React Formik : How to useEffect with formik values? - reactjs

Question

I would like to use useEffect to rerender a field if values of formik has changed. But it doesn't work..
Actually I created a little example to show my problem.
Here I have one field 'title', if this field has changed (when we write in it) it should call useEffect and print 'update!' but it doesn't!!
const FormikWidgetConfigurator = (props) => {
useEffect(() => {
// doesn't work if values has changed
console.log('update!')
}, [props.values]);
return (
<Form onSubmit={ props.handleSubmit } noValidate>
<Form.Group className='py-3' >
<Col md='6' style={{ padding: '0px' }}>
<Form.Group controlId='title'>
<Form.Control
type='text'
value={ props.values.title }
onChange={props.handleChange}
/>
</Form.Group>
</Col>
</Form.Group>
</Form>
)
}
const WidgetConfigurator = withFormik({
mapPropsToValues(props) {
return {
title: 'No Title'
};
},
validationSchema: props => Yup.object().shape({title: Yup.string()}),
handleSubmit(values, { setSubmitting }) {// handle submit}
})(FormikWidgetConfigurator);
export default WidgetConfigurator;
EDIT: Actually it works as expected. (i didn't change anything)
Thanks!

Answer 1

Using vanilla Formik your approach works.
My guess is that the issue is in your custom components, Form.Control, or Form.Group

Answer 2

It's not a great solution, but a hack I found is to have an invisible button inside a Formik form; it has access to all of Formik's attributes and will do whatever logic is needed in its onClick. Then from a useEffect you can simulate the click of that button via document.getElementById("..").click().
// Style it to be invisible
<Button id="testButton" type="button" onClick={() => {
setFieldValue('test', '123');
setTouched({});
// etc. any Formik action
}}>
</Button>
useEffect:
useEffect(() => {
document.getElementById("testButton").click(); // Simulate click
}, [dependency);