How to access next url from browser click from react-native-webview - reactjs

Question

I have a webview source that I have opened using react-native-webview, I want to access any and every url and console it whenever I click on the webview, so that I can use it as source for another webview. However am unable to figure how to do it
I tried using NavigationStateChange and onShouldLoadSTartwithrequest but that did not help.
below is my code
import React, {useState, useRef, useEffect} from 'react';
import {WebView} from 'react-native-webview';
import {
View,
SafeAreaView,
ActivityIndicator,
StyleSheet,
TouchableOpacity,
Text,
Linking,
Alert,
BackHandler,
} from 'react-native';
import Footer from '../components/Footer';
import {useBackHandler} from '#react-native-community/hooks';
import OnlineConsultationWebviewScreen from './OnlineConsultationWebviewScreen';
export default function ConsultationHomeScreen(props) {
const uri = props.route.params.uri;
const [canGoBack, setCanGoBack] = useState(false);
const [canGoForward, setCanGoForward] = useState(false);
const [currentUrl, setCurrentUrl] = useState('');
const webviewRef = useRef(null);
const renderLoadingView = () => {
return (
<View style={{flex: 1, alignItems: 'center', justifyContent: 'center'}}>
<ActivityIndicator size="large" />
</View>
);
};
const onMessage = (e) => {
// retrieve event data
var data = e.nativeEvent.data;
// maybe parse stringified JSON
try {
data = JSON.parse(data);
} catch (e) {}
// check if this message concerns us
if ('object' == typeof data && data.external_url_open) {
// proceed with URL open request
return Alert.alert(
'External URL',
'Do you want to open this URL in your browser?',
[
{text: 'Cancel', style: 'cancel'},
{text: 'OK', onPress: () => Linking.openURL(data.external_url_open)},
],
{cancelable: false},
);
}
};
const jsCode = `!function(){var e=function(e,n,t){if(n=n.replace(/^on/g,""),"addEventListener"in window)e.addEventListener(n,t,!1);else if("attachEvent"in window)e.attachEvent("on"+n,t);else{var o=e["on"+n];e["on"+n]=o?function(e){o(e),t(e)}:t}return e},n=document.querySelectorAll("a[href]");if(n)for(var t in n)n.hasOwnProperty(t)&&e(n[t],"onclick",function(e){new RegExp("^https?://"+location.host,"gi").test(this.href)||(e.preventDefault(),window.postMessage(JSON.stringify({external_url_open:this.href})))})}();`;
return (
<SafeAreaView style={{flex: 1}}>
<WebView
source={{
uri: uri,
}}
renderLoading={renderLoadingView}
javaScriptEnabled={true}
domStorageEnabled={true}
startInLoadingState={true}
ref={webviewRef}
injectedJavaScript={jsCode}
onMessage={onMessage}
onError={console.error.bind(console, 'error')}
// onShouldStartLoadWithRequest={(event) => {
// if (event.url !== uri ){
// Linking.openURL(event.url);
// console.log('Event', event.url);
// return false;
// }
// return true;
// }}
/>
</SafeAreaView>
);
}
const styles = StyleSheet.create({
tabBarContainer: {
padding: 20,
flexDirection: 'row',
justifyContent: 'space-around',
backgroundColor: '#b43757',
},
button: {
color: 'white',
fontSize: 24,
},
});
Am stuck with this since long, please let me know how do I access any and every click and console it, so that I can sue it later as a new source for Webview.
Any suggestion would be great.

Answer 1

Try this :
<WebView
ref="webview"
source={uri}
onNavigationStateChange={this._onNavigationStateChange.bind(this)}
javaScriptEnabled = {true}
domStorageEnabled = {true}
injectedJavaScript = {this.state.cookie}
startInLoadingState={false}
/>
Add this function :
_onNavigationStateChange(webViewState){
console.log(webViewState.url)
}
FYI webviewState object consists of, use the url property:
{
canGoBack: bool,
canGoForward: bool,
loading: bool,
target: number,
title: string,
url: string,
}
let me know if it helps