Array based search function - c

Question

I have been trying to create a search function based exclusively on arrays rather than strings. The problem that I currently seem to be finding is that the code is tagging locations, without actually finding the correct letters. The end goal is for the code to find the full word and state how many characters it is into the line. Any help would be greatly appreciated.
int main()
{
int read = 1, i = 0, z = 0, q, o = 0, b;
char a[15];
char letters [] = "HELLOMYNAMEISELDERPRICEANDIHAVECOMETOSHAREWITHYOUTHISMOSTAMAZINGBOOK";
printf("HELLOMYNAMEISELDERPRICEANDIHAVECOMETOSHAREWITHYOUTHISMOSTAMAZINGBOOK\n");
printf("Please type in a word to search for in upper case:\n");
scanf(" %c", &a[1]);
scanf("%c", &a[2]);
if (a[2] != '\n') {scanf("%c", &a[3]); q=2;}
if (read == 1) {if (a[3] != '\n') {scanf("%c", &a[4]); q=3;} else read = 0;}
if (read == 1) {if (a[4] != '\n') {scanf("%c", &a[5]); q=4;} else read = 0;}
if (read == 1) {if (a[5] != '\n') {scanf("%c", &a[6]); q=5;} else read = 0;}
if (read == 1) {if (a[6] != '\n') {scanf("%c", &a[7]); q=6;} else read = 0;}
if (read == 1) {if (a[7] != '\n') {scanf("%c", &a[8]); q=7;} else read = 0;}
if (read == 1) {if (a[8] != '\n') {scanf("%c", &a[9]); q=8;} else read = 0;}
if (read == 1) {if (a[9] != '\n') {scanf("%c", &a[10]); q=9;} else read = 0;}
if (read == 1) {if (a[10] != '\n') {scanf("%c", &a[11]); q=10;} else read = 0;}
if (read == 1) {if (a[11] != '\n') {scanf("%c", &a[12]); q=11;} else read = 0;}
if (read == 1) {if (a[12] != '\n') {scanf("%c", &a[13]); q=12;} else read = 0;}
if (read == 1) {if (a[13] != '\n') {scanf("%c", &a[14]); q=13;} else read = 0;}
if (read == 1) {if (a[14] != '\n') {scanf("%c", &a[15]); q=14;} else read = 0;}
while (i != 1){
printf("line read\n");
if (a[1] == letters[z]){
printf("Found");
for (int p=0; p < q; p++){
o = z+p;
printf("checking for word\n");
if (a[p] == letters[o]){
printf("That bitch");}
else {break;}
}}
z++;
if (letters[z]=='\n'){i = 1;}
}
printf("%c", letters[z]);
printf("hmmm");
}

Answer 1

This redefined code should work for you:
#include <stdio.h>
#include <string.h>
int main()
{
char str[] = "HELLOMYNAMEISELDERPRICEANDIHAVECOMETOSHAREWITHYOUTHISMOSTAMAZINGBOOK";
char letter[100];
int i, j, k, counter;
i = j = k = counter = 0;
printf("%s\n", str);
printf("Enter a substring to find: ");
scanf("%s", letter);
for (i = 0; str[i]; i++) { // str[i] != '\0'
if (str[i] == letter[j]) {
for (k = i, j = 0; str[k] && letter[j]; j++, k++)
if (str[k] != letter[j])
break;
if (!letter[j]) { // when letter[j] meets false and substring found
printf("\nFound at %d!\n", counter);
return 0;
}
} else {
printf("."); // for decoration
counter++;
}
}
printf(" No matches!\n");
return 0;
}
Sample Output
HELLOMYNAMEISELDERPRICEANDIHAVECOMETOSHAREWITHYOUTHISMOSTAMAZINGBOOK
Enter a substring to find: BOOK
................................................................
Found at 64!