Type Mistmatch Scala Slick Query - database

Question

I am having trouble to get username and password using slick in scala like basically similar to something like
var query = "SELECT * FROM \"default\".users as A " + "WHERE " + " A.username LIKE \'" + email + "\' " + "AND" + " A.password LIKE \'" + password + "\' ";
Here is my case class for schema
case class User(
id: Long = 0L,
username: String,
password: String,
author_id:Long,
created_on: DateTime,
updated_by: Long,
updated_on:Option[DateTime]
)
class UserTable(tag:Tag) extends Table[User](tag,"user"){
override def * = (id,username,password,author_id,created_on,updated_by,updated_on.?) <> (User.tupled,User.unapply)
def id = column[Long]("id",O.PrimaryKey,O.AutoInc)
def username = column[String]("username")
def password = column[String]("password")
def created_on = column[DateTime]("created_on")
def updated_on = column[DateTime]("dateupdated")
def author_id = column[Long]("author_id")
def updated_by = column[Long]("updated_by")
}
lazy val UserTable = TableQuery[UserTable]
Below is my Query
val users = Main.UserTable.filter(_.username == email)
.filter(_.password == password).take(1)

Answer 1

filter(_.username == email)
You probably meant === instead of ==.
That is part of the Slick DSL to build query expressions (and they could not call it == because Scala's equality comparator cannot be replaced).
Warning: Most operators mimic the plain Scala equivalents, but you have to use === instead of == for comparing two values for equality and =!= instead of != for inequality. This is necessary because these operators are already defined (with unsuitable types and semantics) on the base type Any, so they cannot be replaced by extension methods.