C Extract number from infix string - c

Question

I am trying to extract operators and operands from a string/char array, but unable to do so.
I've tried:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(){
char str[] = "222+333";
char *endPtr;
long int x = strtol(str,&endPtr,10);
printf("Number is %d \n" , x);
printf("Operator is %s \n" , *endPtr);
long int y = strtol(endPtr,&endPtr,10);
printf("Number is %d\n" , y);
return 0;}
Not sure how can I get the operator after using the strtol function.
Also are there any ways to do this without using libraries?

Answer 1

You almost had it, the issue with your code is the printing of the operator. %s is trying to print a null terminated string and requires a memory address. You are passing a character + which is probably ascii on your system so turns into the memory address 43
I've changed the printf statement to print a char vs a null terminated string and it works as you expect it too
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
char str[] = "222+333";
char *endPtr;
long int x = strtol(str, &endPtr, 10);
printf("Number is %d \n", x);
printf("Operator is %c \n", *endPtr);
long int y = strtol(endPtr, &endPtr, 10);
printf("Number is %d\n", y);
return 0;
}
To answer the comment question, endPtr is not pointing at the 3 it is pointing at the + which is valid for strtol to read ie a positive number, when you change the sign to divide or multiply it fails (should work with minus)
What you need to do is advance endPtr by 1 char past the operator that it is point at as in the code below
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
char str[] = "222/333";
char *endPtr;
char theOperator= ' ';
long int x = strtol(str, &endPtr, 10);
printf("Number is %d \n", x);
theOperator= *endPtr;
++endPtr;
printf("Operator is %c \n", theOperator);
long int y = strtol(endPtr, &endPtr, 10);
printf("Number is %d\n", y);
return 0;
}