iterative communication between pipes - c

Question

I want to write a code using pipes. This code is about the rock, scissor, paper game, so I need to ask and receive messages all the time until one of two players score 3. So far, now I have the following code, but I don´t know how to iterate this code, could be with a while iteration?
#include <sys/types.h>
#include <sys/wait.h>
#include <unistd.h>
#include <stdio.h>
#include <string.h>
#include <errno.h>
#define READ_END 0 /* index pipe extremo escritura */
#define WRITE_END 1 /* index pipe extremo lectura */
int main(int argc, char* argv[])
{
int fd1[2],fd2[2];
int status, pid;
pipe(fd1); /* comunica ls y grep */
pid = fork();
if(pid == 0) /* hijo 1*/
{
close(fd1[READ_END]); /* cerrar extremo no necesario */
dup2(fd1[WRITE_END], STDOUT_FILENO);
close(fd1[WRITE_END]);
}
else /* padre */
{
close(fd1[WRITE_END]); /* extremo no necesario ya */
pipe(fd2); /* comunica grep y wc */
pid = fork();
if(pid == 0) /* hijo 2 */
{
close(fd2[READ_END]); /* cerrar extremo no necesario */
dup2(fd1[READ_END], STDIN_FILENO);
close(fd1[READ_END]);
dup2(fd2[WRITE_END], STDOUT_FILENO);
close(fd2[WRITE_END]);
}
else /* padre */
{
close(fd1[READ_END]); /* cerrar extremo no necesario */
close(fd2[WRITE_END]); /* cerrar extremo no necesario */
}
}
close(fd2[READ_END]); /* cerrar extremo que queda abierto en el padre */
/* wait para cada hijo */
wait(&status);
wait(&status);
return 0;
}