How to delete all hardlinks of multiple files on windows 10? - batch-file

I create a lot of hardlinks every week. When time comes to clean them, I find myself using the "DeleteAllHardlinks.bat" for ln (https://schinagl.priv.at/nt/ln/ln.html) but I have to drag and drop everyfile one after the other.
I would love to find a way to just select 100 files and drop them on the .bat, wait a while and find all those files and hardlinks deleted for good. Is there anyway to change the .bat file to allow this? (or maybe any other different method to acomplish the same?)
#echo off
REM
REM Check for commandline args
REM
if "[%~1]" == "[]" goto error
set LN=ln.exe
REM
REM List hardlink sibblings and delete all siblings
REM
for /f "delims=" %%a in ('#%LN% --list "%~1"') do (
del /f "%%a"
)
goto ausmausraus
:error
echo DeleteAllHardlinks: Argument is missing. Usage DeleteAllHardlinks ^<filename^>
echo e.g. DeleteAllHardlinks c:\data\myfile.txt
:ausmausraus
echo on
Thanks in advance!

Big thanks to Mofi!
The batch file could be very easily modified to support not just first argument, but all file name argument strings passed to the batch file by using one more for loop and %* as explained by call /?, i.e. use as replacement for the existing for loop:
for %%I in (%*) do for /F "delims=" %%J in ('ln.exe --list "%%~I" 2^>nul') do del /F "%%~J"
But the application starting the batch file has to pass each file name enclosed in double quotes to work properly.
Just using the for as offered in the comment solved the issue perfectly.

Related

Create Folder and SubFolder based on file name using batch file

Coding is not my speciality but I have come across a problem and google search has guided me to using batch file process in solving it. Essentially I have a couple of thousands of files that need to be moved into folders and they have a very simple file structure, listed below:
UK--London--Filename.pdf
UK--London--Filename2.pdf
UK--Manchester--Filename3.pdf
UK--Liverpool--Filename4.pdf
UK--Chester--Filename5.pdf
I would like the script to:
1. Pick up the first "--" check if the folder exists, if not create it
2. Pick up the second "--" check if the folder exists, if not create it
3. As there might be more than two "--", ignore the rest
4. Move file into the subfolder
To that end, the output should be some like (note "FILETEST" is the folder I am using to test the script):
C:\FILETEST\UK\London\UK--London--Filename.pdf
C:\FILETEST\UK\London\UK--London--Filename2.pdf
C:\FILETEST\UK\Manchester\UK--Manchester--Filename3.pdf
C:\FILETEST\UK\Liverpool\UK--Liverpool--Filename4.pdf
C:\FILETEST\UK\Chester\UK--Chester--Filename5.pdf
I have had an attempt to re-using a script from another question in stackoverflow (Batch create folders based on part of file name and move files into that folder). I understand that it would not do exactly what I need, but cant seem to get any output.
#ECHO OFF
SETLOCAL
SET "sourcedir=c:\FILETEST"
PUSHD %sourcedir%
FOR /f "tokens=1*delims=--" %%a IN (
'dir /b /a-d *.*.*'
) DO (
ECHO MD %%a
ECHO MOVE "%%a.%%b" --\%%a\
)
POPD
GOTO :EOF
Apologies for any headaches caused, I am hoping this is a simple one to solve.
Thank you,
Panos
#ECHO OFF
SETLOCAL
SET "sourcedir=c:\FILETEST"
PUSHD %sourcedir%
FOR /f "tokens=1,2*delims=-" %%a IN (
'dir /b /a-d *--*--*.*'
) DO if "%%c" neq "" (
ECHO MD "%%a"
ECHO MD "%%a\%%b"
ECHO MOVE "%%a--%%b--%%c" ".\%%a\%%b\"
)
POPD
GOTO :EOF
Read the directory list of files in the current directory, (/a-d = no directorynames) that match *--*--*. Tokenise so that %%a acquires the part before the first --sequence, %%b the second and %%c the remainder.
If %%c is not empty then make the directories ".\%%a" and ".\%%a\%%b" (quoted because any spaces in the name would otherwise be seen as "create two directories") then move the file, again quoted for the same reason.
Note that each character individually between delims= and the close-quote is a delimiter - a delimiter-string is not supported. Consequently, this code will pick up - as well as --- and any other sequence of - and try to process it. You could gate the create/move further by adding if exist "%%a--%%b--%%c" directly after the if "%%c" neq ""before the (.
The md will create a directory if the target name does not already exist, and produce an error-message if it already exists. To suppress the error message, append 2>nul to the md lines.

Batch script to remove "duplicate" files

I have a list of files named:
file.txt
file (1).txt
file (2).txt
etc.
Where the greater (number) is the last file updated.
I want a .bat script that allows get the content of file (maxnumer).txt to file.txt.
dir /B /OD /TW file*.txt lists file names in sort order of last written time (cf. dir /?).
Next commented batch script could do the job for you:
#echo OFF
SETLOCAL EnableExtensions
rem delete empty `_lastfile` variable
set "_lastfile="
rem store file name of last written time into `_lastfile` variable
for /F "delims=" %%G in ('dir /B /OD /TW file*.txt 2^>NUL') do set "_lastfile=%%~G"
rem ↑↑↑↑↑↑ suppress errors
rem check the `_lastfile` variable
rem is defined?
rem AND is different from "file.txt"?
if defined _lastfile if /I "%_lastfile%" NEQ "file.txt" copy /Y "%_lastfile%" "file.txt"
Resources (required reading):
(command reference) An A-Z Index of the Windows CMD command line
(additional particularities) Windows CMD Shell Command Line Syntax
(%~G etc. special page) Command Line arguments (Parameters)
(2>NUL etc. special page) Redirection
Here is a bit of a hacky answer.
This script will move all files from file (1).txt up to file (10).txt to file.txt , leaving only file.txt which now contains the text that was in file (10).txt
Doing it in ascending order will ensure the highest number that exists is the last one to be moved.
#echo off
set /P name=Enter name of file without extension:
echo enter extension:
set /P ext=.
echo. & echo.
echo these actions will be performed: & echo.
FOR /L %%A IN (1,1,10) DO #echo move /y "%name% (%%A).%ext%" "%name%.%ext%"
echo. & pause & echo.
FOR /L %%A IN (1,1,10) DO move /y "%name% (%%A).%ext%" "%name%.%ext%"
pause
You could use IF EXIST %name% (%%A).%ext% To stop the script from trying to move files that don't exist, but it doesn't really affect anything to do that, so I didn't bother.
The script above will do it for a specific named file. To do it for all files in a directory will be possible, here are some hints to get you going
use a dir /b >filenames.txt to get all files in a directory listed in a text file
to perform an action for every line in a textfile do
for /f "usebackq delims= tokens=* %%a in (`filenames.txt`)" DO (
::some stuff here
)
The way I would go about it would be to get filenames.txt , manually delete all the (n) files so you just have a list of the "non-duplicate" filenames, and use that as your input. You
There are probably more elegant solutions out there, but with all the peculiarities of batch I wouldn't be surprised to find they are pages and pages long.
If you want to keep all the original files not just end up with the final file.txt with no copies, then I you want to use COPY
If you want to keep all the original files, then you would want to use COPY not MOVE.
In that case, to remove all superfluous operations (i.e. only copy the highest numbered file, not copy all the files in order) then something like IF NOT EXIST %name% (!B!).%ext% where !B!=%%A+1 within your (now multiline) for loop and use Setlocal EnableDelayedExpansion on to make the arithmetic work properly. But it's not really necessary, copying 1, then 2, then 3, then 4 does the same thing if a little slower than skipping 1 2 and 3 and just doing 4.
I hope this helps enough to point you in the right direction, feel free to ask questions if this isn't clear.

Batch programing to search some file in sub folders

I have hundreds of csv files . csv files are stored in folders and sub ​​folders . I want to search fifty csv file whose file names have been determined , for example 1.csv , 2.csv , 3.csv , ... , 50.csv . very troublesome if I searched one by one using the Windows search tool . I would like if the files are found , save in the folder named FOUND . please help to overcome this problem by using the batch programming / bat ? thank you very much
There's a number of approaches one can take, depending on how much automation you require... To help you get started, you may want to look at this it helped me (and indeed continues to do so) when I started learning batch. Furthermore I will provide one possible template for achieving your objective, as I have interpreted it. Perhaps it is not the most elegant or efficient method, but it introduces a number of batch commands that you may or may not have encountered, which in turn may help you develop your own method.
#echo off
setlocal enabledelayedexpansion
echo Please enter a drive letter:
set /p "drive=>"
echo Please enter a search string:
set /p "searchstring=>"
echo %searchstring%>search.txt
set /p search=<search.txt
set /a suffix=0
echo.>>search.txt
:LOOP
for /f "tokens=*" %%i in ("search.txt") do (
set /a suffix=suffix+1
set seq=%search% !suffix!
echo !seq!>>search.txt
)
if !suffix! leq 49 goto LOOP
for /f "tokens=*" %%i in (search.txt) do (
for /f "tokens=*" %%j in ('dir /b /s /a-d %drive%:\"%%i.csv" 2^>nul') do (
if not exist "%~dp0\found" md "%~dp0\found"
move /y "%%j" "%~dp0\found\%%~nxj"
)
)
pause
This is not intended as a definitive solution, though you may find it answers your original query/request. All the best.
Here's another working solution for you..
#ECHO OFF
SETLOCAL EnableDelayedExpansion
REM First Set your directories input and output
SET InputDir=C:\Directory to your CSV files\
SET OutputDir=C:\Directory to your CSV files\FOUND
REM check if the FOUND directory exist, if not, then create it.
IF NOT EXIST OutputDir (
mkdir %OutputDir%
)
REM Grab a scan of the input directory and save it to a temporary file list.
Dir /a /b %InputDir%>"%OutputDir%\Found.txt"
REM Set the files you would like to find.
SET "File1=1.csv"
SET "File2=2.csv"
SET "File3=50.csv"
REM The loop, to process the matching file(s).
FOR %%A IN (%File1%,%File2%,%File3%) DO (
FOR /F "usebackq" %%B IN ("%OutputDir%\Found.txt") DO (
IF %%A==%%B (
copy "%InputDir%\%%A" "%OutputDir%\%%A"
)
)
)
REM Clean up the temp file list.
DEL "%OutputDir%\Found.txt"
Make note, I didn't add quotes to the Input and Output variables, but instead added quotes to the copy portion of the code to compensate for white spaces in your directory path. I tried to keep it simple, so you could follow the logic of how it processed what you are looking for, you can now modify this to your liking.. Have fun. Cheers!

Windows batch file: get last folder name from path

I'm trying to rename .jpg files which is in one of many subdirectories of e:\study\pubpmc\test\extracted.
I want to rename files to LastFolderName_ImageName.jpg.
(For example if Figure1.jpg is in e:\study\pubpmc\test\extracted\folder1
I want it to be renamed like this: folder1_Figure1.jpg)
So I need to take out the last folder name from the file's path.
Since it's my first time with batch scripting, I'm having a hard time.
I googled and made code similar to it
but it doesn't seem to work out.
Can you help me with it and tell me where I've done wrong?
Thank you! :)
#echo off
cd /D "e:\study\pubpmc\test\extracted"
for /r %%f in (*.jpg) do (
set mydir=%%~dpf
set mydir=%mydir:\=;%
for /f "tokens=* delims=;" %%i in (%mydir%) do call :LAST_FOLDER %%i
goto :EOF
:LAST_FOLDER
if "%1"=="" (
#echo %LAST%
goto :EOF
)
set LAST=%1
SHIFT
goto :LAST_FOLDER
)
JosefZ explains the obvious problems with your code, but he failed to point out a subtle problem, though his code fixed it:
FOR /R (as well as the simple FOR) begin iterating immediately, before it has finished scanning the disk drive. It is possible for the loop to reiterate the already named file! This would cause it to be renamed twice, giving the wrong result. The solution is to use FOR /F with command 'DIR /B', because FOR /F always processes the command to completion before iterating.
JosefZ also provides code that works for most situations. But there is a much simpler solution that works always:
#echo off
for /f "delims=" %%A in (
'dir /b /s /a-d "e:\study\pubpmc\test\extracted\*.jpg"'
) do for %%B in ("%%A\..") do ren "%%A" "%%~nxB_%%~nxA"
The "%%A\.." treats the file name as a folder and walks up to the parent folder. So %%~nxB gives the name of the parent folder.
The command could be run as a long one liner, directly from the command line (no batch):
for /f "delims=" %A in ('dir /b /s /a-d "e:\study\pubpmc\test\extracted\*.jpg"') do #for %B in ("%A\..") do #ren "%A" "%~nxB_%~nxA"
Avoid using :label and :: label-like comment inside (command block in parentheses). Using any of them within parentheses - including FOR and IF commands - will break their context.
Using variables inside (command block in parentheses). Read EnableDelayedExpansion: Delayed Expansion will cause variables to be expanded at execution time rather than at parse time [and CLI parses all the (command block in parentheses) at once]
Next script should work for you. Note rename statement is merely echoed for debugging purposes.
#ECHO OFF >NUL
SETLOCAL enableextensions disabledelayedexpansion
set "fromFolder=e:\study\pubpmc\test\extracted"
rem my debug setting set "fromFolder=D:\path"
for /F "tokens=*" %%f in ('dir /B /S /A:D "%fromFolder%\*.*"') do (
set "mydir=%%~ff"
set "last=%%~nxf"
call :renameJPG
)
#ENDLOCAL
goto :eof
:renameJPG
rem echo "%mydir%" "%last%"
for /f "tokens=*" %%i in ('dir /B /A:-D "%mydir%\*.jpg" 2^>nul') do (
echo ren "%mydir%\%%~nxi" "%last%_%%~nxi"
)
goto :eof
Resources:
SETLOCAL, disableDelayedExpansion, ENDLOCAL etc.
An A-Z Index of the Windows CMD command line
Windows CMD Shell Command Line Syntax
I already wrote a function for that. You give it any path and it returns you only it's filename or pathname. Works for any path: Url, Windows path, Linux path, etc...
Copy this function at the end of your batch script: (Instructions below)
rem ===========================================================================
:Name_From_Path
SetLocal
set _TMP_FOLDERNAME=%1
for %%g in ("%_TMP_FOLDERNAME%") do set _TMP_FOLDERNAME=%%~nxg
EndLocal & set _Name_From_Path=%_TMP_FOLDERNAME%
goto :EOF
rem ===========================================================================
Usage:
CALL :Name_Of_Path e:\study\pubpmc\test\extracted\folder1
ECHO %_Name_From_Path%
Result: folder1
If your program or com file traverses these folders when renaming, then it should be able to get the present working directory ( path ), pwd. You may be able to chop everything but the LAST_FOLDER out of this by also creating a PREVIOUS_FOLDER and doing a string replacement.
Or you may be able to break the folder names at the '\' token from the pwd into an array and use a -1 array reference to get the last folder name.
In any circumstance you'll want to check for a present working directory command.
If your creating a large text list of all these and issuing a single call to the batch file.
Then you may be better off with something like:
(Symmantic code warning )
(copy) /folderbase/some_folder/oneormore1/image_from_oneormore1.jpg (to) /folderbase/some_folder/oneormore1/oneormore1_image_from_oneormore1.jpg
Instead of copy, window uses rename, linux uses mv.
The latter example would require simply creating a duplicate list and replacing the \ with a _ while parsing through the tokens.
The code you've given is difficult to make sense of, so its hard to discern if you can simple concatenate the current folder and image name (stringify) and then write or rename them where they are.

How do I exclude specific file names from an MS DOS dir list?

I am creating an MS DOS batch script that needs to list every .bat file in the current directory, but not show autoexec.bat or other utilities or systems .bat files that shouldn't be run by the user.
I currently have DIR "*.bat" /B /P
This lists all .bat files appropriately, but it shows autoexec.bat. How would I exclude that from the list? Also slightly important, how could I chop off the file extensions and show more than the 7-characters DOS limits files to?
Constraints: I am not able to use a DOS version above WinME. That is the version I am using.
Thanks for any help.
EDIT:
There is plenty of information on the internet about doing this, but it is all in the windows command processor, not MS DOS. Please understand that DOS and the Command Prompt are not the same thing.
#echo off
setlocal EnableDelayedExpansion
rem Add more names separated with slashes here:
set exclude=/autoexec/
for %%a in (*.bat) do (
if "!exclude:/%%~Na/=!" equ "%exclude%" (
echo %%~Na
)
)
EDIT: Some explanations added
Batch file processing is slow, so you should use techniques that allows a Batch file to run faster. For example:
Try to use the minimum lines/commands to achieve a certain result. Try to avoid external commands (*.exe files) like find, findstr, fc, etc. specially if they work on small amounts of data; use if command instead.
Use for %%a in (*.bat)... instead of for /F %%a in ('dir /B *.bat').... The second method requires to execute cmd.exe and store its output in a file before for command can process its lines.
Avoid pipes and use redirections instead. A pipe require the execution of two copies of cmd.exe to process the command at each side of the pipe.
A simple way to check if a variable contain a given string is trying to delete the string from the variable: if the result is different then the string exists in the variable: if "!variable:%string%=!" neq "%variable%" echo The string is in the variable.
Previous method may also be used to check if a variable have anyone of a list of values: set list=one two three, if "!list:%variable%=!" neq "%list%" echo The variable have one value from the list. If the values of the list may have spaces, they must be separated by another delimiter.
EDIT: New version added as answer to new comments
The easiest way to pause one page at a time is to use more filter this way:
theBatchFile | more
However, the program must reorder the output in order to show it in columns. The new version below achieve both things, so it does not require more filter; you just need to set the desired number of columns and rows per page.
#echo off
setlocal EnableDelayedExpansion
rem Add more names separated with slashes here:
set exclude=/autoexec/
rem Set the first two next variables as desired:
set /A columns=5, rows=41, wide=(80-columns)/columns, col=0, row=0
rem Create filling spaces to align columns
set spaces=
for /L %%a in (1,1,%wide%) do set spaces= !spaces!
set line=
for %%a in (*.bat) do (
if "!exclude:/%%~Na/=!" equ "%exclude%" (
rem If this column is less than the limit...
set /A col+=1
if !col! lss %columns% (
rem ... add it to current line
set name=%%~Na%spaces%
set "line=!line!!name:~0,%wide%! "
) else (
rem ... show current line and reset it
set name=%%~Na
echo !line!!name:~0,%wide%!
set line=
set /a col=0, row+=1
rem If this row is equal to the limit...
if !row! equ %rows% (
rem ...do a pause and reset row
pause
set row=0
)
)
)
)
rem Show last line, if any
if defined line echo %line%
Antonio
attrib +h autoexec.bat
should hide autoexec.bat and it should thus not appear in the list
DIR "*.bat" /B /P | find /v "autoexec" | for %i in (*.bat) do #echo %~ni
Using for to process each file name individually:
setlocal enabledelayedexpansion
for /f %%i in ('dir "*.bat" /b') do (
set system=0
if "%%i"=="autoexec.bat" set system=1
if "%%i"=="somesystem.bat" set system=1
if !system!==0 echo %%i
)
Another method without variables:
for /f %%i in ('dir "*.bat" /b') do call :test %%i
goto continue
:test
if "%1"=="autoexec.bat" goto :eof
if "%1"=="somesystem.bat" goto :eof
echo %1
goto :eof
:continue
For both, you can add new filenames to exclude from the list.

Resources