Linked list program only printing last two nodes of list - c

Question

I wrote a program to create and print a single linked list. I have used structure pointer to structure pointer for modifying the list. When I print the list it only prints last two nodes added.
#include<stdio.h>
#include<stdlib.h>
struct node{
int data;
struct node *next;
};
struct node * createnode(int num){
struct node * n;
n=(struct node*)malloc(sizeof(struct node));
n->data=num;
n->next=NULL;
return n;
}
void createlist(struct node **head,int num){
struct node *temp=createnode(num);
*head=temp;
return;
}
void options(){
printf("Enter your choice\n");
printf("1.Add at end\n");
printf("2.Add at beginning\n");
printf("3.Add at location\n");
printf("4.Print list\n");
}
void add_end(struct node **head){
int info;
printf("Value: ");
scanf("%d",&info);
if(*head==NULL){
createlist(head,info);
return;
}
struct node *temp=createnode(info);
struct node **end=head;
while((*end)->next!=NULL){
(*end)=(*end)->next;
}
(*end)->next=temp;
}
void print2(struct node *head){
struct node * temp=head;
printf("\nList :");
while(temp!=NULL){
printf("%d ",temp->data);
temp=temp->next;
}
printf("\n");
}
int main(){
struct node *head=NULL;
createlist(&head,5);
int choice=0;
options();
scanf("%d",&choice);
while(1){
switch(choice){
case 1:add_end(&head);
break;
case 4:print2(head);
break;
default:exit(0);
}
options();
scanf("%d",&choice);
}
return 0;
}
Each time, I append 5 to 6 nodes at the end of list and when I print the list, it only prints last to nodes added.
I don't know it is wrong with add_end function or print function.

Answer 1

Your add_line routine incorrectly searches for the last node. The end variable is a pointer to pointer, so it is in a sense equivalent to the head parameter and it is not a temporary value, as it should be. Change the last lines to something like this:
void add_end(struct node **head){
...
struct node *end = *head;
while (end->next) {
end = end->next;
// Original line overwrites the 'head': (*end)=(*end)->next;
}
end->next=temp;
}