I can't input a string in c - c

Question

So I've tried so much but I can't input a string even using: fgets, gets, scanf, and scanf("%[^\n]%*c",pharse). I need a string with the spaces. It just jumps the code line of input I think.
Please answer with a explanation of why it doesn't work
https://repl.it/#YashKumar11/String#main.c
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void) {
const int DIMMAX=100;
char pharse[DIMMAX+1];
int stringLength;
int choice=0;
while(choice != '5'){
printf("1)Enter a new pharse.");
printf("\n2)");
printf("\n3)");
printf("\n4)");
printf("\n5)\n");
scanf("%d",&choice);
switch(choice){
case 1:
printf("\n=====================\n");
scanf ("%[^\n]%*c",pharse); //<-----------------------It jumps here
printf("\n=====================\n");
stringLength = strlen(pharse);
printf("%s",pharse);
break;
case 2:
break;
case 3:
break;
case 4:
break;
case 5:
break;
default:
printf("\nNot a valid option.\n\n");
break;
}
}
return 0;
}

Answer 1

the statement to input the parase fails because the input for choice leaves a \n in the input stream.
When the second call to scanf() is made, it immediately returns (with a returned value of 0) because the first character input is \n.
suggest following each call to scanf() with:
int ch;
while( (ch = getchar()) != '\n' && ch != EOF );
that also implies that the format string of the second call to scanf() should have the %*c removed.

Answer 2

Your problem is not in the line that you try to read the string, but in the previous call to scanf()
scanf() was written to scanf formatted input. Keyboard input is not that. It can be everything except formatted. The user has over 100 keys to choose from
When the user types a '1' to input a phrase scanf() does not consume the newline. In fact the user can type 1 here we go to enter some text!
and then ENTER. And scanf() will be ok with just the '1'. The rest of the chars would be left there for the program to read. scanf() has no way to know what is left there.
Also scanf() return an int with the number of values read, and it can be zero if the user entered no digits. And you did not tested in your code.
Compare with your code a bit modified below
#define DIMMAX 100
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void) {
char phrase[DIMMAX + 1];
int stringLength;
printf("1) Enter a new phrase");
printf("\n2)");
printf("\n3)");
printf("\n4)");
printf("\n5) Exit\n\nOption: ");
fgets(phrase, DIMMAX, stdin);
while (phrase[0] != '5')
{
switch (phrase[0]) {
case '1':
printf("\n=====================\n");
fgets(phrase, DIMMAX, stdin);
printf("\n=====================\n");
stringLength = strlen(phrase);
phrase[strlen(phrase) - 1] = 0; // deletes the '\n'
printf("Phrase: '%s', len = %zd\n\n", phrase, strlen(phrase));
break;
case '2':
break;
case '3':
break;
case '4':
break;
case '5':
break;
default:
printf("\n'%c' (dec %d) is not a valid option.\n\n",
phrase[0], phrase[0]);
break;
}
printf("1) Enter a new phrase");
printf("\n2)");
printf("\n3)");
printf("\n4)");
printf("\n5) Exit\n\nOption: ");
fgets(phrase, DIMMAX, stdin);
}; // while()
return 0;
}
Maybe it helps to understand.
Note that instead of stopping rigth at the digit, like scanf(), fgets() read up to and including the newline, so if you are using printf() and not puts() to output it, you must take the last byte off the string read