Average of Numbers in a Loop - c

Question

In my C Program, I want to get the average of the sum of numbers being entered until the program stops. What should I add to check the average? Thank you!
#include <stdio.h>
int main (void)
{
int x;
int sum = 0;
int average;
int testEOF;
//Statements
printf("Enter your numbers: <EOF> to stop.\n");
do
{
testEOF = scanf("%d", &x);
if (testEOF !=EOF)
sum +=x;
} while (testEOF !=EOF);
printf ("\nTotal: %d\n", sum);
printf ("\nAverage: %d\n", average);
return 0;
//main
}

Answer 1

As other people explained, you have to initialize sum and count, they are never given their initial values. No need to initialize average and x because you assign sum/count to average and users will assign any value to x.
You have to put everything you want your if statement to do in {...}. But you didn't. Your if statement only does sum +=x and does not work for count++ and average = sum / count. So your program increases the value of count even after EOF. So you found 14/6 rather than 14/5.
You checked testEOF != EOF twice. One is in the if statement, other is in do-while.
I put the code below:
#include <stdio.h>
int main (void){
float x;
float sum = 0;
float count = 0;
float average;
float testEOF;
printf("Enter your numbers: <EOF> to stop.\n");
while(1){
testEOF = scanf("%f", &x);
if (testEOF ==EOF){
break;
}
sum +=x;
count++;
average = sum / count;
}
printf ("\nTotal: %f\n", sum);
printf ("\nAverage: %.2f\n", average);
return 0;
}

Answer 2

#include <stdio.h>
int main (void)
{
float x;
float sum;
float count;
float average;
float testEOF;
//Statements
printf("Enter your numbers: <EOF> to stop.\n");
do
{
testEOF = scanf("%f", &x);
if (testEOF !=EOF)
sum +=x;
count++;
average = sum / count;
} while (testEOF !=EOF);
printf ("\nTotal: %f\n", sum);
printf ("\nAverage: %.2f\n", average);
return 0;
}
This is now almost correct. The only thing is that the number is not getting divided by the number of values entered.
Example:
2
3
3
3
3
Sum is 14
Average: 2.3 (should be 2.8)
This seems that count is being added by 1 every time I get the average.

Answer 3

Well if you want your output to be printed with decimal point you can do the following , in that case
for inputs like 0, 1, 1 the out would be 0.666667 otherwise it will be simply 0 ignoring the decimal part.
the while part can be optimized as suggested by #David C. Rankin
double sum = 0;
double average = 0;
unsigned int count = 0;
//Statements
printf("Enter your numbers: <EOF> to stop.\n");
do
{
testEOF = scanf("%d", &x);
if (testEOF != EOF)
{
sum += x;
count++;
}
} while (testEOF != EOF);
printf ("\nTotal: %f\n", sum);
average = sum / count;
printf ("\nAverage: %f\n", average);