Inserting spaces between a 5 digit number - c

Question

I have started an intro to programming course that uses the C language and we have an assignment to make a program that takes a 5 digit number from the user such as 12345 and it prints it out as 1 2 3 4 5.
I tried to google around for help but all the answers given used code way too complicated for my understanding considering the course just started and we have only learned printf and scanf, if and switch statements and while and for loops.
I tried putting all the numbers given into separate int variables which made the program stop and then tried to put them into chars but the testing program said it was wrong since we are supposed to use int.
Is there a simple way to do this?
EDIT:
What I have tried:
#include <stdio.h>
int main(void) {
int num1,
num2,
num3,
num4,
num5;
printf("Give 5 digit number > ");
scanf("%d%d%d%d%d", &num1, &num2, &num3, &num4, &num5);
printf("Seperated number is %d %d %d %d %d", num1, num2, num3, num4, num5);
return (0);
}
Also tried that code but with char variable type but that wasn't allowed it has to be int.
The testing program gives an expected output which for 00001 is Given number 1 seperated is 0 0 0 0 1 or for -12321 is Given number -12321 seperated is -1 -2 -3 -2 -1

Answer 1

You can read user input into a char array using scanf.
Then using for loop you can loop through each char (1,2,3,4,5)
Use printf in the loop to print from array and a space. printf("%c ", input_from_user[i]);

Answer 2

I suppose the point here is understanding how C stores things. You're reading in characters (that is a set of 8-byte values that are commonly displayed as letters) and converting each one to an integer (commonly a 32-bit value that stores a number)
So you want to read the input using scanf to get a character string of your 5 digits, then use a for loop to go over each one, reading a single character from the string and converting it into an integer variable. then printf that variable plus a space, and move on to repeat the next digit.
If you read the digits in one by one then its even easier as you only need the for loop to read, convert, and print each digit as its read.

Answer 3

According to the question, you would be given a number of 5 digits and then you have to print the digits of that number as well.
So, in your program, you have taken five digits individually as input, to me it seems wrong. I am giving my solution below:
#include <stdio.h>
int main(void)
{
int num,idx=0,i=0;
int arr[5]; // for storing the five digits;
scanf("%d",&num);
while(num){ //loop will terminate when the num = 0
int digit = num%10;
num = num/10;
arr[idx] = digit;
idx++;
}
//Printing from the last, as the digit are stored in reverse order.
for(int i=4;i>=0;i--){
printf("%d ",arr[i]);
}
return 0;
}

Answer 4

I don't really understand the purpose of this exercise. If you are learning C, the last function you should learn is scanf. It boggles the mind that so many people teach it early. Try very hard not to use scanf at all until you understand the language well enough to realize that you probably never need it. That said, I suppose the point of the exercise is to do something like:
#include <stdio.h>
int
main(void)
{
unsigned num;
char buf[6];
printf("Give 5 digit number > ");
if( scanf("%u", &num) != 1 || num > 99999 ) {
fprintf(stderr, "Invalid input\n");
return 1;
}
printf("Separated number is");
snprintf(buf, sizeof buf, "%d", num);
for( int i = 0; buf[i]; i++ ) {
printf(" %c", buf[i]);
}
putchar('\n');
return 0;
}

Answer 5

Although likely beyond OP's stage, code can use recursion to print the value from most significant to least.
#include <stdio.h>
void print_digit(int n, int depth) {
if (depth > 1) print_digit(n/10, depth - 1); // print "left" digits first
printf(" %d", n%10);
}
void print_5(int n) {
// To do: checking for correct spelling
printf("Given number %d seperated", n); // or separated
print_digit(n, 5);
printf("\n");
}
int main(void)
{
print_5(1);
print_5(-12321);
return 0;
}
Output
Given number 1 seperated 0 0 0 0 1
Given number -12321 seperated -1 -2 -3 -2 -1

Answer 6

You could use your approach by limiting the number of bytes you read for each number:
#include <stdio.h>
int main(void) {
int num1, num2, num3, num4, num5;
printf("Give 5 digit number > ");
if (scanf("%1d%1d%1d%1d%1d", &num1, &num2,&num3, &num4, &num5) == 5) {
printf("Separated number is %d %d %d %d %d\n", num1, num2, num3, num4, num5);
}
return 0;
}
Note however that this is probably not what you are expected to do. You should instead read a single number and decompose it into its five digits:
#include <stdio.h>
int main(void) {
int num;
printf("Give 5 digit number > ");
if (scanf("%d", &num) == 1 && num >= 10000 && num <= 99999) {
printf("Separated number is %d %d %d %d %d\n",
num / 10000, num / 1000 % 10, num / 100 % 10, num / 10 % 10, num % 10);
}
return 0;
}