Hello I am doing a looping on my code with fgets and I want that when user introduces the word "bye" the program ends, so I have a do while like this:
char buf[1000]
do{
fgets(buf, 1000, stdin);
//More code here
while(strcmp(buf, "bye")!=0);
But I have a problem that it is, when user made a space or a tab or multiple spaces before write bye the strcmp doesnt recognize him as bye, so the program only exits when users only type bye without any previous space or tab.
I want to know how can I prevent the spaces or tabs before the by word to exits if user type for example:
' bye'
fgets reads in a complete line, including any starting white spaces and also including the new line character at the end of the line. Even if a user does not enter preceding white spaces, the content of buf is likely to be "bye\n", such that buf will hardly compare equal to "bye" when using strcmp.
I'd suggest to scan the buffer for a single word using sscanf and compare this word to "bye" then. Note that scanf("%s"...) skips white space characters at the beginning of a word and stops before the first white space after the word.
char isStopWord[20];
isStopWord[0] = '\0';
sscanf(buf,"%19s",isStopWord);
}
while(strcmp(isStopWord, "bye")!=0);
It a very strange requirement to use strcmp to remove characters from the array but everything is possible :)
char *removeSpacesAndTabsBeginning(char *str)
{
size_t len;
char savedc;
if(str && *str)
{
len = strlen(str);
savedc = str[1];
str[1] = 0;
while(!strcmp(str, " "))
{
str[1] = savedc;
memmove(str, str + 1, len);
savedc = str[1];
str[1] = 0;
}
str[1] = savedc;
}
return str;
}
int main(void)
{
char z[] = " \t\tHello World.";
printf("`%s`\n", removeSpacesAndTabsBeginning(z));
}
If you want to know if the string contains "bye" use strstr.
int isBye(const char *str)
{
return !!strstr(str, "bye");
}
There are 2 problems in your code:
you should test the return value of fgets() to detect unexpected end of file.
you should ignore whitespace in the comparison. You should just trim the string read by fgets() as the other code probably does not handle these either.
#include <ctype.h>
#include <stdio.h>
#include <string.h>
int main() {
char buf[1000];
while (fgets(buf, sizeof buf, stdin)) {
size_t i = 0, length = strlen(buf);
/* trim trailing white space */
while (length > 0 && isspace((unsigned char)buf[length - 1])) {
buf[--length] = '\0';
}
/* trim leading white space */
while (isspace((unsigned char)buf[i]) {
i++;
}
if (i > 0) {
memmove(buf, buf + i, length - i + 1);
}
// check for end command
if (!strcmp(buf, "bye"))
break;
//More code here: handle other commands
//...
}
return 0;
}
Related
I am writing my own trim() in C. There is a structure which contains all string values, the structure is getting populated from the data coming from a file which contains spaces before and after the beginning of a word.
char *trim(char *string)
{
int stPos,endPos;
int len=strlen(string);
for(stPos=0;stPos<len && string[stPos]==' ';++stPos);
for(endPos=len-1;endPos>=0 && string[endPos]==' ';--endPos);
char *trimmedStr = (char*)malloc(len*sizeof(char));
strncpy(trimmedStr,string+stPos,endPos+1);
return trimmedStr;
}
int main()
{
char string1[]=" a sdf ie ";
char *string =trim(string1);
printf("%s",string);
return 0;
}
Above code is working fine, but i don't want to declare new variable that stores the trimmed word. As the structure contains around 100 variables.
Is there any way to do somthing like below where I dont need any second variable to print the trimmed string.
printf("%s",trim(string1));
I believe above print can create dangling pointer situation.
Also, is there any way where I don't have to charge original string as well, like if I print trim(string) it will print trimmed string and when i print only string, it will print original string
elcuco was faster. but it's done so here we go:
char *trim(char *string)
{
char *ptr = NULL;
while (*string == ' ') string++; // chomp away space at the start
ptr = string + strlen(string) - 1; // jump to the last char (-1 because '\0')
while (*ptr == ' '){ *ptr = '\0' ; ptr--; } ; // overwrite with end of string
return string; // return pointer to the modified start
}
If you don't want to alter the original string I'd write a special print instead:
void trim_print(char *string)
{
char *ptr = NULL;
while (*string == ' ') string++; // chomp away space at the start
ptr = string + strlen(string) - 1; // jump to the last char (-1 because '\0')
while (*ptr == ' '){ ptr--; } ; // find end of string
while (string <= ptr) { putchar(*string++); } // you get the picture
}
something like that.
You could the original string in order to do this. For trimming the prefix I just advance the pointer, and for the suffix, I actually add \0. If you want to keep the original starting as is, you will have to move memory (which makes this an O(n^2) time complexity solution, from an O(n) I provided).
#include <stdio.h>
char *trim(char *string)
{
// trim prefix
while ((*string) == ' ' ) {
string ++;
}
// find end of original string
char *c = string;
while (*c) {
c ++;
}
c--;
// trim suffix
while ((*c) == ' ' ) {
*c = '\0';
c--;
}
return string;
}
int main()
{
char string1[] = " abcdefg abcdf ";
char *string = trim(string1);
printf("String is [%s]\n",string);
return 0;
}
(re-thinking... is it really O(n^2)? Or is it O(2n) which is a higher O(n)...? I guess depending on implementation)
You can modify the function by giving the output in the same input string
void trim(char *string)
{
int i;
int stPos,endPos;
int len=strlen(string);
for(stPos=0;stPos<len && string[stPos]==' ';++stPos);
for(endPos=len-1;endPos>=0 && string[endPos]==' ';--endPos);
for (i=0; i<=(endPos-stPos); i++)
{
string[i] = string[i+stPos];
}
string[i] = '\0'; // terminate the string and discard the remaining spaces.
}
...is there any way where i don't have to charge original string as well, like if i do trim(string) it will print trimmed string and when i print only string, it will print original string – avinashse 8 mins ago
Yes, though it gets silly.
You could modify the original string.
trim(string);
printf("trimmed: %s\n", string);
The advantage is you have the option of duplicating the string if you want to retain the original.
char *original = strdup(string);
trim(string);
printf("trimmed: %s\n", string);
If you don't want to modify the original string, that means you need to allocate memory for the modified string. That memory then must be freed. That means a new variable to hold the pointer so you can free it.
char *trimmed = trim(original);
printf("trimmed: %s\n", trimmed);
free(trimmed);
You can get around this by passing a function pointer into trim and having trim manage all the memory for you.
#include <string.h>
#include <stdlib.h>
#include <stdio.h>
void trim(char *string, void(*func)(char *) )
{
// Advance the pointer to the first non-space char
while( *string == ' ' ) {
string++;
}
// Shrink the length to the last non-space char.
size_t len = strlen(string);
while(string[len-1]==' ') {
len--;
}
// Copy the string to stack memory
char trimmedStr[len + 1];
strncpy(trimmedStr,string, len);
// strncpy does not add a null byte, add it ourselves.
trimmedStr[len] = '\0';
// pass the trimmed string into the user function.
func(trimmedStr);
}
void print_string(char *str) {
printf("'%s'\n", str);
}
int main()
{
char string[]=" a sdf ie ";
trim(string, print_string);
printf("original: '%s'\n", string);
return 0;
}
Ta da! One variable, the original is left unmodified, no memory leaks.
While function pointers have their uses, this is a bit silly.
It's C. Get used to managing memory. ¯\_(ツ)_/¯
Also, is there any way where I don't have to charge original string as
well, like if I print trim(string) it will print trimmed string and
when i print only string, it will print original string
Yes you can, but you cannot allocate new memory in the trim function as you will not be holding the return memory.
You can have a static char buffer in the trim function and operate on it.
Updated version of #elcuco answer.
#include <stdio.h>
char *trim(char *string)
{
static char buff[some max length];
// trim prefix
while ((*string) == ' ' ) {
string++;
}
// find end of original string
int i = 0;
while (*string) {
buff[i++] = *string;
string++;
}
// trim suffix
while ((buff[i]) == ' ' ) {
buff[i] = '\0';
i--;
}
return buff;
}
int main()
{
char string1[] = " abcdefg abcdf ";
char *string = trim(string1);
printf("String is [%s]\n",string);
return 0;
}
With this you don't need to worry about holding reference to trim function return.
Note: Previous values of buff will be overwritten with new call to trim function.
If you don't want to change the original, then you will need to make a copy, or pass a second array of sufficient size as a parameter to your function for filling. Otherwise a simple in-place trmming is fine -- so long as the original string is mutable.
An easy way to approach trimming on leading and trailing whitespace is to determine the number of leading whitespace characters to remove. Then simply use memmove to move from the first non-whitespace character back to the beginning of the string (don't forget to move the nul-character with the right portion of the string).
That leaves only removing trailing whitespace. An easy approach there is to loop from the end of the string toward the beginning, overwriting each character of trailing whitespace with a nul-character until your first non-whitespace character denoting the new end of string is found.
A simple implementation for that could be:
#include <stdio.h>
#include <string.h>
#include <ctype.h>
#define DELIM " \t\n" /* whitespace constant delimiters for strspn */
/** trim leading and trailing whitespace from s, (s must be mutable) */
char *trim (char *s)
{
size_t beg = strspn (s, DELIM), /* no of chars of leading whitespace */
len = strlen (s); /* length of s */
if (beg == len) { /* string is all whitespace */
*s = 0; /* make s the empty-string */
return s;
}
memmove (s, s + beg, len - beg + 1); /* shift string to beginning */
for (int i = (int)(len - beg - 1); i >= 0; i--) { /* loop from end */
if (isspace(s[i])) /* checking if char is whitespace */
s[i] = 0; /* overwrite with nul-character */
else
break; /* otherwise - done */
}
return s; /* Return s */
}
int main (void) {
char string1[] = " a sdf ie ";
printf ("original: '%s'\n", string1);
printf ("trimmed : '%s'\n", trim(string1));
}
(note: additional intervening whitespace was added to your initial string to show that multiple intervening whitespace is left unchanged, the output is single-quoted to show the remaining text boundaries)
Example Use/Output
$ ./bin/strtrim
original: ' a sdf ie '
trimmed : 'a sdf ie'
Look things over and let me know if you have further questions.
I have created a function that reverses all the words in a sentence, meaning that if the input is "Hello World" the output is supposed to be "World Hello". The code below is the function.
char* reversesentence(char sent[]) {
int lth = strlen(sent);
int i;
for(i = lth -1; i >= 0; i--) {
if(sent[i] == ' ') {
sent[i] = '\0';
printf("%s ", &(sent[i]) + 1);
}
}
printf("%s", sent);
}
In the main I am trying to ask the user for the sentence and calling the function in the main.
int main(void)
{
char sentence[2000];
printf("Please enter the sentence you want to be reversed.\n");
scanf("%s", sentence);
reversesentence(sentence);
printf("%s", sentence);
}
It seems that the array is only storing the first word of the sentence only.
Output:
Please enter the sentence you want to be reversed.
hello my name is
hellohello
Process finished with exit code 0`
Can someone help me fix this please? Searched online and found nothing useful.
scanf stops reading when it occurs whitespace,tabs or newline.
Matches a sequence of non-white-space characters; the next pointer
must be a pointer to character array that is long enough to hold the
input sequence and the terminating null byte ('\0'), which is added
automatically. The input string stops at white space or at the maximum
field width, whichever occurs first.
Thus you are not reading the entire string as you input.
Try using fgets as below.
fgets(sentence, sizeof(sentence), stdin);
Note fgets appends \n to end of the string. see how to trim the
new line from
fgets
You have two problems
as it was already said you only read one word using scanf
reversesentence just replace all spaces by a null character, so even you read a full line you cut it at the first space. so if you enter "hello world" the result will be "hello", and if you enter " hello world" the result will be an empty string
The simple way is to read words using scanf in a loop until it returns EOF, memorizing them, to at the end produce the list of words returned
For instance :
#include <stdlib.h>
#include <string.h>
int main()
{
size_t len = 0;
char * result = 0;
char word[256];
while (scanf("%256s", word) != EOF) {
if (result == 0) {
result = strdup(word);
len = strlen(word);
}
else {
size_t l = strlen(word);
char * r = malloc(len + l + 2);
strcpy(r, word);
r[l] = ' ';
strcpy(r + l + 1, result);
free(result);
result = r;
len += l + 1;
}
}
puts(result);
free(result);
return 0;
}
The reading finishes at the end of the input (^d under a linux shell), the words can be given on several lines.
With the input
hello world
how
are you
?
that prints
? you are how world hello
Is there any efficient (- in terms of performance) way for printing some arbitrary string, but only until the first new line character in it (excluding the new line character) ?
Example:
char *string = "Hello\nWorld\n";
printf(foo(string + 6));
Output:
World
If you are concerned about performance this might help (untested code):
void MyPrint(const char *str)
{
int len = strlen(str) + 1;
char *temp = alloca(len);
int i;
for (i = 0; i < len; i++)
{
char ch = str[i];
if (ch == '\n')
break;
temp[i] = ch;
}
temp[i] = 0;
puts(temp);
}
strlen is fast, alloca is fast, copying the string up to the first \n is fast, puts is faster than printf but is is most likely far slower than all three operations mentioned before together.
size_t writetodelim(char const *in, int delim)
{
char *end = strchr(in, delim);
if (!end)
return 0;
return fwrite(in, 1, end - in, stdout);
}
This can be generalized somewhat (pass the FILE* to the function), but it's already flexible enough to terminate the output on any chosen delimiter, including '\n'.
Warning: Do not use printf without format specifier to print a variable string (or from a variable pointer). Use puts instead or "%s", string.
C strings are terminated by '\0' (NUL), not by newline. So, the functions print until the NUL terminator.
You can, however, use your own loop with putchar. If that is any performance penalty is to be tested. Normally printf does much the same in the library and might be even slower, as it has to care for more additional constraints, so your own loop might very well be even faster.
for ( char *sp = string + 6 ; *sp != '\0'; sp++ ) {
if ( *sp == '\n' ) break; // newline will not be printed
putchar(*sp);
}
(Move the if-line to the end of the loop if you want newline to be printed.)
An alternative would be to limit the length of the string to print, but that would require finding the next newline before calling printf.
I don't know if it is fast enough, but there is a way to build a string containing the source string up to a new line character only involving one standard function.
char *string = "Hello\nWorld\nI love C"; // Example of your string
static char newstr [256]; // String large enough to contain the result string, fulled with \0s or NULL-terimated
sscanf(string + 6, "%s", newstr); // sscanf will ignore whitespaces
sprintf(newstr); // printing the string
I guess there is no more efficient way than simply looping over your string until you find the first \n in it. As Olaf mentioned it, a string in C ends with a terminating \0 so if you want to use printf to print the string you need to make sure it contains the terminating \0 or yu could use putchar to print the string character by character.
If you want to provide a function creating a string up to the first found new line you could do something like that:
#include <stdio.h>
#include <string.h>
#define MAX 256
void foo(const char* string, char *ret)
{
int len = (strlen(string) < MAX) ? (int) strlen(string) : MAX;
int i = 0;
for (i = 0; i < len - 1; i++)
{
if (string[i] == '\n') break;
ret[i] = string[i];
}
ret[i + 1] = '\0';
}
int main()
{
const char* string = "Hello\nWorld\n";
char ret[MAX];
foo(string, ret);
printf("%s\n", ret);
foo(string+6, ret);
printf("%s\n", ret);
}
This will print
Hello
World
Another fast way (if the new line character is truly unwanted)
Simply:
*strchr(string, '\n') = '\0';
My program reads in a text file line by line and prints out the largest word in each sentence line. However, it sometimes prints out previous highest words although they have nothing to do with the current sentence and I reset my char array at the end of processing each line. Can someone explain to me what is happening in memory to make this happen? Thanks.
//Program Written and Designed by R.Sharpe
//LONGEST WORD CHALLENGE
//Purpose: Find the longest word in a sentence
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "memwatch.h"
int main(int argc, char** argv)
{
FILE* file;
file = fopen(argv[1], "r");
char* sentence = (char*)malloc(100*sizeof(char));
while(fgets(sentence, 100, file) != NULL)
{
//printf("%s\n", sentence);
char sub[100];
char maxWord[100];
strncpy(sub, sentence, strlen(sentence)-1);
strcpy(sentence, sub);
char* word;
int maxLength = 0;
word = strtok(sentence, " ");
while(word != NULL)
{
if(strlen(word) > maxLength)
{
maxLength = strlen(word);
strcpy(maxWord, word);
//printf("%s\n", maxWord);
}
word = strtok(NULL, " ");
}
printf("%s\n", maxWord);
memset(maxWord, 0, sizeof(char));
maxLength = 0; //reset for next sentence;
}
free(sentence);
return 0;
}
my text file contains . .
some line with text
another line of words
Jimmy John took the a apple and something reallyreallylongword it was nonsense
test test BillGatesSteveJobsWozWasMagnificant
a b billy
the output of the program is . .
some
another
reallyreallylongword
BillGatesSteveJobsWozWasMagnificantllyreallylongword
BillGatesSteveJobsWozWasMagnificantllyreallylongword //should be billy
Also when I arbitrarily change the length of the 5th sentence the last word sometimes
comes out to be "reallyreallylongword" which is odd.
EDIT: Even when I comment MEMSET out I still get the same result so it may not have anything to do with memset but not completely sure
Trailing NULL bytes (\0) are the bane of string manipulation. You have a copy sequence that is not quite doing what you desire of it:
strncpy(sub, sentence, strlen(sentence)-1);
strcpy(sentence, sub);
Sentence is copied into sub, and then back again. Except, strncpy does not copy the '\0' out of sentence. When you copy the string from sub back into sentence, you are copying an unknown length of data back into sentence. Because the stack is being reused and the char arrays are uninitialized, the data is likely residing there from the previous iteration and thus being seen by the next execution.
Adding the following between the two strcpys fixes the problem:
sub[strlen(sentence) - 1] = '\0';
You've got a missing null terminator.
char sub[100];
char maxWord[100];
strncpy(sub, sentence, strlen(sentence)-1);
strcpy(sentence, sub);
When you strncpy, if src is longer than the number of characters to be copied, no null terminator is added. You've guaranteed this is the case, so sub has no terminator, and you're rapidly running into behavior you don't want. It looks like you're trying to trim the last character from the string; the easier way to do that is simply set the character at index strlen(sentence)-1 to '\0'.
This is bad:
strncpy(sub, sentence, strlen(sentence)-1);
strcpy(sentence, sub);
The strncpy function does not null-terminate its buffer if the source string doesn't fit. By doing strlen(sentence)-1 you guaranteed it doesn't fit. Then the strcpy causes undefined behaviour because sub isn't a string.
My advice is to not use strncpy, it is almost never a good solution to a problem. Use strcpy or snprintf.
In this case you never even use sub so you could replace these lines with:
sentence[ strlen(sentence) - 1 ] = 0;
which has the effect of removing the \n on the end that was left by fgets. (If the input was longer than 100 then this deletes a character of input).
Find the corrected code in below
int main(int argc, char** argv)
{
FILE* file;
file = fopen(argv[1], "r");
char sub[100];
char maxWord[100];
char* word;
int maxLength = 0;
char* sentence = (char*)malloc(100*sizeof(char));
while(fgets(sentence, 100, file) != NULL)
{
maxLength = 0;
strncpy(sub, sentence, strlen(sentence)-1);
sub[strlen(sentence) - 1] = '\0'; //Fix1
strcpy(sentence, sub);
word = strtok(sentence, " ");
while(word != NULL)
{
if(strlen(word) > maxLength)
{
maxLength = strlen(word);
strcpy(maxWord, word);
}
word = strtok(NULL, " ");
}
printf("%s\n", maxWord);
memset(maxWord, 0, sizeof(char));
maxLength = 0; //reset for next sentence;
}
free(sentence);
fclose (file); //Fix2
return 0;
}
Ensure that the file is closed at the end. It is good practice.
I have a file like this:
...
words 13
more words 21
even more words 4
...
(General format is a string of non-digits, then a space, then any number of digits and a newline)
and I'd like to parse every line, putting the words into one field of the structure, and the number into the other. Right now I am using an ugly hack of reading the line while the chars are not numbers, then reading the rest. I believe there's a clearer way.
Edit: You can use pNum-buf to get the length of the alphabetical part of the string, and use strncpy() to copy that into another buffer. Be sure to add a '\0' to the end of the destination buffer. I would insert this code before the pNum++.
int len = pNum-buf;
strncpy(newBuf, buf, len-1);
newBuf[len] = '\0';
You could read the entire line into a buffer and then use:
char *pNum;
if (pNum = strrchr(buf, ' ')) {
pNum++;
}
to get a pointer to the number field.
fscanf(file, "%s %d", word, &value);
This gets the values directly into a string and an integer, and copes with variations in whitespace and numerical formats, etc.
Edit
Ooops, I forgot that you had spaces between the words.
In that case, I'd do the following. (Note that it truncates the original text in 'line')
// Scan to find the last space in the line
char *p = line;
char *lastSpace = null;
while(*p != '\0')
{
if (*p == ' ')
lastSpace = p;
p++;
}
if (lastSpace == null)
return("parse error");
// Replace the last space in the line with a NUL
*lastSpace = '\0';
// Advance past the NUL to the first character of the number field
lastSpace++;
char *word = text;
int number = atoi(lastSpace);
You can solve this using stdlib functions, but the above is likely to be more efficient as you're only searching for the characters you are interested in.
Given the description, I think I'd use a variant of this (now tested) C99 code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
struct word_number
{
char word[128];
long number;
};
int read_word_number(FILE *fp, struct word_number *wnp)
{
char buffer[140];
if (fgets(buffer, sizeof(buffer), fp) == 0)
return EOF;
size_t len = strlen(buffer);
if (buffer[len-1] != '\n') // Error if line too long to fit
return EOF;
buffer[--len] = '\0';
char *num = &buffer[len-1];
while (num > buffer && !isspace((unsigned char)*num))
num--;
if (num == buffer) // No space in input data
return EOF;
char *end;
wnp->number = strtol(num+1, &end, 0);
if (*end != '\0') // Invalid number as last word on line
return EOF;
*num = '\0';
if (num - buffer >= sizeof(wnp->word)) // Non-number part too long
return EOF;
memcpy(wnp->word, buffer, num - buffer);
return(0);
}
int main(void)
{
struct word_number wn;
while (read_word_number(stdin, &wn) != EOF)
printf("Word <<%s>> Number %ld\n", wn.word, wn.number);
return(0);
}
You could improve the error reporting by returning different values for different problems.
You could make it work with dynamically allocated memory for the word portion of the lines.
You could make it work with longer lines than I allow.
You could scan backwards over digits instead of non-spaces - but this allows the user to write "abc 0x123" and the hex value is handled correctly.
You might prefer to ensure there are no digits in the word part; this code does not care.
You could try using strtok() to tokenize each line, and then check whether each token is a number or a word (a fairly trivial check once you have the token string - just look at the first character of the token).
Assuming that the number is immediately followed by '\n'.
you can read each line to chars buffer, use sscanf("%d") on the entire line to get the number, and then calculate the number of chars that this number takes at the end of the text string.
Depending on how complex your strings become you may want to use the PCRE library. At least that way you can compile a perl'ish regular expression to split your lines. It may be overkill though.
Given the description, here's what I'd do: read each line as a single string using fgets() (making sure the target buffer is large enough), then split the line using strtok(). To determine if each token is a word or a number, I'd use strtol() to attempt the conversion and check the error condition. Example:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
/**
* Read the next line from the file, splitting the tokens into
* multiple strings and a single integer. Assumes input lines
* never exceed MAX_LINE_LENGTH and each individual string never
* exceeds MAX_STR_SIZE. Otherwise things get a little more
* interesting. Also assumes that the integer is the last
* thing on each line.
*/
int getNextLine(FILE *in, char (*strs)[MAX_STR_SIZE], int *numStrings, int *value)
{
char buffer[MAX_LINE_LENGTH];
int rval = 1;
if (fgets(buffer, buffer, sizeof buffer))
{
char *token = strtok(buffer, " ");
*numStrings = 0;
while (token)
{
char *chk;
*value = (int) strtol(token, &chk, 10);
if (*chk != 0 && *chk != '\n')
{
strcpy(strs[(*numStrings)++], token);
}
token = strtok(NULL, " ");
}
}
else
{
/**
* fgets() hit either EOF or error; either way return 0
*/
rval = 0;
}
return rval;
}
/**
* sample main
*/
int main(void)
{
FILE *input;
char strings[MAX_NUM_STRINGS][MAX_STRING_LENGTH];
int numStrings;
int value;
input = fopen("datafile.txt", "r");
if (input)
{
while (getNextLine(input, &strings, &numStrings, &value))
{
/**
* Do something with strings and value here
*/
}
fclose(input);
}
return 0;
}