Error : Expected expression before 'struct' - c

Question

I cant figure out what I am doing wrong here / how do I fix it. It is giving me an indication of expecting an expression before struct on line 90. Can somebody help me out with this problem?
I want to print a structure that is in a function, but because of the 2 arguments behind it I cant find a proper way to code it. The other functions do work fine, but when I add this one it all goes wrong.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct geboorteDatum
{
int geboortedag;
int geboortemaand;
int geboortejaar;
};
struct Persoon
{
struct geboorteDatum;
char naam[20];
};
void printPersonen(struct Persoon *pt, int persoonCount);
void scanPersonen(int persoonCount);
int startMenu(void);
int main()
{
startMenu();
}
void printPersonen(struct Persoon *pt, int persoonCount)
{
printf("Gegevens persoon 1 : ");
printf("\n%s",pt[persoonCount].naam);
printf("\n%d",pt[persoonCount].geboortedag);
printf("\n%d",pt[persoonCount].geboortemaand);
printf("\n%d",pt[persoonCount].geboortejaar);
printf("\n");
}
void scanPersonen(int persoonCount)
{
struct Persoon pt[100];
printf("Voer Gegevens persoon . : \n");
scanf("%s", pt[persoonCount].naam);
scanf("%d", &pt[persoonCount].geboortedag);
scanf("%d", &pt[persoonCount].geboortemaand);
scanf("%d", &pt[persoonCount].geboortejaar);
}
int startMenu(void)
{
int keuze = 0;
int persoonCount = 0;
int * p1 = &persoonCount;
do
{
printf("MENU \n");
printf("1 : Voer een persoon in \n");
printf("2 : Toon alle geboortedatums \n");
printf("3 : Toon de jongste persoon \n");
printf("4 : Toon verjaardagen in een maand \n");
printf("0 : Einde \n\n");
printf("Maak een keus : ");
scanf("%d", &keuze);
printf("\n");
if(keuze == 1)
{
persoonCount++;
scanPersonen(persoonCount);
}
else if(keuze == 2)
{
printPersonen(struct Persoon *pt, int persoonCount);
}
else if(keuze == 3)
{
printf("jo3");
}
else if(keuze == 4)
{
printf("%d",persoonCount);
}
else
{
printf("Deze keus is niet mogelijk, kies opnieuw \n\n");
return startMenu();
}
} while (keuze > 0);
return persoonCount;
}

Answer 1

Well, in:
struct Persoon
{
struct geboorteDatum;
char naam[20];
};
that struct geboorteDatum specifies a type, but no member name! You can fix that by adding one struct geboorteDatum d;
Then in your print and scan functions replace
printf("\n%d",pt[persoonCount].geboortedag);
with
printf("\n%d",pt[persoonCount].d.geboortedag);
But even better would be to change the struct geboorteDatum to
struct Date {
int day;
int month;
int year;
}
as a birthday is just a date. you do not need a special type to represent birthdays.
Then struct Persoon becomes:
struct Person {
struct Data birthday;
char name[20];
};
And the print statements become
printf("\n%d", pt[persoonCount].birthday.day);
(And translate all code to English for easier sharing. I could understand the dutch part, but most people cannot.)

Answer 2

Cough
well....
printPersonen(struct Persoon *pt, int persoonCount);
means you are declaring a prototype, and in that context is incorrect. May be it should be:
printPersonen(pt, persoonCount);