MongoDB Array Query - Single out an array element - arrays

I am having trouble with querying a MongoDB collection with an array inside.
Here is the structure of my collection that I am querying. This is one record:
{
"_id": "abc123def4567890",
"profile_id": "abc123def4567890",
"image_count": 2,
"images": [
{
"image_id": "ABC123456789",
"image_url": "images/something.jpg",
"geo_loc": "-0.1234,11.234567890",
"title": "A Title",
"shot_time": "01:23:33",
"shot_date": "11/22/2222",
"shot_type": "scenery",
"conditions": "cloudy",
"iso": 16,
"f": 2.4,
"ss": "1/545",
"focal": 6.0,
"equipment": "",
"instructions": "",
"upload_date": 1234567890,
"update_date": 1234567890
},
{
"image_id": "ABC123456789",
"image_url": "images/something.jpg",
"geo_loc": "-0.1234,11.234567890",
"title": "A Title",
"shot_time": "01:23:33",
"shot_date": "11/22/2222",
"shot_type": "portrait",
"conditions": "cloudy",
"iso": "16",
"f": "2.4",
"ss": "1/545",
"focal": "6.0",
"equipment": "",
"instructions": "",
"upload_date": 1234567890,
"update_date": 1234567890
}
]
}
Forgive the formatting, I didn't know how else to show this.
As you can see, it's a profile with a series of images within an array called 'images' and there are 2 images. Each of the 'images' array items contain an object of attributes for the image (url, title, type, etc).
All I want to do is to return the object element whose attributes match certain criteria:
Select object from images which has shot_type = "scenery"
I tried to make it as simple as possible so i started with:
find( { "images.shot_type": "scenery" } )
This returns the entire record and both the images within. So I tried projection but I could not isolate the single object within the array (in this case object at position 0) and return it.
I think the answer lies with projection but I am unsure.
I have gone through the MongoDB documents for hours now and can't find inspiration. I have read about $elemMatch, $, and the other array operators, nothing seems to allow you to single out an array item based on data within. I have been through this page too https://docs.mongodb.com/manual/tutorial/query-arrays/ Still can't work it out.
Can anyone provide help?
Have I made an error by using '$push' to populate my images field (making it an array) instead of using '$set' which would have made it into an embedded document? Would this have made a difference?

Using aggregation:
db.collection.aggregate({
$project: {
_id: 0,
"result": {
$filter: {
input: "$images",
as: "img",
cond: {
$eq: [
"$$img.shot_type",
"scenery"
]
}
}
}
}
})
Playground

You can use $elemMatch in this way (simplified query):
db.collection.find({
"profile_id": "1",
},
{
"images": {
"$elemMatch": {
"shot_type": 1
}
}
})
You can use two objects into find query. The first will filter all document and will only get those whose profile_id is 1. You can omit this stage and use only { } if you wnat to search into the entire collection.
Then, the other object uses $elemMatch to get only the element whose shot_type is 1.
Check an example here

Related

Mongodb - Take only one element in nested array

I'm using mongodb to store my data. My collection consists in a list of objects identified by a type a list of other objects for each of them.
An example of my collection is:
[
{
"type": "a",
"properties": [
{
"value": "value_a",
"date": "my_date_a"
},
{
"value": "value_b",
"date": "my_date_b"
},
...
]
},
...
]
Based on the above data structure, I want to retrieve all collections by a given type, taking for each of them only one element in the nested array (reducing the nested list to a list of only one element).
So, given a type "a", an example of the result may be:
[
{
"type": "a",
"properties": [
{
"value": "value_a",
"date": "my_date_a"
}
]
},
...
]
I'm started trying this query { "type": "a" } to filter the collections. But, how can I do to take only one "properties" element? I cannot use the "slice" operator.
Thanks a lot.
I'm assuming from your reference to slice, that you're not interested in matching a particular nested element, and rather just getting a value at a fixed index (eg, 0).
If you're willing to use the aggregation pipeline, you can use arrayElementAt within a projection:
db.collection.aggregate([
// matches documents with type 'a'
{ $match: { type: 'a' } },
// creates a new document for each
{ $project: {
// that contains the original value for type
type: 1,
// and the first element from the original properties for properties
properties: { $arrayElemAt: [ "$properties", 0 ] }
} }
])

Query an array of users based on an array of users

Basically I'm having trouble understanding how I would figure this out.
I have a document in a mongodb collection, and that document has field called friends which is an array of usernames.
I want to query through each username in the array friends, and have an array of those user documents. I'm terrible at explaining maybe if I draw this out it'll make sense.
mongodb document:
{
"_id": {
"$oid": "59a20e65f94cb5e924af774e"
},
"name": "Nick",
"friends": ["Jones","Mark","Mike"]
}
Now with this friends array, I want to search the same collection for an object with the "name" Jones, Mark, and Mike. When I find that object, I want to put it into an array.
Basically I want it to return this, (for this example let's say Jones, Mark, and Mike only have one friend, and that friend is Nick.
[{
"_id": {
"$oid": "59a20e65f94cb5e924af774e"
},
"name": "Jones",
"friends": ["Nick"]
},
{
"_id": {
"$oid": "59a20e65f94cb5e924af774e"
},
"name": "Mark",
"friends": ["Nick"]
},
{
"_id": {
"$oid": "59a20e65f94cb5e924af774e"
},
"name": "Mike",
"friends": ["Nick"]
}]
^ an array of three objects, which are all the friends of Nick.
If you need any more explanation please let me know, I'm terrible at this type of stuff.
For the record, I'm using node, and basic mongodb (not mongoose).
I believe you are looking for $in operator.
// doc.friends = ["Jones","Mark","Mike"]
db.collection.find({ name: { $in: doc.friends }})

How to projection element in array field of MongoDb collection?

MongoDb Collection Example (Person):
{
"id": "12345",
"schools": [
{
"name": "A",
"zipcode": "12345"
},
{
"name": "B",
"zipcode": "67890"
}
]
}
Desired output:
{
"id": "12345",
"schools": [
{
"zipcode": "12345"
},
{
"zipcode": "67890"
}
]
}
My current partial code for retrieving all:
collection.find({}, {id: true, schools: true})
I am querying the entire collection. But I only want to return zipcode part of school element, not other fields (because the actual school object might contain much more data which I do not need). I could retrieve all and remove those un-needed fields (like "name" of school) in code, but that's not what I am looking for. I want to do a MongoDb query.
You can use the dot notation to project specific fields inside documents embedded in an array.
db.collection.find({},{id:true, "schools.zipcode":1}).pretty()

Multiple search filtering is not working in cloudant, why?

Here i quoted my code for multiple search filtering. I could not find the mistakes in that. please give a right code to make it work well.
Employee document:
{
"_id": "527c8d9327c6f27f17df0d2e17000530",
"_rev": "24-276a8dc913559901897fd601d2f9654f",
"proj_role": "TeamMember",
"work_total_experience": "3",
"personal": {
"languages_known": [
"English","Telugu"
]},
"skills": [
{
"skill_set": "Webservices Framework",
"skill_exp": 1,
"skill_certified": "yes",
"skill_rating": 3,
},
{
"skill_set": "Microsoft",
"skill_exp": 1,
"skill_certified": "yes",
"skill_rating": 3,
}
]
"framework_competency": "Nasscom",
"type": "employee-docs"
}
Design Document:
{
"_id": "_design/sample",
"_rev": "86-1250f792e6e84f6f33447a00cf64d61d",
"views": {},
"language": "javascript",
"indexes": {
"search": {
"index": "function(doc){\n index(\"default\", doc._id);if(doc.type=='employee-docs'){\nif (doc.proj_role){index(\"project_role\", doc.proj_role);}if(doc.work_total_experience){\nindex(\"work_experience\", doc.work_total_experience);}\nif(doc.personal.languages_known){for(c in doc.personal.languages_known){ \n index(\"languages_known\",doc.personal.languages_known[c]);}} if(doc.skills){for (var i=0;i<doc.skills.length;i++){\nindex('skill_set',doc.skills[i].skill_set);}}}}"
}
}
}
Run using below URL : https://ideyeah4.cloudant.com/opteamize_new/_design/sample/_search/search?q=project_role:TeamMember%20AND%20work_experience:%223%22%20AND%20languages_known:Telugu%20AND%20skill_set:Microsoft&include_docs=true
A simple way to debug this is to query the top 100 results in your index:
https://ideyeah4.cloudant.com/opteamize_new/_design/sample/_search/search?q=*:*&limit=100
This will at least tell you whether there are any documents in your index at all.
Your current query (without URL encoding) looks like:
project_role:TeamMember AND work_experience:"3" AND languages_known:Telugu AND skill_set:Microsoft
I'd suggest that some of these search values require quotes - always true when you are searching string values. Next, you could try:
project_role:"TeamMember"
see if you get any results and refine from there.
Debugging this might also be easier if you store the values as well as index them (so you can see exactly what is indexed). To do this, add an object to each index call { "store": true }. For example,
index("languages_known", doc.personal.languages_known[c], { "store": true });
Now, when you query the index it will return a list of fields which were stored with each match.

Mapping an array inside an array with a JSON Reader

My JSON looks as follows:
{
"records": [
{
"_id": "5106f97bdcb713b818d7f1f1",
"cn": "lsacco",
"favorites": [
{
"fullName": "Friend One",
"uid": "friend1"
},
{
"fullName": "Friend Two",
"uid": "friend2"
}
]
}
]
}
When I try to use records.favorites as the root for my JSON reader, I do not get any results populated to my model. Is there a way to do this without having to resort to using an association? Note that in my case, records will only have one element despite it showing an array.
records.favorites isn't valid because the property doesn't exist.
You want:
records[0].favorites
records has been declared as an array so records.favorites will point to nothing in the json data file.
using the index in records should solve the problem.

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