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So, I am supposed to print out the following series using a C program:
I decide to use a recursive approach and come up with this code:
#include<stdio.h>
float series(int n, float x)
{
float prod;
if(n==1)
return 1;
else
{
prod = (x*x)/((2*n-2)(2*n-3)); //line 10
return prod*series(n-1,x);
}
}
int main()
{
int n;
float x;
printf("\n Enter the values of n and x : ");
scanf("%d %f",&n,&x);
printf("\n The series is :");
for(int i=1;i<=n;i++)
printf(" %f,",series(i,x));
printf("\n\n");
return 0;
}
But this gives an error on line 10:
error: called object type 'int' is not a function or function pointer
I don't see any syntactical error on the line. It would be great if you could point it out.
Thank You!
prod = (x*x)/((2*n-2)(2*n-3)); //line 10
should be
prod = (x*x)/((2*n-2)*(2*n-3)); //line 10
The compiler sees this as a function call where 2*n-2 is the function pointer and 2*n-3 is the argument.
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#include<stdio.h>
int reverse(int );
int main()`
{
int num,rem,r;
printf("Enter a number:");
scanf("%d",&num);
r=reverse(num);
r=reverse(num);
return 0;
}
int reverse(int num)
{
int rem,rev=0;
while(num>=0)
{
rem=num%10;
rev=rev*10+rem;
num=num/10;
}
return rev;
}
Its not showing any errors and after entering the number the program stay still, its neither showing any output nor terminating
You have not used printf for output.
r = reverse(num);
printf("%d",r);
return 0;
Use this.
And also while condition should be
while (num > 0)
There is no need to call reverse function twice as well.
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Write a C program to calculate (x^n)/(n!) where x is a floating point number and n is an integer greater than or equal to zero.
I coded the following:
#include<stdio.h>
#include<math.h>
void main()
{
float x,p;
int i,n,f=1;
printf("Enter the value of x,n\n");
scanf("%d %d",&x,&n);
if(n>0)
{
for(i=1;i<=n;i++)
{
f=f*i;
}
p=(float)pow(x,n)/f;
printf("The value of p is %.3f",p);
}
if(n==0)
{
p=(float)pow(x,n)/1;
printf("The value of p is %d",p);
}
getch();
}
But this is not running well. Where have I gone wrong?
PS: Edit
In your question I have recognize 3 problems.
main problem is scanf("%d %d",&x,&n); should be change into scanf("%f %d",&x,&n);
because x is `float type #dragosht has mentioned it.
printf("The value of p is %d",p); should be correct as printf("The value of p is %f",p); beacause p is also float type.
It is better to set p = 0; at the beginning because you did not assign value to p using keyboard. There for some times you will get corrupted values because of this.
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In the following program when the value of N is less than 100 the program is executing perfectly but for bigger values of N its showing segmentation fault.I sit because of less memory or anything wrong with program??
#include<stdio.h>
int main()
{
int N,iteration,MAX_ITERATONS;
int i,j,k,n,index,boundary1,boundary2;
double h[2][100][100];
int current = 0;
int next = 1;
printf("Enter the number of points\n ");
scanf("%d", &N);
boundary1=0.4*N;
boundary2=(0.6*N);
printf("The boundary is between %d and %d .\n",boundary1,boundary2);
for(k=0;k<2;k++)
{
for(i=0;i<N;i++)
{
for(j=0;j<N;j++)
{
if((i==0)&&(j>=boundary1&&j<boundary2))
h[k][i][j]=100;
else
h[k][i][j]=20;
}
}
}
printf("Initial Values\n");
index = N/10;
for(i=0;i<N;)
{
for(j=0;j<N;)
{
printf("%.2f\t",h[0][i][j]);
j=j+index;
}
i=i+index;
printf("\n");
}
}
When N > 100, h is accessed to an index greater than 100, inside the nested for loop
h[k][i][j]=100;
but h is defined as
double h[2][100][100];
You are going out of bounds for h
If you want N as greater than 100 you need to redefine h or malloc it.
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I type this code on Ubuntu 14.04
#include<stdio.h>
int main() {
int i, j, n;
scanf("%",&n);
for (i=0;i<=n;i++){
for (j=0;j<=i;j++){
printf("*");
}
printf("\n");
}
return 0;
}
but it print too much stars and it Continue until I close it.
Should be:
#include<stdio.h>
int main() {
int i, j, n;
scanf("%d",&n);
for (i=0;i<=n;i++){
for (j=0;j<=i;j++){
printf("*");
}
printf("\n");
}
return 0;
}
You forgot to tell scanf you were reading in an integer by using the %d argument
There is mistake in
scanf("%",&n);
it will be:
scanf("%d",&n);
to tell the complier that the value of n is an integer type.
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I keep getting the warning that my function has an undefined reference and that doesn't really say much to me or how to fix it. Here are the errors
log_2.c: In function ‘main’: log_2.c:29: warning: implicit
declaration of function ‘logbase2’ /tmp/ccAXAmVb.o: In function
'main': log_2.c:(.text+0x5e): undefined reference to `logbase2'
collect2: ld returned 1 exit status
Heres my code:
int logbasetwo (int number)
{
int test;
for (int i = 0; i< number; i++){
test = 2 ^ i;
int result = i;
}
return result;
}
int main(){
printf("Enter a positive integer: ");
int number = get_int();
int logresult;
if (number > 0){
logresult=logbase2(number);
}
else (number < 0){
printf("Not a positive number. Re-enter: ");
number = get_int();
}
printf("Log base two of number is:%i", logresult);
}
return 0;
}
Well, in your code , both logbase2() and logbasetwo() are used, which are not the same !!!
You have defined a function named logbasetwo(), but you called logbase2().
Change either of them to match other one.
Also, you need to change the logic test = 2 ^ i;. As mentioned in earlier comment by Mr. #Bathsheba, ^ operator is for XOR, not exponentiation.
You need to use pow().