Convert words to binary values - c

Question

I need to convert words to binary numbers, positioned vertically (\n).
I need to write a function, which will do this convert.. Below is a sample..
Can you help me please?
//main
char* text = "Hello, how are you?";
const int len = strlen(text);
bool bytes1[len+1][8];
encode_string(text, bytes1);
for(int j = 0; j <= len; j++){
printf("%c: ", text[j]);
for(int i = 0; i < 8; i++){
printf("%d", bytes1[j][i]);
}
printf("\n");
}
// prints:
// H: 01001000
// e: 01100101
// l: 01101100
// l: 01101100
// o: 01101111
// ,: 00101100
// : 00100000
// h: 01101000
// o: 01101111
// w: 01110111
// : 00100000
// a: 01100001
// r: 01110010
// e: 01100101
// : 00100000
// y: 01111001
// o: 01101111
// u: 01110101
// ?: 00111111
// : 00000000
//function
void encode_string(const char string[], bool bytes[strlen(string)+1][8]){
}

Answer 1

Hy man you can use this:
Converting every char:
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <string.h>
int main(void){
char* text = "Hello, how are you?";
int len_size = strlen(text);
for(int j = 0; j <= len_size; j++){
printf("%c: ", text[j]);
for( int i = 7; i >= 0; i-- ) {
printf( "%d", ( text[j] >> i ) & 1 ? 1 : 0 );
}
printf("\n");
}
return 0;
}
Onother option with your function:
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <string.h>
void encode_string(char string[], int len_size);
int main(void){
char* text = "Hello, how are you?";
int len_size = strlen(text);
encode_string(text, len_size);
return 0;
}
void encode_string(char string[], int len_size){
for(int j = 0; j <= len_size; j++){
printf("%c: ", string[j]);
for( int i = 7; i >= 0; i-- ) {
printf( "%d", ( string[j] >> i ) & 1 ? 1 : 0 );
}
printf("\n");
}
}
I know your error already, your are trying to send to the function, and you dont send the right parameters...