React Modal Submit Form - reactjs

Question

I'm trying to print out a simple buttton clicked text whenever the submit button is click on my reactstrap modal and somehow my code doesn't do anything, not sure what I have wrong.
I have attached a picture for better visualisation , I'm using reactstrap Modal.
import React, { useState } from "react";
import { Modal, ModalHeader, ModalBody, ModalFooter } from "reactstrap";
import Button from "./Button";
// NOTICE
// Modal is brought in with it's own trigger, so import the component where you want the trigger to be.
const ModalComponent = (props) => {
const {
buttonText,
title,
actionButtonText,
cancelButtonText,
children,
className,
} = props;
const [modal, setModal] = useState(false);
const toggle = () => setModal(!modal);
const alertshow = () => {
alert("button clicked");
};
const closeBtn = (
<button className="close" onClick={toggle}>
×
</button>
);
return (
<div>
<a className="btn_link" onClick={toggle}>
{buttonText}
</a>
<form onSubmit={alertshow}>
<Modal isOpen={modal} toggle={toggle} className={className}>
<ModalHeader className=" border-0" toggle={toggle} close={closeBtn}>
{title}
</ModalHeader>
<ModalBody className="text-left border-0">
<p className="modal-label">Please enter your email address</p>
{children}
</ModalBody>
<ModalFooter className="modal-footer border-0">
<Button className="btn_secondary modal-btn" onClick={toggle}>
{cancelButtonText}
</Button>{" "}
<input
className="btn btn_primary modal-btn"
type="submit"
value={actionButtonText}
/>
</ModalFooter>
</Modal>
</form>
</div>
);
};
export default ModalComponent;

Answer 1

Its happening form should be part of modal not modal should be part of form. This is why its not referencing onSubmit. You need to do this:
<Modal isOpen={modal} toggle={toggle} className={className}>
<form onSubmit={alertshow}>
...rest all content
</Form>
</Modal>
Here is full code:
import React, { useState } from "react";
import "./styles.css";
import { Modal, ModalHeader, ModalBody, ModalFooter, Button } from "reactstrap";
// NOTICE
// Modal is brought in with it's own trigger, so import the component where you want the trigger to be.
const ModalComponent = (props) => {
const {
buttonText,
title,
actionButtonText,
cancelButtonText,
children,
className
} = props;
const [modal, setModal] = useState(false);
const toggle = () => setModal(!modal);
const alertshow = () => {
alert("button clicked");
};
const closeBtn = (
<button className="close" onClick={toggle}>
×
</button>
);
return (
<div>
<div onClick={toggle}>{buttonText}</div>
<Modal isOpen={modal} toggle={toggle} className={className}>
<form onSubmit={alertshow}>
<ModalHeader className=" border-0" toggle={toggle} close={closeBtn}>
{title}
</ModalHeader>
<ModalBody className="text-left border-0">
<p className="modal-label">Please enter your email address</p>
{children}
</ModalBody>
<ModalFooter className="modal-footer border-0">
<Button className="btn_secondary modal-btn" onClick={toggle}>
{cancelButtonText}
</Button>{" "}
<input
className="btn btn_primary modal-btn"
type="submit"
value={actionButtonText}
/>
</ModalFooter>
</form>
</Modal>
</div>
);
};
export default function App() {
return (
<div className="App">
<ModalComponent
title="Hello"
cancelButtonText="Cancel"
actionButtonText="Submit"
buttonText="testing"
/>
</div>
);
}
Here is the demo: https://codesandbox.io/s/fervent-bash-51lxe?file=/src/App.js:0-1826

Answer 2

Accepted answer doesn't work when Modal is scrollable.
Here is how to resolve the issue:
<Modal show={ show } onHide={ onClose }
scrollable={ true }
onSubmit={ handleSubmit(onSave) }
dialogAs={ FormWrappedModal }>
<Modal.Header closeButton>
<Modal.Title>some title</Modal.Title>
</Modal.Header>
<Modal.Body>some body</Modal.Body>
<Modal.Footer>some body</Modal.Footer>
</Modal>
We need to introduce custom component FormWrappedModal for that purpose:
const FormWrappedModal = ( props: any)=>{
return (
<form onSubmit={ props.onSubmit }>
<Modal.Dialog { ...props } />
</form>
);
};