Null When Passing String - c

Question

I got this output "Hospital (null) ΓÇô Report for COVIC19 ΓÇô Community Visit"
I'm trying to printout the name of the hospital from the function readHospital() but all I got for the output is these weird looking text. So sorry I'm very new to coding.
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <conio.h>
char readHospital();
void intro(char a);
int main() {
char hospital_name;
hospital_name = readHospital();
intro(hospital_name);
}
char readHospital() {
char a[100];
printf("Enter Hospital Name: ");
fgets(a, 100, stdin);
return a;
}
void intro(char hospital_name) {
printf("Hospital %s – Report for COVIC19 – Community Visit", hospital_name);
}

Answer 1

I've changed your code, The readHospital function that you are using in your code is not a correct function for reading the input string from the user and returning it.
Instead, you can use the readNewString function that I've written.
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <conio.h>
char * readNewString();
void intro(char a[100]);
int main() {
char * hospital_name;
hospital_name = readNewString();
intro(hospital_name);
}
char *readNewString(void) {
char buffer[1024];
if (!fgets(buffer, sizeof buffer, stdin)) {
return NULL; // read failed, e.g., EOF
}
int len = strlen(buffer);
if (len > 0 && buffer[len - 1] == '\n') {
buffer[--len] = '\0'; // remove the newline
// You may also wish to remove trailing and/or leading whitespace
} else {
// Invalid input
//
// Depending on the context you may wish to e.g.,
// consume input until newline/EOF or abort.
}
char *str = malloc(len + 1);
if (!str) {
return NULL; // out of memory (unlikely)
}
return strcpy(str, buffer); // or use `memcpy` but then be careful with length
}
void intro(char hospital_name[100]) {
printf("Hospital %s – Report for COVIC19 – Community Visit", hospital_name);
}

Answer 2

Please note that hospital_name is of char type and you return a string, char list char*