How to close an open PowerShell WPF Dialog without using a button - wpf

Question

Hi there I am launch a WPF Dialog from PowerShell with other processes controlled in a Do While loop. On exiting the loop I am hoping to close the open Dialog. Here is some of the relevant code used.
Function New-WPFDialog {
<#
.SYNOPSIS
This neat little function is based on the one from Brian Posey's Article on Powershell GUIs
.DESCRIPTION
AW re-factored a bit to return the resulting XaML Reader and controls as a single, named collection.
.PARAMETER XamlData
XamlData - A string containing valid XaML data
.EXAMPLE
$MyForm = New-WPFDialog -XamlData $XaMLData
$MyForm.Exit.Add_Click({...})
$null = $MyForm.UI.Dispatcher.InvokeAsync{$MyForm.UI.ShowDialog()}.Wait()
.NOTES
Place additional notes here.
.LINK
http://www.windowsnetworking.com/articles-tutorials/netgeneral/building-powershell-gui-part2.html
.INPUTS
XamlData - A string containing valid XaML data
.OUTPUTS
a collection of WPF GUI objects.
#>
Param(
[Parameter(Mandatory = $True, HelpMessage = 'XaML Data defining a GUI', Position = 1)]
[string]$XamlData
)
# Add WPF and Windows Forms assemblies
try {
Add-Type -AssemblyName PresentationCore, PresentationFramework, WindowsBase, system.windows.forms
}
catch {
Throw 'Failed to load Windows Presentation Framework assemblies.'
}
# Create an XML Object with the XaML data in it
[xml]$xmlWPF = $XamlData
# Create the XAML reader using a new XML node reader, UI is the only hard-coded object name here
Set-Variable -Name XaMLReader -Value #{ 'UI' = ([Windows.Markup.XamlReader]::Load((new-object -TypeName System.Xml.XmlNodeReader -ArgumentList $xmlWPF))) }
# Create hooks to each named object in the XAML reader
$Elements = $xmlWPF.SelectNodes('//*[#Name]')
ForEach ( $Element in $Elements ) {
$VarName = $Element.Name
$VarValue = $XaMLReader.UI.FindName($Element.Name)
$XaMLReader.Add($VarName, $VarValue)
}
return $XaMLReader
}
Function New-PopUpWindowAlertFixed {
param(
[string]
$MessageText = "No Message Supplied")
# This is the XaML that defines the GUI.
$WPFXamLAlertFixed = #'
<Window xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
WindowStyle="None"
Background="#006373"
Width="300"
Height="300">
<ContentControl Foreground="White">
<Grid VerticalAlignment="Center" HorizontalAlignment="Right" Background="#006373" >
<Grid.RowDefinitions>
<RowDefinition/>
<RowDefinition Height="Auto"/>
<RowDefinition Height="Auto"/>
</Grid.RowDefinitions>
<StackPanel Orientation="Horizontal" HorizontalAlignment="Left" Grid.Row="0">
<TextBlock Name="Message10" Margin="20,32,20,20" TextWrapping="Wrap" Text="Session Manager" FontSize="18"/>
</StackPanel>
</Grid>
</ContentControl>
</Window>
'#
$WPFGuiAlert2 = New-WPFDialog -XamlData $WPFXamlAlertFixed
$WPFGuiAlert2.Message10.Text = "Session Manager"
# $WPFGuiAlert.ApplicationExitCode = 99
<# CODE #>
$null = $WPFGUIAlert2.UI.Dispatcher.InvokeAsync{ $WPFGuiAlert2.UI.Show() }.Wait()
}
Do {
New-PopUpWindowStart
If ( $Script:VarStart -eq $true ) {
New-PopUpWindowAlertFixed
$Script:VarLoop = 1
<# I'd like to close the Dialog here #>
}
} While ( $Script:VarLoop -eq 1 )
Does anyone have any suggestions how I can close the dialog without using a button. The dialog is launched using:
$null = $WPFGUIAlert2.UI.Dispatcher.InvokeAsync{ $WPFGuiAlert2.UI.Show() }.Wait()

Answer 1

I resolved this by changing:
$WPFGuiAlert2 = New-WPFDialog -XamlData $WPFXamlAlertFixed
to
$Script:WPFGuiAlert2 = New-WPFDialog -XamlData $WPFXamlAlertFixed
then closing the dialog with:
$WPFGuiAlert2.UI.Close()
My error detailed null expression so realised my variable was out of scope.