feed command output into for /f - batch-file

Question

Is it possible to pipe the command output to the following batch file as its input?
I'd like to feed output from commands such as dir c:\temp |find "05" |find "new" to the following batch file. Because my command have many variations and I don't want to edit the batch file every time I need it, thus, I'm looking for a way to feed the command output directly to the batch file, instead of having the batch file generate its input using dir /b. Basically, what I'd like to achieve is to find from a list of files (generated using the dir command) the file whose name contains the highest number (achieved using the batch file.) Example:
today123.txt
today456.txt
tomorrow123.txt
tomorrow456.txt
With the dir command, I can filter off today or tomorrow, leaving only two files. Then, feed these two files to the batch file and have it select the one which has 456 in the file name. Of course, this is a simplified example. I may have more files and more groups than those in the example.
for /f %%a in ('dir /b ^|sort /r ^|findstr /r [0-9]') do (
set "filename=%%a"
goto done
)
:done
echo the highest found is %filename%
exit /b 0

Answer 1

There are quite a number of ways. This is one of them:
#echo off & set filename=
if "%~5" == "" set "myfind=dir /b ^| find "%~2" ^| find "%~3" ^| find "%~4" ^|sort /r ^|findstr /r [0-9]"
if "%~4" == "" set "myfind=dir /b ^| find "%~2" ^| find "%~3" ^|sort /r ^|findstr /r [0-9]"
if "%~3" == "" set "myfind=dir /b ^| find "%~2" ^|sort /r ^|findstr /r [0-9]"
if "%~2" == "" set "myfind=dir /b ^|sort /r ^|findstr /r [0-9]"
pushd "%~1"
for /f %%a in ('%myfind%') do (
set "filename=%%a"
goto done
)
:done
popd
if not defined filename echo Not match found & exit /b 1
echo the highest found is %filename%
exit /b 0
Typically you would run it as:
batch-file-name.cmd "C:\path\to\search" "search1" "search2" "search3"
for instance, using your example:
batch-file-name.cmd "c:\temp" "05" "new"
or even extend the search:
batch-file-name.cmd "c:\temp" "05" "new" ".txt"
How it works:
We set the search string each time in the case an additional find command is required. for now we have up to three finds and one path, but it can be extended to more. You have to set them in descending order though.
I also added an additional statement if not defined filename to ensure you are alerted if a find is not matched.

Answer 2

The following gets the highest of a given group:
#echo off
setlocal enabledelayedexpansion
set "search=today"
set "max=0"
for %%a in (%search%*.txt) do (
set "name=%%~na"
set "number=!name:%search%=!"
if !number! gtr !max! set /a max=number
)
echo max number for %search% is %max%
set "highest=%search%%max%.txt"
echo %highest%
Attention, there is no errorchecking at all, so it depends on the correct format of the file names. (errorchecking can be added when needed)
To get the search string as a parameter, simply replace set "search=today" with set "search=%~1"