Basex Xquery filter retrieved data - basex

Question

<a id="aId" deleted="false">
<b id="bIdOne" deleted="false">
<c>cValue</c>
<d id="dId" deleted="true">
<e>eValue</e>
</d>
<f id="fId" deleted="false">
<g>gValue</g>
</f>
</b>
<b id="bIdTwo" deleted="true">
<c>cValue</c>
<d id="dId" deleted="true">
<e>eValue</e>
</d>
<f id="fId" deleted="false">
<g>gValue</g>
</f>
</b>
<b id="bIdThree" deleted="false">
<c>cValue</c>
<d id="dId" deleted="true">
<e>eValue</e>
</d>
<f id="fId" deleted="true">
<g>gValue</g>
</f>
</b>
<Y><yValue</Y>
</a>
Expected Output :
retrieve list of b and its child where deleted attribute is false, Expected output is below
query should be something like :
for $x in $data//descendant::[(#deleted=\"false\" or empty(#deleted))] return $x/b";
<b id="bIdOne" deleted="false">
<c>cValue</c>
<f id="fId" deleted="false">
<g>gValue</g>
</f>
</b>
<b id="bIdThree" deleted="false">
<c>cValue</c>
<Y><yValue</Y>
</b>

Answer 1

You are probably looking for something like this:
let $data := [your code above, fixed - your <Y> is in the wrong place for your output]
return
element root
{
for $e1 in $data//b[#deleted="false"]
let $dat :=$e1//*[not(#deleted="true")][not(ancestor::*[#deleted="true"])]
return
element{name($e1)}{$e1/#*,$dat}
}
Output should be your desired output.