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So i want my code actualy had different sum each cases, but the sum keep adding from the other cases, like for example the cases 2 sum are sum from loop 2nd + cases 1, the cases 4 sum are sum from cases 1,2,3 and loop number 4
the Output.
`
#include <stdio.h>
int main() {
int cases;
int day;
int animal;
int n;
int a;
int sum = 0;
animal = 0;
printf("Enter cases \n ");
scanf(" %d", &n);
for (cases = 0; cases < n; cases++)
{
printf("cases #%d\n", cases+1);
printf("Enter how many days.\n");
scanf(" %d", &a);
for(day=1;day<=a;){
printf("Enter how many animal that you capture at day #%d\n", day);
scanf(" %d", &animal);
day++;
sum = sum + animal;
}
animal = 0;
day = 1;
printf("cases#%d = %d\n", cases + 1, sum);
}
return 0;
}`
You need to return sum to 0 in every case
Put sum=0; under for (cases...
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Im trying to find the sum of n numbers using a while loop so that it runs like so:
How many numbers: 3
-3,
4,
13,
The sum is: 14
However what I am getting is this:
How many numbers: 3
2,
1,
The sum is: 3
I dont understand it, because i set i = 0
#include <stdio.h>
int main(void) {
int numbers;
printf("How many numbers: ");
scanf("%d", &numbers);
int sum = 0;
int i = 0;
while (i < numbers) {
scanf("%d", &numbers);
sum = sum + numbers;
i++;
}
printf("The sum is: %d", sum);
return 0;
}
A correct solution would be:
#include <stdio.h>
int main(void) {
int numbers;
printf("How many numbers: ");
scanf("%d", &numbers);
int sum = 0;
int i = 0;
int number; // use different variable for the input numbers
while (i < numbers) {
scanf("%d", &number);
sum = sum + number;
i++;
}
printf("The sum is: %d", sum);
return 0;
}
The problem was that you were using one variable for two different things.
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I am trying to figure out how to get the prime number n, and calculate the sum of cubes for that n (1^3 + 2^3 + ... + n^3). So far I can figure out how to get the primes. I just can't figure out how to get that same n to calculate its primes. This is what I have so far:
#include <stdio.h>
int main() {
int n, i, c = 0
printf("Enter any number n: ");
scanf("%d", &n);
for(i=2; i<=n/2; i++){
if(n%i == 0){
c=1;
break;
}
}
if (c==0)
printf(%d is a prime number.",n);
else
printf("%d is not a prime number.",n);
printf("Enter that same number n: ");
scanf("%d", &num);
int num, cube, sum = 0, j=1;
while (j <= num) {
cube = j*j*j;
sum = sum + cube;
j++;
}
printf("sum of cubes of %d is %d\n", num, sum);
return 0:
}
I get an error on the second scanf because it says num is undeclared. What should I do to fix this situation.
Use scanf after declaring int num. Also you have used % in 2nd num. Use
int num, cube, sum = 0, j=1;
scanf("%d", &num);
instead of
scanf("%d", %num);
int num, cube, sum = 0, j=1;
Consider this starting piece
long double sumcubs(int n)
{
int i;
long double ret = 0;
for (i = 1; i <= n; ++i)
ret += (i * i * i);
return ret;
}
Once you have encapsulated this sum of cubes function, it should become easier to organize and write the rest of your code.
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I have the following code, which is not how to implement in C, (if it has one, the keyword with.On the other hand because the program does not access the data type structure, it should not give an error because the variables partial_n2, final_n2, name2 are defined in the struct.
The program has to store in an array of records the names of the students, their partial and final grades. Find the average grade and show a message of SUIT if the student exceeds or equals the grade of 5 or NOT SUIT if it is not enough. Do it for a number of 5 students.
#include <stdio.h>
#include <windows.h>
#include <conio.h>
//PROGRAM EJER009
#define numstudents 5
typedef struct notas{
char name2[20];
float partial_n2, final_n2;
}tnotas;
tnotas notas[numstudents];
tnotas clase;
char name[20];
float partial_n, final_n, n_media;
int i;
int main(){
for (i = 0; i <= numstudents;i++)
{
printf("Enter the student's name% d: ",i);
scanf("%s",name);
printf("Enter your partial note: ");
scanf("%f",&partial_n);
printf("Enter your final note: ");
scanf("%f",&final_n);
printf("\n");
with (clase[i])
{
partial_n2 = partial_n;
final_n2 = final_n;
name2 = name;
}
}
printf("cls");
printf("NAME\tPartial\tFinal\tMedia\tQUALIFICATION\n");
for (i = 1; i<=numstudents;i++){
with clase[i]
{
n_media = (partial_n2 + final_n2) / 2;
printf("%d %d %d",name2,partial_n2,final_n2);
system("color 14"); printf("%lf",n_media);
if (n_media >= 5)
{
system("color 11");
printf("SUITABLE :-)");
}
else
{
system("color 1");
printf("NOT SUITABLE :-(");
}
system("color 7");
}
}
getch();
return 0;
}
You can read a value of a member by:
float f;
f = notas[0].partial_n2;
You can write a value of a member by:
notas[0].partial_n2 = 10.3;
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I need to create a program that gives the sum of the all the numbers between the constants of a and b given by the user. b needs to be greater than a.
#include <stdio.h>
void main()
{
int index, begno, endno, sum = 0;
printf("Program for sum of all numbers in the given range\n");
printf("Enter Beg. No.: ");
scanf("%d", &begno);
printf("Enter End. No.: ");
scanf("%d", &endno);
index = begno;
for(; index <= endno; index ++)
sum = sum + index;
printf("The sum of even numbers between %d and %d is: %d", begno, endno, sum);
}
The code given looks OK, but if you want the sum without including the last number, as is generally the case you should change the for loop like this
for(; index < endno; index ++)
I would start by implementing a loop to compute:
$$\sum_{n=a}^{b}
n$$
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I'm a beginner and I am having a really hard time while doing this program.
The question is:
(1/1!)+(2/2!)+(3/3!)+(4/4!)- - - -n
So here are the n number of terms(in which a number is divided by its factorial) and I have to display the output of the sum of any number of terms which are given in scanf function.
Only one thing I know is that this program can be done by using "Nested for" loop but I haven't perfect grip yet on C language. So you guys have to have help me out in this. :)
#include <stdio.h>
#include <conio.h>
void main(void){
int s,a,b,n,fact=1;
//clrscr();
printf("Enter number of terms=");
scanf("%d",&n);
for(a=1;a<=n;a++) {
fact=fact*a;
b=(a/fact);
printf("Sum=%d",s);
}
getche();
}
P.S It's must for me to do it with "Nested for" loop.
No you do not need any Nested for loops to solve your problem. Here's a procedure you may follow:
function factorial
Input: numbers L.
Output: factorial of L.
function sum
Input: n.
Output: sum.
sum = 0;
for i = 1 to n, do
sum ← sum + (i / factorial(i))
return sum
#include <stdio.h>
int main(void) {
// your code goes here
int n;
float sum = 0,d,fact =1,j,i;
printf("Enter the number:");
scanf("%d",&n);
for(i=1;i<=n;i++){
fact = 1;
for (j = 1; j <= i; j++){
fact = fact * j;
}
d = (float) i / (float) fact ;
sum = sum + d;
}
printf("sum = %f", sum);
return 0;
}
Its working ..you can check over here :-https://ideone.com/JVXQVX