doc.ImageDocumentSaveToFile("TIFF Format", path )
Hi i have a sitiation where there is a Source which it self produce Sources. The number of source that would be produced is not know in advanced. is there a proper design pattern to handle this case. Basically it would look like Source ----->Multiple Sources ------->Sink
EDIT
The Scenario for this is as follows.
Create a Source out of a database iterator
For each data base file provided by the above source transform the file to a Source
Attach those dynamically created source to a file IO sink
Basically i want bunch of data base content to be written to separate files via streams with back pressuring
Given a Source of Sources:
type Data = ???
val sos : Source[Source[Data, _], _] = ???
Each of the Data Sources can be drained into individual File Sinks using Source.runForeach.
We first need a function that can generate the Path that you want the data written to:
val pathCreator : () => Path = ???
And a way of converting Data to ByteString:
val dataToByteString : Data => ByteString = ???
These functions can finally be combined to get the behavior you're looking for:
val drainSourceToFile : Source[Data, _] => Future[IOResult] =
_.map(dataToByteString)
.to(FileIO.toPath(pathCreator()))
.run()
sos runForeach drainSourceToFile
If you want all of the IOResult values from FileIO.toPath so that you can know whether the writing was successful then you'll need a slightly more complicated setup:
val allIOResults : Future[Seq[IOResult]] =
sos.map(drainSourceToFile)
.to(Sink.seq)
.run()
.flatMap(Future.sequence)
I have a requirement where I want to merge two pdfs in to a single pdf and attach in the attachements to the custom object in salesforce then this merged pdf is sent via email.
Here is my code snippet. Where contentPdf is one pdf and b is another pdf content which needs to be merged.
PageReference pdf = PageReference(/apex/FirstPDF?id='+ccId);
Blob contentPdf = pdf.getContent();
PageReference cadre = new PageReference('/apex/SecondPDF?id=' + ccId);
Blob b = cadre.getContentPdf();
String combinedPdf = EncodingUtil.convertToHex(contentPdf)+EncodingUtil.convertToHex(b);
Blob horodatagePdf = EncodingUtil.convertFromHex(combinedPdf);
Attachment attachment = new Attachment();
attachment.Body = horodatagePdf;
attachment.Name = String.valueOf('New pdf.pdf');
attachment.ParentId = ccId;
insert attachment;
But the problem is that it does not show the right documents merged instead it shows only one page in the final pdf saved in my machine. I have tried to use contentAsPdf() to retrieve content from pageReference but it does not work. Moreover the page is not well generated the one I get in the attachment. Or if there is any other way to do it quuickely.
I don't think you can merge PDF documents like that. It looks crazy. You can simply join text files together but anything more complex (JPEGs, PDFs...) has special structure... It's quite possible that your code works, in the sense that it generates a file which size is a sum of single files' sizes but it's not a valid document so only 1st part renders OK.
Try making another page which would just reuse the other 2 pages by calling them (use <apex:include>). Check if it renders close to what you're after (there might be style clashes for example) and if it's any good - call getContentAsPdf() on that?
I'm currently trying to attach image files to a model directly from a zip file (i.e. without first saving them on a disk). It seems like there should be a clearer way of converting a ZipEntry to a Tempfile or File that can be stored in memory to be passed to another method or object that knows what to do with it.
Here's my code:
def extract (file = nil)
Zip::ZipFile.open(file) { |zip_file|
zip_file.each { |image|
photo = self.photos.build
# photo.image = image # this doesn't work
# photo.image = File.open image # also doesn't work
# photo.image = File.new image.filename
photo.save
}
}
end
But the problem is that photo.image is an attachment (via paperclip) to the model, and assigning something as an attachment requires that something to be a File object. However, I cannot for the life of me figure out how to convert a ZipEntry to a File. The only way I've seen of opening or creating a File is to use a string to its path - meaning I have to extract the file to a location. Really, that just seems silly. Why can't I just extract the ZipEntry file to the output stream and convert it to a File there?
So the ultimate question: Can I extract a ZipEntry from a Zip file and turn it directly into a File object (or attach it directly as a Paperclip object)? Or am I stuck actually storing it on the hard drive before I can attach it, even though that version will be deleted in the end?
UPDATE
Thanks to blueberry fields, I think I'm a little closer to my solution. Here's the line of code that I added, and it gives me the Tempfile/File that I need:
photo.image = zip_file.get_output_stream image
However, my Photo object won't accept the file that's getting passed, since it's not an image/jpeg. In fact, checking the content_type of the file shows application/x-empty. I think this may be because getting the output stream seems to append a timestamp to the end of the file, so that it ends up looking like imagename.jpg20110203-20203-hukq0n. Edit: Also, the tempfile that it creates doesn't contain any data and is of size 0. So it's looking like this might not be the answer.
So, next question: does anyone know how to get this to give me an image/jpeg file?
UPDATE:
I've been playing around with this some more. It seems output stream is not the way to go, but rather an input stream (which is which has always kind of confused me). Using get_input_stream on the ZipEntry, I get the binary data in the file. I think now I just need to figure out how to get this into a Paperclip attachment (as a File object). I've tried pushing the ZipInputStream directly to the attachment, but of course, that doesn't work. I really find it hard to believe that no one has tried to cast an extracted ZipEntry as a File. Is there some reason that this would be considered bad programming practice? It seems to me like skipping the disk write for a temp file would be perfectly acceptable and supported in something like Zip archive management.
Anyway, the question still stands:
Is there a way of converting an Input Stream to a File object (or Tempfile)? Preferably without having to write to a disk.
Try this
Zip::ZipFile.open(params[:avatar].path) do |zipfile|
zipfile.each do |entry|
filename = entry.name
basename = File.basename(filename)
tempfile = Tempfile.new(basename)
tempfile.binmode
tempfile.write entry.get_input_stream.read
user = User.new
user.avatar = {
:tempfile => tempfile,
:filename => filename
}
user.save
end
end
Check out the get_input_stream and get_output_stream messages on ZipFile.