I would like to write an ID number from this format YYMMDDXXXXXXX to this 19YY-MM-DD or 20YY-MM-DD in sql.
select Customer_identifier from MartDB.DBO.BAW_AllSources_Stage1_202005
Customer_identifier cexample is 8801213535353 where 88 represents year of birth 1988, 01 represents month of birth January, 21 represents day of birth the 21st. 21 Jan 1988. I want to convert that to a date 1988-01-21
Below the script but work only with born date <2000 because you have a design problem
SELECT TRY_CAST('19'+ SUBSTRING(CAST(8801213535353 AS varchar(13)), 1, 6) AS date)
I used TRY_CAST because return a value cast to the specified data type if the cast succeeds, otherwise, returns null.
You can also format the date in a different way using FORMAT function (from SQL Server 2012).
Some example:
SELECT FORMAT(TRY_CAST('19'+ SUBSTRING(CAST(8801213535353 AS varchar(13)), 1, 6) AS date), 'yyyy-MMMM-dd')
The output is: 1988-January-21
Example with culture parameter:
SELECT FORMAT(TRY_CAST('19'+ SUBSTRING(CAST(8801213535353 AS varchar(13)), 1, 6) AS date), 'D', 'En-Us')
The output is: Thursday, January 21, 1988
Related
select DATENAME(month,29*5)
Can any one please tell me logic behind the above query.
How it always returns correct month name when provided month number as integer.
Datetime values in Sql server are stored on 8 bytes.
The first 4 bytes represents the date and the last 4 byte represents the time.
On the date part, date is stored as the number of days since 1900-01-01.
On the time part, it's the number of clock ticks since midnight.
There are 300 clock ticks per second, so a tick is 3.33333 milliseconds.
That's also the reason why datetime is only accurate to .003 of a second.
This query will hopefully help to explain:
SELECT CAST(0 As datetime) As Date_0,
29*5 As NumberOfDays,
CAST(29*5 as datetime) As TheDate,
DATENAME(month,29*5) As TheMonthName
Results:
Date_0 NumberOfDays TheDate TheMonthName
----------------------- ------------ ----------------------- ------------
1900-01-01 00:00:00.000 145 1900-05-26 00:00:00.000 May
As for the last part of your question, 29 (28 would work as well) is the magic number here - 30 is too big (May would be returned for 4 and 5) and 27 is too small - (September would be returned for 9 and 10).
Basically i'ts just math - get the number correctly so that each time you double it with any number between 1 and 12 will give you a number of days that sums up to a day that belongs to the correct month.
You can test it yourself using this script:
DECLARE #MagicNumber int = 28
;With cte as
(
select 1 as num
union all
select num + 1
from cte
where num < 12
)
SELECT num, DATENAME(month, #MagicNumber * num ) As TheMonthName
from cte
Just change the value of #MagicNumber and see the results you get.
I think I will able to explain.
The default year-month-day for any date data type is 1900-01-01. If we consider above select query, it add 29*5 days into default date and gives the MONTHNAME.
Select DATENAME(month,29*5)
Now understand the DATENAME
DateName - Returns a character string that represents the specified datepart of the specified date. Its have different -2 argument and give the different-2 result as per datepart.
Argument 1 - Is the part of the date to return.
Argument 2 - Is a any date (Is an expression that can be resolved to a
time, date, smalldatetime, datetime, datetime2, or datetimeoffset
value.)
Here we given month as a first argument. Which means it return monthname.
The calculation of 29*5 gives 145 answer and if we simply cast into date it consider as a days and calculate as 1900-01-01 + 145 and gives the date 1900-05-26 00:00:00.000.
Means if we get the month of this will give the 5 - MAY as a answer.
Execute this query and check the answer for the above logic.
Select DATENAME(month,29*5), (29*5) , DATENAME(month, '12:10:30.123'), DATENAME(month, getdate())
select cast (145 as datetime)
DECLARE #t datetime = '12:10:30.123';
SELECT DATENAME(month, 29*5), 145/30.00;
Check for further.
MSDN Link
Convert Month Number to Month Name Function in SQL (check the #user275683 answer)
If you are simply want to show the month corresponding to month number then you should have to use like this.
declare #intMonth as int
set #intMonth = 5
Select DateName( month , DateAdd( month , #intMonth , -1 ))
I'm trying to write a MSSQL query that will return the name of the day (e.g. Monday, Tuesday...) using the supplied day of year (e.g. 1 for 1st of January, 2 for 2nd of January).
SELECT DATENAME(dy, '2016-03-01') - returns 61
SELECT DATENAME(dw, '2016-03-01') - returns Tuesday
SELECT DATENAME(dw, 61) - returns Saturday
I want my 3rd query to return the correct day name (Tuesday in this instance), using the supplied day of year (61 in this instance). I understand that the problem is to do with the date portion in DATENAME(datepart, date), as it is in the incorrect date format but I do not have the full date, only the day of year.
Many thanks!
DECLARE #day_of_year int
SELECT #day_of_year = 61
SELECT DATENAME(dw, DATEADD(DAY, #day_of_year - 1, '2016-01-01'))
I am getting date in following format in a flat file. How do I convert into valid date format (YYYY-MM-DD) in Informatica?
Input data:
Jan 4, 2016
Feb 2, 2016
Desired Output :
2016-01-04
2016-02-02
Use this expression in a output column of type String
TO_CHAR(TO_DATE(inputField,'MON DD,YYYY'),'YYYY-MM-DD')
The inner TO_DATE function converts the string 'Jan 4, 2016' to a Date type. Note the format string 'MON DD,YYYY', it is the format in which it is coming from source.
The outer TO_CHAR function converts the Date to a String again in the specified format 'YYYY-MM-DD'
I imported a table into SQL Server 2014 and I found that the date format is in BST and GST format. I want to create a view and change the whole column to SQL Server date type to perform operations. I don't mind truncating the time section.
Wed Apr 07 00:00:00 BST 1943
Tue Jan 08 00:00:00 GMT 1985
I was able to do it in Excel with the following formula but want to do it in SQL Server:
=IFERROR(DATEVALUE(MID(E2,9,2)&"-"&MID(E2,5,3)&"-"&RIGHT(E2,4)), "")
All I am looking for is
1943-04-07
1985-01-08
This solution assumes that every row in the source data follows the same format. If there are any fringe cases these will fail.
With SQL Server 2012, and higher, you have the handy DATEFROMPARTS function. This function returns a date when passed a year, month and day. These can be extracted with SUBSTRING and RIGHT from the source string.
Extracting the month number (1~12) is achieved by building an arbitrary date string (01-mmm-2000). This is cast into a date, from which the month number is extracted. Generally speaking I would't recommend using date strings in any format other than YYYY-MM-DD. However this avoids the use of a CTE, which OP was keen to do.
Example
/* Let's create some sample values to
* experiment with.
*/
DECLARE #Sample TABLE
(
DateVal VARCHAR(50)
)
;
INSERT INTO #Sample
(
DateVal
)
VALUES
('Wed Apr 07 00:00:00 BST 1943'),
('Tue Jan 08 00:00:00 GMT 1985')
;
/* Extracting the month number is achieved by first casting the 3 character month
* name as a full date, by appended a day and year. Then the month number is
* extracted from this.
*/
SELECT
s.DateVal,
SUBSTRING(s.DateVal, 9, 2) AS [Day],
MONTH(CAST('01-' + SUBSTRING(s.DateVal, 5, 3) + '-2000' AS DATE)) AS [Month],
RIGHT(s.DateVal, 4) AS [Year],
-- Reuse the values shown above.
DATEFROMPARTS(
RIGHT(s.DateVal, 4),
MONTH(CAST('01-' + SUBSTRING(s.DateVal, 5, 3) + '-2000' AS DATE)),
SUBSTRING(s.DateVal, 9, 2)
) AS [Date]
FROM
#Sample AS s
;
EDIT: The original solution contained a CTE, used to look up the month number from a 3 character month name. This has been replaced.
SELECT CONVERT(date, RIGHT(DateColumn, 4)+ '-' + RIGHT('0' + Convert(nvarchar, (Month(SUBSTRING(DateColumn, 5, 3) + '2016'))), 2) + '-' + SUBSTRING(DateColumn, 9, 2)) as dob
FROM MyTable
Your sample output doesn't match your input data. I think you meant 1985-01-08.
For a shorter solution, you can use CAST or CONVERT with style 107. It expects the string to be in the Mon dd, yyyy format:
SELECT CONVERT(datetime, SUBSTRING(DateColumn, 5, 6) + ', ' + RIGHT(DateColumn, 4), 107)
FROM MyTable
I have an issue retrieving the data that I would like. I have a Varchar column that consist of various information. I would like to extract the date from that column only. However, I have been unsuccessful. I used the following SQL(2008) to get the data below, But I can't seem to just get the date only without the time. Obviously, the date and time are in different position. Hope you can help.
SELECT substring(Data, 8, 17)
from mastInfo
9/25/2013 12:36:5
Jul 8 2013 11:40
9/25/2013 12:43:5
SELECT convert(date, Case When IsDate(substring(Data, 8, 17)) = 1
Then substring(Data, 8, 17)
Else NULL END)
from mastInfo
Since you are starting off with a string, it is possible that it does not represent a valid date. Using the IsDate function will return 1 when the string can be converted to a date. Basically, this code will convert to date those values that can be converted, and will return NULL for those values that cannot be converted to a valid date.
If you are using SQL Server 2012 or newer, then you can use Try_Convert().
Here's the SQL Fiddle.
Here's an example (from the above SQLFiddle):
Select Try_Convert(datetime, DateAsString) As DateAsDateTime
,DateAsString
From SomeTable
Here's the result:
DATEASDATETIME DATEASSTRING
September, 25 2013 12:36:05+0000 9/25/2013 12:36:5
September, 25 2013 12:43:05+0000 9/25/2013 12:43:5
July, 08 2013 11:40:00+0000 Jul 8 2013 11:40
if you want convert it to date time use :
SELECT CONVERT(Datetime, '2011-09-28 18:01:00', 120) -- to convert it to Datetime
if you want get time :
SELECT LTRIM(RIGHT(CONVERT(VARCHAR(20), '2011-09-28 18:01:00', 100), 7))
if you want date part :
SELECT CONVERT (DATE, GETDATE())
what version of sql server?
can you try this:
SELECT convert(date, substring(Data, 8, 17))
from mastInfo
First convert Varchar into DateTime and after that again convert it in varchar in desired date format like 101,102,103
Try this:
select convert(varchar(50),convert(datetime,'9/25/2013 12:43:5'),101)