scanf not reading the whole string - c

Question

I was writing a program in C for lexicographically sorting the strings entered by user , but whenever i am entering a string with string length greater than 3 my code shows some garbage values and i am not able to understand why ?
My line of Code
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void lexiiographic_sort(char** , int );
int main(void)
{
int n;
scanf_s("%d", &n);
char** arr;
arr = (char**)malloc(n * sizeof(char*));
for (int i = 0; i < n; i++)
{
if ((*(arr + i) = (char*)malloc(1024 * sizeof(char))) == NULL) { exit(1); }
scanf_s("%s", *(arr + i),sizeof(*(arr + i)));
if ((*(arr + i) = (char*)realloc(*(arr + i), strlen(*(arr + i)) + 1)) == NULL) { exit(1); }
printf("%s\n", *(arr + i));
}
lexiiographic_sort(arr, n);
for (int i = 0; i < n; i++)
{
printf("%s\n", *(arr + i));
}
}
void lexiiographic_sort(char** string, int size)
{
char* temp;
for (int i = 1; i < size; i++)
{
for (int j = 1; j < size; j++)
{
if ((int)(*(*(string + j - 1))) > (int)(*(*(string + j))))
{
if ((temp = (char*)malloc(strlen(*(string + i - 1)) * sizeof(char) + 1)) == NULL) { exit(1); }
temp = *(string + j - 1);
if((temp = ((char*)realloc(temp, strlen(*(string + j)) * sizeof(char) + 1))) == NULL){exit(1); }
*(string + j - 1) = *(string + j);
*(string + j) = temp;
}
}
}
}
}

Answer 1

You cannot get size of dynamically allocated buffer via sizeof. sizeof(*(arr + i)) is the size of a pointer char*. It seems it is 4 in your environment and it is the reason of the 3-character limit (one is left for terminating null-character).
You used the hard-coded number 1024 as the buffer size, so use that instead.
scanf_s("%s", *(arr + i),1024);
Defining a macro for buffer size and using them will improve your code more.