I have column which has a long string with multiple sentences. Each sentence is separated by a plus (+) character. For an example: 1. This is line one + 2. This is line two + 3. This is line Four
Now I would like to replace the plus (+) character by a new line. Using T-SQL how can I get the output like:
This is line one
This is line two
This is line three
Just use REPLACE and replace the + character with a carriage return and line break:
SELECT REPLACE(YourString,'+', CHAR(13) + CHAR(10)) AS YourString
FROM dbo.YourTable;
Related
I need to extract substring from list of file paths. Paths are like "\rootfolder\subfolder". Need extract substring as "rootfolder" ( between 2nd backslash and 3rd backslash.
select SUBSTR('\\rootfolder\subfolder\', 3, (REGEXP_INSTR('\\rootfolder\subfolder\','\', 1, 3) - 3)) from table;
But this expression didn't give right result in Snowflake. problem is with backslash character.
Using SPLIT_PART:
SELECT SPLIT_PART($$\\rootfolder\subfolder\$$, $$\$$, 3);
--
SELECT SPLIT_PART('\\\\rootfolder\\subfolder\\', '\\', 3);
Output:
Dollar quoting was used to avoid doubling \.
I have a simple string; for example,'01023201580001'.
I would like to replace the last two characters of this string; '01', with '00'.
I could extract the last two characters from this string as RIGHT(columname,2) and then use
REPLACE([columname], RIGHT([columname], 2), '00') as newColumnString
But in the result, it replaces the first two characters as well?
Expected result: 01023201580000
Result I get: 00023201580000
What am I doing wrong?
The second argument to the replace() function defines a pattern to match. The function will look for all instances of that pattern in the target string (first argument) and replace them with the replacement text (third argument).
If you know you only need to change the last two characters, you can take the value excluding those characters and then append the characters you want:
select left(columname, len(columname) - 2) + '00';
If you are doing this for an entire column and some of the rows might not end with '01', you can filter those out:
update MyTable
set columname = left(columname, len(columname) - 2) + '00'
where columname like '%01';
You could also use stuff() in a similar way.
In SQL server, you can use substring like so:
DECLARE #s NVARCHAR(20) = N'01023201580001';
DECLARE #ReplaceWith NVARCHAR(20) = N'00';
SELECT SUBSTRING(#s, 0, LEN(#s) - 1) + #ReplaceWith;
Output: 01023201580000
I'm looking to extract all the text up until a '\' (backslash).
The substring is required to remove all proceeding characters (17 in total) and so I would like to return all after the 17th until it comes across a backslash.
I've tried using charindex but it doesn't seem to stop at the \ it returns characters afterward. My code is as follows
SELECT path, substring(path,17, CHARINDEX('\',Path)+ LEN(Path)) As Data
FROM [Table].[dbo].[Projects]
WHERE Path like '\ENQ%\' AND
Deleted = '0'
Example
The below screen shot shows the basic query and result i.e the whole string
I then use substring to remove the first X characters as there will always be the same amount of proceeding characters
But what Im actually after is (based on the above result) the "Testing 1" "Testing 2" and "Testing ABC" section
The substring is required to remove all proceeding characters (17 in total) and so I would like to return all after the 17th until it comes across a backslash.
select
substring(path,17,CHARINDEX('\',Path)-17)
from
table
To overcome Invalid length parameter passed to the LEFT or SUBSTRING function error, you can use CASE
select
substring(path,17,
CASE when CHARINDEX('\',Path,17)>0
Then CHARINDEX('\',Path)-17)
else VA end
)
from
table
I have a database that has multiple columns populated with various numeric fields. While trying to populate from a CSV, I must have mucked up assigning delimited fields. The end result is a column containing It's Correct information, but also contains the next column over's data- seperated by a comma.
So instead of Column UPC1 containing "958634", it contains "958634,95877456". The "95877456" is supposed to be in the UPC2 column, instead UPC2 is NULL.
Is there a way for me to split on the comma and send the data to UPC2 while keeping UPC1 data before the comma in tact?
Thanks.
You can do this with string functions. To query the values and verify the logic, try this:
SELECT
LEFT(UPC1, CHARINDEX(',', UPC1) - 1),
SUBSTRING(UPC1, CHARINDEX(',', UPC1) + 1, 1000)
FROM myTable;
If the result is what you want, turn it into an update:
UPDATE myTable SET
UPC1 = LEFT(UPC1, CHARINDEX(',', UPC1) - 1),
UPC2 = SUBSTRING(UPC1, CHARINDEX(',', UPC1) + 1, 1000);
The expression for UPC1 takes the left side of UPC1 up to one character before the comma.
The expression for UPC2 takes the remainder of the UPC1 string starting one character after the comma.
The third argument to SUBSTRING needs some explaining. It's the number of characters you want to include after the starting position of the string (which in this case is one character after the comma's location). If you specify a value that's longer than the string SUBSTRING will just return to the end of the string. Using 1000 here is a lot easier than calculating the exact number of characters you need to get to the end.
I have some data which is stored in a VARCHAR(MAX) column that contains the control characters CR & LF (CHAR(10) & CHAR(13)).
I have some start and end position numbers that I need to use to extract a substring from the text - but when I use SUBSTRING these control characters are ignored, which results in the substring being extracted incorrectly.
I wrote a query using a CTE that replaced all instances of CRLF with another character (¬¬) and then the substring works correctly - however I need to retain the CRLFs in the text as they are used for display purposes.
Can anyone think of a way I can get the SUBSTRING function to include the control characters when it is calculating which part of the string to extract?
The SQL Server version of substring treats CRLF like other characters. For example:
select substring('123' + char(10) + char(13) + '678',1,3)
-->
123
select substring('123' + char(10) + char(13) + '678',4,2)
-->
\r\n
select substring('123' + char(10) + char(13) + '678',6,3)
-->
678
Check your code again, or post a more specific example of where substring does not work as expected.