Related
I've seen the word static used in different places in C code; is this like a static function/class in C# (where the implementation is shared across objects)?
A static variable inside a function keeps its value between invocations.
A static global variable or a function is "seen" only in the file it's declared in
(1) is the more foreign topic if you're a newbie, so here's an example:
#include <stdio.h>
void foo()
{
int a = 10;
static int sa = 10;
a += 5;
sa += 5;
printf("a = %d, sa = %d\n", a, sa);
}
int main()
{
int i;
for (i = 0; i < 10; ++i)
foo();
}
This prints:
a = 15, sa = 15
a = 15, sa = 20
a = 15, sa = 25
a = 15, sa = 30
a = 15, sa = 35
a = 15, sa = 40
a = 15, sa = 45
a = 15, sa = 50
a = 15, sa = 55
a = 15, sa = 60
This is useful for cases where a function needs to keep some state between invocations, and you don't want to use global variables. Beware, however, this feature should be used very sparingly - it makes your code not thread-safe and harder to understand.
(2) Is used widely as an "access control" feature. If you have a .c file implementing some functionality, it usually exposes only a few "public" functions to users. The rest of its functions should be made static, so that the user won't be able to access them. This is encapsulation, a good practice.
Quoting Wikipedia:
In the C programming language, static
is used with global variables and
functions to set their scope to the
containing file. In local variables,
static is used to store the variable
in the statically allocated memory
instead of the automatically allocated
memory. While the language does not
dictate the implementation of either
type of memory, statically allocated
memory is typically reserved in data
segment of the program at compile
time, while the automatically
allocated memory is normally
implemented as a transient call stack.
And to answer your second question, it's not like in C#.
In C++, however, static is also used to define class attributes (shared between all objects of the same class) and methods. In C there are no classes, so this feature is irrelevant.
There is one more use not covered here, and that is as part of an array type declaration as an argument to a function:
int someFunction(char arg[static 10])
{
...
}
In this context, this specifies that arguments passed to this function must be an array of type char with at least 10 elements in it. For more info see my question here.
Short answer ... it depends.
Static defined local variables do not lose their value between function calls. In other words they are global variables, but scoped to the local function they are defined in.
Static global variables are not visible outside of the C file they are defined in.
Static functions are not visible outside of the C file they are defined in.
Multi-file variable scope example
Here I illustrate how static affects the scope of function definitions across multiple files.
a.c
#include <stdio.h>
/*
Undefined behavior: already defined in main.
Binutils 2.24 gives an error and refuses to link.
https://stackoverflow.com/questions/27667277/why-does-borland-compile-with-multiple-definitions-of-same-object-in-different-c
*/
/*int i = 0;*/
/* Works in GCC as an extension: https://stackoverflow.com/a/3692486/895245 */
/*int i;*/
/* OK: extern. Will use the one in main. */
extern int i;
/* OK: only visible to this file. */
static int si = 0;
void a() {
i++;
si++;
puts("a()");
printf("i = %d\n", i);
printf("si = %d\n", si);
puts("");
}
main.c
#include <stdio.h>
int i = 0;
static int si = 0;
void a();
void m() {
i++;
si++;
puts("m()");
printf("i = %d\n", i);
printf("si = %d\n", si);
puts("");
}
int main() {
m();
m();
a();
a();
return 0;
}
GitHub upstream.
Compile and run:
gcc -c a.c -o a.o
gcc -c main.c -o main.o
gcc -o main main.o a.o
Output:
m()
i = 1
si = 1
m()
i = 2
si = 2
a()
i = 3
si = 1
a()
i = 4
si = 2
Interpretation
there are two separate variables for si, one for each file
there is a single shared variable for i
As usual, the smaller the scope, the better, so always declare variables static if you can.
In C programming, files are often used to represent "classes", and static variables represent private static members of the class.
What standards say about it
C99 N1256 draft 6.7.1 "Storage-class specifiers" says that static is a "storage-class specifier".
6.2.2/3 "Linkages of identifiers" says static implies internal linkage:
If the declaration of a file scope identifier for an object or a function contains the storage-class specifier static, the identifier has internal linkage.
and 6.2.2/2 says that internal linkage behaves like in our example:
In the set of translation units and libraries that constitutes an entire program, each declaration of a particular identifier with external linkage denotes the same object or function. Within one translation unit, each declaration of an identifier with internal linkage denotes the same object or function.
where "translation unit is a source file after preprocessing.
How GCC implements it for ELF (Linux)?
With the STB_LOCAL binding.
If we compile:
int i = 0;
static int si = 0;
and disassemble the symbol table with:
readelf -s main.o
the output contains:
Num: Value Size Type Bind Vis Ndx Name
5: 0000000000000004 4 OBJECT LOCAL DEFAULT 4 si
10: 0000000000000000 4 OBJECT GLOBAL DEFAULT 4 i
so the binding is the only significant difference between them. Value is just their offset into the .bss section, so we expect it to differ.
STB_LOCAL is documented on the ELF spec at http://www.sco.com/developers/gabi/2003-12-17/ch4.symtab.html:
STB_LOCAL Local symbols are not visible outside the object file containing their definition. Local symbols of the same name may exist in multiple files without interfering with each other
which makes it a perfect choice to represent static.
Variables without static are STB_GLOBAL, and the spec says:
When the link editor combines several relocatable object files, it does not allow multiple definitions of STB_GLOBAL symbols with the same name.
which is coherent with the link errors on multiple non static definitions.
If we crank up the optimization with -O3, the si symbol is removed entirely from the symbol table: it cannot be used from outside anyways. TODO why keep static variables on the symbol table at all when there is no optimization? Can they be used for anything? Maybe for debugging.
See also
analogous for static functions: https://stackoverflow.com/a/30319812/895245
compare static with extern, which does "the opposite": How do I use extern to share variables between source files?
C++ anonymous namespaces
In C++, you might want to use anonymous namespaces instead of static, which achieves a similar effect, but further hides type definitions: Unnamed/anonymous namespaces vs. static functions
It depends:
int foo()
{
static int x;
return ++x;
}
The function would return 1, 2, 3, etc. --- the variable is not on the stack.
a.c:
static int foo()
{
}
It means that this function has scope only in this file. So a.c and b.c can have different foo()s, and foo is not exposed to shared objects. So if you defined foo in a.c you couldn't access it from b.c or from any other places.
In most C libraries all "private" functions are static and most "public" are not.
People keep saying that 'static' in C has two meanings. I offer an alternate way of viewing it that gives it a single meaning:
Applying 'static' to an item forces that item to have two properties: (a) It is not visible outside the current scope; (b) It is persistent.
The reason it seems to have two meanings is that, in C, every item to which 'static' may be applied already has one of these two properties, so it seems as if that particular usage only involves the other.
For example, consider variables. Variables declared outside of functions already have persistence (in the data segment), so applying 'static' can only make them not visible outside the current scope (compilation unit). Contrariwise, variables declared inside of functions already have non-visibility outside the current scope (function), so applying 'static' can only make them persistent.
Applying 'static' to functions is just like applying it to global variables - code is necessarily persistent (at least within the language), so only visibility can be altered.
NOTE: These comments only apply to C. In C++, applying 'static' to class methods is truly giving the keyword a different meaning. Similarly for the C99 array-argument extension.
static means different things in different contexts.
You can declare a static variable in a C function. This variable is only visible in the function however it behaves like a global in that it is only initialized once and it retains its value. In this example, everytime you call foo() it will print an increasing number. The static variable is initialized only once.
void foo ()
{
static int i = 0;
printf("%d", i); i++
}
Another use of static is when you implement a function or global variable in a .c file but don't want its symbol to be visible outside of the .obj generated by the file. e.g.
static void foo() { ... }
From Wikipedia:
In the C programming language, static is used with global variables and functions to set their scope to the containing file. In local variables, static is used to store the variable in the statically allocated memory instead of the automatically allocated memory. While the language does not dictate the implementation of either type of memory, statically allocated memory is typically reserved in data segment of the program at compile time, while the automatically allocated memory is normally implemented as a transient call stack.
I hate to answer an old question, but I don't think anybody has mentioned how K&R explain it in section A4.1 of "The C Programming Language".
In short, the word static is used with two meanings:
Static is one of the two storage classes (the other being
automatic). A static object keeps its value between invocations. The objects declared outside all blocks are always static and cannot be made automatic.
But, when the static keyword (big emphasis on it being used in
code as a keyword) is used with a declaration, it gives that object internal linkage so it can only be used within that translation unit. But if the keyword is used in a function, it changes the storage class of the object (the object would only be visible within that function anyway). The opposite of static is the extern keyword, which gives an object external linkage.
Peter Van Der Linden gives these two meanings in "Expert C Programming":
Inside a function, retains its value between calls.
At the function level, visible only in this file.
If you declare a variable in a function static, its value will not be stored on the function call stack and will still be available when you call the function again.
If you declare a global variable static, its scope will be restricted to within the file in which you declared it. This is slightly safer than a regular global which can be read and modified throughout your entire program.
A static variable is a special variable that you can use in a function, and it saves the data between calls, and it does not delete it between calls. For example:
void func(void) {
static int count; // If you don't declare its value, it is initialized with zero
printf("%d, ", count);
++count;
}
int main(void) {
while(true) {
func();
}
return 0;
}
The output:
0, 1, 2, 3, 4, 5, ...
In C, static has two meanings, depending on scope of its use. In the global scope, when an object is declared at the file level, it means that that object is only visible within that file.
At any other scope it declares an object that will retain its value between the different times that the particular scope is entered. For example, if an int is delcared within a procedure:
void procedure(void)
{
static int i = 0;
i++;
}
the value of 'i' is initialized to zero on the first call to the procedure, and the value is retained each subsequent time the procedure is called. if 'i' were printed it would output a sequence of 0, 1, 2, 3, ...
If you declare this in a mytest.c file:
static int my_variable;
Then this variable can only be seen from this file. The variable cannot be exported anywhere else.
If you declare inside a function the value of the variable will keep its value each time the function is called.
A static function cannot be exported from outside the file. So in a *.c file, you are hiding the functions and the variables if you declare them static.
Share what I learned about this point.
In C static is a declaration specifier, which falls into three categories:
storage classes: there are four classes: auto, static, extern and register.
type qualifiers: like keywords: const, volatile, etc.
type specifiers: like keywords: void, char, short, int, etc.
So static is a storage classes. It will determine the following three properties of each variable in a C program.
storage duration: means when memory is allocated for the variable and when the memory is released. A variable with static storage duration stays at the same memory location as long as the program is running.
scope: means the portion of the program text in which the variable can be accessed. A static variable has a file scope instead of a block scope.
linkage: means the extent to which the variable can be shared by different parts(or files) of a program. If a static variable is declared inside a block then it has no linkage. If a static variable is declared outside blocks, then it has internal linkage. Internal linkage makes it accessible in a single file.
The static storage class has a different effect on a variable depending on it is declared outside a block or inside a block. Need to consider case by case.
It is important to note that static variables in functions get initialized at the first entry into that function and persist even after their call has been finished; in case of recursive functions the static variable gets initialized only once and persists as well over all recursive calls and even after the call of the function has been finished.
If the variable has been created outside a function, it means that the programmer is only able to use the variable in the source-file the variable has been declared.
Static variables in C have the lifetime of the program.
If defined in a function, they have local scope, i.e. they can be accessed only inside those functions. The value of static variables is preserved between function calls.
For example:
void function()
{
static int var = 1;
var++;
printf("%d", var);
}
int main()
{
function(); // Call 1
function(); // Call 2
}
In the above program, var is stored in the data segment. Its lifetime is the whole C program.
After function call 1, var becomes 2. After function call 2, var becomes 3.
The value of var is not destroyed between functions calls.
If var had between non static and local variable, it would be stored in the stack segment in the C program. Since the stack frame of the function is destroyed after the function returns, the value of var is also destroyed.
Initialized static variables are stored in the data segment of the C program whereas uninitialized ones are stored in the BSS segment.
Another information about static: If a variable is global and static, it has the life time of the C program, but it has file scope. It is visible only in that file.
To try this:
file1.c
static int x;
int main()
{
printf("Accessing in same file%d", x):
}
file2.c
extern int x;
func()
{
printf("accessing in different file %d",x); // Not allowed, x has the file scope of file1.c
}
run gcc -c file1.c
gcc -c file2.c
Now try to link them using:
gcc -o output file1.o file2.o
It would give a linker error as x has the file scope of file1.c and the linker would not be able to resolve the reference to variable x used in file2.c.
References:
http://en.wikipedia.org/wiki/Translation_unit_(programming)
http://en.wikipedia.org/wiki/Call_stack
A static variable value persists between different function calls andits scope is limited to the local block
a static var always initializes with value 0
There are 2 cases:
(1) Local variables declared static: Allocated in data segment instead of stack. Its value retains when you call the function again.
(2) Global variables or functions declared static: Invisible outside compilation unit (i.e. are local symbols in symbol table during linking).
Static variables have a property of preserving their value even after they are out of their scope!Hence, static variables preserve their previous value in their previous scope and are not initialized again in the new scope.
Look at this for example -
A static int variable remains in memory while the program is running. A normal or auto variable is destroyed when a function call where the variable was declared is over.
#include<stdio.h>
int fun()
{
static int count = 0;
count++;
return count;
}
int main()
{
printf("%d ", fun());
printf("%d ", fun());
return 0;
}
This will output: 1 2
As 1 stays in the memory as it was declared static
Static variables (like global variables) are initialized as 0 if not initialized explicitly. For example in the below program, value of x is printed as 0, while value of y is something garbage. See this for more details.
#include <stdio.h>
int main()
{
static int x;
int y;
printf("%d \n %d", x, y);
}
This will output : 0
[some_garbage_value]
These are the major ones I found that weren't explained above for a newbie!
In C programming, static is a reserved keyword which controls both lifetime as well as visibility. If we declare a variable as static inside a function then it will only visible throughout that function. In this usage, this static variable's lifetime will start when a function call and it will destroy after the execution of that function. you can see the following example:
#include<stdio.h>
int counterFunction()
{
static int count = 0;
count++;
return count;
}
int main()
{
printf("First Counter Output = %d\n", counterFunction());
printf("Second Counter Output = %d ", counterFunction());
return 0;
}
Above program will give us this Output:
First Counter Output = 1
Second Counter Output = 1
Because as soon as we call the function it will initialize the count = 0. And while we execute the counterFunction it will destroy the count variable.
I'm trying to fully understand how static variables work in C. I understand that using the static keyword makes the lifetime of the variable equal to the duration of the program. The following example has one thing that confuses me though...
My static_test.c file:
#include <stdio.h>
void foo(){
static int counter = 0;
counter++;
printf("This function has been called %i times.\n",counter);
return;
}
int main(){
int i;
for(i=0;i<10;i++){
foo();
}
return 0;
}
When I first read this example it makes me wonder why the function doesn't print out 0 every time since we are assigning 0 to the static variable.
Is this because once a static variable is declared the compiler ignores another declaration of the same variable on the next calls to my foo() function?
Thanks!
Despite the use of =, this is an initialization, NOT an assignment. So it happens when the variable is initialized and not when the 'statement' is apparently 'executed'. Since it is a static variable, it is initialized once when the program starts, rather than every time the function runs.
Static variables are initialized exactly once at program start, before your function is ever called. The fact that it's a local variable doesn't affect this rule.
In addition, static storage class variables are automatically initialized to zero if not explicitly initialized; the = 0 in your program is superfluous.
From the C11 drafts standard (ISO/IEC 9899:201x), section 6.2.4 Storage durations of objects, paragraph 3:
An object whose identifier is declared … with the storage-class specifier static has static storage duration. Its lifetime is the entire execution of the program and its stored value is initialized only once, prior to program startup.
Yes, the compiler looks for an initial assignment after declaring a static variable and only executes it once, when the program starts.
This only happens when you declare the variable though. For example,
void foo(){
static int counter;
counter = 0;
counter++;
printf("This function has been called %i times.\n",counter);
return;
}
Would print 1 every time.
Static means the variable exists outside of the life time of the function. Think of it as a slightly clever global variable.
#include <stdio.h>
int foo(){
return 1;
}
int main(void) {
static int q = foo();
return 0;
}
Here is a link for the same. This is a C code and not C++. It compiles and run fine in C++ but not C.
This code was getting compilation error. Can someone please explain why is it getting error? Can static members only be initialized by constant values ? In C++ we need to DEFINE static members after declaring them , why is it not required in C ? I couldn't find any thread with similar query or a good answer.
Global and static variables can only be initialized with constant expressions known at compile time. Calling your foo() function does not constitute using a constant expression. Further, the order in which global and static variables are initialized is not specified. Generally, calling foo() would mean that there must be a certain order, because the function can reasonably expect some other variables to be already initialized.
IOW, in C, neither of your code is executed before main().
In C++ there are ways around it, but not in C.
All the static variables are compile time and the function is giving the output at run time so you are initializing a compile time variable with a run time variable which is not possible so it is giving error.
Another example may be as follows
int main()
{
int p=9;
static int x=p;
}
the above code is also gives you compile time error,The cause is same as above.
If you are doing this in C rather than C++ you can only assign static variables values that are available during compilation. So the use of foo() is not permitted due to its value not being determined until runtime.
I have tried this example of array of pointers. I am getting the error "Illegal initialisation in function main"
int main()
{
int a[]={1,2,3,4,5};
int b[]={1,2,3,4,5};
int c[]={1,2,3,4,5};
int *p[3]={a,b,c};
int i;
clrscr();
for(i=0;i<3;i++)
printf("%d - %u\n",*p[i],p[i]);
getch();
}
If I use static int instead of int in array declarations, it works fine. Can any one tell me the effect of static here. Thanks a lot.
In gcc you see warnings about this if you use the -pedantic flag.
But this is apparently something that has changed in the standard, in C90 it say:
All the expressions in an initializer for an object that has static
storage duration or in an initializer list for an object that has
aggregate or union type shall be constant expressions
and it was not allowed as the p array is an aggregate type, but in C99 we have:
All the expressions in an initializer for an object that has static
storage duration shall be constant expressions or string literals.
This compiles fine with gcc and gcc -ansi. gcc -ansi -pedantic however gives the following warning:
blackjack.c: In function ‘main’:
blackjack.c:8: warning: initializer element is not computable at load time
blackjack.c:8: warning: initializer element is not computable at load time
blackjack.c:8: warning: initializer element is not computable at load time
Whereas line 8 is:
int *p[3]={a,b,c};
As I see it the problem is that at the time a, b, and c would be stored in p, they don't exist yet. That's because they will be put on the stack and the position on the stack depends on things outside the scope of a function. To clarify this, 'load time' means the time the program is loaded into memory, not the time it is already in execution. (Don't ask me why/how it works anyway)
try:
printf("%d - %u\n",*(p[i]),p[i]);
although I have a feeling you're trying to do something more like:
int a[]={1,2,3,4,5};
int b[]={1,2,3,4,5};
int c[]={1,2,3,4,5};
int *p[3]={a,b,c};
int i;
clrscr();
for(i=0;i<sizeof(p)/sizeof(int*);i++) {
for (int j =0; j < sizeof(a)/sizeof(int); j++) {
printf("%d - %u\n",(p[i])[j],p[i]);
}
}
getch();
The rules are pretty simple.For static objects the initialization list should be constant.No such restriction exists for the elements that will be allocated space on stack.
It appears logical too,as the static objects need to be written in the data section and the compiler must be able to resolve their values beforehand.
On stack memory is allocated once the function in question(main) is called.So no problem there.I don't know why the opposite behavior on turbo-c.
on gcc this happens:(on compiling with gcc -Wall prog.c
int *p[]={a,b,c} //works fine
static int *p[]={a,b,c} //oops blunder
I've seen the word static used in different places in C code; is this like a static function/class in C# (where the implementation is shared across objects)?
A static variable inside a function keeps its value between invocations.
A static global variable or a function is "seen" only in the file it's declared in
(1) is the more foreign topic if you're a newbie, so here's an example:
#include <stdio.h>
void foo()
{
int a = 10;
static int sa = 10;
a += 5;
sa += 5;
printf("a = %d, sa = %d\n", a, sa);
}
int main()
{
int i;
for (i = 0; i < 10; ++i)
foo();
}
This prints:
a = 15, sa = 15
a = 15, sa = 20
a = 15, sa = 25
a = 15, sa = 30
a = 15, sa = 35
a = 15, sa = 40
a = 15, sa = 45
a = 15, sa = 50
a = 15, sa = 55
a = 15, sa = 60
This is useful for cases where a function needs to keep some state between invocations, and you don't want to use global variables. Beware, however, this feature should be used very sparingly - it makes your code not thread-safe and harder to understand.
(2) Is used widely as an "access control" feature. If you have a .c file implementing some functionality, it usually exposes only a few "public" functions to users. The rest of its functions should be made static, so that the user won't be able to access them. This is encapsulation, a good practice.
Quoting Wikipedia:
In the C programming language, static
is used with global variables and
functions to set their scope to the
containing file. In local variables,
static is used to store the variable
in the statically allocated memory
instead of the automatically allocated
memory. While the language does not
dictate the implementation of either
type of memory, statically allocated
memory is typically reserved in data
segment of the program at compile
time, while the automatically
allocated memory is normally
implemented as a transient call stack.
And to answer your second question, it's not like in C#.
In C++, however, static is also used to define class attributes (shared between all objects of the same class) and methods. In C there are no classes, so this feature is irrelevant.
There is one more use not covered here, and that is as part of an array type declaration as an argument to a function:
int someFunction(char arg[static 10])
{
...
}
In this context, this specifies that arguments passed to this function must be an array of type char with at least 10 elements in it. For more info see my question here.
Short answer ... it depends.
Static defined local variables do not lose their value between function calls. In other words they are global variables, but scoped to the local function they are defined in.
Static global variables are not visible outside of the C file they are defined in.
Static functions are not visible outside of the C file they are defined in.
Multi-file variable scope example
Here I illustrate how static affects the scope of function definitions across multiple files.
a.c
#include <stdio.h>
/*
Undefined behavior: already defined in main.
Binutils 2.24 gives an error and refuses to link.
https://stackoverflow.com/questions/27667277/why-does-borland-compile-with-multiple-definitions-of-same-object-in-different-c
*/
/*int i = 0;*/
/* Works in GCC as an extension: https://stackoverflow.com/a/3692486/895245 */
/*int i;*/
/* OK: extern. Will use the one in main. */
extern int i;
/* OK: only visible to this file. */
static int si = 0;
void a() {
i++;
si++;
puts("a()");
printf("i = %d\n", i);
printf("si = %d\n", si);
puts("");
}
main.c
#include <stdio.h>
int i = 0;
static int si = 0;
void a();
void m() {
i++;
si++;
puts("m()");
printf("i = %d\n", i);
printf("si = %d\n", si);
puts("");
}
int main() {
m();
m();
a();
a();
return 0;
}
GitHub upstream.
Compile and run:
gcc -c a.c -o a.o
gcc -c main.c -o main.o
gcc -o main main.o a.o
Output:
m()
i = 1
si = 1
m()
i = 2
si = 2
a()
i = 3
si = 1
a()
i = 4
si = 2
Interpretation
there are two separate variables for si, one for each file
there is a single shared variable for i
As usual, the smaller the scope, the better, so always declare variables static if you can.
In C programming, files are often used to represent "classes", and static variables represent private static members of the class.
What standards say about it
C99 N1256 draft 6.7.1 "Storage-class specifiers" says that static is a "storage-class specifier".
6.2.2/3 "Linkages of identifiers" says static implies internal linkage:
If the declaration of a file scope identifier for an object or a function contains the storage-class specifier static, the identifier has internal linkage.
and 6.2.2/2 says that internal linkage behaves like in our example:
In the set of translation units and libraries that constitutes an entire program, each declaration of a particular identifier with external linkage denotes the same object or function. Within one translation unit, each declaration of an identifier with internal linkage denotes the same object or function.
where "translation unit is a source file after preprocessing.
How GCC implements it for ELF (Linux)?
With the STB_LOCAL binding.
If we compile:
int i = 0;
static int si = 0;
and disassemble the symbol table with:
readelf -s main.o
the output contains:
Num: Value Size Type Bind Vis Ndx Name
5: 0000000000000004 4 OBJECT LOCAL DEFAULT 4 si
10: 0000000000000000 4 OBJECT GLOBAL DEFAULT 4 i
so the binding is the only significant difference between them. Value is just their offset into the .bss section, so we expect it to differ.
STB_LOCAL is documented on the ELF spec at http://www.sco.com/developers/gabi/2003-12-17/ch4.symtab.html:
STB_LOCAL Local symbols are not visible outside the object file containing their definition. Local symbols of the same name may exist in multiple files without interfering with each other
which makes it a perfect choice to represent static.
Variables without static are STB_GLOBAL, and the spec says:
When the link editor combines several relocatable object files, it does not allow multiple definitions of STB_GLOBAL symbols with the same name.
which is coherent with the link errors on multiple non static definitions.
If we crank up the optimization with -O3, the si symbol is removed entirely from the symbol table: it cannot be used from outside anyways. TODO why keep static variables on the symbol table at all when there is no optimization? Can they be used for anything? Maybe for debugging.
See also
analogous for static functions: https://stackoverflow.com/a/30319812/895245
compare static with extern, which does "the opposite": How do I use extern to share variables between source files?
C++ anonymous namespaces
In C++, you might want to use anonymous namespaces instead of static, which achieves a similar effect, but further hides type definitions: Unnamed/anonymous namespaces vs. static functions
It depends:
int foo()
{
static int x;
return ++x;
}
The function would return 1, 2, 3, etc. --- the variable is not on the stack.
a.c:
static int foo()
{
}
It means that this function has scope only in this file. So a.c and b.c can have different foo()s, and foo is not exposed to shared objects. So if you defined foo in a.c you couldn't access it from b.c or from any other places.
In most C libraries all "private" functions are static and most "public" are not.
People keep saying that 'static' in C has two meanings. I offer an alternate way of viewing it that gives it a single meaning:
Applying 'static' to an item forces that item to have two properties: (a) It is not visible outside the current scope; (b) It is persistent.
The reason it seems to have two meanings is that, in C, every item to which 'static' may be applied already has one of these two properties, so it seems as if that particular usage only involves the other.
For example, consider variables. Variables declared outside of functions already have persistence (in the data segment), so applying 'static' can only make them not visible outside the current scope (compilation unit). Contrariwise, variables declared inside of functions already have non-visibility outside the current scope (function), so applying 'static' can only make them persistent.
Applying 'static' to functions is just like applying it to global variables - code is necessarily persistent (at least within the language), so only visibility can be altered.
NOTE: These comments only apply to C. In C++, applying 'static' to class methods is truly giving the keyword a different meaning. Similarly for the C99 array-argument extension.
static means different things in different contexts.
You can declare a static variable in a C function. This variable is only visible in the function however it behaves like a global in that it is only initialized once and it retains its value. In this example, everytime you call foo() it will print an increasing number. The static variable is initialized only once.
void foo ()
{
static int i = 0;
printf("%d", i); i++
}
Another use of static is when you implement a function or global variable in a .c file but don't want its symbol to be visible outside of the .obj generated by the file. e.g.
static void foo() { ... }
From Wikipedia:
In the C programming language, static is used with global variables and functions to set their scope to the containing file. In local variables, static is used to store the variable in the statically allocated memory instead of the automatically allocated memory. While the language does not dictate the implementation of either type of memory, statically allocated memory is typically reserved in data segment of the program at compile time, while the automatically allocated memory is normally implemented as a transient call stack.
I hate to answer an old question, but I don't think anybody has mentioned how K&R explain it in section A4.1 of "The C Programming Language".
In short, the word static is used with two meanings:
Static is one of the two storage classes (the other being
automatic). A static object keeps its value between invocations. The objects declared outside all blocks are always static and cannot be made automatic.
But, when the static keyword (big emphasis on it being used in
code as a keyword) is used with a declaration, it gives that object internal linkage so it can only be used within that translation unit. But if the keyword is used in a function, it changes the storage class of the object (the object would only be visible within that function anyway). The opposite of static is the extern keyword, which gives an object external linkage.
Peter Van Der Linden gives these two meanings in "Expert C Programming":
Inside a function, retains its value between calls.
At the function level, visible only in this file.
If you declare a variable in a function static, its value will not be stored on the function call stack and will still be available when you call the function again.
If you declare a global variable static, its scope will be restricted to within the file in which you declared it. This is slightly safer than a regular global which can be read and modified throughout your entire program.
A static variable is a special variable that you can use in a function, and it saves the data between calls, and it does not delete it between calls. For example:
void func(void) {
static int count; // If you don't declare its value, it is initialized with zero
printf("%d, ", count);
++count;
}
int main(void) {
while(true) {
func();
}
return 0;
}
The output:
0, 1, 2, 3, 4, 5, ...
In C, static has two meanings, depending on scope of its use. In the global scope, when an object is declared at the file level, it means that that object is only visible within that file.
At any other scope it declares an object that will retain its value between the different times that the particular scope is entered. For example, if an int is delcared within a procedure:
void procedure(void)
{
static int i = 0;
i++;
}
the value of 'i' is initialized to zero on the first call to the procedure, and the value is retained each subsequent time the procedure is called. if 'i' were printed it would output a sequence of 0, 1, 2, 3, ...
If you declare this in a mytest.c file:
static int my_variable;
Then this variable can only be seen from this file. The variable cannot be exported anywhere else.
If you declare inside a function the value of the variable will keep its value each time the function is called.
A static function cannot be exported from outside the file. So in a *.c file, you are hiding the functions and the variables if you declare them static.
Share what I learned about this point.
In C static is a declaration specifier, which falls into three categories:
storage classes: there are four classes: auto, static, extern and register.
type qualifiers: like keywords: const, volatile, etc.
type specifiers: like keywords: void, char, short, int, etc.
So static is a storage classes. It will determine the following three properties of each variable in a C program.
storage duration: means when memory is allocated for the variable and when the memory is released. A variable with static storage duration stays at the same memory location as long as the program is running.
scope: means the portion of the program text in which the variable can be accessed. A static variable has a file scope instead of a block scope.
linkage: means the extent to which the variable can be shared by different parts(or files) of a program. If a static variable is declared inside a block then it has no linkage. If a static variable is declared outside blocks, then it has internal linkage. Internal linkage makes it accessible in a single file.
The static storage class has a different effect on a variable depending on it is declared outside a block or inside a block. Need to consider case by case.
It is important to note that static variables in functions get initialized at the first entry into that function and persist even after their call has been finished; in case of recursive functions the static variable gets initialized only once and persists as well over all recursive calls and even after the call of the function has been finished.
If the variable has been created outside a function, it means that the programmer is only able to use the variable in the source-file the variable has been declared.
Static variables in C have the lifetime of the program.
If defined in a function, they have local scope, i.e. they can be accessed only inside those functions. The value of static variables is preserved between function calls.
For example:
void function()
{
static int var = 1;
var++;
printf("%d", var);
}
int main()
{
function(); // Call 1
function(); // Call 2
}
In the above program, var is stored in the data segment. Its lifetime is the whole C program.
After function call 1, var becomes 2. After function call 2, var becomes 3.
The value of var is not destroyed between functions calls.
If var had between non static and local variable, it would be stored in the stack segment in the C program. Since the stack frame of the function is destroyed after the function returns, the value of var is also destroyed.
Initialized static variables are stored in the data segment of the C program whereas uninitialized ones are stored in the BSS segment.
Another information about static: If a variable is global and static, it has the life time of the C program, but it has file scope. It is visible only in that file.
To try this:
file1.c
static int x;
int main()
{
printf("Accessing in same file%d", x):
}
file2.c
extern int x;
func()
{
printf("accessing in different file %d",x); // Not allowed, x has the file scope of file1.c
}
run gcc -c file1.c
gcc -c file2.c
Now try to link them using:
gcc -o output file1.o file2.o
It would give a linker error as x has the file scope of file1.c and the linker would not be able to resolve the reference to variable x used in file2.c.
References:
http://en.wikipedia.org/wiki/Translation_unit_(programming)
http://en.wikipedia.org/wiki/Call_stack
A static variable value persists between different function calls andits scope is limited to the local block
a static var always initializes with value 0
There are 2 cases:
(1) Local variables declared static: Allocated in data segment instead of stack. Its value retains when you call the function again.
(2) Global variables or functions declared static: Invisible outside compilation unit (i.e. are local symbols in symbol table during linking).
Static variables have a property of preserving their value even after they are out of their scope!Hence, static variables preserve their previous value in their previous scope and are not initialized again in the new scope.
Look at this for example -
A static int variable remains in memory while the program is running. A normal or auto variable is destroyed when a function call where the variable was declared is over.
#include<stdio.h>
int fun()
{
static int count = 0;
count++;
return count;
}
int main()
{
printf("%d ", fun());
printf("%d ", fun());
return 0;
}
This will output: 1 2
As 1 stays in the memory as it was declared static
Static variables (like global variables) are initialized as 0 if not initialized explicitly. For example in the below program, value of x is printed as 0, while value of y is something garbage. See this for more details.
#include <stdio.h>
int main()
{
static int x;
int y;
printf("%d \n %d", x, y);
}
This will output : 0
[some_garbage_value]
These are the major ones I found that weren't explained above for a newbie!
In C programming, static is a reserved keyword which controls both lifetime as well as visibility. If we declare a variable as static inside a function then it will only visible throughout that function. In this usage, this static variable's lifetime will start when a function call and it will destroy after the execution of that function. you can see the following example:
#include<stdio.h>
int counterFunction()
{
static int count = 0;
count++;
return count;
}
int main()
{
printf("First Counter Output = %d\n", counterFunction());
printf("Second Counter Output = %d ", counterFunction());
return 0;
}
Above program will give us this Output:
First Counter Output = 1
Second Counter Output = 1
Because as soon as we call the function it will initialize the count = 0. And while we execute the counterFunction it will destroy the count variable.