Join the SQL Bridge table - sql-server

I have the following tables
User
+--------+------+
| UserID | Name |
+--------+------+
| User1 | John |
| User2 | Mike |
+--------+------+
Device
+----------+------------+------------+------+
| DeviceID | DeviceName | DeviceType | Good |
+----------+------------+------------+------+
| 1 | Device1 | A | 0 |
| 2 | Device2 | A | 1 |
| 3 | Device7 | B | 0 |
| 4 | Device8 | B | 1 |
| 5 | Device11 | C | 0 |
| 6 | Device12 | C | 1 |
+----------+------------+------------+------+
UserDevice
+--------------+--------+----------+
| UserDeviceID | UserID | DeviceID |
+--------------+--------+----------+
| z | User1 | 1 |
| y | User1 | 3 |
| x | User1 | 5 |
| w | User2 | 2 |
| v | User2 | 4 |
| u | User2 | 6 |
+--------------+--------+----------+
I want to join these tables like below
+----------+-------------+-------------+-------------+
| UserName | DeviceTypeA | DeviceTypeB | DeviceTypeC |
+----------+-------------+-------------+-------------+
| User1 | Device1 | Device7 | Device11 |
| User2 | Device2 | Device8 | Device22 |
+----------+-------------+-------------+-------------+
I tried all types of join query but unfortunately, I could not get the data in the above format. Could someone please help?

You can do this using PIVOT (documentation)
SELECT P.[Name], P.A AS DeviceTypeA, P.B AS DeviceTypeB, P.C AS DeviceTypeC
FROM
(
SELECT U.[Name], D.DeviceName, D.DeviceType
FROM [User] U
INNER JOIN DeviceUser DU
ON DU.UserID = U.UserID
INNER JOIN Device D
ON D.DeviceID = DU.DeviceID
) AS X
PIVOT
(
MAX(X.DeviceName)
FOR X.DeviceType IN([A], [B], [C])
) AS P;
Note however that this will return only one device name for a certain user and device type even if there are more devices of a device type for a that user.

Related

How can I improve the response time of this query in Oracle

this query takes 24 seconds and returns 1891 results:
SELECT p.STATE, p.REFNUM, p.CODE, p.TYPE, i.STATE, pj.NAME, pj.DOCUMENT
TABLE p
inner join TABLE2 i on i.REFNUM = p.REFNUM
inner join TABLE3 pj on pj.NUMBER = i.NUMBER and p.OFIC_ID = pj.OFIC_ID and p.PUB_ID = pj.PUB_ID
inner join OFICE o on t.OFIC_ID = p.OFIC_ID and o.PUB_ID = p.PUB_ID
inner join GROUP glad on glad.GROUP_CODE=p.GROUP_CODE
WHERE glad.GROUP_TYPE ='3' AND i.STATE = '1'
AND p.PUB_ID IN ('05','11','12','09','08','13','04','02','01','06','10','03','07','14')
AND pj.NAME LIKE 'BANK%'
ORDER BY o.NAME,p.ID;
I have these indexes:
CREATE INDEX IND_TABLE1_REFNUM_ZONE ON TABLE1 (PUB_ID, OFIC_ID, REFNUM, ZONE_ID)
CREATE INDEX IND_TABLE1_REFNUMPUB ON TABLE1 (REFNUM, PUB_ID, OFIC_ID, GROUP_CODE );
CREATE INDEX IND_TABLE1_GROUP ON TABLE1 (PUB_ID, GROUP_CODE, REFNUM, OFIC_ID)
CREATE INDEX IND_TABLE2_REF ON TABLE2 (REFNUM, NUMBER, STATE);
CREATE INDEX IND_TABLE2_QUERY ON TABLE2 (NUMBER, TYPE, STATE, REFNUM, NUM, CODE);
CREATE INDEX IND_TABLE2_REFNUM ON TABLE2 (REFNUM)
CREATE INDEX IND_TABLE2_NUMBER ON TABLE2 (NUMBER)
CREATE INDEX IND_TABLE3_NUM ON TABLE3 (NUMBER, PUB_ID, OFIC_ID, NAME );
CREATE INDEX IND_TABLE3_NAME ON TABLE3 ( NAME );
CREATE INDEX IND_GROUP_COD ON GROUP (GROUP_CODE, GROUP_TYPE)
I made the following queries to see how many records are in each table:
SELECT count(*) FROM TABLE1 --> 18298458 results
SELECT count(*) FROM TABLE2 --> 60627924 results
SELECT count(*) FROM TABLE3 --> 18425913 results
SELECT count(*) FROM OFICE --> 65 results
SELECT count(*) FROM TABLE1 p INNER JOIN GROUP glad on glad.GROUP_CODE=p.GROUP_CODE where glad.GROUP_TYPE ='3' AND p.PUB_ID IN ('05','11','12','09','08','13','04','02','01','06','10','03','07','14') --> 1314077 results
SELECT count(*) FROM TABLE1 p INNER JOIN GROUP glad on glad.GROUP_CODE=p.GROUP_CODE where glad.GROUP_TYPE ='3' AND p.PUB_ID IN ('05') --> 53754 results
SELECT count(*) FROM TABLE3 WHERE NAME LIKE 'BANK%' --> 1922081 results
this is the plan generated by oracle:
-----------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost | Pstart| Pstop |
-----------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 291K| 38M| 384K| | |
| 1 | SORT ORDER BY | | 291K| 38M| 384K| | |
| 2 | HASH JOIN | | 291K| 38M| 375K| | |
| 3 | TABLE ACCESS FULL | OFICE | 64 | 960 | 3 | | |
| 4 | HASH JOIN | | 291K| 34M| 375K| | |
| 5 | INDEX SKIP SCAN | IND_GROUP_COD | 47 | 329 | 1 | | |
| 6 | HASH JOIN | | 452K| 50M| 375K| | |
| 7 | PART JOIN FILTER CREATE | :BF0000 | 452K| 50M| 375K| | |
| 8 | NESTED LOOPS | | 452K| 50M| 375K| | |
| 9 | NESTED LOOPS | | | | | | |
| 10 | STATISTICS COLLECTOR | | | | | | |
| 11 | HASH JOIN | | 2100K| 166M| 252K| | |
| 12 | NESTED LOOPS | | 2100K| 166M| 252K| | |
| 13 | STATISTICS COLLECTOR | | | | | | |
| 14 | PARTITION RANGE ALL | | 1681K| 89M| 82582 | 1 | 19 |
| 15 | PARTITION HASH ALL | | 1681K| 89M| 82582 | 1 | 32 |
| 16 | TABLE ACCESS FULL | TABLE3 | 1681K| 89M| 82582 | 1 | 608 |
| 17 | INDEX RANGE SCAN | IND_TABLE2_QUERY | 1 | 27 | 103K| | |
| 18 | INDEX FAST FULL SCAN | IND_TABLE2_QUERY | 32M| 845M| 103K| | |
| 19 | INDEX RANGE SCAN | IND_TABLE1_REFNUM_ZONE| | | | | |
| 20 | TABLE ACCESS BY GLOBAL INDEX ROWID| TABLE1 | 1 | 35 | 70380 | ROWID | ROWID |
| 21 | PARTITION RANGE ALL | | 19M| 650M| 70380 | 1 | 19 |
| 22 | PARTITION HASH JOIN-FILTER | | 19M| 650M| 70380 |:BF0000|:BF0000|
| 23 | TABLE ACCESS FULL | TABLE1 | 19M| 650M| 70380 | 1 | 608 |
-----------------------------------------------------------------------------------------------------------------
I think it takes time because this one is using TABLE ACCESS FULL for TABLE1 and TABLE3
if I perform the query filtering only PUB_ID='05' instead of all the numbers in the above query, the query returns 181 results and takes 8 seconds and in that case oracle generates this plan:
--------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost | Pstart| Pstop |
--------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 797 | 108K| 312K| | |
| 1 | SORT ORDER BY | | 797 | 108K| 312K| | |
| 2 | NESTED LOOPS | | 797 | 108K| 312K| | |
| 3 | HASH JOIN | | 1238 | 160K| 312K| | |
| 4 | TABLE ACCESS BY INDEX ROWID BATCHED| OFICE | 3 | 45 | 2 | | |
| 5 | INDEX RANGE SCAN | SYS_C0034405 | 3 | | 1 | | |
| 6 | HASH JOIN | | 2091 | 240K| 312K| | |
| 7 | PART JOIN FILTER CREATE | :BF0000 | 66316 | 5375K| 241K| | |
| 8 | NESTED LOOPS | | 66316 | 5375K| 241K| | |
| 9 | PARTITION RANGE ALL | | 53085 | 2903K| 82490 | 1 | 19 |
| 10 | PARTITION HASH ALL | | 53085 | 2903K| 82490 | 1 | 32 |
| 11 | TABLE ACCESS FULL | TABLE3 | 53085 | 2903K| 82490 | 1 | 608 |
| 12 | INDEX RANGE SCAN | IND_TABLE2_QUERY | 1 | 27 | 3 | | |
| 13 | PARTITION RANGE ALL | | 762K| 25M| 68657 | 1 | 19 |
| 14 | PARTITION HASH JOIN-FILTER | | 762K| 25M| 68657 |:BF0000|:BF0000|
| 15 | TABLE ACCESS FULL | TABLE1 | 762K| 25M| 68657 | 1 | 608 |
| 16 | INDEX RANGE SCAN | IND_GROUP_COD | 1 | 7 | 0 | | |
--------------------------------------------------------------------------------------------------------------
SYS_C0034405 is the primary key of OFFICE which contains these fields: (PUB_ID, REG_ID)
if in addition to filtering only PUB_ID='05' I remove the "order by", the query takes only 3.5 seconds but I definitely have to return the ordered data and I would prefer to be able to filter several PUB_IDs
I thought the query could be improved if I removed the "inner join" from GROUP and changed the filter "glad.GROUP_TYPE ='3'" to "p.GROUP_CODE in ('01','07','10','21 ')" (these are all type 3 codes), because now it should use the IND_TABLE1_GROUP index but instead of improving, it gets worse, it takes 13 seconds even filtering only PUB_ID='05'; This is the plan that oracle generates:
------------------------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost | Pstart| Pstop |
------------------------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 47 | 6251 | 172K| | |
| 1 | SORT ORDER BY | | 47 | 6251 | 172K| | |
| 2 | HASH JOIN | | 47 | 6251 | 172K| | |
| 3 | PARTITION RANGE ALL | | 47786 | 2613K| 82490 | 1 | 19 |
| 4 | PARTITION HASH ALL | | 47786 | 2613K| 82490 | 1 | 32 |
| 5 | TABLE ACCESS FULL | TABLE3 | 47786 | 2613K| 82490 | 1 | 608 |
| 6 | HASH JOIN | | 41945 | 3154K| 89633 | | |
| 7 | NESTED LOOPS | | 41945 | 3154K| 89633 | | |
| 8 | NESTED LOOPS | | 75740 | 3154K| 89633 | | |
| 9 | STATISTICS COLLECTOR | | | | | | |
| 10 | NESTED LOOPS | | 18935 | 924K| 15985 | | |
| 11 | TABLE ACCESS BY INDEX ROWID BATCHED | OFICE | 3 | 45 | 2 | | |
| 12 | INDEX RANGE SCAN | SYS_C0034405 | 3 | | 1 | | |
| 13 | INLIST ITERATOR | | | | | | |
| 14 | TABLE ACCESS BY GLOBAL INDEX ROWID BATCHED| TABLE1 | 6312 | 215K| 7039 | ROWID | ROWID |
| 15 | INDEX RANGE SCAN | IND_TABLE1_GROUP | 6828 | | 284 | | |
| 16 | INDEX RANGE SCAN | IND_TABLE2_REFNUM | 4 | | 2 | | |
| 17 | TABLE ACCESS BY INDEX ROWID | TABLE2 | 2 | 54 | 4 | | |
| 18 | INDEX FAST FULL SCAN | IND_TABLE2_QUERY | 2 | 54 | 2 | | |
------------------------------------------------------------------------------------------------------------------------------
And if I put all the PUB_IDs, Oracle generates this plan (it doesn't even use the IND_TABLE1_GROUP index anymore):
-------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost | Pstart| Pstop |
-------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 35661 | 4631K| 345K| | |
| 1 | SORT ORDER BY | | 35661 | 4631K| 345K| | |
| 2 | HASH JOIN | | 35661 | 4631K| 344K| | |
| 3 | TABLE ACCESS FULL | OFICE | 64 | 960 | 3 | | |
| 4 | HASH JOIN | | 35661 | 4109K| 344K| | |
| 5 | PARTITION RANGE ALL | | 1360K| 45M| 79580 | 1 | 19 |
| 6 | PARTITION HASH ALL | | 1360K| 45M| 79580 | 1 | 32 |
| 7 | TABLE ACCESS FULL | TABLE1 | 1360K| 45M| 79580 | 1 | 608 |
| 8 | HASH JOIN | | 2100K| 166M| 252K| | |
| 9 | NESTED LOOPS | | 2100K| 166M| 252K| | |
| 10 | STATISTICS COLLECTOR | | | | | | |
| 11 | PARTITION RANGE ALL | | 1681K| 89M| 82582 | 1 | 19 |
| 12 | PARTITION HASH ALL | | 1681K| 89M| 82582 | 1 | 32 |
| 13 | TABLE ACCESS FULL | TABLE3 | 1681K| 89M| 82582 | 1 | 608 |
| 14 | INDEX RANGE SCAN | IND_TABLE2_QUERY | 1 | 27 | 103K| | |
| 15 | INDEX FAST FULL SCAN | IND_TABLE2_QUERY | 32M| 845M| 103K| | |
-------------------------------------------------------------------------------------------------

SQL Server: How to unpivot from pivoted table back to a self referencing table

I've looked at examples from: https://learn.microsoft.com/en-us/sql/t-sql/queries/from-using-pivot-and-unpivot?view=sql-server-ver15 but I couldn't seem to find samples of what I'm trying to do.
I'm wondering if there's a way to unpivot from this:
+----+------------+--------+--------+--------+
| Id | Level0 | Level1 | Level2 | Level3 |
+----+------------+--------+--------+--------+
| 0 | TMI | | | |
+----+------------+--------+--------+--------+
| 1 | TMI | A | | |
+----+------------+--------+--------+--------+
| 2 | TMI | A | B | |
+----+------------+--------+--------+--------+
| 3 | TMI | A | B | C |
+----+------------+--------+--------+--------+
| 4 | TMI | A | B | D |
+----+------------+--------+--------+--------+
Back to self referencing table like this:
+----+-----------+----------+--------+
| Id | LevelName | ParentId | Level |
+----+-----------+----------+--------+
| 0 | TMI | | Level0 |
+----+-----------+----------+--------+
| 1 | A | 0 | Level1 |
+----+-----------+----------+--------+
| 2 | B | 1 | Level2 |
+----+-----------+----------+--------+
| 3 | C | 2 | Level3 |
+----+-----------+----------+--------+
| 4 | D | 2 | Level3 |
+----+-----------+----------+--------+

SQL query to aggregate result from child table

I need to join 4 table and display records in my application
route1
-------------------------
| ID | MODE | SCH DATE |
| 1 | T | 1/12019 |
| 2 | T | 2/12019 |
| 3 | T | 2/12019 |
--------------------------
Stop2
----------------------------
| ID | routeID | LocationID |
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 1 | 3 |
| 4 | 2 | 4 |
| 5 | 2 | 5 |
| 6 | 3 | 6 |
-----------------------------
StopOrder2
----------------------------
| ID | StopID | Wight |
| 1 | 1 | 100 |
| 2 | 1 | 2 |
| 3 | 2 | 3 |
| 4 | 2 | 1 |
| 5 | 3 | 2 |
| 6 | 3 | 3 |
| 7 | 4 | 2 |
| 8 | 4 | 3 |
| 9 | 5 | 2 |
| 10 | 5 | 3 |
| 11 | 6 | 2 |
| 12 | 6 | 3 |
-----------------------------
Location
| LocationID | Name, City, Zip
| 1 | name1,city1 1111
| 2 | name2,city2 2222
| 3 | name3,city3 333
-----------------------------
I want final result with each route have how many records and how many orders and sum of all order wight
-----------------------------------------
| RouteID | MODE | SCH DATE |No Of Stop |LastLocatioID|OrderCount|
| 1 | T | 1/12019 | 3 | 3 | 6 |
| 2 | T | 2/12019 | 2 | 5 | 4 |
| 3 | T | 2/12019 | 1 | 6 | 2 |
How can I write the SQL query I need?
All you need is a simple group by:
SELECT
r.ID AS RouteID,
r.MODE,
r.[SCH DATE],
COUNT(s.ID) AS [No Of Stop],
MAX(s.LocationID) AS [LastLocationID],
COUNT(o.ID) AS OrderCount
FROM
#route1 r
INNER JOIN #Stop2 s
ON r.ID = s.routeID
INNER JOIN #StopOrder2 o
ON s.ID = o.StopID
GROUP BY
r.ID,
r.MODE,
r.[SCH DATE]
Output:

How to place NULLs last in ascending order

I need to sort a table and I need to display the rows that include Nulls at the bottom. Whenever I run the below query
select * from t1
order by status, date;
Nulls show up in the first row which I don't want:
+--------+------------+--+
| Status | Date | |
+--------+------------+--+
| 1 | NULL | |
| 1 | 2011-12-01 | |
| 1 | 2011-12-21 | |
| 2 | NULL | |
| 2 | 2005-09-02 | |
| 3 | 2000-08-07 | |
| | | |
+--------+------------+--+
This is what I need:
+--------+------------+--+
| Status | Date | |
+--------+------------+--+
| 1 | 2011-12-01 | |
| 1 | 2011-12-21 | |
| 1 | NULL | |
| 2 | 2005-09-02 | |
| 2 | NULL | |
| 3 | 2000-08-07 | |
| | | |
+--------+------------+--+
How can I do it?
select * from t1
order by status,
date,
CASE WHEN date is NULL
THEN 1
ELSE 0
END;
Would this work: order by col asc nulls last?

Need to update "orderby" column

I have a table test
+----+--+------+--+--+----------+--+--------------+
| ID | | Name | | | orderby | | processgroup |
+----+--+------+--+--+----------+--+--------------+
| 1 | | ABC | | | 10 | | 1 |
| 10 | | DEF | | | 12 | | 1 |
| 15 | | LMN | | | 1 | | 1 |
| 44 | | JKL | | | 4 | | 1 |
| 42 | | XYZ | | | 3 | | 2 |
+----+--+------+--+--+----------+--+--------------+
I want to update the orderby column in the sequence, I am expecting output like
+----+--+------+--+--+----------+--+--------------+
| ID | | Name | | | orderby | | processgroup |
+----+--+------+--+--+----------+--+--------------+
| 1 | | ABC | | | 1 | | 1 |
| 10 | | DEF | | | 2 | | 1 |
| 15 | | LMN | | | 3 | | 1 |
| 44 | | JKL | | | 4 | | 1 |
| 42 | | XYZ | | | 5 | | 1 |
+----+--+------+--+--+----------+--+--------------+
Logic behind this is when we have procesgroup as 1, orderby column should update as 1,2,3,4 and when procesgroup is 2 then update orderby as 5.
This might help you
;WITH CTE AS (
SELECT ROW_NUMBER() OVER (ORDER BY processgroup, ID ) AS SNO, ID FROM TABLE1
)
UPDATE TABLE1 SET TABLE1.orderby= CTE.SNO FROM CTE WHERE TABLE1.ID = CTE.ID

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